Execute code inside IF statement in all cases but one
What would be the right way to do this? For example:
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
I was thinking of using keyword continue insided if but I would also like to know if there is a better way?
EDIT
To be more precise I am going to try explaining it better. $var1 is current logged in user's role and $var2 is role of user whose details (let's say email) are being inserted into table. code2 is part that always need to be executed and there are a lot of lines there and therefore I shouldn't duplicate it. code1 is part where I am informing user that he is supposed to verify his email address and I am inserting into table the same thing (that email is still not verified). There is only one case when this shouldn't happen and when email should be automatically verified upon adding and that case is when $var1 is ADMIN and $var2 is REGULAR USER. In all other cases, code1 should be executed.
php if-statement
asked Nov 23 '18 at 10:27
niknamenikname
7718
add a comment |
What would be the right way to do this? For example:
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
I was thinking of using keyword continue insided if but I would also like to know if there is a better way?
EDIT
To be more precise I am going to try explaining it better. $var1 is current logged in user's role and $var2 is role of user whose details (let's say email) are being inserted into table. code2 is part that always need to be executed and there are a lot of lines there and therefore I shouldn't duplicate it. code1 is part where I am informing user that he is supposed to verify his email address and I am inserting into table the same thing (that email is still not verified). There is only one case when this shouldn't happen and when email should be automatically verified upon adding and that case is when $var1 is ADMIN and $var2 is REGULAR USER. In all other cases, code1 should be executed.
php if-statement
asked Nov 23 '18 at 10:27
niknamenikname
7718
4
Don't understand your question please more elobrate
– user10186369
Nov 23 '18 at 10:29
Exactly. It seems to me you do not need the else statement at all, because the code 2 should be executed all the time
– Pavel Janicek
Nov 23 '18 at 10:30
add a comment |
What would be the right way to do this? For example:
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
I was thinking of using keyword continue insided if but I would also like to know if there is a better way?
EDIT
To be more precise I am going to try explaining it better. $var1 is current logged in user's role and $var2 is role of user whose details (let's say email) are being inserted into table. code2 is part that always need to be executed and there are a lot of lines there and therefore I shouldn't duplicate it. code1 is part where I am informing user that he is supposed to verify his email address and I am inserting into table the same thing (that email is still not verified). There is only one case when this shouldn't happen and when email should be automatically verified upon adding and that case is when $var1 is ADMIN and $var2 is REGULAR USER. In all other cases, code1 should be executed.
php if-statement
asked Nov 23 '18 at 10:27
niknamenikname
7718
What would be the right way to do this? For example:
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
I was thinking of using keyword continue insided if but I would also like to know if there is a better way?
EDIT
To be more precise I am going to try explaining it better. $var1 is current logged in user's role and $var2 is role of user whose details (let's say email) are being inserted into table. code2 is part that always need to be executed and there are a lot of lines there and therefore I shouldn't duplicate it. code1 is part where I am informing user that he is supposed to verify his email address and I am inserting into table the same thing (that email is still not verified). There is only one case when this shouldn't happen and when email should be automatically verified upon adding and that case is when $var1 is ADMIN and $var2 is REGULAR USER. In all other cases, code1 should be executed.
php if-statement
php if-statement
asked Nov 23 '18 at 10:27
niknamenikname
7718
asked Nov 23 '18 at 10:27
niknamenikname
7718
edited Nov 23 '18 at 10:38
nikname
asked Nov 23 '18 at 10:27
niknamenikname
7718
asked Nov 23 '18 at 10:27
niknamenikname
7718
asked Nov 23 '18 at 10:27
niknamenikname
7718
7718
4
Don't understand your question please more elobrate
– user10186369
Nov 23 '18 at 10:29
Exactly. It seems to me you do not need the else statement at all, because the code 2 should be executed all the time
– Pavel Janicek
Nov 23 '18 at 10:30
add a comment |
4
Don't understand your question please more elobrate
– user10186369
Nov 23 '18 at 10:29
Exactly. It seems to me you do not need the else statement at all, because the code 2 should be executed all the time
– Pavel Janicek
Nov 23 '18 at 10:30
4
4
Don't understand your question please more elobrate
– user10186369
Nov 23 '18 at 10:29
Don't understand your question please more elobrate
– user10186369
Nov 23 '18 at 10:29
Exactly. It seems to me you do not need the else statement at all, because the code 2 should be executed all the time
– Pavel Janicek
Nov 23 '18 at 10:30
Exactly. It seems to me you do not need the else statement at all, because the code 2 should be executed all the time
– Pavel Janicek
Nov 23 '18 at 10:30
add a comment |
1 Answer
1
active
oldest
votes
From your question
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
That sounds to me that code2 should be executed no matter what. In that case, you have to switch the if statement:
if( $var1 != 'value1' || $var2 != 'value2'){
code1();
}
code2();
The code2 will be always execute and in the case you need, the code1 will execute too
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
add a comment |
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1 Answer
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1 Answer
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oldest
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oldest
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From your question
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
That sounds to me that code2 should be executed no matter what. In that case, you have to switch the if statement:
if( $var1 != 'value1' || $var2 != 'value2'){
code1();
}
code2();
The code2 will be always execute and in the case you need, the code1 will execute too
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
add a comment |
From your question
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
That sounds to me that code2 should be executed no matter what. In that case, you have to switch the if statement:
if( $var1 != 'value1' || $var2 != 'value2'){
code1();
}
code2();
The code2 will be always execute and in the case you need, the code1 will execute too
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
add a comment |
From your question
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
That sounds to me that code2 should be executed no matter what. In that case, you have to switch the if statement:
if( $var1 != 'value1' || $var2 != 'value2'){
code1();
}
code2();
The code2 will be always execute and in the case you need, the code1 will execute too
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
From your question
if ($var1 == 'value1' && $var2 == 'value2') {
//code2
return;
} else {
//code1
}
//code2
That sounds to me that code2 should be executed no matter what. In that case, you have to switch the if statement:
if( $var1 != 'value1' || $var2 != 'value2'){
code1();
}
code2();
The code2 will be always execute and in the case you need, the code1 will execute too
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
answered Nov 23 '18 at 10:34
Pavel JanicekPavel Janicek
8,809114268
8,809114268
add a comment |
add a comment |
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4
Don't understand your question please more elobrate
– user10186369
Nov 23 '18 at 10:29
Exactly. It seems to me you do not need the else statement at all, because the code 2 should be executed all the time
– Pavel Janicek
Nov 23 '18 at 10:30