How can I form in python this matrix to the corresponding graph?
$begingroup$
im working in graph theory and sagemath or python.
for prove that R(3,3)=6 is necessary to find a counterexample of a graph where it has neither a triangle monochromatic red nor a K_3 blue, for this case, an adjacency matrix is designed with entries 1 and -1, where the entry in the matrix is 1 if the corresponding edge is red or -1 if the corresponding edge is blue, the main diagonal 0 since there are no edges.
I would like to know if it is possible to build the corresponding graph in sage with the adjacency matrix
Ex: part of the code says,
"""Subgraph"""
for k in range(2**10):
G=CrearMatriz(k,5)
if Encontrar_Subgrafo(G,3)==True:
print (str(k)+ " Passed")
k=k+1
else:
print(k)
U=CrearMatriz(k,5)
print (U)
break
print("Done")
where the counterexample is
array([[ 0, -1, -1, 1, 1],
[-1, 0, 1, -1, 1],
[-1, 1, 0, 1, -1],
[ 1, -1, 1, 0, -1],
[ 1, 1, -1, -1, 0]])
How can I form in sage or python this matrix to the corresponding graph?
python graph
New contributor
$endgroup$
add a comment |
$begingroup$
im working in graph theory and sagemath or python.
for prove that R(3,3)=6 is necessary to find a counterexample of a graph where it has neither a triangle monochromatic red nor a K_3 blue, for this case, an adjacency matrix is designed with entries 1 and -1, where the entry in the matrix is 1 if the corresponding edge is red or -1 if the corresponding edge is blue, the main diagonal 0 since there are no edges.
I would like to know if it is possible to build the corresponding graph in sage with the adjacency matrix
Ex: part of the code says,
"""Subgraph"""
for k in range(2**10):
G=CrearMatriz(k,5)
if Encontrar_Subgrafo(G,3)==True:
print (str(k)+ " Passed")
k=k+1
else:
print(k)
U=CrearMatriz(k,5)
print (U)
break
print("Done")
where the counterexample is
array([[ 0, -1, -1, 1, 1],
[-1, 0, 1, -1, 1],
[-1, 1, 0, 1, -1],
[ 1, -1, 1, 0, -1],
[ 1, 1, -1, -1, 0]])
How can I form in sage or python this matrix to the corresponding graph?
python graph
New contributor
$endgroup$
add a comment |
$begingroup$
im working in graph theory and sagemath or python.
for prove that R(3,3)=6 is necessary to find a counterexample of a graph where it has neither a triangle monochromatic red nor a K_3 blue, for this case, an adjacency matrix is designed with entries 1 and -1, where the entry in the matrix is 1 if the corresponding edge is red or -1 if the corresponding edge is blue, the main diagonal 0 since there are no edges.
I would like to know if it is possible to build the corresponding graph in sage with the adjacency matrix
Ex: part of the code says,
"""Subgraph"""
for k in range(2**10):
G=CrearMatriz(k,5)
if Encontrar_Subgrafo(G,3)==True:
print (str(k)+ " Passed")
k=k+1
else:
print(k)
U=CrearMatriz(k,5)
print (U)
break
print("Done")
where the counterexample is
array([[ 0, -1, -1, 1, 1],
[-1, 0, 1, -1, 1],
[-1, 1, 0, 1, -1],
[ 1, -1, 1, 0, -1],
[ 1, 1, -1, -1, 0]])
How can I form in sage or python this matrix to the corresponding graph?
python graph
New contributor
$endgroup$
im working in graph theory and sagemath or python.
for prove that R(3,3)=6 is necessary to find a counterexample of a graph where it has neither a triangle monochromatic red nor a K_3 blue, for this case, an adjacency matrix is designed with entries 1 and -1, where the entry in the matrix is 1 if the corresponding edge is red or -1 if the corresponding edge is blue, the main diagonal 0 since there are no edges.
I would like to know if it is possible to build the corresponding graph in sage with the adjacency matrix
Ex: part of the code says,
"""Subgraph"""
for k in range(2**10):
G=CrearMatriz(k,5)
if Encontrar_Subgrafo(G,3)==True:
print (str(k)+ " Passed")
k=k+1
else:
print(k)
U=CrearMatriz(k,5)
print (U)
break
print("Done")
where the counterexample is
array([[ 0, -1, -1, 1, 1],
[-1, 0, 1, -1, 1],
[-1, 1, 0, 1, -1],
[ 1, -1, 1, 0, -1],
[ 1, 1, -1, -1, 0]])
How can I form in sage or python this matrix to the corresponding graph?
python graph
python graph
New contributor
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