How to construct DTO in Nest.js for @Body
I am a beginner in Nest.js and I found it extremely good. I read the official docs and learned about DTOs. When My Body is like this:
{
"username" : "username",
"password" : "password"
}then I can simply create user.dto.ts like this:
import { IsNotEmpty } from 'class-validator';
export class UserDTO {
@IsNotEmpty()
username: string;
@IsNotEmpty()
password: string;
}Then I use this in my controller like this.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: UserDTO) {
return this.userService.login(data);
}But my question is what if my Body is something like this.
{
"data": {
"username": "username",
"password": "password",
}
}then what modifications I need to make in my ```user.dto.ts`` file to make it work? Thanks
javascript nestjs typeorm
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
add a comment |
I am a beginner in Nest.js and I found it extremely good. I read the official docs and learned about DTOs. When My Body is like this:
{
"username" : "username",
"password" : "password"
}then I can simply create user.dto.ts like this:
import { IsNotEmpty } from 'class-validator';
export class UserDTO {
@IsNotEmpty()
username: string;
@IsNotEmpty()
password: string;
}Then I use this in my controller like this.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: UserDTO) {
return this.userService.login(data);
}But my question is what if my Body is something like this.
{
"data": {
"username": "username",
"password": "password",
}
}then what modifications I need to make in my ```user.dto.ts`` file to make it work? Thanks
javascript nestjs typeorm
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
add a comment |
I am a beginner in Nest.js and I found it extremely good. I read the official docs and learned about DTOs. When My Body is like this:
{
"username" : "username",
"password" : "password"
}then I can simply create user.dto.ts like this:
import { IsNotEmpty } from 'class-validator';
export class UserDTO {
@IsNotEmpty()
username: string;
@IsNotEmpty()
password: string;
}Then I use this in my controller like this.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: UserDTO) {
return this.userService.login(data);
}But my question is what if my Body is something like this.
{
"data": {
"username": "username",
"password": "password",
}
}then what modifications I need to make in my ```user.dto.ts`` file to make it work? Thanks
javascript nestjs typeorm
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
I am a beginner in Nest.js and I found it extremely good. I read the official docs and learned about DTOs. When My Body is like this:
{
"username" : "username",
"password" : "password"
}then I can simply create user.dto.ts like this:
import { IsNotEmpty } from 'class-validator';
export class UserDTO {
@IsNotEmpty()
username: string;
@IsNotEmpty()
password: string;
}Then I use this in my controller like this.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: UserDTO) {
return this.userService.login(data);
}But my question is what if my Body is something like this.
{
"data": {
"username": "username",
"password": "password",
}
}then what modifications I need to make in my ```user.dto.ts`` file to make it work? Thanks
{
"username" : "username",
"password" : "password"
}{
"username" : "username",
"password" : "password"
}import { IsNotEmpty } from 'class-validator';
export class UserDTO {
@IsNotEmpty()
username: string;
@IsNotEmpty()
password: string;
}import { IsNotEmpty } from 'class-validator';
export class UserDTO {
@IsNotEmpty()
username: string;
@IsNotEmpty()
password: string;
} @Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: UserDTO) {
return this.userService.login(data);
} @Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: UserDTO) {
return this.userService.login(data);
}{
"data": {
"username": "username",
"password": "password",
}
}{
"data": {
"username": "username",
"password": "password",
}
}javascript nestjs typeorm
javascript nestjs typeorm
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
asked Nov 25 '18 at 23:46
Usama TahirUsama Tahir
313112
313112
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The answer is: You don't need to modify your DTO.
@Body() decorator also takes in an optional argument: @Body(path?: string).
The key here is to understand what @Body() does. @Body() without any argument will return req.body object. @Body('path') will return req.body.path (or req.body['path']. With this knowledge, you can pass 'data' in @Body('data') and it will return req.body.data which will be your DTO.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body('data') data: UserDTO) {
// data will be your req.body.data which is your UserDTO
return this.userService.login(data);
}
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
add a comment |
You may create a wrapper class that would carry your dto such as
export class Data<T> {
@ApiModelProperty()
readonly data: T;
constructor(data: any = {}) {
this.data = data;
}
}
and in your controller you will have
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: Data<UserDTO>) {
return this.userService.login(data);
}
in your service you will do something like
return new Data(this.userDto);
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The answer is: You don't need to modify your DTO.
@Body() decorator also takes in an optional argument: @Body(path?: string).
The key here is to understand what @Body() does. @Body() without any argument will return req.body object. @Body('path') will return req.body.path (or req.body['path']. With this knowledge, you can pass 'data' in @Body('data') and it will return req.body.data which will be your DTO.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body('data') data: UserDTO) {
// data will be your req.body.data which is your UserDTO
return this.userService.login(data);
}
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
add a comment |
The answer is: You don't need to modify your DTO.
@Body() decorator also takes in an optional argument: @Body(path?: string).
The key here is to understand what @Body() does. @Body() without any argument will return req.body object. @Body('path') will return req.body.path (or req.body['path']. With this knowledge, you can pass 'data' in @Body('data') and it will return req.body.data which will be your DTO.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body('data') data: UserDTO) {
// data will be your req.body.data which is your UserDTO
return this.userService.login(data);
}
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
add a comment |
The answer is: You don't need to modify your DTO.
@Body() decorator also takes in an optional argument: @Body(path?: string).
The key here is to understand what @Body() does. @Body() without any argument will return req.body object. @Body('path') will return req.body.path (or req.body['path']. With this knowledge, you can pass 'data' in @Body('data') and it will return req.body.data which will be your DTO.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body('data') data: UserDTO) {
// data will be your req.body.data which is your UserDTO
return this.userService.login(data);
}
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
The answer is: You don't need to modify your DTO.
@Body() decorator also takes in an optional argument: @Body(path?: string).
The key here is to understand what @Body() does. @Body() without any argument will return req.body object. @Body('path') will return req.body.path (or req.body['path']. With this knowledge, you can pass 'data' in @Body('data') and it will return req.body.data which will be your DTO.
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body('data') data: UserDTO) {
// data will be your req.body.data which is your UserDTO
return this.userService.login(data);
}
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
answered Nov 26 '18 at 4:03
Chau TranChau Tran
1,3311423
1,3311423
add a comment |
add a comment |
You may create a wrapper class that would carry your dto such as
export class Data<T> {
@ApiModelProperty()
readonly data: T;
constructor(data: any = {}) {
this.data = data;
}
}
and in your controller you will have
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: Data<UserDTO>) {
return this.userService.login(data);
}
in your service you will do something like
return new Data(this.userDto);
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
add a comment |
You may create a wrapper class that would carry your dto such as
export class Data<T> {
@ApiModelProperty()
readonly data: T;
constructor(data: any = {}) {
this.data = data;
}
}
and in your controller you will have
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: Data<UserDTO>) {
return this.userService.login(data);
}
in your service you will do something like
return new Data(this.userDto);
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
add a comment |
You may create a wrapper class that would carry your dto such as
export class Data<T> {
@ApiModelProperty()
readonly data: T;
constructor(data: any = {}) {
this.data = data;
}
}
and in your controller you will have
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: Data<UserDTO>) {
return this.userService.login(data);
}
in your service you will do something like
return new Data(this.userDto);
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
You may create a wrapper class that would carry your dto such as
export class Data<T> {
@ApiModelProperty()
readonly data: T;
constructor(data: any = {}) {
this.data = data;
}
}
and in your controller you will have
@Post('login')
@UsePipes(new ValidationPipe())
login(@Body() data: Data<UserDTO>) {
return this.userService.login(data);
}
in your service you will do something like
return new Data(this.userDto);
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
answered Nov 26 '18 at 15:35
kyserslickkyserslick
146116
146116
add a comment |
add a comment |
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