How to select only the fields without Display: none CSS property using JQuery?
Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?
function (controlId) {
var returnValidFlag = true;
//var requiredClass = $this.find('.required');
//console.log(requiredClass);
$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');
// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);
// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);
if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});
return returnValidFlag;
}
jquery
add a comment |
Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?
function (controlId) {
var returnValidFlag = true;
//var requiredClass = $this.find('.required');
//console.log(requiredClass);
$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');
// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);
// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);
if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});
return returnValidFlag;
}
jquery
Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?
– billynoah
Nov 26 '18 at 0:28
add a comment |
Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?
function (controlId) {
var returnValidFlag = true;
//var requiredClass = $this.find('.required');
//console.log(requiredClass);
$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');
// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);
// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);
if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});
return returnValidFlag;
}
jquery
Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?
function (controlId) {
var returnValidFlag = true;
//var requiredClass = $this.find('.required');
//console.log(requiredClass);
$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');
// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);
// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);
if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});
return returnValidFlag;
}
jquery
jquery
asked Nov 25 '18 at 23:49
Sarbraj DulaiSarbraj Dulai
305
305
Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?
– billynoah
Nov 26 '18 at 0:28
add a comment |
Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?
– billynoah
Nov 26 '18 at 0:28
Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?
– billynoah
Nov 26 '18 at 0:28
Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?
– billynoah
Nov 26 '18 at 0:28
add a comment |
2 Answers
2
active
oldest
votes
You can use :visible
selector.
display
is not part of an element's attributes , it is a style property
$('.required:visible)').each(...
add a comment |
In jQuery, you can use filter.
$('div').filter((index, node) => $(node).css('display') !== 'none')
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use :visible
selector.
display
is not part of an element's attributes , it is a style property
$('.required:visible)').each(...
add a comment |
You can use :visible
selector.
display
is not part of an element's attributes , it is a style property
$('.required:visible)').each(...
add a comment |
You can use :visible
selector.
display
is not part of an element's attributes , it is a style property
$('.required:visible)').each(...
You can use :visible
selector.
display
is not part of an element's attributes , it is a style property
$('.required:visible)').each(...
answered Nov 26 '18 at 0:01
charlietflcharlietfl
140k1389123
140k1389123
add a comment |
add a comment |
In jQuery, you can use filter.
$('div').filter((index, node) => $(node).css('display') !== 'none')
add a comment |
In jQuery, you can use filter.
$('div').filter((index, node) => $(node).css('display') !== 'none')
add a comment |
In jQuery, you can use filter.
$('div').filter((index, node) => $(node).css('display') !== 'none')
In jQuery, you can use filter.
$('div').filter((index, node) => $(node).css('display') !== 'none')
answered Nov 26 '18 at 0:13
user44user44
435318
435318
add a comment |
add a comment |
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Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?
– billynoah
Nov 26 '18 at 0:28