Write a method to replace all spaces in a string with %20











up vote
8
down vote

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I have implemented a solution to this Cracking the Coding Interview question:



Write a method to replace all spaces in a string with %20.
You may assume that the string has sufficient space at the end of the string to hold the additional characters,
and that you are given the true length of the string.
USE character array to perform this operation in place.



public static String conversion(String str, int length){

char strChars = str.toCharArray();
int numSpaces = 0;

for(int i = 0; i < length; i++){
if(strChars[i] == ' ')
numSpaces++;
}

int newLength = length + 2 * numSpaces;
char newChars = new char[newLength];

for(int i = length - 1; i >= 0; i--){
char c = strChars[i];
if(c != ' '){
newChars[i + 2 * numSpaces] = c;
}
else{
newChars[i + 2 * numSpaces] = '0';
newChars[i + 2 * numSpaces - 1] = '2';
newChars[i + 2 * numSpaces - 2] = '%';
numSpaces--;
}
}
String newString = String.valueOf(newChars);
return newString;
}


Can anyone give me any feedback on my implementation in regards of efficiency or improvements?










share|improve this question




















  • 1




    Whatever your implementation is, you should ask them why they decided to let a C programmer design their Java interview questions. A Java string cannot have space at the end of the string. Java strings are not modified in-place. Therefore the whole question doesn't make sense.
    – Roland Illig
    Jun 30 '17 at 17:54






  • 1




    And by the way: don't trust that book. I just filed several bug reports against its "solutions".
    – Roland Illig
    Jun 30 '17 at 19:41















up vote
8
down vote

favorite












I have implemented a solution to this Cracking the Coding Interview question:



Write a method to replace all spaces in a string with %20.
You may assume that the string has sufficient space at the end of the string to hold the additional characters,
and that you are given the true length of the string.
USE character array to perform this operation in place.



public static String conversion(String str, int length){

char strChars = str.toCharArray();
int numSpaces = 0;

for(int i = 0; i < length; i++){
if(strChars[i] == ' ')
numSpaces++;
}

int newLength = length + 2 * numSpaces;
char newChars = new char[newLength];

for(int i = length - 1; i >= 0; i--){
char c = strChars[i];
if(c != ' '){
newChars[i + 2 * numSpaces] = c;
}
else{
newChars[i + 2 * numSpaces] = '0';
newChars[i + 2 * numSpaces - 1] = '2';
newChars[i + 2 * numSpaces - 2] = '%';
numSpaces--;
}
}
String newString = String.valueOf(newChars);
return newString;
}


Can anyone give me any feedback on my implementation in regards of efficiency or improvements?










share|improve this question




















  • 1




    Whatever your implementation is, you should ask them why they decided to let a C programmer design their Java interview questions. A Java string cannot have space at the end of the string. Java strings are not modified in-place. Therefore the whole question doesn't make sense.
    – Roland Illig
    Jun 30 '17 at 17:54






  • 1




    And by the way: don't trust that book. I just filed several bug reports against its "solutions".
    – Roland Illig
    Jun 30 '17 at 19:41













up vote
8
down vote

favorite









up vote
8
down vote

favorite











I have implemented a solution to this Cracking the Coding Interview question:



Write a method to replace all spaces in a string with %20.
You may assume that the string has sufficient space at the end of the string to hold the additional characters,
and that you are given the true length of the string.
USE character array to perform this operation in place.



public static String conversion(String str, int length){

char strChars = str.toCharArray();
int numSpaces = 0;

for(int i = 0; i < length; i++){
if(strChars[i] == ' ')
numSpaces++;
}

int newLength = length + 2 * numSpaces;
char newChars = new char[newLength];

for(int i = length - 1; i >= 0; i--){
char c = strChars[i];
if(c != ' '){
newChars[i + 2 * numSpaces] = c;
}
else{
newChars[i + 2 * numSpaces] = '0';
newChars[i + 2 * numSpaces - 1] = '2';
newChars[i + 2 * numSpaces - 2] = '%';
numSpaces--;
}
}
String newString = String.valueOf(newChars);
return newString;
}


Can anyone give me any feedback on my implementation in regards of efficiency or improvements?










share|improve this question















I have implemented a solution to this Cracking the Coding Interview question:



Write a method to replace all spaces in a string with %20.
You may assume that the string has sufficient space at the end of the string to hold the additional characters,
and that you are given the true length of the string.
USE character array to perform this operation in place.



public static String conversion(String str, int length){

char strChars = str.toCharArray();
int numSpaces = 0;

for(int i = 0; i < length; i++){
if(strChars[i] == ' ')
numSpaces++;
}

int newLength = length + 2 * numSpaces;
char newChars = new char[newLength];

for(int i = length - 1; i >= 0; i--){
char c = strChars[i];
if(c != ' '){
newChars[i + 2 * numSpaces] = c;
}
else{
newChars[i + 2 * numSpaces] = '0';
newChars[i + 2 * numSpaces - 1] = '2';
newChars[i + 2 * numSpaces - 2] = '%';
numSpaces--;
}
}
String newString = String.valueOf(newChars);
return newString;
}


Can anyone give me any feedback on my implementation in regards of efficiency or improvements?







java strings interview-questions escaping






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edited Mar 3 '17 at 20:11









200_success

127k15148411




127k15148411










asked Mar 3 '17 at 15:44









TheLearner

400312




400312








  • 1




    Whatever your implementation is, you should ask them why they decided to let a C programmer design their Java interview questions. A Java string cannot have space at the end of the string. Java strings are not modified in-place. Therefore the whole question doesn't make sense.
    – Roland Illig
    Jun 30 '17 at 17:54






  • 1




    And by the way: don't trust that book. I just filed several bug reports against its "solutions".
    – Roland Illig
    Jun 30 '17 at 19:41














  • 1




    Whatever your implementation is, you should ask them why they decided to let a C programmer design their Java interview questions. A Java string cannot have space at the end of the string. Java strings are not modified in-place. Therefore the whole question doesn't make sense.
    – Roland Illig
    Jun 30 '17 at 17:54






  • 1




    And by the way: don't trust that book. I just filed several bug reports against its "solutions".
    – Roland Illig
    Jun 30 '17 at 19:41








1




1




Whatever your implementation is, you should ask them why they decided to let a C programmer design their Java interview questions. A Java string cannot have space at the end of the string. Java strings are not modified in-place. Therefore the whole question doesn't make sense.
– Roland Illig
Jun 30 '17 at 17:54




Whatever your implementation is, you should ask them why they decided to let a C programmer design their Java interview questions. A Java string cannot have space at the end of the string. Java strings are not modified in-place. Therefore the whole question doesn't make sense.
– Roland Illig
Jun 30 '17 at 17:54




1




1




And by the way: don't trust that book. I just filed several bug reports against its "solutions".
– Roland Illig
Jun 30 '17 at 19:41




And by the way: don't trust that book. I just filed several bug reports against its "solutions".
– Roland Illig
Jun 30 '17 at 19:41










5 Answers
5






active

oldest

votes

















up vote
5
down vote













Your strategy of counting the spaces and then back-looping to shift the characters right (and replace spaces with %20) is good. The basic algorithm is probably as good as it gets as a character array system.



Your variable names are decent, and the code flows well.



On the other hand, there are some small things I would change.



Possible bug



Your code, given the input conversion("abc ", 3) you would output "abc" but you should not remove any "extra" padding in the string, you should return "abc "



In fact, you should only really have the one char array. The second one is making you do bad things ;-)



Enhanced fors



Use enhanced-for loops when possible, and always use {} blocks for if-statements, even 1-liners:




for(int i = 0; i < length; i++){
if(strChars[i] == ' ')
numSpaces++;
}




should be:



for(char c : strChars){
if(c == ' ') {
numSpaces++;
}
}



Comments



Comment unusual loops - your second for-loop is an odd one, and it often helps the reader if you comment why a loop is non-sequential (or even if you just make sure they are aware of it).



multiple indexes



Have you considered having a separate index for each position in the array - the position of the source character, and the position of where to insert it?



public static String conversion(String str, int length){

char strChars = str.toCharArray();

int numSpaces = 0;
for(int i = 0; i < length; i++){
if(strChars[i] == ' ') {
numSpaces++;
}
}

int insert = length + 2 * numSpaces - 1;

// loop backwards through source characters.
for(int i = length - 1; i >= 0; i--){
char c = strChars[i];
if(c == ' '){
strChars[insert--] = '0';
strChars[insert--] = '2';
strChars[insert--] = '%';
} else{
strChars[insert--] = c;
}
}
return String.valueOf(strChars);
}


The benefit of two indexes is that you can keep the logic more readable ... ("more" is relative) as each index moves by one character at a time... and a space counts as 3 characters.






share|improve this answer





















  • A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
    – Thomas Junk
    Mar 3 '17 at 19:24










  • I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
    – TheLearner
    Mar 3 '17 at 20:14


















up vote
4
down vote













You have re-invented the wheel which makes for a rather poor answer to an interview question (Academic context would be different). A good interview answer emphasises knowledge of the inbuilt capabilities balanced with an appreciation of development priorities. Simple code that uses inbuilt libraries is quick to code, robust, widely understandable and maintainable. I would expect to see something like:



log.info(new String("/A A/B B/C C").replaceAll(" ", "%20"));


Even better would be the following proving an appreciation of Test driven development:



@Test
public void test() {
final String actualResult = new String("/A /B /C /D ").replaceAll(" ", "%20");
assertEquals("/A%20/B%20/C%20/D%20", actualResult);
}


Otherwise your coding practice is reasonable.




  • You have used Java naming conventions. +1

  • You have mostly named for the problem domain. +1

  • Your code is readable. +1


Expanding on Interview aspect
The ability to stick closely to the requirements is an important skill in a developer but should not mean blindly following the specification. The specification is a reflection of requirements. Requirements shouldn't specify implementation details and may be in error. Spotting bogus things and having the strength of character to call them out in a constructive manner are important skills in a developer. A skilled interviewer can also use coding questions to test your reaction and behaviour as well as your technical/coding skills.






share|improve this answer



















  • 1




    As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
    – D. Jurcau
    Mar 3 '17 at 20:22






  • 1




    The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
    – Martin Spamer
    Mar 3 '17 at 21:00




















up vote
2
down vote













You ignored the instructions



According to the problem statement, the String passed in has enough room to hold all the expanded characters, and you are supposed to do the expansion in-place. You went ahead and allocated a second character array and copied the characters from one array to another.



The whole backwards loop you used only makes sense if you are expanding in-place in the same array. If you allocate a new array, you might as well write the loop in the forwards direction since it doesn't make any difference.



Other things




  1. I find it easier to read an if-else statement if the if condition is written in the positive sense if (c == ' ') rather than if (c != ' ').

  2. Although your backwards loop does the right thing, I had to stare at it for a long time to convince myself that it was correct. Instead of an expression for the insertion point, I would just use another index.


(I just noticed that @rolfl already covered these points)



Rewrite



Here is how I would have modified your function. (It looks a lot like @rolfl's version actually):



public static String conversion(String str, int length)
{
char strChars = str.toCharArray();
int numSpaces = 0;

for (int i = 0; i < length; i++) {
if (strChars[i] == ' ') {
numSpaces++;
}
}

int newLength = length + 2 * numSpaces;

for (int i = length - 1, j = newLength - 1; i >= 0; i--) {
char c = strChars[i];
if (c == ' ') {
strChars[j--] = '0';
strChars[j--] = '2';
strChars[j--] = '%';
} else {
strChars[j--] = c;
}
}

return String.valueOf(strChars);
}





share|improve this answer




























    up vote
    2
    down vote













    How come nobody notices the name of the method conversion() ? Shouldn't your method names be verbs? convert() is a better method name in this case.






    share|improve this answer





















    • Good catch, someone mentioned this before.Thank you.
      – TheLearner
      Mar 4 '17 at 23:45


















    up vote
    0
    down vote













    How to split a string in Java



    A tad bit on the concerned side here as I am not sure if your goal is a brute force coding requirement or not but the above link shows how to use the string split function an example is



    String out = string.split("-");


    Then just reassemble the string from out






    share|improve this answer























    • »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
      – Thomas Junk
      Mar 3 '17 at 19:14











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    5 Answers
    5






    active

    oldest

    votes








    5 Answers
    5






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    5
    down vote













    Your strategy of counting the spaces and then back-looping to shift the characters right (and replace spaces with %20) is good. The basic algorithm is probably as good as it gets as a character array system.



    Your variable names are decent, and the code flows well.



    On the other hand, there are some small things I would change.



    Possible bug



    Your code, given the input conversion("abc ", 3) you would output "abc" but you should not remove any "extra" padding in the string, you should return "abc "



    In fact, you should only really have the one char array. The second one is making you do bad things ;-)



    Enhanced fors



    Use enhanced-for loops when possible, and always use {} blocks for if-statements, even 1-liners:




    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ')
    numSpaces++;
    }




    should be:



    for(char c : strChars){
    if(c == ' ') {
    numSpaces++;
    }
    }



    Comments



    Comment unusual loops - your second for-loop is an odd one, and it often helps the reader if you comment why a loop is non-sequential (or even if you just make sure they are aware of it).



    multiple indexes



    Have you considered having a separate index for each position in the array - the position of the source character, and the position of where to insert it?



    public static String conversion(String str, int length){

    char strChars = str.toCharArray();

    int numSpaces = 0;
    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ') {
    numSpaces++;
    }
    }

    int insert = length + 2 * numSpaces - 1;

    // loop backwards through source characters.
    for(int i = length - 1; i >= 0; i--){
    char c = strChars[i];
    if(c == ' '){
    strChars[insert--] = '0';
    strChars[insert--] = '2';
    strChars[insert--] = '%';
    } else{
    strChars[insert--] = c;
    }
    }
    return String.valueOf(strChars);
    }


    The benefit of two indexes is that you can keep the logic more readable ... ("more" is relative) as each index moves by one character at a time... and a space counts as 3 characters.






    share|improve this answer





















    • A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
      – Thomas Junk
      Mar 3 '17 at 19:24










    • I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
      – TheLearner
      Mar 3 '17 at 20:14















    up vote
    5
    down vote













    Your strategy of counting the spaces and then back-looping to shift the characters right (and replace spaces with %20) is good. The basic algorithm is probably as good as it gets as a character array system.



    Your variable names are decent, and the code flows well.



    On the other hand, there are some small things I would change.



    Possible bug



    Your code, given the input conversion("abc ", 3) you would output "abc" but you should not remove any "extra" padding in the string, you should return "abc "



    In fact, you should only really have the one char array. The second one is making you do bad things ;-)



    Enhanced fors



    Use enhanced-for loops when possible, and always use {} blocks for if-statements, even 1-liners:




    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ')
    numSpaces++;
    }




    should be:



    for(char c : strChars){
    if(c == ' ') {
    numSpaces++;
    }
    }



    Comments



    Comment unusual loops - your second for-loop is an odd one, and it often helps the reader if you comment why a loop is non-sequential (or even if you just make sure they are aware of it).



    multiple indexes



    Have you considered having a separate index for each position in the array - the position of the source character, and the position of where to insert it?



    public static String conversion(String str, int length){

    char strChars = str.toCharArray();

    int numSpaces = 0;
    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ') {
    numSpaces++;
    }
    }

    int insert = length + 2 * numSpaces - 1;

    // loop backwards through source characters.
    for(int i = length - 1; i >= 0; i--){
    char c = strChars[i];
    if(c == ' '){
    strChars[insert--] = '0';
    strChars[insert--] = '2';
    strChars[insert--] = '%';
    } else{
    strChars[insert--] = c;
    }
    }
    return String.valueOf(strChars);
    }


    The benefit of two indexes is that you can keep the logic more readable ... ("more" is relative) as each index moves by one character at a time... and a space counts as 3 characters.






    share|improve this answer





















    • A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
      – Thomas Junk
      Mar 3 '17 at 19:24










    • I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
      – TheLearner
      Mar 3 '17 at 20:14













    up vote
    5
    down vote










    up vote
    5
    down vote









    Your strategy of counting the spaces and then back-looping to shift the characters right (and replace spaces with %20) is good. The basic algorithm is probably as good as it gets as a character array system.



    Your variable names are decent, and the code flows well.



    On the other hand, there are some small things I would change.



    Possible bug



    Your code, given the input conversion("abc ", 3) you would output "abc" but you should not remove any "extra" padding in the string, you should return "abc "



    In fact, you should only really have the one char array. The second one is making you do bad things ;-)



    Enhanced fors



    Use enhanced-for loops when possible, and always use {} blocks for if-statements, even 1-liners:




    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ')
    numSpaces++;
    }




    should be:



    for(char c : strChars){
    if(c == ' ') {
    numSpaces++;
    }
    }



    Comments



    Comment unusual loops - your second for-loop is an odd one, and it often helps the reader if you comment why a loop is non-sequential (or even if you just make sure they are aware of it).



    multiple indexes



    Have you considered having a separate index for each position in the array - the position of the source character, and the position of where to insert it?



    public static String conversion(String str, int length){

    char strChars = str.toCharArray();

    int numSpaces = 0;
    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ') {
    numSpaces++;
    }
    }

    int insert = length + 2 * numSpaces - 1;

    // loop backwards through source characters.
    for(int i = length - 1; i >= 0; i--){
    char c = strChars[i];
    if(c == ' '){
    strChars[insert--] = '0';
    strChars[insert--] = '2';
    strChars[insert--] = '%';
    } else{
    strChars[insert--] = c;
    }
    }
    return String.valueOf(strChars);
    }


    The benefit of two indexes is that you can keep the logic more readable ... ("more" is relative) as each index moves by one character at a time... and a space counts as 3 characters.






    share|improve this answer












    Your strategy of counting the spaces and then back-looping to shift the characters right (and replace spaces with %20) is good. The basic algorithm is probably as good as it gets as a character array system.



    Your variable names are decent, and the code flows well.



    On the other hand, there are some small things I would change.



    Possible bug



    Your code, given the input conversion("abc ", 3) you would output "abc" but you should not remove any "extra" padding in the string, you should return "abc "



    In fact, you should only really have the one char array. The second one is making you do bad things ;-)



    Enhanced fors



    Use enhanced-for loops when possible, and always use {} blocks for if-statements, even 1-liners:




    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ')
    numSpaces++;
    }




    should be:



    for(char c : strChars){
    if(c == ' ') {
    numSpaces++;
    }
    }



    Comments



    Comment unusual loops - your second for-loop is an odd one, and it often helps the reader if you comment why a loop is non-sequential (or even if you just make sure they are aware of it).



    multiple indexes



    Have you considered having a separate index for each position in the array - the position of the source character, and the position of where to insert it?



    public static String conversion(String str, int length){

    char strChars = str.toCharArray();

    int numSpaces = 0;
    for(int i = 0; i < length; i++){
    if(strChars[i] == ' ') {
    numSpaces++;
    }
    }

    int insert = length + 2 * numSpaces - 1;

    // loop backwards through source characters.
    for(int i = length - 1; i >= 0; i--){
    char c = strChars[i];
    if(c == ' '){
    strChars[insert--] = '0';
    strChars[insert--] = '2';
    strChars[insert--] = '%';
    } else{
    strChars[insert--] = c;
    }
    }
    return String.valueOf(strChars);
    }


    The benefit of two indexes is that you can keep the logic more readable ... ("more" is relative) as each index moves by one character at a time... and a space counts as 3 characters.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 3 '17 at 18:40









    rolfl

    90.6k13190393




    90.6k13190393












    • A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
      – Thomas Junk
      Mar 3 '17 at 19:24










    • I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
      – TheLearner
      Mar 3 '17 at 20:14


















    • A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
      – Thomas Junk
      Mar 3 '17 at 19:24










    • I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
      – TheLearner
      Mar 3 '17 at 20:14
















    A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
    – Thomas Junk
    Mar 3 '17 at 19:24




    A pleasure to read . And solves the problem as reuired in place :] Nitpick: I do not like the "hungarian" notations like strChars and numSpaces. But TO came up with this in the first place.
    – Thomas Junk
    Mar 3 '17 at 19:24












    I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
    – TheLearner
    Mar 3 '17 at 20:14




    I have made it a habit to not include {} on one liners but working on it, thanks for the reminder. Also good point on the multiple indexes.
    – TheLearner
    Mar 3 '17 at 20:14












    up vote
    4
    down vote













    You have re-invented the wheel which makes for a rather poor answer to an interview question (Academic context would be different). A good interview answer emphasises knowledge of the inbuilt capabilities balanced with an appreciation of development priorities. Simple code that uses inbuilt libraries is quick to code, robust, widely understandable and maintainable. I would expect to see something like:



    log.info(new String("/A A/B B/C C").replaceAll(" ", "%20"));


    Even better would be the following proving an appreciation of Test driven development:



    @Test
    public void test() {
    final String actualResult = new String("/A /B /C /D ").replaceAll(" ", "%20");
    assertEquals("/A%20/B%20/C%20/D%20", actualResult);
    }


    Otherwise your coding practice is reasonable.




    • You have used Java naming conventions. +1

    • You have mostly named for the problem domain. +1

    • Your code is readable. +1


    Expanding on Interview aspect
    The ability to stick closely to the requirements is an important skill in a developer but should not mean blindly following the specification. The specification is a reflection of requirements. Requirements shouldn't specify implementation details and may be in error. Spotting bogus things and having the strength of character to call them out in a constructive manner are important skills in a developer. A skilled interviewer can also use coding questions to test your reaction and behaviour as well as your technical/coding skills.






    share|improve this answer



















    • 1




      As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
      – D. Jurcau
      Mar 3 '17 at 20:22






    • 1




      The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
      – Martin Spamer
      Mar 3 '17 at 21:00

















    up vote
    4
    down vote













    You have re-invented the wheel which makes for a rather poor answer to an interview question (Academic context would be different). A good interview answer emphasises knowledge of the inbuilt capabilities balanced with an appreciation of development priorities. Simple code that uses inbuilt libraries is quick to code, robust, widely understandable and maintainable. I would expect to see something like:



    log.info(new String("/A A/B B/C C").replaceAll(" ", "%20"));


    Even better would be the following proving an appreciation of Test driven development:



    @Test
    public void test() {
    final String actualResult = new String("/A /B /C /D ").replaceAll(" ", "%20");
    assertEquals("/A%20/B%20/C%20/D%20", actualResult);
    }


    Otherwise your coding practice is reasonable.




    • You have used Java naming conventions. +1

    • You have mostly named for the problem domain. +1

    • Your code is readable. +1


    Expanding on Interview aspect
    The ability to stick closely to the requirements is an important skill in a developer but should not mean blindly following the specification. The specification is a reflection of requirements. Requirements shouldn't specify implementation details and may be in error. Spotting bogus things and having the strength of character to call them out in a constructive manner are important skills in a developer. A skilled interviewer can also use coding questions to test your reaction and behaviour as well as your technical/coding skills.






    share|improve this answer



















    • 1




      As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
      – D. Jurcau
      Mar 3 '17 at 20:22






    • 1




      The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
      – Martin Spamer
      Mar 3 '17 at 21:00















    up vote
    4
    down vote










    up vote
    4
    down vote









    You have re-invented the wheel which makes for a rather poor answer to an interview question (Academic context would be different). A good interview answer emphasises knowledge of the inbuilt capabilities balanced with an appreciation of development priorities. Simple code that uses inbuilt libraries is quick to code, robust, widely understandable and maintainable. I would expect to see something like:



    log.info(new String("/A A/B B/C C").replaceAll(" ", "%20"));


    Even better would be the following proving an appreciation of Test driven development:



    @Test
    public void test() {
    final String actualResult = new String("/A /B /C /D ").replaceAll(" ", "%20");
    assertEquals("/A%20/B%20/C%20/D%20", actualResult);
    }


    Otherwise your coding practice is reasonable.




    • You have used Java naming conventions. +1

    • You have mostly named for the problem domain. +1

    • Your code is readable. +1


    Expanding on Interview aspect
    The ability to stick closely to the requirements is an important skill in a developer but should not mean blindly following the specification. The specification is a reflection of requirements. Requirements shouldn't specify implementation details and may be in error. Spotting bogus things and having the strength of character to call them out in a constructive manner are important skills in a developer. A skilled interviewer can also use coding questions to test your reaction and behaviour as well as your technical/coding skills.






    share|improve this answer














    You have re-invented the wheel which makes for a rather poor answer to an interview question (Academic context would be different). A good interview answer emphasises knowledge of the inbuilt capabilities balanced with an appreciation of development priorities. Simple code that uses inbuilt libraries is quick to code, robust, widely understandable and maintainable. I would expect to see something like:



    log.info(new String("/A A/B B/C C").replaceAll(" ", "%20"));


    Even better would be the following proving an appreciation of Test driven development:



    @Test
    public void test() {
    final String actualResult = new String("/A /B /C /D ").replaceAll(" ", "%20");
    assertEquals("/A%20/B%20/C%20/D%20", actualResult);
    }


    Otherwise your coding practice is reasonable.




    • You have used Java naming conventions. +1

    • You have mostly named for the problem domain. +1

    • Your code is readable. +1


    Expanding on Interview aspect
    The ability to stick closely to the requirements is an important skill in a developer but should not mean blindly following the specification. The specification is a reflection of requirements. Requirements shouldn't specify implementation details and may be in error. Spotting bogus things and having the strength of character to call them out in a constructive manner are important skills in a developer. A skilled interviewer can also use coding questions to test your reaction and behaviour as well as your technical/coding skills.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 9 hours ago

























    answered Mar 3 '17 at 20:10









    Martin Spamer

    24329




    24329








    • 1




      As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
      – D. Jurcau
      Mar 3 '17 at 20:22






    • 1




      The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
      – Martin Spamer
      Mar 3 '17 at 21:00
















    • 1




      As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
      – D. Jurcau
      Mar 3 '17 at 20:22






    • 1




      The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
      – Martin Spamer
      Mar 3 '17 at 21:00










    1




    1




    As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
    – D. Jurcau
    Mar 3 '17 at 20:22




    As the question mentions USE character array to perform this operation in place it probably doesn't except the use of replaceAll
    – D. Jurcau
    Mar 3 '17 at 20:22




    1




    1




    The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
    – Martin Spamer
    Mar 3 '17 at 21:00






    The internal implementation of a Java String is a char array. However that is bogus requirement anyway, they do not and should not dictate implementation. Just because a blog has re-printed a facsimile of an interview question doesn't mean the person that posted it understand the marking or the expectations of the interviewer. I would treat that as a trap to sort the wheat from the chaff. I've set out my criteria and I would be confident saying others would take a similar view on re-using and not inventing the wheel.
    – Martin Spamer
    Mar 3 '17 at 21:00












    up vote
    2
    down vote













    You ignored the instructions



    According to the problem statement, the String passed in has enough room to hold all the expanded characters, and you are supposed to do the expansion in-place. You went ahead and allocated a second character array and copied the characters from one array to another.



    The whole backwards loop you used only makes sense if you are expanding in-place in the same array. If you allocate a new array, you might as well write the loop in the forwards direction since it doesn't make any difference.



    Other things




    1. I find it easier to read an if-else statement if the if condition is written in the positive sense if (c == ' ') rather than if (c != ' ').

    2. Although your backwards loop does the right thing, I had to stare at it for a long time to convince myself that it was correct. Instead of an expression for the insertion point, I would just use another index.


    (I just noticed that @rolfl already covered these points)



    Rewrite



    Here is how I would have modified your function. (It looks a lot like @rolfl's version actually):



    public static String conversion(String str, int length)
    {
    char strChars = str.toCharArray();
    int numSpaces = 0;

    for (int i = 0; i < length; i++) {
    if (strChars[i] == ' ') {
    numSpaces++;
    }
    }

    int newLength = length + 2 * numSpaces;

    for (int i = length - 1, j = newLength - 1; i >= 0; i--) {
    char c = strChars[i];
    if (c == ' ') {
    strChars[j--] = '0';
    strChars[j--] = '2';
    strChars[j--] = '%';
    } else {
    strChars[j--] = c;
    }
    }

    return String.valueOf(strChars);
    }





    share|improve this answer

























      up vote
      2
      down vote













      You ignored the instructions



      According to the problem statement, the String passed in has enough room to hold all the expanded characters, and you are supposed to do the expansion in-place. You went ahead and allocated a second character array and copied the characters from one array to another.



      The whole backwards loop you used only makes sense if you are expanding in-place in the same array. If you allocate a new array, you might as well write the loop in the forwards direction since it doesn't make any difference.



      Other things




      1. I find it easier to read an if-else statement if the if condition is written in the positive sense if (c == ' ') rather than if (c != ' ').

      2. Although your backwards loop does the right thing, I had to stare at it for a long time to convince myself that it was correct. Instead of an expression for the insertion point, I would just use another index.


      (I just noticed that @rolfl already covered these points)



      Rewrite



      Here is how I would have modified your function. (It looks a lot like @rolfl's version actually):



      public static String conversion(String str, int length)
      {
      char strChars = str.toCharArray();
      int numSpaces = 0;

      for (int i = 0; i < length; i++) {
      if (strChars[i] == ' ') {
      numSpaces++;
      }
      }

      int newLength = length + 2 * numSpaces;

      for (int i = length - 1, j = newLength - 1; i >= 0; i--) {
      char c = strChars[i];
      if (c == ' ') {
      strChars[j--] = '0';
      strChars[j--] = '2';
      strChars[j--] = '%';
      } else {
      strChars[j--] = c;
      }
      }

      return String.valueOf(strChars);
      }





      share|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        You ignored the instructions



        According to the problem statement, the String passed in has enough room to hold all the expanded characters, and you are supposed to do the expansion in-place. You went ahead and allocated a second character array and copied the characters from one array to another.



        The whole backwards loop you used only makes sense if you are expanding in-place in the same array. If you allocate a new array, you might as well write the loop in the forwards direction since it doesn't make any difference.



        Other things




        1. I find it easier to read an if-else statement if the if condition is written in the positive sense if (c == ' ') rather than if (c != ' ').

        2. Although your backwards loop does the right thing, I had to stare at it for a long time to convince myself that it was correct. Instead of an expression for the insertion point, I would just use another index.


        (I just noticed that @rolfl already covered these points)



        Rewrite



        Here is how I would have modified your function. (It looks a lot like @rolfl's version actually):



        public static String conversion(String str, int length)
        {
        char strChars = str.toCharArray();
        int numSpaces = 0;

        for (int i = 0; i < length; i++) {
        if (strChars[i] == ' ') {
        numSpaces++;
        }
        }

        int newLength = length + 2 * numSpaces;

        for (int i = length - 1, j = newLength - 1; i >= 0; i--) {
        char c = strChars[i];
        if (c == ' ') {
        strChars[j--] = '0';
        strChars[j--] = '2';
        strChars[j--] = '%';
        } else {
        strChars[j--] = c;
        }
        }

        return String.valueOf(strChars);
        }





        share|improve this answer












        You ignored the instructions



        According to the problem statement, the String passed in has enough room to hold all the expanded characters, and you are supposed to do the expansion in-place. You went ahead and allocated a second character array and copied the characters from one array to another.



        The whole backwards loop you used only makes sense if you are expanding in-place in the same array. If you allocate a new array, you might as well write the loop in the forwards direction since it doesn't make any difference.



        Other things




        1. I find it easier to read an if-else statement if the if condition is written in the positive sense if (c == ' ') rather than if (c != ' ').

        2. Although your backwards loop does the right thing, I had to stare at it for a long time to convince myself that it was correct. Instead of an expression for the insertion point, I would just use another index.


        (I just noticed that @rolfl already covered these points)



        Rewrite



        Here is how I would have modified your function. (It looks a lot like @rolfl's version actually):



        public static String conversion(String str, int length)
        {
        char strChars = str.toCharArray();
        int numSpaces = 0;

        for (int i = 0; i < length; i++) {
        if (strChars[i] == ' ') {
        numSpaces++;
        }
        }

        int newLength = length + 2 * numSpaces;

        for (int i = length - 1, j = newLength - 1; i >= 0; i--) {
        char c = strChars[i];
        if (c == ' ') {
        strChars[j--] = '0';
        strChars[j--] = '2';
        strChars[j--] = '%';
        } else {
        strChars[j--] = c;
        }
        }

        return String.valueOf(strChars);
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 4 '17 at 10:50









        JS1

        27.2k32976




        27.2k32976






















            up vote
            2
            down vote













            How come nobody notices the name of the method conversion() ? Shouldn't your method names be verbs? convert() is a better method name in this case.






            share|improve this answer





















            • Good catch, someone mentioned this before.Thank you.
              – TheLearner
              Mar 4 '17 at 23:45















            up vote
            2
            down vote













            How come nobody notices the name of the method conversion() ? Shouldn't your method names be verbs? convert() is a better method name in this case.






            share|improve this answer





















            • Good catch, someone mentioned this before.Thank you.
              – TheLearner
              Mar 4 '17 at 23:45













            up vote
            2
            down vote










            up vote
            2
            down vote









            How come nobody notices the name of the method conversion() ? Shouldn't your method names be verbs? convert() is a better method name in this case.






            share|improve this answer












            How come nobody notices the name of the method conversion() ? Shouldn't your method names be verbs? convert() is a better method name in this case.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 4 '17 at 15:28









            Tunde Michael

            212




            212












            • Good catch, someone mentioned this before.Thank you.
              – TheLearner
              Mar 4 '17 at 23:45


















            • Good catch, someone mentioned this before.Thank you.
              – TheLearner
              Mar 4 '17 at 23:45
















            Good catch, someone mentioned this before.Thank you.
            – TheLearner
            Mar 4 '17 at 23:45




            Good catch, someone mentioned this before.Thank you.
            – TheLearner
            Mar 4 '17 at 23:45










            up vote
            0
            down vote













            How to split a string in Java



            A tad bit on the concerned side here as I am not sure if your goal is a brute force coding requirement or not but the above link shows how to use the string split function an example is



            String out = string.split("-");


            Then just reassemble the string from out






            share|improve this answer























            • »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
              – Thomas Junk
              Mar 3 '17 at 19:14















            up vote
            0
            down vote













            How to split a string in Java



            A tad bit on the concerned side here as I am not sure if your goal is a brute force coding requirement or not but the above link shows how to use the string split function an example is



            String out = string.split("-");


            Then just reassemble the string from out






            share|improve this answer























            • »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
              – Thomas Junk
              Mar 3 '17 at 19:14













            up vote
            0
            down vote










            up vote
            0
            down vote









            How to split a string in Java



            A tad bit on the concerned side here as I am not sure if your goal is a brute force coding requirement or not but the above link shows how to use the string split function an example is



            String out = string.split("-");


            Then just reassemble the string from out






            share|improve this answer














            How to split a string in Java



            A tad bit on the concerned side here as I am not sure if your goal is a brute force coding requirement or not but the above link shows how to use the string split function an example is



            String out = string.split("-");


            Then just reassemble the string from out







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited May 23 '17 at 12:41









            Community

            1




            1










            answered Mar 3 '17 at 18:57









            Enigma Maitreya

            20216




            20216












            • »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
              – Thomas Junk
              Mar 3 '17 at 19:14


















            • »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
              – Thomas Junk
              Mar 3 '17 at 19:14
















            »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
            – Thomas Junk
            Mar 3 '17 at 19:14




            »USE character array to perform this operation in place« was one of the requirements. And I would not call that in place
            – Thomas Junk
            Mar 3 '17 at 19:14


















             

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