Multiplying N x N matrices using Diagonal storage












0















This question is a part of my research. I am trying to multiply two N X N matrices which are stored diagonally. I implemented the following algorithm for this purpose which is working correctly but the problem is it is taking way too much time. For example, To multiply 1000 x 1000 matrices, it is taking almost 26 minutes. I am giving an small example for better understanding of what I am trying to accomplish.



Matrix A = [ 1 2
3 4
],
Matrix B =[ 5 6
7 8],
diagArrayA= [1 4 2 3] (Elements stored diagonally in the order main diagonal - super diagonal -sub diagonal),
diagArrayB = [5 8 6 7] (Same as above),



Result = A X B = [ 19 50 22 43] (Correct output)
The code for multiply function is followed: (The problem seems to be in this function). I will appreciate any comment on the problem/code.



void multiplyDiag(vector <float> diagArrayA, vector <float> diagArrayB){


cout << "function called " << endl;
//please declare as array


// float *a=cutDiagElement(getArray(diagArrayA,-1),0,0);
// cout << "Value : " << a[0];

vector <float> result;
result.resize(n*n);
float total_time=0.0;
// const int sum=n*(n+1)/2;


for(int k=0; k<=n-1;k++)
{ //1



             int start_index=k*n-k*(k-1)/2;

//cout << start_index;

// int stop_index=start_index+n-k-1;

for(int i=k+1; i<=n-1; i++){ //2

vector <float> diag_a1=cutDiagElement(getArray(diagArrayA,k-i),0,k);
// cout << diag_a1[0] <<endl;

vector <float> diag_b1=cutDiagElement(getArray(diagArrayB,i),0,0);

int length1=diag_b1.size();
// int length1=n-i;
// length1=length1-0-0;
//cout << length1;
float start1=clock();
for(int j=0; j<=length1-1;j++)
{ //3
//cout << "OK";

result[start_index+i-k+j]+=diag_a1[j]*diag_b1[j];




} //3

float end1=clock();
total_time=total_time+(end1-start1);



vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i), 0, 0);

vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,k-i), k, 0);
// cout << diag_b2[0];
// int length2=diag_a2.size();

float start2=clock();
for(int j=0; j<=length1-1;j++)
{ //4


result[start_index+j]+=diag_a2[j]*diag_b2[j];
// cout<< multiply_result[start_index+j] << endl;

} //4

float end2=clock();

total_time=total_time+(end2-start2);


} //2

for(int i=0; i<=k; i++)
{ //5
vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, i), 0, k-i);

vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, k-i), i, 0);

int length3=diag_a3.size();
// int length3=n-i;
// length3=length3-(k-i);

float start3=clock();

for(int j=0; j<=length3-1;j++){ //6

result[start_index+j]+=diag_a3[j]*diag_b3[j];

//cout<< multiply_result[start_index+j] << endl;

} //6

float end3=clock();
total_time=total_time+(end3-start3);


} //5


}//1



// computing sub diagonal



for(int k=1; k<=n-1; k++)
{ //7



    int start_index=n*(n+1)/2+(k-1)*n-k*(k-1)/2;
// int stop_index=start_index+n-k-1;
for(int i=k+1; i<=n-1; i++)
{ //8
vector <float> diag_a1=cutDiagElement(getArray(diagArrayA, -i), 0, 0);
vector <float> diag_b1= cutDiagElement(getArray(diagArrayB, i-k), 0, k);
int length1=diag_b1.size();
// int length1=n-(i-k);
// length1=length1-k;
float start4=clock();
for(int j=0; j<=length1-1;j++){ //9

result[start_index+i+j-k]+=diag_a1[j]*diag_b1[j];


} //9

float end4=clock();
total_time=total_time+(end4-start4);

vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i-k), k, 0);

vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,-i), 0, 0);
// int length2=diag_a2.size();

float start5=clock();

for(int j=0; j<=length1-1;j++)
{ //10

result[start_index+j]+=diag_a2[j]*diag_b2[j];

}//10

float end5=clock();

total_time=total_time+(end5-start5);


} //8

for(int i=0; i<=k; i++)
{ //11
vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, -i), k-i, 0);

vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, i-k), 0, i);

int length3=diag_a3.size();
// int length3=n-i;
// length3=length3-(k-i);

float start6=clock();

for(int j=0; j<=length3-1;j++){ //12

result[start_index+j]+=diag_a3[j]*diag_b3[j];

} //12
float end6=clock();
total_time=total_time+(end6-start6);


} //11


} //7



cout << "time :" << (total_time) / CLOCKS_PER_SEC*1000 <


           cout << result[x] << endl;

}


}










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    This question is a part of my research. I am trying to multiply two N X N matrices which are stored diagonally. I implemented the following algorithm for this purpose which is working correctly but the problem is it is taking way too much time. For example, To multiply 1000 x 1000 matrices, it is taking almost 26 minutes. I am giving an small example for better understanding of what I am trying to accomplish.



    Matrix A = [ 1 2
    3 4
    ],
    Matrix B =[ 5 6
    7 8],
    diagArrayA= [1 4 2 3] (Elements stored diagonally in the order main diagonal - super diagonal -sub diagonal),
    diagArrayB = [5 8 6 7] (Same as above),



    Result = A X B = [ 19 50 22 43] (Correct output)
    The code for multiply function is followed: (The problem seems to be in this function). I will appreciate any comment on the problem/code.



    void multiplyDiag(vector <float> diagArrayA, vector <float> diagArrayB){


    cout << "function called " << endl;
    //please declare as array


    // float *a=cutDiagElement(getArray(diagArrayA,-1),0,0);
    // cout << "Value : " << a[0];

    vector <float> result;
    result.resize(n*n);
    float total_time=0.0;
    // const int sum=n*(n+1)/2;


    for(int k=0; k<=n-1;k++)
    { //1



                 int start_index=k*n-k*(k-1)/2;

    //cout << start_index;

    // int stop_index=start_index+n-k-1;

    for(int i=k+1; i<=n-1; i++){ //2

    vector <float> diag_a1=cutDiagElement(getArray(diagArrayA,k-i),0,k);
    // cout << diag_a1[0] <<endl;

    vector <float> diag_b1=cutDiagElement(getArray(diagArrayB,i),0,0);

    int length1=diag_b1.size();
    // int length1=n-i;
    // length1=length1-0-0;
    //cout << length1;
    float start1=clock();
    for(int j=0; j<=length1-1;j++)
    { //3
    //cout << "OK";

    result[start_index+i-k+j]+=diag_a1[j]*diag_b1[j];




    } //3

    float end1=clock();
    total_time=total_time+(end1-start1);



    vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i), 0, 0);

    vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,k-i), k, 0);
    // cout << diag_b2[0];
    // int length2=diag_a2.size();

    float start2=clock();
    for(int j=0; j<=length1-1;j++)
    { //4


    result[start_index+j]+=diag_a2[j]*diag_b2[j];
    // cout<< multiply_result[start_index+j] << endl;

    } //4

    float end2=clock();

    total_time=total_time+(end2-start2);


    } //2

    for(int i=0; i<=k; i++)
    { //5
    vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, i), 0, k-i);

    vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, k-i), i, 0);

    int length3=diag_a3.size();
    // int length3=n-i;
    // length3=length3-(k-i);

    float start3=clock();

    for(int j=0; j<=length3-1;j++){ //6

    result[start_index+j]+=diag_a3[j]*diag_b3[j];

    //cout<< multiply_result[start_index+j] << endl;

    } //6

    float end3=clock();
    total_time=total_time+(end3-start3);


    } //5


    }//1



    // computing sub diagonal



    for(int k=1; k<=n-1; k++)
    { //7



        int start_index=n*(n+1)/2+(k-1)*n-k*(k-1)/2;
    // int stop_index=start_index+n-k-1;
    for(int i=k+1; i<=n-1; i++)
    { //8
    vector <float> diag_a1=cutDiagElement(getArray(diagArrayA, -i), 0, 0);
    vector <float> diag_b1= cutDiagElement(getArray(diagArrayB, i-k), 0, k);
    int length1=diag_b1.size();
    // int length1=n-(i-k);
    // length1=length1-k;
    float start4=clock();
    for(int j=0; j<=length1-1;j++){ //9

    result[start_index+i+j-k]+=diag_a1[j]*diag_b1[j];


    } //9

    float end4=clock();
    total_time=total_time+(end4-start4);

    vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i-k), k, 0);

    vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,-i), 0, 0);
    // int length2=diag_a2.size();

    float start5=clock();

    for(int j=0; j<=length1-1;j++)
    { //10

    result[start_index+j]+=diag_a2[j]*diag_b2[j];

    }//10

    float end5=clock();

    total_time=total_time+(end5-start5);


    } //8

    for(int i=0; i<=k; i++)
    { //11
    vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, -i), k-i, 0);

    vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, i-k), 0, i);

    int length3=diag_a3.size();
    // int length3=n-i;
    // length3=length3-(k-i);

    float start6=clock();

    for(int j=0; j<=length3-1;j++){ //12

    result[start_index+j]+=diag_a3[j]*diag_b3[j];

    } //12
    float end6=clock();
    total_time=total_time+(end6-start6);


    } //11


    } //7



    cout << "time :" << (total_time) / CLOCKS_PER_SEC*1000 <


               cout << result[x] << endl;

    }


    }










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    Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























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      This question is a part of my research. I am trying to multiply two N X N matrices which are stored diagonally. I implemented the following algorithm for this purpose which is working correctly but the problem is it is taking way too much time. For example, To multiply 1000 x 1000 matrices, it is taking almost 26 minutes. I am giving an small example for better understanding of what I am trying to accomplish.



      Matrix A = [ 1 2
      3 4
      ],
      Matrix B =[ 5 6
      7 8],
      diagArrayA= [1 4 2 3] (Elements stored diagonally in the order main diagonal - super diagonal -sub diagonal),
      diagArrayB = [5 8 6 7] (Same as above),



      Result = A X B = [ 19 50 22 43] (Correct output)
      The code for multiply function is followed: (The problem seems to be in this function). I will appreciate any comment on the problem/code.



      void multiplyDiag(vector <float> diagArrayA, vector <float> diagArrayB){


      cout << "function called " << endl;
      //please declare as array


      // float *a=cutDiagElement(getArray(diagArrayA,-1),0,0);
      // cout << "Value : " << a[0];

      vector <float> result;
      result.resize(n*n);
      float total_time=0.0;
      // const int sum=n*(n+1)/2;


      for(int k=0; k<=n-1;k++)
      { //1



                   int start_index=k*n-k*(k-1)/2;

      //cout << start_index;

      // int stop_index=start_index+n-k-1;

      for(int i=k+1; i<=n-1; i++){ //2

      vector <float> diag_a1=cutDiagElement(getArray(diagArrayA,k-i),0,k);
      // cout << diag_a1[0] <<endl;

      vector <float> diag_b1=cutDiagElement(getArray(diagArrayB,i),0,0);

      int length1=diag_b1.size();
      // int length1=n-i;
      // length1=length1-0-0;
      //cout << length1;
      float start1=clock();
      for(int j=0; j<=length1-1;j++)
      { //3
      //cout << "OK";

      result[start_index+i-k+j]+=diag_a1[j]*diag_b1[j];




      } //3

      float end1=clock();
      total_time=total_time+(end1-start1);



      vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i), 0, 0);

      vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,k-i), k, 0);
      // cout << diag_b2[0];
      // int length2=diag_a2.size();

      float start2=clock();
      for(int j=0; j<=length1-1;j++)
      { //4


      result[start_index+j]+=diag_a2[j]*diag_b2[j];
      // cout<< multiply_result[start_index+j] << endl;

      } //4

      float end2=clock();

      total_time=total_time+(end2-start2);


      } //2

      for(int i=0; i<=k; i++)
      { //5
      vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, i), 0, k-i);

      vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, k-i), i, 0);

      int length3=diag_a3.size();
      // int length3=n-i;
      // length3=length3-(k-i);

      float start3=clock();

      for(int j=0; j<=length3-1;j++){ //6

      result[start_index+j]+=diag_a3[j]*diag_b3[j];

      //cout<< multiply_result[start_index+j] << endl;

      } //6

      float end3=clock();
      total_time=total_time+(end3-start3);


      } //5


      }//1



      // computing sub diagonal



      for(int k=1; k<=n-1; k++)
      { //7



          int start_index=n*(n+1)/2+(k-1)*n-k*(k-1)/2;
      // int stop_index=start_index+n-k-1;
      for(int i=k+1; i<=n-1; i++)
      { //8
      vector <float> diag_a1=cutDiagElement(getArray(diagArrayA, -i), 0, 0);
      vector <float> diag_b1= cutDiagElement(getArray(diagArrayB, i-k), 0, k);
      int length1=diag_b1.size();
      // int length1=n-(i-k);
      // length1=length1-k;
      float start4=clock();
      for(int j=0; j<=length1-1;j++){ //9

      result[start_index+i+j-k]+=diag_a1[j]*diag_b1[j];


      } //9

      float end4=clock();
      total_time=total_time+(end4-start4);

      vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i-k), k, 0);

      vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,-i), 0, 0);
      // int length2=diag_a2.size();

      float start5=clock();

      for(int j=0; j<=length1-1;j++)
      { //10

      result[start_index+j]+=diag_a2[j]*diag_b2[j];

      }//10

      float end5=clock();

      total_time=total_time+(end5-start5);


      } //8

      for(int i=0; i<=k; i++)
      { //11
      vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, -i), k-i, 0);

      vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, i-k), 0, i);

      int length3=diag_a3.size();
      // int length3=n-i;
      // length3=length3-(k-i);

      float start6=clock();

      for(int j=0; j<=length3-1;j++){ //12

      result[start_index+j]+=diag_a3[j]*diag_b3[j];

      } //12
      float end6=clock();
      total_time=total_time+(end6-start6);


      } //11


      } //7



      cout << "time :" << (total_time) / CLOCKS_PER_SEC*1000 <


                 cout << result[x] << endl;

      }


      }










      share|improve this question







      New contributor




      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      This question is a part of my research. I am trying to multiply two N X N matrices which are stored diagonally. I implemented the following algorithm for this purpose which is working correctly but the problem is it is taking way too much time. For example, To multiply 1000 x 1000 matrices, it is taking almost 26 minutes. I am giving an small example for better understanding of what I am trying to accomplish.



      Matrix A = [ 1 2
      3 4
      ],
      Matrix B =[ 5 6
      7 8],
      diagArrayA= [1 4 2 3] (Elements stored diagonally in the order main diagonal - super diagonal -sub diagonal),
      diagArrayB = [5 8 6 7] (Same as above),



      Result = A X B = [ 19 50 22 43] (Correct output)
      The code for multiply function is followed: (The problem seems to be in this function). I will appreciate any comment on the problem/code.



      void multiplyDiag(vector <float> diagArrayA, vector <float> diagArrayB){


      cout << "function called " << endl;
      //please declare as array


      // float *a=cutDiagElement(getArray(diagArrayA,-1),0,0);
      // cout << "Value : " << a[0];

      vector <float> result;
      result.resize(n*n);
      float total_time=0.0;
      // const int sum=n*(n+1)/2;


      for(int k=0; k<=n-1;k++)
      { //1



                   int start_index=k*n-k*(k-1)/2;

      //cout << start_index;

      // int stop_index=start_index+n-k-1;

      for(int i=k+1; i<=n-1; i++){ //2

      vector <float> diag_a1=cutDiagElement(getArray(diagArrayA,k-i),0,k);
      // cout << diag_a1[0] <<endl;

      vector <float> diag_b1=cutDiagElement(getArray(diagArrayB,i),0,0);

      int length1=diag_b1.size();
      // int length1=n-i;
      // length1=length1-0-0;
      //cout << length1;
      float start1=clock();
      for(int j=0; j<=length1-1;j++)
      { //3
      //cout << "OK";

      result[start_index+i-k+j]+=diag_a1[j]*diag_b1[j];




      } //3

      float end1=clock();
      total_time=total_time+(end1-start1);



      vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i), 0, 0);

      vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,k-i), k, 0);
      // cout << diag_b2[0];
      // int length2=diag_a2.size();

      float start2=clock();
      for(int j=0; j<=length1-1;j++)
      { //4


      result[start_index+j]+=diag_a2[j]*diag_b2[j];
      // cout<< multiply_result[start_index+j] << endl;

      } //4

      float end2=clock();

      total_time=total_time+(end2-start2);


      } //2

      for(int i=0; i<=k; i++)
      { //5
      vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, i), 0, k-i);

      vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, k-i), i, 0);

      int length3=diag_a3.size();
      // int length3=n-i;
      // length3=length3-(k-i);

      float start3=clock();

      for(int j=0; j<=length3-1;j++){ //6

      result[start_index+j]+=diag_a3[j]*diag_b3[j];

      //cout<< multiply_result[start_index+j] << endl;

      } //6

      float end3=clock();
      total_time=total_time+(end3-start3);


      } //5


      }//1



      // computing sub diagonal



      for(int k=1; k<=n-1; k++)
      { //7



          int start_index=n*(n+1)/2+(k-1)*n-k*(k-1)/2;
      // int stop_index=start_index+n-k-1;
      for(int i=k+1; i<=n-1; i++)
      { //8
      vector <float> diag_a1=cutDiagElement(getArray(diagArrayA, -i), 0, 0);
      vector <float> diag_b1= cutDiagElement(getArray(diagArrayB, i-k), 0, k);
      int length1=diag_b1.size();
      // int length1=n-(i-k);
      // length1=length1-k;
      float start4=clock();
      for(int j=0; j<=length1-1;j++){ //9

      result[start_index+i+j-k]+=diag_a1[j]*diag_b1[j];


      } //9

      float end4=clock();
      total_time=total_time+(end4-start4);

      vector <float> diag_a2=cutDiagElement(getArray(diagArrayA, i-k), k, 0);

      vector <float> diag_b2= cutDiagElement(getArray(diagArrayB,-i), 0, 0);
      // int length2=diag_a2.size();

      float start5=clock();

      for(int j=0; j<=length1-1;j++)
      { //10

      result[start_index+j]+=diag_a2[j]*diag_b2[j];

      }//10

      float end5=clock();

      total_time=total_time+(end5-start5);


      } //8

      for(int i=0; i<=k; i++)
      { //11
      vector <float> diag_a3=cutDiagElement(getArray(diagArrayA, -i), k-i, 0);

      vector <float> diag_b3 = cutDiagElement(getArray(diagArrayB, i-k), 0, i);

      int length3=diag_a3.size();
      // int length3=n-i;
      // length3=length3-(k-i);

      float start6=clock();

      for(int j=0; j<=length3-1;j++){ //12

      result[start_index+j]+=diag_a3[j]*diag_b3[j];

      } //12
      float end6=clock();
      total_time=total_time+(end6-start6);


      } //11


      } //7



      cout << "time :" << (total_time) / CLOCKS_PER_SEC*1000 <


                 cout << result[x] << endl;

      }


      }







      c++






      share|improve this question







      New contributor




      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 10 mins ago









      Mahmud SakibMahmud Sakib

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      New contributor




      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Mahmud Sakib is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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