Set specific group of Django user as celery worker
I need to make a specific group of Django user(group : delivery person) as celery worker. Whenever any registered django user from that specific group logs in, they can pick task from the celery queue and complete. As soon as one user completes a task, it must be dequeued from the queue and asynchronously it should not be visible to the next logged in user from that group.
django celery django-celery django-middleware
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
add a comment |
I need to make a specific group of Django user(group : delivery person) as celery worker. Whenever any registered django user from that specific group logs in, they can pick task from the celery queue and complete. As soon as one user completes a task, it must be dequeued from the queue and asynchronously it should not be visible to the next logged in user from that group.
django celery django-celery django-middleware
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
You can't apply absolute celery in such case, you need to put these task in database table's queue and then apply celery and dequeue those from table's row / column flag. Even I would suggest don't use celery at all in your case that will also work.
– Anup Yadav
Nov 21 '18 at 7:24
Ok.. I'm new with Django, so was wondering if I could make a user as celery worker
– boom_itsme
Nov 21 '18 at 8:01
add a comment |
I need to make a specific group of Django user(group : delivery person) as celery worker. Whenever any registered django user from that specific group logs in, they can pick task from the celery queue and complete. As soon as one user completes a task, it must be dequeued from the queue and asynchronously it should not be visible to the next logged in user from that group.
django celery django-celery django-middleware
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
I need to make a specific group of Django user(group : delivery person) as celery worker. Whenever any registered django user from that specific group logs in, they can pick task from the celery queue and complete. As soon as one user completes a task, it must be dequeued from the queue and asynchronously it should not be visible to the next logged in user from that group.
django celery django-celery django-middleware
django celery django-celery django-middleware
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
asked Nov 21 '18 at 7:15
boom_itsmeboom_itsme
318
318
You can't apply absolute celery in such case, you need to put these task in database table's queue and then apply celery and dequeue those from table's row / column flag. Even I would suggest don't use celery at all in your case that will also work.
– Anup Yadav
Nov 21 '18 at 7:24
Ok.. I'm new with Django, so was wondering if I could make a user as celery worker
– boom_itsme
Nov 21 '18 at 8:01
add a comment |
You can't apply absolute celery in such case, you need to put these task in database table's queue and then apply celery and dequeue those from table's row / column flag. Even I would suggest don't use celery at all in your case that will also work.
– Anup Yadav
Nov 21 '18 at 7:24
Ok.. I'm new with Django, so was wondering if I could make a user as celery worker
– boom_itsme
Nov 21 '18 at 8:01
You can't apply absolute celery in such case, you need to put these task in database table's queue and then apply celery and dequeue those from table's row / column flag. Even I would suggest don't use celery at all in your case that will also work.
– Anup Yadav
Nov 21 '18 at 7:24
You can't apply absolute celery in such case, you need to put these task in database table's queue and then apply celery and dequeue those from table's row / column flag. Even I would suggest don't use celery at all in your case that will also work.
– Anup Yadav
Nov 21 '18 at 7:24
Ok.. I'm new with Django, so was wondering if I could make a user as celery worker
– boom_itsme
Nov 21 '18 at 8:01
Ok.. I'm new with Django, so was wondering if I could make a user as celery worker
– boom_itsme
Nov 21 '18 at 8:01
add a comment |
1 Answer
1
active
oldest
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As @Anup Yadav noted, Celery is not a good fit for this use case. Storing your tasks in the database works fine, you just have to lock the row using select_for_update to ensure that a task can't be picked twice. Something like this should work:
class Task(models.Model):
is_available = models.BooleanField(default=True)
def pick_task():
"""
Selects a task and marks it as unavailable.
Returns Task or None, if no Task is available.
"""
task = Task.objects.select_for_update().filter(is_available=True).first()
if task is not None:
task.is_available = False
task.save()
return task
Checking if the user has the right group would be done in the view. Note that pick_task should probably be a method of a custom manager.
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
You have to store that information somewhere. The easiest way would probably be a fieldrejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.
– Daniel Hepper
Nov 22 '18 at 10:25
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
As @Anup Yadav noted, Celery is not a good fit for this use case. Storing your tasks in the database works fine, you just have to lock the row using select_for_update to ensure that a task can't be picked twice. Something like this should work:
class Task(models.Model):
is_available = models.BooleanField(default=True)
def pick_task():
"""
Selects a task and marks it as unavailable.
Returns Task or None, if no Task is available.
"""
task = Task.objects.select_for_update().filter(is_available=True).first()
if task is not None:
task.is_available = False
task.save()
return task
Checking if the user has the right group would be done in the view. Note that pick_task should probably be a method of a custom manager.
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
You have to store that information somewhere. The easiest way would probably be a fieldrejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.
– Daniel Hepper
Nov 22 '18 at 10:25
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
add a comment |
As @Anup Yadav noted, Celery is not a good fit for this use case. Storing your tasks in the database works fine, you just have to lock the row using select_for_update to ensure that a task can't be picked twice. Something like this should work:
class Task(models.Model):
is_available = models.BooleanField(default=True)
def pick_task():
"""
Selects a task and marks it as unavailable.
Returns Task or None, if no Task is available.
"""
task = Task.objects.select_for_update().filter(is_available=True).first()
if task is not None:
task.is_available = False
task.save()
return task
Checking if the user has the right group would be done in the view. Note that pick_task should probably be a method of a custom manager.
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
You have to store that information somewhere. The easiest way would probably be a fieldrejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.
– Daniel Hepper
Nov 22 '18 at 10:25
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
add a comment |
As @Anup Yadav noted, Celery is not a good fit for this use case. Storing your tasks in the database works fine, you just have to lock the row using select_for_update to ensure that a task can't be picked twice. Something like this should work:
class Task(models.Model):
is_available = models.BooleanField(default=True)
def pick_task():
"""
Selects a task and marks it as unavailable.
Returns Task or None, if no Task is available.
"""
task = Task.objects.select_for_update().filter(is_available=True).first()
if task is not None:
task.is_available = False
task.save()
return task
Checking if the user has the right group would be done in the view. Note that pick_task should probably be a method of a custom manager.
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
As @Anup Yadav noted, Celery is not a good fit for this use case. Storing your tasks in the database works fine, you just have to lock the row using select_for_update to ensure that a task can't be picked twice. Something like this should work:
class Task(models.Model):
is_available = models.BooleanField(default=True)
def pick_task():
"""
Selects a task and marks it as unavailable.
Returns Task or None, if no Task is available.
"""
task = Task.objects.select_for_update().filter(is_available=True).first()
if task is not None:
task.is_available = False
task.save()
return task
Checking if the user has the right group would be done in the view. Note that pick_task should probably be a method of a custom manager.
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
answered Nov 21 '18 at 7:39
Daniel HepperDaniel Hepper
16.9k44660
16.9k44660
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
You have to store that information somewhere. The easiest way would probably be a fieldrejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.
– Daniel Hepper
Nov 22 '18 at 10:25
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
add a comment |
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
You have to store that information somewhere. The easiest way would probably be a fieldrejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.
– Daniel Hepper
Nov 22 '18 at 10:25
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
I will try this way. For making it asynchronous across all users I possibly can use websockets.
– boom_itsme
Nov 21 '18 at 8:02
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
what if a user declines a task, and I set is_available back to True but it must not be visible to him? I mean, whever a user declines a task it will be available for other users to accept the task but not for the specific user whoever declined it.
– boom_itsme
Nov 22 '18 at 3:32
You have to store that information somewhere. The easiest way would probably be a field
rejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.– Daniel Hepper
Nov 22 '18 at 10:25
You have to store that information somewhere. The easiest way would probably be a field
rejected_by = models.ManyToMany(get_user_model()), but if this is the best way depends on your exact requirements. This really should be a separate question.– Daniel Hepper
Nov 22 '18 at 10:25
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
Alright. Thanks for the suggestion.
– boom_itsme
Nov 22 '18 at 11:41
add a comment |
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You can't apply absolute celery in such case, you need to put these task in database table's queue and then apply celery and dequeue those from table's row / column flag. Even I would suggest don't use celery at all in your case that will also work.
– Anup Yadav
Nov 21 '18 at 7:24
Ok.. I'm new with Django, so was wondering if I could make a user as celery worker
– boom_itsme
Nov 21 '18 at 8:01