Str_replace for multiple items
I remember doing this before, but can't find the code. I use str_replace to replace one character like this: str_replace(':', ' ', $string); but I want to replace all the following characters /:*?"<>|, without doing a str_replace for each.
php string str-replace
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
add a comment |
I remember doing this before, but can't find the code. I use str_replace to replace one character like this: str_replace(':', ' ', $string); but I want to replace all the following characters /:*?"<>|, without doing a str_replace for each.
php string str-replace
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
1
you want to replace all these chars with a space?
– Book Of Zeus
Sep 30 '11 at 2:53
7
Don't be afraid to reference the excellent php.net manual and review the params section to see if what you want is possible.
– Mike B
Sep 30 '11 at 2:57
add a comment |
I remember doing this before, but can't find the code. I use str_replace to replace one character like this: str_replace(':', ' ', $string); but I want to replace all the following characters /:*?"<>|, without doing a str_replace for each.
php string str-replace
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
I remember doing this before, but can't find the code. I use str_replace to replace one character like this: str_replace(':', ' ', $string); but I want to replace all the following characters /:*?"<>|, without doing a str_replace for each.
php string str-replace
php string str-replace
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
asked Sep 30 '11 at 2:51
sameoldsameold
5,937164779
5,937164779
1
you want to replace all these chars with a space?
– Book Of Zeus
Sep 30 '11 at 2:53
7
Don't be afraid to reference the excellent php.net manual and review the params section to see if what you want is possible.
– Mike B
Sep 30 '11 at 2:57
add a comment |
1
you want to replace all these chars with a space?
– Book Of Zeus
Sep 30 '11 at 2:53
7
Don't be afraid to reference the excellent php.net manual and review the params section to see if what you want is possible.
– Mike B
Sep 30 '11 at 2:57
1
1
you want to replace all these chars with a space?
– Book Of Zeus
Sep 30 '11 at 2:53
you want to replace all these chars with a space?
– Book Of Zeus
Sep 30 '11 at 2:53
7
7
Don't be afraid to reference the excellent php.net manual and review the params section to see if what you want is possible.
– Mike B
Sep 30 '11 at 2:57
Don't be afraid to reference the excellent php.net manual and review the params section to see if what you want is possible.
– Mike B
Sep 30 '11 at 2:57
add a comment |
8 Answers
8
active
oldest
votes
str_replace() can take an array, so you could do:
$new_str = str_replace(str_split('\/:*?"<>|'), ' ', $string);
Alternatively you could use preg_replace():
$new_str = preg_replace('~[\\/:*?"<>|]~', ' ', $string);
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
2
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
add a comment |
Like this:
str_replace(array(':', '\', '/', '*'), ' ', $string);
Or, in modern PHP (anything from 5.4 onwards), the slighty less wordy:
str_replace([':', '\', '/', '*'], ' ', $string);
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
add a comment |
For example, if you want to replace search1 with replace1 and search2 with replace2 then following code will work:
print str_replace(
array("search1","search2"),
array("replace1", "replace2"),
"search1 search2"
);
// Output: replace1 replace2
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
add a comment |
str_replace(
array("search","items"),
array("replace", "items"),
$string
);
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
add a comment |
If you're only replacing single characters, you should use strtr()
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
1
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
add a comment |
You could use preg_replace(). The following example can be run using command line php:
<?php
$s1 = "the string \/:*?"<>|";
$s2 = preg_replace("^[\\/:*?"<>|]^", " ", $s1) ;
echo "n$s2: "" . $s2 . ""n";
?>
Output:
$s2: "the string "
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
add a comment |
I guess you are looking after this:
// example
private const TEMPLATE = __DIR__.'/Resources/{type}_{language}.json';
...
public function templateFor(string $type, string $language): string
{
return str_replace(['{type}', '{language}'], [$type, $language], self::TEMPLATE);
}
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
add a comment |
I had a situation whereby I had to replace the HTML tags with two different replacement results.
$trades = "<li>Sprinkler and Fire Protection Installer</li>
<li>Steamfitter </li>
<li>Terrazzo, Tile and Marble Setter</li>";
$s1 = str_replace('<li>', '"', $trades);
$s2 = str_replace('</li>', '",', $s1);
echo $s2;
result
"Sprinkler and Fire Protection Installer", "Steamfitter ", "Terrazzo, Tile and Marble Setter",
answered Feb 15 '17 at 18:19
TemptehTempteh
11
add a comment |
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8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
str_replace() can take an array, so you could do:
$new_str = str_replace(str_split('\/:*?"<>|'), ' ', $string);
Alternatively you could use preg_replace():
$new_str = preg_replace('~[\\/:*?"<>|]~', ' ', $string);
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
2
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
add a comment |
str_replace() can take an array, so you could do:
$new_str = str_replace(str_split('\/:*?"<>|'), ' ', $string);
Alternatively you could use preg_replace():
$new_str = preg_replace('~[\\/:*?"<>|]~', ' ', $string);
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
2
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
add a comment |
str_replace() can take an array, so you could do:
$new_str = str_replace(str_split('\/:*?"<>|'), ' ', $string);
Alternatively you could use preg_replace():
$new_str = preg_replace('~[\\/:*?"<>|]~', ' ', $string);
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
str_replace() can take an array, so you could do:
$new_str = str_replace(str_split('\/:*?"<>|'), ' ', $string);
Alternatively you could use preg_replace():
$new_str = preg_replace('~[\\/:*?"<>|]~', ' ', $string);
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
edited Sep 30 '11 at 4:26
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
answered Sep 30 '11 at 2:54
NullUserExceptionNullUserException
65.5k22176214
65.5k22176214
2
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
add a comment |
2
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
2
2
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
Assuming the OP meant that the backslash should be replaced, that preg_replace pattern didn't work for me. To get the backslash to work as expected, I had to use 4 of them (i.e. "\\") in the pattern.
– GreenMatt
Sep 30 '11 at 4:13
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
@GreenMatt You are right.
– NullUserException
Sep 30 '11 at 4:26
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
Good answer, adding @dogbert answer in would make it complete for the people who don't read the manual and don't realise str_split returns an array.
– Bradmage
Dec 31 '15 at 23:13
add a comment |
Like this:
str_replace(array(':', '\', '/', '*'), ' ', $string);
Or, in modern PHP (anything from 5.4 onwards), the slighty less wordy:
str_replace([':', '\', '/', '*'], ' ', $string);
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
add a comment |
Like this:
str_replace(array(':', '\', '/', '*'), ' ', $string);
Or, in modern PHP (anything from 5.4 onwards), the slighty less wordy:
str_replace([':', '\', '/', '*'], ' ', $string);
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
add a comment |
Like this:
str_replace(array(':', '\', '/', '*'), ' ', $string);
Or, in modern PHP (anything from 5.4 onwards), the slighty less wordy:
str_replace([':', '\', '/', '*'], ' ', $string);
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
Like this:
str_replace(array(':', '\', '/', '*'), ' ', $string);
Or, in modern PHP (anything from 5.4 onwards), the slighty less wordy:
str_replace([':', '\', '/', '*'], ' ', $string);
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
edited Oct 23 '16 at 17:07
Codemonkey
1,61822241
1,61822241
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
answered Sep 30 '11 at 2:53
DogbertDogbert
152k28240265
152k28240265
add a comment |
add a comment |
For example, if you want to replace search1 with replace1 and search2 with replace2 then following code will work:
print str_replace(
array("search1","search2"),
array("replace1", "replace2"),
"search1 search2"
);
// Output: replace1 replace2
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
add a comment |
For example, if you want to replace search1 with replace1 and search2 with replace2 then following code will work:
print str_replace(
array("search1","search2"),
array("replace1", "replace2"),
"search1 search2"
);
// Output: replace1 replace2
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
add a comment |
For example, if you want to replace search1 with replace1 and search2 with replace2 then following code will work:
print str_replace(
array("search1","search2"),
array("replace1", "replace2"),
"search1 search2"
);
// Output: replace1 replace2
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
For example, if you want to replace search1 with replace1 and search2 with replace2 then following code will work:
print str_replace(
array("search1","search2"),
array("replace1", "replace2"),
"search1 search2"
);
// Output: replace1 replace2
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
answered Feb 10 '15 at 20:36
SumoanandSumoanand
7,24213741
7,24213741
add a comment |
add a comment |
str_replace(
array("search","items"),
array("replace", "items"),
$string
);
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
add a comment |
str_replace(
array("search","items"),
array("replace", "items"),
$string
);
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
add a comment |
str_replace(
array("search","items"),
array("replace", "items"),
$string
);
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
str_replace(
array("search","items"),
array("replace", "items"),
$string
);
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
answered Sep 30 '11 at 2:54
MartyMarty
31k1874147
31k1874147
add a comment |
add a comment |
If you're only replacing single characters, you should use strtr()
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
1
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
add a comment |
If you're only replacing single characters, you should use strtr()
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
1
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
add a comment |
If you're only replacing single characters, you should use strtr()
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
If you're only replacing single characters, you should use strtr()
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
answered Sep 30 '11 at 3:05
Explosion PillsExplosion Pills
149k38226310
149k38226310
1
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
add a comment |
1
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
1
1
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
Single characters only? How come?
– Jimmy Kane
Jul 31 '14 at 13:41
add a comment |
You could use preg_replace(). The following example can be run using command line php:
<?php
$s1 = "the string \/:*?"<>|";
$s2 = preg_replace("^[\\/:*?"<>|]^", " ", $s1) ;
echo "n$s2: "" . $s2 . ""n";
?>
Output:
$s2: "the string "
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
add a comment |
You could use preg_replace(). The following example can be run using command line php:
<?php
$s1 = "the string \/:*?"<>|";
$s2 = preg_replace("^[\\/:*?"<>|]^", " ", $s1) ;
echo "n$s2: "" . $s2 . ""n";
?>
Output:
$s2: "the string "
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
add a comment |
You could use preg_replace(). The following example can be run using command line php:
<?php
$s1 = "the string \/:*?"<>|";
$s2 = preg_replace("^[\\/:*?"<>|]^", " ", $s1) ;
echo "n$s2: "" . $s2 . ""n";
?>
Output:
$s2: "the string "
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
You could use preg_replace(). The following example can be run using command line php:
<?php
$s1 = "the string \/:*?"<>|";
$s2 = preg_replace("^[\\/:*?"<>|]^", " ", $s1) ;
echo "n$s2: "" . $s2 . ""n";
?>
Output:
$s2: "the string "
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
edited Sep 30 '11 at 4:08
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
answered Sep 30 '11 at 2:54
GreenMattGreenMatt
13.3k54269
13.3k54269
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
add a comment |
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
Too much escaping inside the character class. (see accepted answer)
– mickmackusa
Apr 21 '18 at 6:31
add a comment |
I guess you are looking after this:
// example
private const TEMPLATE = __DIR__.'/Resources/{type}_{language}.json';
...
public function templateFor(string $type, string $language): string
{
return str_replace(['{type}', '{language}'], [$type, $language], self::TEMPLATE);
}
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
add a comment |
I guess you are looking after this:
// example
private const TEMPLATE = __DIR__.'/Resources/{type}_{language}.json';
...
public function templateFor(string $type, string $language): string
{
return str_replace(['{type}', '{language}'], [$type, $language], self::TEMPLATE);
}
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
add a comment |
I guess you are looking after this:
// example
private const TEMPLATE = __DIR__.'/Resources/{type}_{language}.json';
...
public function templateFor(string $type, string $language): string
{
return str_replace(['{type}', '{language}'], [$type, $language], self::TEMPLATE);
}
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
I guess you are looking after this:
// example
private const TEMPLATE = __DIR__.'/Resources/{type}_{language}.json';
...
public function templateFor(string $type, string $language): string
{
return str_replace(['{type}', '{language}'], [$type, $language], self::TEMPLATE);
}
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
answered Oct 2 '18 at 11:20
Erald KarakashiErald Karakashi
7114
7114
add a comment |
add a comment |
I had a situation whereby I had to replace the HTML tags with two different replacement results.
$trades = "<li>Sprinkler and Fire Protection Installer</li>
<li>Steamfitter </li>
<li>Terrazzo, Tile and Marble Setter</li>";
$s1 = str_replace('<li>', '"', $trades);
$s2 = str_replace('</li>', '",', $s1);
echo $s2;
result
"Sprinkler and Fire Protection Installer", "Steamfitter ", "Terrazzo, Tile and Marble Setter",
answered Feb 15 '17 at 18:19
TemptehTempteh
11
add a comment |
I had a situation whereby I had to replace the HTML tags with two different replacement results.
$trades = "<li>Sprinkler and Fire Protection Installer</li>
<li>Steamfitter </li>
<li>Terrazzo, Tile and Marble Setter</li>";
$s1 = str_replace('<li>', '"', $trades);
$s2 = str_replace('</li>', '",', $s1);
echo $s2;
result
"Sprinkler and Fire Protection Installer", "Steamfitter ", "Terrazzo, Tile and Marble Setter",
answered Feb 15 '17 at 18:19
TemptehTempteh
11
add a comment |
I had a situation whereby I had to replace the HTML tags with two different replacement results.
$trades = "<li>Sprinkler and Fire Protection Installer</li>
<li>Steamfitter </li>
<li>Terrazzo, Tile and Marble Setter</li>";
$s1 = str_replace('<li>', '"', $trades);
$s2 = str_replace('</li>', '",', $s1);
echo $s2;
result
"Sprinkler and Fire Protection Installer", "Steamfitter ", "Terrazzo, Tile and Marble Setter",
answered Feb 15 '17 at 18:19
TemptehTempteh
11
I had a situation whereby I had to replace the HTML tags with two different replacement results.
$trades = "<li>Sprinkler and Fire Protection Installer</li>
<li>Steamfitter </li>
<li>Terrazzo, Tile and Marble Setter</li>";
$s1 = str_replace('<li>', '"', $trades);
$s2 = str_replace('</li>', '",', $s1);
echo $s2;
result
"Sprinkler and Fire Protection Installer", "Steamfitter ", "Terrazzo, Tile and Marble Setter",
answered Feb 15 '17 at 18:19
TemptehTempteh
11
answered Feb 15 '17 at 18:19
TemptehTempteh
11
answered Feb 15 '17 at 18:19
TemptehTempteh
11
answered Feb 15 '17 at 18:19
TemptehTempteh
11
11
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1
you want to replace all these chars with a space?
– Book Of Zeus
Sep 30 '11 at 2:53
7
Don't be afraid to reference the excellent php.net manual and review the params section to see if what you want is possible.
– Mike B
Sep 30 '11 at 2:57