Check if a String startsWith() and isn't equal to another String












1















I wanna know if a String (for example: "Hello World!") starts with "Hello" and isn't equal to "Hello Wourld" but I don't know how to make it. I tried:
if(String.startsWith("Hello") && (String !== "Hello Wourld")) {
// Do something
}

But it doesn't work. Can someone help me?
Thanks










share|improve this question


















  • 3





    jsfiddle.net/toc02re1 works for me

    – apokryfos
    Nov 23 '18 at 17:05











  • Works on browser as well

    – Monica Acha
    Nov 23 '18 at 17:06






  • 1





    May be your browser doesn't have the 'startsWith' function (IE 11 doesn't).

    – Poul Bak
    Nov 23 '18 at 17:07








  • 3





    String is a reserved native constructor for strings,. try and avoid creating a var named this way.

    – Keith
    Nov 23 '18 at 17:13
















1















I wanna know if a String (for example: "Hello World!") starts with "Hello" and isn't equal to "Hello Wourld" but I don't know how to make it. I tried:
if(String.startsWith("Hello") && (String !== "Hello Wourld")) {
// Do something
}

But it doesn't work. Can someone help me?
Thanks










share|improve this question


















  • 3





    jsfiddle.net/toc02re1 works for me

    – apokryfos
    Nov 23 '18 at 17:05











  • Works on browser as well

    – Monica Acha
    Nov 23 '18 at 17:06






  • 1





    May be your browser doesn't have the 'startsWith' function (IE 11 doesn't).

    – Poul Bak
    Nov 23 '18 at 17:07








  • 3





    String is a reserved native constructor for strings,. try and avoid creating a var named this way.

    – Keith
    Nov 23 '18 at 17:13














1












1








1








I wanna know if a String (for example: "Hello World!") starts with "Hello" and isn't equal to "Hello Wourld" but I don't know how to make it. I tried:
if(String.startsWith("Hello") && (String !== "Hello Wourld")) {
// Do something
}

But it doesn't work. Can someone help me?
Thanks










share|improve this question














I wanna know if a String (for example: "Hello World!") starts with "Hello" and isn't equal to "Hello Wourld" but I don't know how to make it. I tried:
if(String.startsWith("Hello") && (String !== "Hello Wourld")) {
// Do something
}

But it doesn't work. Can someone help me?
Thanks







javascript string startswith






share|improve this question













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share|improve this question




share|improve this question










asked Nov 23 '18 at 17:02









demostanisdemostanis

166




166








  • 3





    jsfiddle.net/toc02re1 works for me

    – apokryfos
    Nov 23 '18 at 17:05











  • Works on browser as well

    – Monica Acha
    Nov 23 '18 at 17:06






  • 1





    May be your browser doesn't have the 'startsWith' function (IE 11 doesn't).

    – Poul Bak
    Nov 23 '18 at 17:07








  • 3





    String is a reserved native constructor for strings,. try and avoid creating a var named this way.

    – Keith
    Nov 23 '18 at 17:13














  • 3





    jsfiddle.net/toc02re1 works for me

    – apokryfos
    Nov 23 '18 at 17:05











  • Works on browser as well

    – Monica Acha
    Nov 23 '18 at 17:06






  • 1





    May be your browser doesn't have the 'startsWith' function (IE 11 doesn't).

    – Poul Bak
    Nov 23 '18 at 17:07








  • 3





    String is a reserved native constructor for strings,. try and avoid creating a var named this way.

    – Keith
    Nov 23 '18 at 17:13








3




3





jsfiddle.net/toc02re1 works for me

– apokryfos
Nov 23 '18 at 17:05





jsfiddle.net/toc02re1 works for me

– apokryfos
Nov 23 '18 at 17:05













Works on browser as well

– Monica Acha
Nov 23 '18 at 17:06





Works on browser as well

– Monica Acha
Nov 23 '18 at 17:06




1




1





May be your browser doesn't have the 'startsWith' function (IE 11 doesn't).

– Poul Bak
Nov 23 '18 at 17:07







May be your browser doesn't have the 'startsWith' function (IE 11 doesn't).

– Poul Bak
Nov 23 '18 at 17:07






3




3





String is a reserved native constructor for strings,. try and avoid creating a var named this way.

– Keith
Nov 23 '18 at 17:13





String is a reserved native constructor for strings,. try and avoid creating a var named this way.

– Keith
Nov 23 '18 at 17:13












1 Answer
1






active

oldest

votes


















1














you can use a regular expression to test for "starts with" in any version of javascript.



var value = 'Hello There';

if (/^Hello/.test(value) && value !== 'Hello World') {
console.log('yes it is!')
}





share|improve this answer



















  • 1





    Hello,thank you a lot for your answer

    – demostanis
    Nov 24 '18 at 15:57











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1 Answer
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1 Answer
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active

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active

oldest

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active

oldest

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1














you can use a regular expression to test for "starts with" in any version of javascript.



var value = 'Hello There';

if (/^Hello/.test(value) && value !== 'Hello World') {
console.log('yes it is!')
}





share|improve this answer



















  • 1





    Hello,thank you a lot for your answer

    – demostanis
    Nov 24 '18 at 15:57
















1














you can use a regular expression to test for "starts with" in any version of javascript.



var value = 'Hello There';

if (/^Hello/.test(value) && value !== 'Hello World') {
console.log('yes it is!')
}





share|improve this answer



















  • 1





    Hello,thank you a lot for your answer

    – demostanis
    Nov 24 '18 at 15:57














1












1








1







you can use a regular expression to test for "starts with" in any version of javascript.



var value = 'Hello There';

if (/^Hello/.test(value) && value !== 'Hello World') {
console.log('yes it is!')
}





share|improve this answer













you can use a regular expression to test for "starts with" in any version of javascript.



var value = 'Hello There';

if (/^Hello/.test(value) && value !== 'Hello World') {
console.log('yes it is!')
}






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 23 '18 at 17:55









BenjaBenja

3,35612024




3,35612024








  • 1





    Hello,thank you a lot for your answer

    – demostanis
    Nov 24 '18 at 15:57














  • 1





    Hello,thank you a lot for your answer

    – demostanis
    Nov 24 '18 at 15:57








1




1





Hello,thank you a lot for your answer

– demostanis
Nov 24 '18 at 15:57





Hello,thank you a lot for your answer

– demostanis
Nov 24 '18 at 15:57




















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