JavaScript create object merging array and a Dict
1
I have a reference dict:
a = [
{ name: 'a'},
{ name: 'b'},
{ name: 'c'}
];
and a second array called (received via a API as a response)
data = [10,20,30]
I want to join the Dict and the array together and make something like:
Output:
[{
'a': 10,
'b': 20,
'c':30
}]
i tried foreach() though 'data' and pass the index to Dict 'a' obtain the key and do a push() for a new Dict but seems like foreach() exiting prematurely.
Any pointers appreciated.
javascript
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
asked Nov 20 at 18:05
sheeni
14310
add a comment |
1
I have a reference dict:
a = [
{ name: 'a'},
{ name: 'b'},
{ name: 'c'}
];
and a second array called (received via a API as a response)
data = [10,20,30]
I want to join the Dict and the array together and make something like:
Output:
[{
'a': 10,
'b': 20,
'c':30
}]
i tried foreach() though 'data' and pass the index to Dict 'a' obtain the key and do a push() for a new Dict but seems like foreach() exiting prematurely.
Any pointers appreciated.
javascript
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
asked Nov 20 at 18:05
sheeni
14310
Please add a Minimal, Complete, and Verifiable example which shows the actual problem. Ifahas at least the same number of elements the described way shouldn't "exit prematurely"
– Andreas
Nov 20 at 18:10
add a comment |
1
1
1
I have a reference dict:
a = [
{ name: 'a'},
{ name: 'b'},
{ name: 'c'}
];
and a second array called (received via a API as a response)
data = [10,20,30]
I want to join the Dict and the array together and make something like:
Output:
[{
'a': 10,
'b': 20,
'c':30
}]
i tried foreach() though 'data' and pass the index to Dict 'a' obtain the key and do a push() for a new Dict but seems like foreach() exiting prematurely.
Any pointers appreciated.
javascript
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
asked Nov 20 at 18:05
sheeni
14310
I have a reference dict:
a = [
{ name: 'a'},
{ name: 'b'},
{ name: 'c'}
];
and a second array called (received via a API as a response)
data = [10,20,30]
I want to join the Dict and the array together and make something like:
Output:
[{
'a': 10,
'b': 20,
'c':30
}]
i tried foreach() though 'data' and pass the index to Dict 'a' obtain the key and do a push() for a new Dict but seems like foreach() exiting prematurely.
Any pointers appreciated.
javascript
javascript
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
asked Nov 20 at 18:05
sheeni
14310
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
asked Nov 20 at 18:05
sheeni
14310
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
edited Nov 20 at 18:27
Aluan Haddad
12.1k22549
12.1k22549
asked Nov 20 at 18:05
sheeni
14310
asked Nov 20 at 18:05
sheeni
14310
asked Nov 20 at 18:05
sheeni
14310
14310
Please add a Minimal, Complete, and Verifiable example which shows the actual problem. Ifahas at least the same number of elements the described way shouldn't "exit prematurely"
– Andreas
Nov 20 at 18:10
add a comment |
Please add a Minimal, Complete, and Verifiable example which shows the actual problem. Ifahas at least the same number of elements the described way shouldn't "exit prematurely"
– Andreas
Nov 20 at 18:10
Please add a Minimal, Complete, and Verifiable example which shows the actual problem. If
a has at least the same number of elements the described way shouldn't "exit prematurely"– Andreas
Nov 20 at 18:10
Please add a Minimal, Complete, and Verifiable example which shows the actual problem. If
a has at least the same number of elements the described way shouldn't "exit prematurely"– Andreas
Nov 20 at 18:10
add a comment |
2 Answers
2
active
oldest
votes
0
Give this a try:
var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);answered Nov 20 at 18:15
SiddAjmera
12.9k31137
add a comment |
0
You can reduce a and take advantage of the index in the callback to create your merged object:
var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);edited Nov 20 at 18:28
SiddAjmera
12.9k31137
answered Nov 20 at 18:14
slider
8,0601129
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Give this a try:
var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);answered Nov 20 at 18:15
SiddAjmera
12.9k31137
add a comment |
0
Give this a try:
var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);answered Nov 20 at 18:15
SiddAjmera
12.9k31137
add a comment |
0
0
0
Give this a try:
var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);answered Nov 20 at 18:15
SiddAjmera
12.9k31137
Give this a try:
var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);var initial = performance.now();
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' }
];
var data = [10, 20, 30];
var finalObject = {};
a.forEach((item, index) => finalObject[item.name] = data[index]);
var result = [finalObject];
console.log(result);
var final = performance.now();
console.log(`Time taken to run: ${final - initial}`);answered Nov 20 at 18:15
SiddAjmera
12.9k31137
edited Nov 20 at 18:26
answered Nov 20 at 18:15
SiddAjmera
12.9k31137
answered Nov 20 at 18:15
SiddAjmera
12.9k31137
answered Nov 20 at 18:15
SiddAjmera
12.9k31137
12.9k31137
add a comment |
add a comment |
0
You can reduce a and take advantage of the index in the callback to create your merged object:
var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);edited Nov 20 at 18:28
SiddAjmera
12.9k31137
answered Nov 20 at 18:14
slider
8,0601129
add a comment |
0
You can reduce a and take advantage of the index in the callback to create your merged object:
var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);edited Nov 20 at 18:28
SiddAjmera
12.9k31137
answered Nov 20 at 18:14
slider
8,0601129
add a comment |
0
0
0
You can reduce a and take advantage of the index in the callback to create your merged object:
var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);edited Nov 20 at 18:28
SiddAjmera
12.9k31137
answered Nov 20 at 18:14
slider
8,0601129
You can reduce a and take advantage of the index in the callback to create your merged object:
var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);var initial = performance.now();
var a = [
{name: 'a'},
{name: 'b'},
{name: 'c'}
];
var data = [10, 20, 30];
var output = [a.reduce((acc, x, i) => {
acc[x.name] = data[i]
return acc;
}, {})];
console.log(output);
var final = performance.now();
console.log(`Time taken to run: ${final-initial}`);edited Nov 20 at 18:28
SiddAjmera
12.9k31137
answered Nov 20 at 18:14
slider
8,0601129
edited Nov 20 at 18:28
SiddAjmera
12.9k31137
edited Nov 20 at 18:28
SiddAjmera
12.9k31137
edited Nov 20 at 18:28
SiddAjmera
12.9k31137
12.9k31137
answered Nov 20 at 18:14
slider
8,0601129
answered Nov 20 at 18:14
slider
8,0601129
answered Nov 20 at 18:14
slider
8,0601129
8,0601129
add a comment |
add a comment |
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Please add a Minimal, Complete, and Verifiable example which shows the actual problem. If
ahas at least the same number of elements the described way shouldn't "exit prematurely"– Andreas
Nov 20 at 18:10