square the elements of a sorted list and give the output in sorted order
$begingroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 10 mins ago
thadeuszlaythadeuszlay
550214
$endgroup$
add a comment |
$begingroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 10 mins ago
thadeuszlaythadeuszlay
550214
$endgroup$
add a comment |
$begingroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 10 mins ago
thadeuszlaythadeuszlay
550214
$endgroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 10 mins ago
thadeuszlaythadeuszlay
550214
asked 10 mins ago
thadeuszlaythadeuszlay
550214
asked 10 mins ago
thadeuszlaythadeuszlay
550214
asked 10 mins ago
thadeuszlaythadeuszlay
550214
asked 10 mins ago
thadeuszlaythadeuszlay
550214
550214
add a comment |
add a comment |
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