TypeScript mixin constrained to different classes
2
I would like to build a mixin and have it so it can be applied to different classes (in this case "Sprite" and "Graphics").
Line three does not work:
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
TypeScript complains that "T is not a constructor function".
import { Sprite, Texture, Container, Graphics } from "pixi.js";
type Constructor<T = {}> = new (...args: any) => T;
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
return class extends Base {
constructor(...args) {
super(...args);
}
animate() {
console.log('animte it');
}
}
}
export class AnimatedSprite extends Animated(Sprite) {
constructor(texture? : Texture) {
super(texture);
}
}
export class AnimatedContainer extends Animated(Graphics) {
constructor(nativeLines?: boolean) {
super(nativeLines);
}
}
typescript mixins
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
add a comment |
2
I would like to build a mixin and have it so it can be applied to different classes (in this case "Sprite" and "Graphics").
Line three does not work:
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
TypeScript complains that "T is not a constructor function".
import { Sprite, Texture, Container, Graphics } from "pixi.js";
type Constructor<T = {}> = new (...args: any) => T;
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
return class extends Base {
constructor(...args) {
super(...args);
}
animate() {
console.log('animte it');
}
}
}
export class AnimatedSprite extends Animated(Sprite) {
constructor(texture? : Texture) {
super(texture);
}
}
export class AnimatedContainer extends Animated(Graphics) {
constructor(nativeLines?: boolean) {
super(nativeLines);
}
}
typescript mixins
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
add a comment |
2
2
2
1
I would like to build a mixin and have it so it can be applied to different classes (in this case "Sprite" and "Graphics").
Line three does not work:
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
TypeScript complains that "T is not a constructor function".
import { Sprite, Texture, Container, Graphics } from "pixi.js";
type Constructor<T = {}> = new (...args: any) => T;
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
return class extends Base {
constructor(...args) {
super(...args);
}
animate() {
console.log('animte it');
}
}
}
export class AnimatedSprite extends Animated(Sprite) {
constructor(texture? : Texture) {
super(texture);
}
}
export class AnimatedContainer extends Animated(Graphics) {
constructor(nativeLines?: boolean) {
super(nativeLines);
}
}
typescript mixins
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
I would like to build a mixin and have it so it can be applied to different classes (in this case "Sprite" and "Graphics").
Line three does not work:
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
TypeScript complains that "T is not a constructor function".
import { Sprite, Texture, Container, Graphics } from "pixi.js";
type Constructor<T = {}> = new (...args: any) => T;
function Animated<T extends Constructor<Sprite> | Constructor<Graphics>>(Base: T) {
return class extends Base {
constructor(...args) {
super(...args);
}
animate() {
console.log('animte it');
}
}
}
export class AnimatedSprite extends Animated(Sprite) {
constructor(texture? : Texture) {
super(texture);
}
}
export class AnimatedContainer extends Animated(Graphics) {
constructor(nativeLines?: boolean) {
super(nativeLines);
}
}
typescript mixins
typescript mixins
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
asked Nov 23 '18 at 21:34
WolfgangWolfgang
1,1001216
1,1001216
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
Ok, found a solution:
export interface IAnimated {
animate():void;
}
export const AnimatedSprite: Constructor<IAnimated> & typeof Sprite = <any>Animated(Sprite);
export const AnimatedGraphics: Constructor<IAnimated> & typeof Graphics = <any>Animated(Graphics);
Later (usage):
let s = new AnimatedSprite(someTexture); // has type "Sprite" and also interface IAnimated
let g = new AnimatedGraphics(false); // has type "Graphics" and also interface IAnimated
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
add a comment |
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oldest
votes
1
Ok, found a solution:
export interface IAnimated {
animate():void;
}
export const AnimatedSprite: Constructor<IAnimated> & typeof Sprite = <any>Animated(Sprite);
export const AnimatedGraphics: Constructor<IAnimated> & typeof Graphics = <any>Animated(Graphics);
Later (usage):
let s = new AnimatedSprite(someTexture); // has type "Sprite" and also interface IAnimated
let g = new AnimatedGraphics(false); // has type "Graphics" and also interface IAnimated
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
add a comment |
1
Ok, found a solution:
export interface IAnimated {
animate():void;
}
export const AnimatedSprite: Constructor<IAnimated> & typeof Sprite = <any>Animated(Sprite);
export const AnimatedGraphics: Constructor<IAnimated> & typeof Graphics = <any>Animated(Graphics);
Later (usage):
let s = new AnimatedSprite(someTexture); // has type "Sprite" and also interface IAnimated
let g = new AnimatedGraphics(false); // has type "Graphics" and also interface IAnimated
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
add a comment |
1
1
1
Ok, found a solution:
export interface IAnimated {
animate():void;
}
export const AnimatedSprite: Constructor<IAnimated> & typeof Sprite = <any>Animated(Sprite);
export const AnimatedGraphics: Constructor<IAnimated> & typeof Graphics = <any>Animated(Graphics);
Later (usage):
let s = new AnimatedSprite(someTexture); // has type "Sprite" and also interface IAnimated
let g = new AnimatedGraphics(false); // has type "Graphics" and also interface IAnimated
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
Ok, found a solution:
export interface IAnimated {
animate():void;
}
export const AnimatedSprite: Constructor<IAnimated> & typeof Sprite = <any>Animated(Sprite);
export const AnimatedGraphics: Constructor<IAnimated> & typeof Graphics = <any>Animated(Graphics);
Later (usage):
let s = new AnimatedSprite(someTexture); // has type "Sprite" and also interface IAnimated
let g = new AnimatedGraphics(false); // has type "Graphics" and also interface IAnimated
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
answered Nov 24 '18 at 16:35
WolfgangWolfgang
1,1001216
1,1001216
add a comment |
add a comment |
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