Make password/hash verification algorithm more efficient

I am trying to guess the paswords from the etc/shadow file(it has 43 user/passwords). And I have been given some hints about the passwords:

Length is between 4 and 8 characters

There can be only 2 numbers and only at the end

Capital letters only in the beginning

So I started just with a small group composed by 4 character with 2 digits in it. But it takes so much time to process:

import crypt

import string

import itertools

import datetime



dir = "shadow3"

file = open(dir, 'r').readlines() #Read all the 43 hashes



username = 

hashed = 

c = 0

cc = 0



for x in file: #Split the hash and the username

    usr, hshd, wtf, iss, this, thing, here, doing, example = x.split(':')

    username.append(usr)

    hashed.append(hshd)

#GRUPO1 4 caracteres 2 numeros

letters = string.ascii_lowercase

digits = string.digits

grupo1=

group1=itertools.product(letters,repeat=2)

group1b=itertools.product(digits,repeat=2)

for x in itertools.product(group1,group1b):  #Join the possible iterations

  string=''.join([''.join(k) for k in x])

  grupo1.append(string)

print(len(grupo1))

for y in grupo1:#Get the one of the iterations and try it 

  prueba=y

  for x in hashed: #Verify if that iteration is the password to any of the 43 users

    rehashed = crypt.crypt(prueba, x)

    if rehashed == x: #Password is found

        print('La contraseña del usuario ' + username[c] + ' es ' + prueba)

        cc = 1

    c = c + 1

if cc == 0: #after all iterations password is not found

    print('Lo sentimos "' + prueba + '" no es la contraseña de ningun usuario')

How can I improve the efficiency of this? I have a GTX 1070 if it helps for any kind of GPU processing.

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

asked Nov 23 '18 at 14:33

19mike95

5518

1

If your code works without errors, Code Review might be a better place to ask on. Stack Overflow soecializes in not-working code.

– usr2564301
Nov 23 '18 at 16:24

add a comment |

I am trying to guess the paswords from the etc/shadow file(it has 43 user/passwords). And I have been given some hints about the passwords:

Length is between 4 and 8 characters

There can be only 2 numbers and only at the end

Capital letters only in the beginning

So I started just with a small group composed by 4 character with 2 digits in it. But it takes so much time to process:

import crypt

import string

import itertools

import datetime



dir = "shadow3"

file = open(dir, 'r').readlines() #Read all the 43 hashes



username = 

hashed = 

c = 0

cc = 0



for x in file: #Split the hash and the username

    usr, hshd, wtf, iss, this, thing, here, doing, example = x.split(':')

    username.append(usr)

    hashed.append(hshd)

#GRUPO1 4 caracteres 2 numeros

letters = string.ascii_lowercase

digits = string.digits

grupo1=

group1=itertools.product(letters,repeat=2)

group1b=itertools.product(digits,repeat=2)

for x in itertools.product(group1,group1b):  #Join the possible iterations

  string=''.join([''.join(k) for k in x])

  grupo1.append(string)

print(len(grupo1))

for y in grupo1:#Get the one of the iterations and try it 

  prueba=y

  for x in hashed: #Verify if that iteration is the password to any of the 43 users

    rehashed = crypt.crypt(prueba, x)

    if rehashed == x: #Password is found

        print('La contraseña del usuario ' + username[c] + ' es ' + prueba)

        cc = 1

    c = c + 1

if cc == 0: #after all iterations password is not found

    print('Lo sentimos "' + prueba + '" no es la contraseña de ningun usuario')

How can I improve the efficiency of this? I have a GTX 1070 if it helps for any kind of GPU processing.

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

asked Nov 23 '18 at 14:33

19mike95

5518

1

If your code works without errors, Code Review might be a better place to ask on. Stack Overflow soecializes in not-working code.

– usr2564301
Nov 23 '18 at 16:24

add a comment |

I am trying to guess the paswords from the etc/shadow file(it has 43 user/passwords). And I have been given some hints about the passwords:

Length is between 4 and 8 characters

There can be only 2 numbers and only at the end

Capital letters only in the beginning

So I started just with a small group composed by 4 character with 2 digits in it. But it takes so much time to process:

import crypt

import string

import itertools

import datetime



dir = "shadow3"

file = open(dir, 'r').readlines() #Read all the 43 hashes



username = 

hashed = 

c = 0

cc = 0



for x in file: #Split the hash and the username

    usr, hshd, wtf, iss, this, thing, here, doing, example = x.split(':')

    username.append(usr)

    hashed.append(hshd)

#GRUPO1 4 caracteres 2 numeros

letters = string.ascii_lowercase

digits = string.digits

grupo1=

group1=itertools.product(letters,repeat=2)

group1b=itertools.product(digits,repeat=2)

for x in itertools.product(group1,group1b):  #Join the possible iterations

  string=''.join([''.join(k) for k in x])

  grupo1.append(string)

print(len(grupo1))

for y in grupo1:#Get the one of the iterations and try it 

  prueba=y

  for x in hashed: #Verify if that iteration is the password to any of the 43 users

    rehashed = crypt.crypt(prueba, x)

    if rehashed == x: #Password is found

        print('La contraseña del usuario ' + username[c] + ' es ' + prueba)

        cc = 1

    c = c + 1

if cc == 0: #after all iterations password is not found

    print('Lo sentimos "' + prueba + '" no es la contraseña de ningun usuario')

How can I improve the efficiency of this? I have a GTX 1070 if it helps for any kind of GPU processing.

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

asked Nov 23 '18 at 14:33

19mike95

5518

I am trying to guess the paswords from the etc/shadow file(it has 43 user/passwords). And I have been given some hints about the passwords:

Length is between 4 and 8 characters

There can be only 2 numbers and only at the end

Capital letters only in the beginning

So I started just with a small group composed by 4 character with 2 digits in it. But it takes so much time to process:

import crypt

import string

import itertools

import datetime



dir = "shadow3"

file = open(dir, 'r').readlines() #Read all the 43 hashes



username = 

hashed = 

c = 0

cc = 0



for x in file: #Split the hash and the username

    usr, hshd, wtf, iss, this, thing, here, doing, example = x.split(':')

    username.append(usr)

    hashed.append(hshd)

#GRUPO1 4 caracteres 2 numeros

letters = string.ascii_lowercase

digits = string.digits

grupo1=

group1=itertools.product(letters,repeat=2)

group1b=itertools.product(digits,repeat=2)

for x in itertools.product(group1,group1b):  #Join the possible iterations

  string=''.join([''.join(k) for k in x])

  grupo1.append(string)

print(len(grupo1))

for y in grupo1:#Get the one of the iterations and try it 

  prueba=y

  for x in hashed: #Verify if that iteration is the password to any of the 43 users

    rehashed = crypt.crypt(prueba, x)

    if rehashed == x: #Password is found

        print('La contraseña del usuario ' + username[c] + ' es ' + prueba)

        cc = 1

    c = c + 1

if cc == 0: #after all iterations password is not found

    print('Lo sentimos "' + prueba + '" no es la contraseña de ningun usuario')

How can I improve the efficiency of this? I have a GTX 1070 if it helps for any kind of GPU processing.

python hash coding-efficiency

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

asked Nov 23 '18 at 14:33

19mike95

5518

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

asked Nov 23 '18 at 14:33

19mike95

5518

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

edited Nov 24 '18 at 0:29

James K Polk

30.2k116896

asked Nov 23 '18 at 14:33

19mike95

5518

asked Nov 23 '18 at 14:33

19mike95

5518

asked Nov 23 '18 at 14:33

19mike95

5518

1

If your code works without errors, Code Review might be a better place to ask on. Stack Overflow soecializes in not-working code.

– usr2564301
Nov 23 '18 at 16:24

add a comment |

1

If your code works without errors, Code Review might be a better place to ask on. Stack Overflow soecializes in not-working code.

– usr2564301
Nov 23 '18 at 16:24

If your code works without errors, Code Review might be a better place to ask on. Stack Overflow soecializes in not-working code.

– usr2564301
Nov 23 '18 at 16:24

add a comment |

2 Answers
2

active

oldest

votes

I believe your code has errors. Your problem could be re-modelled so that it could be faster:

Generate all combination of possible passwords, based on your criteria
- Length is between 4 and 8 characters
- There can be only 2 numbers and only at the end
- Capital letters only in the beginning

Generate crypt() on each of the combinations
Compare passwords vs the crypted values.

answered Nov 23 '18 at 16:36

yoonghm

1,106918

add a comment |

Luckily, Python comes with a profiler to help solve this kind of problem. Look at the cProfile documentation.

answered Nov 23 '18 at 15:02

musbur

947

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

I believe your code has errors. Your problem could be re-modelled so that it could be faster:

Generate all combination of possible passwords, based on your criteria
- Length is between 4 and 8 characters
- There can be only 2 numbers and only at the end
- Capital letters only in the beginning

Generate crypt() on each of the combinations
Compare passwords vs the crypted values.

answered Nov 23 '18 at 16:36

yoonghm

1,106918

add a comment |

I believe your code has errors. Your problem could be re-modelled so that it could be faster:

Generate all combination of possible passwords, based on your criteria
- Length is between 4 and 8 characters
- There can be only 2 numbers and only at the end
- Capital letters only in the beginning

Generate crypt() on each of the combinations
Compare passwords vs the crypted values.

answered Nov 23 '18 at 16:36

yoonghm

1,106918

add a comment |

I believe your code has errors. Your problem could be re-modelled so that it could be faster:

Generate all combination of possible passwords, based on your criteria
- Length is between 4 and 8 characters
- There can be only 2 numbers and only at the end
- Capital letters only in the beginning

Generate crypt() on each of the combinations
Compare passwords vs the crypted values.

answered Nov 23 '18 at 16:36

yoonghm

1,106918

I believe your code has errors. Your problem could be re-modelled so that it could be faster:

Generate all combination of possible passwords, based on your criteria
- Length is between 4 and 8 characters
- There can be only 2 numbers and only at the end
- Capital letters only in the beginning

Generate crypt() on each of the combinations
Compare passwords vs the crypted values.

answered Nov 23 '18 at 16:36

yoonghm

1,106918

answered Nov 23 '18 at 16:36

yoonghm

1,106918

answered Nov 23 '18 at 16:36

yoonghm

1,106918

answered Nov 23 '18 at 16:36

yoonghm

1,106918

add a comment |

Luckily, Python comes with a profiler to help solve this kind of problem. Look at the cProfile documentation.

answered Nov 23 '18 at 15:02

musbur

947

add a comment |

Luckily, Python comes with a profiler to help solve this kind of problem. Look at the cProfile documentation.

answered Nov 23 '18 at 15:02

musbur

947

add a comment |

Luckily, Python comes with a profiler to help solve this kind of problem. Look at the cProfile documentation.

answered Nov 23 '18 at 15:02

musbur

947

Luckily, Python comes with a profiler to help solve this kind of problem. Look at the cProfile documentation.

answered Nov 23 '18 at 15:02

musbur

947

answered Nov 23 '18 at 15:02

musbur

947

answered Nov 23 '18 at 15:02

musbur

947

answered Nov 23 '18 at 15:02

musbur

947

add a comment |

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