Values from dictionary to excel sheet












0















output saved in excel



Values saved as dictionary in each run. Below image shows how values are saved as list for each variable in run9



at run9, ACTB variable has value for every time step (first 17 time steps are shown)



I have 134 nodes. Fourteen different analysis (run) has been performed. Each run has values saved as dictionary, for all the 134 nodes. Each node has values saved for 150 time steps (150 values for each node).For example, Run 1 is saved as dictionary (10 time steps) i.e. node A, (0,1,0,5,6, 7, 8, 1, 0,6) and node B, (1,2,3,4,5,7, 6, 8,9,1). Similarly Run 2 is saved as dictionary. I could export these values to an excel sheet, but the values are saved together as (0,1,0,5,6, 7, 8, 1, 0,6). I want only the first three values for each node to be exported to excel sheet in three separate columns (instead of all the 10 values)



How to export the individual values in each column from run 1 and run 2 and save it in a excel sheet?



Code, which saves an excel sheet with all values listed in one column:



run1, run2, run3, run4, run5, run6, run7, run8, run9, run10, run11, run12, run13, run14 = data # each run has 5 values for 2 variables
df = pd.DataFrame.from_dict(data)
df.to_excel("data.xlsx")


When I run this code, df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]



I got the following error:



TypeError                                 Traceback (most recent call last)
<ipython-input-84-8d2d90289161> in <module>()
----> 1 df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1308
1309 if type(key) is tuple:
-> 1310 return self._getitem_tuple(key)
1311 else:
1312 return self._getitem_axis(key, axis=0)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
794 def _getitem_tuple(self, tup):
795 try:
--> 796 return self._getitem_lowerdim(tup)
797 except IndexingError:
798 pass

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
920 for i, key in enumerate(tup):
921 if is_label_like(key) or isinstance(key, tuple):
--> 922 section = self._getitem_axis(key, axis=i)
923
924 # we have yielded a scalar ?

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1470 raise ValueError('Cannot index with multidimensional key')
1471
-> 1472 return self._getitem_iterable(key, axis=axis)
1473
1474 # nested tuple slicing

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_iterable(self, key, axis)
1034 def _getitem_iterable(self, key, axis=0):
1035 if self._should_validate_iterable(axis):
-> 1036 self._has_valid_type(key, axis)
1037
1038 labels = self.obj._get_axis(axis)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _has_valid_type(self, key, axis)
1390
1391 # TODO: don't check the entire key unless necessary
-> 1392 if len(key) and np.all(ax.get_indexer_for(key) < 0):
1393
1394 raise KeyError("None of [%s] are in the [%s]" %

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer_for(self, target, **kwargs)
2384 """ guaranteed return of an indexer even when non-unique """
2385 if self.is_unique:
-> 2386 return self.get_indexer(target, **kwargs)
2387 indexer, _ = self.get_indexer_non_unique(target, **kwargs)
2388 return indexer

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer(self, target, method, limit, tolerance)
2284 'backfill or nearest reindexing')
2285
-> 2286 indexer = self._engine.get_indexer(target._values)
2287
2288 return _ensure_platform_int(indexer)

pandas/index.pyx in pandas.index.IndexEngine.get_indexer (pandas/index.c:6077)()

pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.lookup (pandas/hashtable.c:14050)()

TypeError: unhashable type


Thank you



Priya










share|improve this question

























  • Please update your question for clarity. Two things primarily: 1) you say that you want to export value 1,3,6, from each column but your columns only have lists with 5 values and 2) the title of your question should summarise your problem, as it stands now it is too broad. In essence you want to first split a column containing a list into multiple columns and after that choose specific columns to export to excel. This is two different problems.

    – user3471881
    Nov 23 '18 at 9:30













  • Do you try my solution? If yes, there is some problem?

    – jezrael
    Nov 24 '18 at 12:51
















0















output saved in excel



Values saved as dictionary in each run. Below image shows how values are saved as list for each variable in run9



at run9, ACTB variable has value for every time step (first 17 time steps are shown)



I have 134 nodes. Fourteen different analysis (run) has been performed. Each run has values saved as dictionary, for all the 134 nodes. Each node has values saved for 150 time steps (150 values for each node).For example, Run 1 is saved as dictionary (10 time steps) i.e. node A, (0,1,0,5,6, 7, 8, 1, 0,6) and node B, (1,2,3,4,5,7, 6, 8,9,1). Similarly Run 2 is saved as dictionary. I could export these values to an excel sheet, but the values are saved together as (0,1,0,5,6, 7, 8, 1, 0,6). I want only the first three values for each node to be exported to excel sheet in three separate columns (instead of all the 10 values)



How to export the individual values in each column from run 1 and run 2 and save it in a excel sheet?



Code, which saves an excel sheet with all values listed in one column:



run1, run2, run3, run4, run5, run6, run7, run8, run9, run10, run11, run12, run13, run14 = data # each run has 5 values for 2 variables
df = pd.DataFrame.from_dict(data)
df.to_excel("data.xlsx")


When I run this code, df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]



I got the following error:



TypeError                                 Traceback (most recent call last)
<ipython-input-84-8d2d90289161> in <module>()
----> 1 df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1308
1309 if type(key) is tuple:
-> 1310 return self._getitem_tuple(key)
1311 else:
1312 return self._getitem_axis(key, axis=0)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
794 def _getitem_tuple(self, tup):
795 try:
--> 796 return self._getitem_lowerdim(tup)
797 except IndexingError:
798 pass

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
920 for i, key in enumerate(tup):
921 if is_label_like(key) or isinstance(key, tuple):
--> 922 section = self._getitem_axis(key, axis=i)
923
924 # we have yielded a scalar ?

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1470 raise ValueError('Cannot index with multidimensional key')
1471
-> 1472 return self._getitem_iterable(key, axis=axis)
1473
1474 # nested tuple slicing

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_iterable(self, key, axis)
1034 def _getitem_iterable(self, key, axis=0):
1035 if self._should_validate_iterable(axis):
-> 1036 self._has_valid_type(key, axis)
1037
1038 labels = self.obj._get_axis(axis)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _has_valid_type(self, key, axis)
1390
1391 # TODO: don't check the entire key unless necessary
-> 1392 if len(key) and np.all(ax.get_indexer_for(key) < 0):
1393
1394 raise KeyError("None of [%s] are in the [%s]" %

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer_for(self, target, **kwargs)
2384 """ guaranteed return of an indexer even when non-unique """
2385 if self.is_unique:
-> 2386 return self.get_indexer(target, **kwargs)
2387 indexer, _ = self.get_indexer_non_unique(target, **kwargs)
2388 return indexer

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer(self, target, method, limit, tolerance)
2284 'backfill or nearest reindexing')
2285
-> 2286 indexer = self._engine.get_indexer(target._values)
2287
2288 return _ensure_platform_int(indexer)

pandas/index.pyx in pandas.index.IndexEngine.get_indexer (pandas/index.c:6077)()

pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.lookup (pandas/hashtable.c:14050)()

TypeError: unhashable type


Thank you



Priya










share|improve this question

























  • Please update your question for clarity. Two things primarily: 1) you say that you want to export value 1,3,6, from each column but your columns only have lists with 5 values and 2) the title of your question should summarise your problem, as it stands now it is too broad. In essence you want to first split a column containing a list into multiple columns and after that choose specific columns to export to excel. This is two different problems.

    – user3471881
    Nov 23 '18 at 9:30













  • Do you try my solution? If yes, there is some problem?

    – jezrael
    Nov 24 '18 at 12:51














0












0








0








output saved in excel



Values saved as dictionary in each run. Below image shows how values are saved as list for each variable in run9



at run9, ACTB variable has value for every time step (first 17 time steps are shown)



I have 134 nodes. Fourteen different analysis (run) has been performed. Each run has values saved as dictionary, for all the 134 nodes. Each node has values saved for 150 time steps (150 values for each node).For example, Run 1 is saved as dictionary (10 time steps) i.e. node A, (0,1,0,5,6, 7, 8, 1, 0,6) and node B, (1,2,3,4,5,7, 6, 8,9,1). Similarly Run 2 is saved as dictionary. I could export these values to an excel sheet, but the values are saved together as (0,1,0,5,6, 7, 8, 1, 0,6). I want only the first three values for each node to be exported to excel sheet in three separate columns (instead of all the 10 values)



How to export the individual values in each column from run 1 and run 2 and save it in a excel sheet?



Code, which saves an excel sheet with all values listed in one column:



run1, run2, run3, run4, run5, run6, run7, run8, run9, run10, run11, run12, run13, run14 = data # each run has 5 values for 2 variables
df = pd.DataFrame.from_dict(data)
df.to_excel("data.xlsx")


When I run this code, df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]



I got the following error:



TypeError                                 Traceback (most recent call last)
<ipython-input-84-8d2d90289161> in <module>()
----> 1 df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1308
1309 if type(key) is tuple:
-> 1310 return self._getitem_tuple(key)
1311 else:
1312 return self._getitem_axis(key, axis=0)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
794 def _getitem_tuple(self, tup):
795 try:
--> 796 return self._getitem_lowerdim(tup)
797 except IndexingError:
798 pass

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
920 for i, key in enumerate(tup):
921 if is_label_like(key) or isinstance(key, tuple):
--> 922 section = self._getitem_axis(key, axis=i)
923
924 # we have yielded a scalar ?

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1470 raise ValueError('Cannot index with multidimensional key')
1471
-> 1472 return self._getitem_iterable(key, axis=axis)
1473
1474 # nested tuple slicing

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_iterable(self, key, axis)
1034 def _getitem_iterable(self, key, axis=0):
1035 if self._should_validate_iterable(axis):
-> 1036 self._has_valid_type(key, axis)
1037
1038 labels = self.obj._get_axis(axis)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _has_valid_type(self, key, axis)
1390
1391 # TODO: don't check the entire key unless necessary
-> 1392 if len(key) and np.all(ax.get_indexer_for(key) < 0):
1393
1394 raise KeyError("None of [%s] are in the [%s]" %

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer_for(self, target, **kwargs)
2384 """ guaranteed return of an indexer even when non-unique """
2385 if self.is_unique:
-> 2386 return self.get_indexer(target, **kwargs)
2387 indexer, _ = self.get_indexer_non_unique(target, **kwargs)
2388 return indexer

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer(self, target, method, limit, tolerance)
2284 'backfill or nearest reindexing')
2285
-> 2286 indexer = self._engine.get_indexer(target._values)
2287
2288 return _ensure_platform_int(indexer)

pandas/index.pyx in pandas.index.IndexEngine.get_indexer (pandas/index.c:6077)()

pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.lookup (pandas/hashtable.c:14050)()

TypeError: unhashable type


Thank you



Priya










share|improve this question
















output saved in excel



Values saved as dictionary in each run. Below image shows how values are saved as list for each variable in run9



at run9, ACTB variable has value for every time step (first 17 time steps are shown)



I have 134 nodes. Fourteen different analysis (run) has been performed. Each run has values saved as dictionary, for all the 134 nodes. Each node has values saved for 150 time steps (150 values for each node).For example, Run 1 is saved as dictionary (10 time steps) i.e. node A, (0,1,0,5,6, 7, 8, 1, 0,6) and node B, (1,2,3,4,5,7, 6, 8,9,1). Similarly Run 2 is saved as dictionary. I could export these values to an excel sheet, but the values are saved together as (0,1,0,5,6, 7, 8, 1, 0,6). I want only the first three values for each node to be exported to excel sheet in three separate columns (instead of all the 10 values)



How to export the individual values in each column from run 1 and run 2 and save it in a excel sheet?



Code, which saves an excel sheet with all values listed in one column:



run1, run2, run3, run4, run5, run6, run7, run8, run9, run10, run11, run12, run13, run14 = data # each run has 5 values for 2 variables
df = pd.DataFrame.from_dict(data)
df.to_excel("data.xlsx")


When I run this code, df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]



I got the following error:



TypeError                                 Traceback (most recent call last)
<ipython-input-84-8d2d90289161> in <module>()
----> 1 df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1308
1309 if type(key) is tuple:
-> 1310 return self._getitem_tuple(key)
1311 else:
1312 return self._getitem_axis(key, axis=0)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
794 def _getitem_tuple(self, tup):
795 try:
--> 796 return self._getitem_lowerdim(tup)
797 except IndexingError:
798 pass

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
920 for i, key in enumerate(tup):
921 if is_label_like(key) or isinstance(key, tuple):
--> 922 section = self._getitem_axis(key, axis=i)
923
924 # we have yielded a scalar ?

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1470 raise ValueError('Cannot index with multidimensional key')
1471
-> 1472 return self._getitem_iterable(key, axis=axis)
1473
1474 # nested tuple slicing

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_iterable(self, key, axis)
1034 def _getitem_iterable(self, key, axis=0):
1035 if self._should_validate_iterable(axis):
-> 1036 self._has_valid_type(key, axis)
1037
1038 labels = self.obj._get_axis(axis)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _has_valid_type(self, key, axis)
1390
1391 # TODO: don't check the entire key unless necessary
-> 1392 if len(key) and np.all(ax.get_indexer_for(key) < 0):
1393
1394 raise KeyError("None of [%s] are in the [%s]" %

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer_for(self, target, **kwargs)
2384 """ guaranteed return of an indexer even when non-unique """
2385 if self.is_unique:
-> 2386 return self.get_indexer(target, **kwargs)
2387 indexer, _ = self.get_indexer_non_unique(target, **kwargs)
2388 return indexer

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer(self, target, method, limit, tolerance)
2284 'backfill or nearest reindexing')
2285
-> 2286 indexer = self._engine.get_indexer(target._values)
2287
2288 return _ensure_platform_int(indexer)

pandas/index.pyx in pandas.index.IndexEngine.get_indexer (pandas/index.c:6077)()

pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.lookup (pandas/hashtable.c:14050)()

TypeError: unhashable type


Thank you



Priya







python excel pandas






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 29 '18 at 9:41







Priya

















asked Nov 23 '18 at 9:22









PriyaPriya

207




207













  • Please update your question for clarity. Two things primarily: 1) you say that you want to export value 1,3,6, from each column but your columns only have lists with 5 values and 2) the title of your question should summarise your problem, as it stands now it is too broad. In essence you want to first split a column containing a list into multiple columns and after that choose specific columns to export to excel. This is two different problems.

    – user3471881
    Nov 23 '18 at 9:30













  • Do you try my solution? If yes, there is some problem?

    – jezrael
    Nov 24 '18 at 12:51



















  • Please update your question for clarity. Two things primarily: 1) you say that you want to export value 1,3,6, from each column but your columns only have lists with 5 values and 2) the title of your question should summarise your problem, as it stands now it is too broad. In essence you want to first split a column containing a list into multiple columns and after that choose specific columns to export to excel. This is two different problems.

    – user3471881
    Nov 23 '18 at 9:30













  • Do you try my solution? If yes, there is some problem?

    – jezrael
    Nov 24 '18 at 12:51

















Please update your question for clarity. Two things primarily: 1) you say that you want to export value 1,3,6, from each column but your columns only have lists with 5 values and 2) the title of your question should summarise your problem, as it stands now it is too broad. In essence you want to first split a column containing a list into multiple columns and after that choose specific columns to export to excel. This is two different problems.

– user3471881
Nov 23 '18 at 9:30







Please update your question for clarity. Two things primarily: 1) you say that you want to export value 1,3,6, from each column but your columns only have lists with 5 values and 2) the title of your question should summarise your problem, as it stands now it is too broad. In essence you want to first split a column containing a list into multiple columns and after that choose specific columns to export to excel. This is two different problems.

– user3471881
Nov 23 '18 at 9:30















Do you try my solution? If yes, there is some problem?

– jezrael
Nov 24 '18 at 12:51





Do you try my solution? If yes, there is some problem?

– jezrael
Nov 24 '18 at 12:51












3 Answers
3






active

oldest

votes


















3














Use dictionary comprehension with concat and then filter MultiIndex in columns by slicers:



#python 3.6 +
f = lambda x: f'Value {x + 1}'
#python bellow 3.6
#f = lambda x: 'Value {}'.format(x + 1)
d = {x: pd.DataFrame(df[x].values.tolist(), index=df.index).rename(columns=f)
for x in df.columns}
df = pd.concat(d, axis=1)

df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]
print (df)
A B
Value 1 Value 3 Value 5 Value 1 Value 3 Value 5
Run 1 0 0 6 1 3 5
Run 2 0 0 1 1 3 0

df.to_excel(file)





share|improve this answer

































    1














    This would work:





    1. Split your list of values in a column to multiple columns by this:



      df[['Value1','Value2','Value3','Value4','Value5','Value6']] = pd.DataFrame(df.A.values.tolist(), index= df.index)




    2. Select the columns you want:



      df = df[['Value1','Value3','Value6']]




    3. Write to csv



      import pandas as pd



      df.to_csv("Output.csv")








    share|improve this answer
























    • @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

      – Priya
      Nov 24 '18 at 5:00











    • Good it solved your problem but my code and your code looks similar!!

      – Rahul Agarwal
      Nov 24 '18 at 6:51











    • @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

      – Priya
      Nov 24 '18 at 7:27











    • What is the excat error or problem my code is causing?

      – Rahul Agarwal
      Nov 24 '18 at 7:50











    • @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

      – Priya
      Nov 24 '18 at 8:07



















    0














    As I don't have heading for values, I found the value location for the node I was interested using the below code:



    df_1= df_1.iloc[:, [Node 1]]



    When you run this code, it gives the start and stop location of node 1. So I gave this line in the above code provided by jezrael and saved my results to excel sheet.



    Replaced this below line in jezrael code with the above line:



    df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]



    @jezrael and Rahul Agarwal Thank you for all the help






    share|improve this answer























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      3 Answers
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      3














      Use dictionary comprehension with concat and then filter MultiIndex in columns by slicers:



      #python 3.6 +
      f = lambda x: f'Value {x + 1}'
      #python bellow 3.6
      #f = lambda x: 'Value {}'.format(x + 1)
      d = {x: pd.DataFrame(df[x].values.tolist(), index=df.index).rename(columns=f)
      for x in df.columns}
      df = pd.concat(d, axis=1)

      df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]
      print (df)
      A B
      Value 1 Value 3 Value 5 Value 1 Value 3 Value 5
      Run 1 0 0 6 1 3 5
      Run 2 0 0 1 1 3 0

      df.to_excel(file)





      share|improve this answer






























        3














        Use dictionary comprehension with concat and then filter MultiIndex in columns by slicers:



        #python 3.6 +
        f = lambda x: f'Value {x + 1}'
        #python bellow 3.6
        #f = lambda x: 'Value {}'.format(x + 1)
        d = {x: pd.DataFrame(df[x].values.tolist(), index=df.index).rename(columns=f)
        for x in df.columns}
        df = pd.concat(d, axis=1)

        df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]
        print (df)
        A B
        Value 1 Value 3 Value 5 Value 1 Value 3 Value 5
        Run 1 0 0 6 1 3 5
        Run 2 0 0 1 1 3 0

        df.to_excel(file)





        share|improve this answer




























          3












          3








          3







          Use dictionary comprehension with concat and then filter MultiIndex in columns by slicers:



          #python 3.6 +
          f = lambda x: f'Value {x + 1}'
          #python bellow 3.6
          #f = lambda x: 'Value {}'.format(x + 1)
          d = {x: pd.DataFrame(df[x].values.tolist(), index=df.index).rename(columns=f)
          for x in df.columns}
          df = pd.concat(d, axis=1)

          df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]
          print (df)
          A B
          Value 1 Value 3 Value 5 Value 1 Value 3 Value 5
          Run 1 0 0 6 1 3 5
          Run 2 0 0 1 1 3 0

          df.to_excel(file)





          share|improve this answer















          Use dictionary comprehension with concat and then filter MultiIndex in columns by slicers:



          #python 3.6 +
          f = lambda x: f'Value {x + 1}'
          #python bellow 3.6
          #f = lambda x: 'Value {}'.format(x + 1)
          d = {x: pd.DataFrame(df[x].values.tolist(), index=df.index).rename(columns=f)
          for x in df.columns}
          df = pd.concat(d, axis=1)

          df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]
          print (df)
          A B
          Value 1 Value 3 Value 5 Value 1 Value 3 Value 5
          Run 1 0 0 6 1 3 5
          Run 2 0 0 1 1 3 0

          df.to_excel(file)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 23 '18 at 10:00

























          answered Nov 23 '18 at 9:43









          jezraeljezrael

          335k25281357




          335k25281357

























              1














              This would work:





              1. Split your list of values in a column to multiple columns by this:



                df[['Value1','Value2','Value3','Value4','Value5','Value6']] = pd.DataFrame(df.A.values.tolist(), index= df.index)




              2. Select the columns you want:



                df = df[['Value1','Value3','Value6']]




              3. Write to csv



                import pandas as pd



                df.to_csv("Output.csv")








              share|improve this answer
























              • @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

                – Priya
                Nov 24 '18 at 5:00











              • Good it solved your problem but my code and your code looks similar!!

                – Rahul Agarwal
                Nov 24 '18 at 6:51











              • @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

                – Priya
                Nov 24 '18 at 7:27











              • What is the excat error or problem my code is causing?

                – Rahul Agarwal
                Nov 24 '18 at 7:50











              • @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

                – Priya
                Nov 24 '18 at 8:07
















              1














              This would work:





              1. Split your list of values in a column to multiple columns by this:



                df[['Value1','Value2','Value3','Value4','Value5','Value6']] = pd.DataFrame(df.A.values.tolist(), index= df.index)




              2. Select the columns you want:



                df = df[['Value1','Value3','Value6']]




              3. Write to csv



                import pandas as pd



                df.to_csv("Output.csv")








              share|improve this answer
























              • @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

                – Priya
                Nov 24 '18 at 5:00











              • Good it solved your problem but my code and your code looks similar!!

                – Rahul Agarwal
                Nov 24 '18 at 6:51











              • @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

                – Priya
                Nov 24 '18 at 7:27











              • What is the excat error or problem my code is causing?

                – Rahul Agarwal
                Nov 24 '18 at 7:50











              • @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

                – Priya
                Nov 24 '18 at 8:07














              1












              1








              1







              This would work:





              1. Split your list of values in a column to multiple columns by this:



                df[['Value1','Value2','Value3','Value4','Value5','Value6']] = pd.DataFrame(df.A.values.tolist(), index= df.index)




              2. Select the columns you want:



                df = df[['Value1','Value3','Value6']]




              3. Write to csv



                import pandas as pd



                df.to_csv("Output.csv")








              share|improve this answer













              This would work:





              1. Split your list of values in a column to multiple columns by this:



                df[['Value1','Value2','Value3','Value4','Value5','Value6']] = pd.DataFrame(df.A.values.tolist(), index= df.index)




              2. Select the columns you want:



                df = df[['Value1','Value3','Value6']]




              3. Write to csv



                import pandas as pd



                df.to_csv("Output.csv")









              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 23 '18 at 9:37









              Rahul AgarwalRahul Agarwal

              2,20051027




              2,20051027













              • @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

                – Priya
                Nov 24 '18 at 5:00











              • Good it solved your problem but my code and your code looks similar!!

                – Rahul Agarwal
                Nov 24 '18 at 6:51











              • @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

                – Priya
                Nov 24 '18 at 7:27











              • What is the excat error or problem my code is causing?

                – Rahul Agarwal
                Nov 24 '18 at 7:50











              • @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

                – Priya
                Nov 24 '18 at 8:07



















              • @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

                – Priya
                Nov 24 '18 at 5:00











              • Good it solved your problem but my code and your code looks similar!!

                – Rahul Agarwal
                Nov 24 '18 at 6:51











              • @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

                – Priya
                Nov 24 '18 at 7:27











              • What is the excat error or problem my code is causing?

                – Rahul Agarwal
                Nov 24 '18 at 7:50











              • @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

                – Priya
                Nov 24 '18 at 8:07

















              @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

              – Priya
              Nov 24 '18 at 5:00





              @ Rahul Agarwal. Thanks. I tried your code, but still I couldn't save each value in separate column. Please find the code, which I have used in the above question.

              – Priya
              Nov 24 '18 at 5:00













              Good it solved your problem but my code and your code looks similar!!

              – Rahul Agarwal
              Nov 24 '18 at 6:51





              Good it solved your problem but my code and your code looks similar!!

              – Rahul Agarwal
              Nov 24 '18 at 6:51













              @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

              – Priya
              Nov 24 '18 at 7:27





              @ Rahul Agarwal. No I tried your code, which I have posted in the above question. It did not work for me. I am still looking for answers

              – Priya
              Nov 24 '18 at 7:27













              What is the excat error or problem my code is causing?

              – Rahul Agarwal
              Nov 24 '18 at 7:50





              What is the excat error or problem my code is causing?

              – Rahul Agarwal
              Nov 24 '18 at 7:50













              @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

              – Priya
              Nov 24 '18 at 8:07





              @ Rahul Agarwal. The code did not throw any error as well I did not get any excel sheet saved. But when I used the modified code (please see the above question), I get an excel sheet but with list of all the 5 values saved in one column, instead of 5 columns. As well as, I don't know how to save only 3 values instead of all the 5 values

              – Priya
              Nov 24 '18 at 8:07











              0














              As I don't have heading for values, I found the value location for the node I was interested using the below code:



              df_1= df_1.iloc[:, [Node 1]]



              When you run this code, it gives the start and stop location of node 1. So I gave this line in the above code provided by jezrael and saved my results to excel sheet.



              Replaced this below line in jezrael code with the above line:



              df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]



              @jezrael and Rahul Agarwal Thank you for all the help






              share|improve this answer




























                0














                As I don't have heading for values, I found the value location for the node I was interested using the below code:



                df_1= df_1.iloc[:, [Node 1]]



                When you run this code, it gives the start and stop location of node 1. So I gave this line in the above code provided by jezrael and saved my results to excel sheet.



                Replaced this below line in jezrael code with the above line:



                df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]



                @jezrael and Rahul Agarwal Thank you for all the help






                share|improve this answer


























                  0












                  0








                  0







                  As I don't have heading for values, I found the value location for the node I was interested using the below code:



                  df_1= df_1.iloc[:, [Node 1]]



                  When you run this code, it gives the start and stop location of node 1. So I gave this line in the above code provided by jezrael and saved my results to excel sheet.



                  Replaced this below line in jezrael code with the above line:



                  df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]



                  @jezrael and Rahul Agarwal Thank you for all the help






                  share|improve this answer













                  As I don't have heading for values, I found the value location for the node I was interested using the below code:



                  df_1= df_1.iloc[:, [Node 1]]



                  When you run this code, it gives the start and stop location of node 1. So I gave this line in the above code provided by jezrael and saved my results to excel sheet.



                  Replaced this below line in jezrael code with the above line:



                  df = df.loc[:, pd.IndexSlice[:, ['Value 1','Value 3','Value 5']]]



                  @jezrael and Rahul Agarwal Thank you for all the help







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Dec 4 '18 at 6:28









                  PriyaPriya

                  207




                  207






























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