ionic 3 angularfire2 code to ionic 4 angularfire2 code
i have my code with ionic 3 angular 5 working as below
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) =>
{
this.db.object("/users/" + uid).snapshotChanges().map(
(snapshot) => {return snapshot.payload.val()}
).subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
however, with ionic 4 .map does not work any more. how do i convert this code?
ionic-framework angularfire2 ionic4 angularfire5
add a comment |
i have my code with ionic 3 angular 5 working as below
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) =>
{
this.db.object("/users/" + uid).snapshotChanges().map(
(snapshot) => {return snapshot.payload.val()}
).subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
however, with ionic 4 .map does not work any more. how do i convert this code?
ionic-framework angularfire2 ionic4 angularfire5
add a comment |
i have my code with ionic 3 angular 5 working as below
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) =>
{
this.db.object("/users/" + uid).snapshotChanges().map(
(snapshot) => {return snapshot.payload.val()}
).subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
however, with ionic 4 .map does not work any more. how do i convert this code?
ionic-framework angularfire2 ionic4 angularfire5
i have my code with ionic 3 angular 5 working as below
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) =>
{
this.db.object("/users/" + uid).snapshotChanges().map(
(snapshot) => {return snapshot.payload.val()}
).subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
however, with ionic 4 .map does not work any more. how do i convert this code?
ionic-framework angularfire2 ionic4 angularfire5
ionic-framework angularfire2 ionic4 angularfire5
asked Nov 26 '18 at 5:11
VikVik
2,0751346101
2,0751346101
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Just like you can see here
Starting in version 5.5 we have shipped "pipeable operators", which
can be accessed in rxjs/operators (notice the pluralized "operators").
These are meant to be a better approach for pulling in just the
operators you need than the "patch" operators found in rxjs-compat
package.
NOTE: Using rxjs or rxjs/operators without making changes to your
build process can result in larger bundles.
So now you can use map() like this:
// RxJS
import { map } from 'rxjs/operators/map';
// ...
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) => {
this.db.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
})
)
.subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
Not related to the question itself but just in case, if you want your getUser() method to return a promise, you can use RXJS operators as well (instead of creating and resolving a promise), like this:
// RxJS
import { map } from 'rxjs/operators/map';
import { tap } from 'rxjs/operators/tap';
// ...
public getUser(uid: string): Promise<any> {
console.log('start of getUser with uid:' + uid)
return this.db
.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
}),
tap((response) => {
console.log('response:' + response);
})
)
.toPromise()
}
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just like you can see here
Starting in version 5.5 we have shipped "pipeable operators", which
can be accessed in rxjs/operators (notice the pluralized "operators").
These are meant to be a better approach for pulling in just the
operators you need than the "patch" operators found in rxjs-compat
package.
NOTE: Using rxjs or rxjs/operators without making changes to your
build process can result in larger bundles.
So now you can use map() like this:
// RxJS
import { map } from 'rxjs/operators/map';
// ...
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) => {
this.db.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
})
)
.subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
Not related to the question itself but just in case, if you want your getUser() method to return a promise, you can use RXJS operators as well (instead of creating and resolving a promise), like this:
// RxJS
import { map } from 'rxjs/operators/map';
import { tap } from 'rxjs/operators/tap';
// ...
public getUser(uid: string): Promise<any> {
console.log('start of getUser with uid:' + uid)
return this.db
.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
}),
tap((response) => {
console.log('response:' + response);
})
)
.toPromise()
}
add a comment |
Just like you can see here
Starting in version 5.5 we have shipped "pipeable operators", which
can be accessed in rxjs/operators (notice the pluralized "operators").
These are meant to be a better approach for pulling in just the
operators you need than the "patch" operators found in rxjs-compat
package.
NOTE: Using rxjs or rxjs/operators without making changes to your
build process can result in larger bundles.
So now you can use map() like this:
// RxJS
import { map } from 'rxjs/operators/map';
// ...
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) => {
this.db.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
})
)
.subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
Not related to the question itself but just in case, if you want your getUser() method to return a promise, you can use RXJS operators as well (instead of creating and resolving a promise), like this:
// RxJS
import { map } from 'rxjs/operators/map';
import { tap } from 'rxjs/operators/tap';
// ...
public getUser(uid: string): Promise<any> {
console.log('start of getUser with uid:' + uid)
return this.db
.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
}),
tap((response) => {
console.log('response:' + response);
})
)
.toPromise()
}
add a comment |
Just like you can see here
Starting in version 5.5 we have shipped "pipeable operators", which
can be accessed in rxjs/operators (notice the pluralized "operators").
These are meant to be a better approach for pulling in just the
operators you need than the "patch" operators found in rxjs-compat
package.
NOTE: Using rxjs or rxjs/operators without making changes to your
build process can result in larger bundles.
So now you can use map() like this:
// RxJS
import { map } from 'rxjs/operators/map';
// ...
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) => {
this.db.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
})
)
.subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
Not related to the question itself but just in case, if you want your getUser() method to return a promise, you can use RXJS operators as well (instead of creating and resolving a promise), like this:
// RxJS
import { map } from 'rxjs/operators/map';
import { tap } from 'rxjs/operators/tap';
// ...
public getUser(uid: string): Promise<any> {
console.log('start of getUser with uid:' + uid)
return this.db
.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
}),
tap((response) => {
console.log('response:' + response);
})
)
.toPromise()
}
Just like you can see here
Starting in version 5.5 we have shipped "pipeable operators", which
can be accessed in rxjs/operators (notice the pluralized "operators").
These are meant to be a better approach for pulling in just the
operators you need than the "patch" operators found in rxjs-compat
package.
NOTE: Using rxjs or rxjs/operators without making changes to your
build process can result in larger bundles.
So now you can use map() like this:
// RxJS
import { map } from 'rxjs/operators/map';
// ...
getUser(uid:string){
console.log('start of getUser with uid:' + uid)
return new Promise((resolve, reject) => {
this.db.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
})
)
.subscribe(
res => {
console.log('response:' + res)
resolve(res)
},
err => {
console.log(err)
reject(err)
}
)
})
}
Not related to the question itself but just in case, if you want your getUser() method to return a promise, you can use RXJS operators as well (instead of creating and resolving a promise), like this:
// RxJS
import { map } from 'rxjs/operators/map';
import { tap } from 'rxjs/operators/tap';
// ...
public getUser(uid: string): Promise<any> {
console.log('start of getUser with uid:' + uid)
return this.db
.object("/users/" + uid)
.snapshotChanges()
.pipe(
map((snapshot) => {
return snapshot.payload.val();
}),
tap((response) => {
console.log('response:' + response);
})
)
.toPromise()
}
edited Nov 26 '18 at 5:28
answered Nov 26 '18 at 5:20
sebaferrerassebaferreras
33.3k87999
33.3k87999
add a comment |
add a comment |
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