Radio buttons give wrong value in php
-3
So, I am trying to make a login + register page in-one. Where I use radio buttons to get the value if you want to login or register.
Here is the radio button s code;
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check" value="1">
<label class="form-check-label" for="check">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check" value="0" checked>
<label class="form-check-label" for="check">Login</label>
</div>
So, I am checking for $_POST['check'] if the value is 0 or 1. But somehow it just ignores that, and always registers. Here is my php code;
session_start();
if (isset($_POST['username'])) {
$value = $_POST['check'];
// Do some stuff here
if ($value == 1) {
// register
} elseif ($value == 0) {
// login
} else {
// Do something for bad results
}
}
Somehow when I check login it wants to register, but when I click on register, it still registers. Something is going wrong here right?
php html forms session
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
|
show 3 more comments
-3
So, I am trying to make a login + register page in-one. Where I use radio buttons to get the value if you want to login or register.
Here is the radio button s code;
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check" value="1">
<label class="form-check-label" for="check">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check" value="0" checked>
<label class="form-check-label" for="check">Login</label>
</div>
So, I am checking for $_POST['check'] if the value is 0 or 1. But somehow it just ignores that, and always registers. Here is my php code;
session_start();
if (isset($_POST['username'])) {
$value = $_POST['check'];
// Do some stuff here
if ($value == 1) {
// register
} elseif ($value == 0) {
// login
} else {
// Do something for bad results
}
}
Somehow when I check login it wants to register, but when I click on register, it still registers. Something is going wrong here right?
php html forms session
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
1
And what will change?
– Oleg Nurutdinov
Nov 26 '18 at 9:38
2
@Twinkle1 == "1"is true in PHP
– Cid
Nov 26 '18 at 9:38
2
You can var_dump($_POST['check']) to find out what you are receiving
– Gasanov
Nov 26 '18 at 9:39
2
I tried your code and I have the expected result.$valuemight be overwritten in the// Do some stuff here. This is by the way a very bad naming which can lead to confusion/overwritting.
– Cid
Nov 26 '18 at 9:47
1
I agree with user @Cid; tested your code as is and it worked as intended for me. Perhaps posting more code may be appropriate to identify the issue.
– cmprogram
Nov 26 '18 at 9:54
|
show 3 more comments
-3
-3
-3
So, I am trying to make a login + register page in-one. Where I use radio buttons to get the value if you want to login or register.
Here is the radio button s code;
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check" value="1">
<label class="form-check-label" for="check">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check" value="0" checked>
<label class="form-check-label" for="check">Login</label>
</div>
So, I am checking for $_POST['check'] if the value is 0 or 1. But somehow it just ignores that, and always registers. Here is my php code;
session_start();
if (isset($_POST['username'])) {
$value = $_POST['check'];
// Do some stuff here
if ($value == 1) {
// register
} elseif ($value == 0) {
// login
} else {
// Do something for bad results
}
}
Somehow when I check login it wants to register, but when I click on register, it still registers. Something is going wrong here right?
php html forms session
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
So, I am trying to make a login + register page in-one. Where I use radio buttons to get the value if you want to login or register.
Here is the radio button s code;
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check" value="1">
<label class="form-check-label" for="check">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check" value="0" checked>
<label class="form-check-label" for="check">Login</label>
</div>
So, I am checking for $_POST['check'] if the value is 0 or 1. But somehow it just ignores that, and always registers. Here is my php code;
session_start();
if (isset($_POST['username'])) {
$value = $_POST['check'];
// Do some stuff here
if ($value == 1) {
// register
} elseif ($value == 0) {
// login
} else {
// Do something for bad results
}
}
Somehow when I check login it wants to register, but when I click on register, it still registers. Something is going wrong here right?
php html forms session
php html forms session
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
edited Nov 26 '18 at 13:35
Funk Forty Niner
1
1
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
asked Nov 26 '18 at 9:34
minecraft accountminecraft account
13
13
1
And what will change?
– Oleg Nurutdinov
Nov 26 '18 at 9:38
2
@Twinkle1 == "1"is true in PHP
– Cid
Nov 26 '18 at 9:38
2
You can var_dump($_POST['check']) to find out what you are receiving
– Gasanov
Nov 26 '18 at 9:39
2
I tried your code and I have the expected result.$valuemight be overwritten in the// Do some stuff here. This is by the way a very bad naming which can lead to confusion/overwritting.
– Cid
Nov 26 '18 at 9:47
1
I agree with user @Cid; tested your code as is and it worked as intended for me. Perhaps posting more code may be appropriate to identify the issue.
– cmprogram
Nov 26 '18 at 9:54
|
show 3 more comments
1
And what will change?
– Oleg Nurutdinov
Nov 26 '18 at 9:38
2
@Twinkle1 == "1"is true in PHP
– Cid
Nov 26 '18 at 9:38
2
You can var_dump($_POST['check']) to find out what you are receiving
– Gasanov
Nov 26 '18 at 9:39
2
I tried your code and I have the expected result.$valuemight be overwritten in the// Do some stuff here. This is by the way a very bad naming which can lead to confusion/overwritting.
– Cid
Nov 26 '18 at 9:47
1
I agree with user @Cid; tested your code as is and it worked as intended for me. Perhaps posting more code may be appropriate to identify the issue.
– cmprogram
Nov 26 '18 at 9:54
1
1
And what will change?
– Oleg Nurutdinov
Nov 26 '18 at 9:38
And what will change?
– Oleg Nurutdinov
Nov 26 '18 at 9:38
2
2
@Twinkle
1 == "1" is true in PHP– Cid
Nov 26 '18 at 9:38
@Twinkle
1 == "1" is true in PHP– Cid
Nov 26 '18 at 9:38
2
2
You can var_dump($_POST['check']) to find out what you are receiving
– Gasanov
Nov 26 '18 at 9:39
You can var_dump($_POST['check']) to find out what you are receiving
– Gasanov
Nov 26 '18 at 9:39
2
2
I tried your code and I have the expected result.
$value might be overwritten in the // Do some stuff here. This is by the way a very bad naming which can lead to confusion/overwritting.– Cid
Nov 26 '18 at 9:47
I tried your code and I have the expected result.
$value might be overwritten in the // Do some stuff here. This is by the way a very bad naming which can lead to confusion/overwritting.– Cid
Nov 26 '18 at 9:47
1
1
I agree with user @Cid; tested your code as is and it worked as intended for me. Perhaps posting more code may be appropriate to identify the issue.
– cmprogram
Nov 26 '18 at 9:54
I agree with user @Cid; tested your code as is and it worked as intended for me. Perhaps posting more code may be appropriate to identify the issue.
– cmprogram
Nov 26 '18 at 9:54
|
show 3 more comments
1 Answer
1
active
oldest
votes
-2
id of element must be unique
code should look like this
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check_1" value="1">
<label class="form-check-label" for="check_1">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check_0" value="0" checked>
<label class="form-check-label" for="check_0">Login</label>
</div>
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
-2
id of element must be unique
code should look like this
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check_1" value="1">
<label class="form-check-label" for="check_1">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check_0" value="0" checked>
<label class="form-check-label" for="check_0">Login</label>
</div>
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
add a comment |
-2
id of element must be unique
code should look like this
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check_1" value="1">
<label class="form-check-label" for="check_1">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check_0" value="0" checked>
<label class="form-check-label" for="check_0">Login</label>
</div>
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
add a comment |
-2
-2
-2
id of element must be unique
code should look like this
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check_1" value="1">
<label class="form-check-label" for="check_1">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check_0" value="0" checked>
<label class="form-check-label" for="check_0">Login</label>
</div>
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
id of element must be unique
code should look like this
<div class="form-check">
<input class="form-check-input" type="radio" name="check" id="check_1" value="1">
<label class="form-check-label" for="check_1">Register</label>
<br>
<input class="form-check-input" type="radio" name="check" id="check_0" value="0" checked>
<label class="form-check-label" for="check_0">Login</label>
</div>
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
answered Nov 26 '18 at 9:43
EK LYEK LY
2715
2715
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
add a comment |
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
Although this is fixing an invalid HTML, this has nothing to do with the problem.
– Cid
Nov 26 '18 at 9:50
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
point of problem may be at the last line of this question
– EK LY
Nov 26 '18 at 10:02
add a comment |
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1
And what will change?
– Oleg Nurutdinov
Nov 26 '18 at 9:38
2
@Twinkle
1 == "1"is true in PHP– Cid
Nov 26 '18 at 9:38
2
You can var_dump($_POST['check']) to find out what you are receiving
– Gasanov
Nov 26 '18 at 9:39
2
I tried your code and I have the expected result.
$valuemight be overwritten in the// Do some stuff here. This is by the way a very bad naming which can lead to confusion/overwritting.– Cid
Nov 26 '18 at 9:47
1
I agree with user @Cid; tested your code as is and it worked as intended for me. Perhaps posting more code may be appropriate to identify the issue.
– cmprogram
Nov 26 '18 at 9:54