Nsryjdtyk

I have a question in Python 3.7. I am opening a text file (input.txt) and creating variables from various lines of the text file. For example my text file looks as follows:

Case1

P

1.00E+02

5.

I need to create variables so that:

title = "Case1"

area = "P"

distance = 100

factor = 5

So far this is what I have:

f = open('C:\input.txt',"r")

title = f.readline().strip()

area = f.readline().strip()

distance = f.readline().strip()

factor = f.readline().strip().strip(".")

f.close

print(title)

print(area)

print(distance)

print(factor)

which results in:

Case1

P

1.00E+02

5

How do I get the distance variable to show up as 100 instead of 1.00E+02?

I found the link below thinking it would help, but wasn't able to solve my problem from there. This is a very small segment of my larger program that was simplified, but if it works here it will work for my needs. My program needs to open a generated text file and produce another text file, so the scientific notation number will change between 1.00E-06 and 1.00E+03. The generated text file needs to have these numbers as integers (i.e. between 0.000001 and 1000). Thanks for any help!

Converting number in scientific notation to int

The link you posted actually gives the answer, albeit in a roundabout way.
int() cannot parse strings that don't already represent integers.
But a scientific number is a float.

So, you need to cast it to float first to parse the string.

Try:

print(float(distance))

For numbers with more decimals (e.g your example of 1.00E-06), you can force float notation all the time. Try:

print(format(float(distance), 'f'))

If you only want a certain number of decimals, try:

print(format(float(distance), '.2f'))  

(for example)