How can I show a progress bar in Pharo?

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I have a do: in Pharo that takes a long time to process. I'd like to show the progress of it to the user. How is that done in Pharo?

edited Nov 19 at 15:32

asked Nov 19 at 13:23

Fuhrmanator

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Dear down voter who left no comment: how is this question worse than stackoverflow.com/questions/3951903 or stackoverflow.com/q/238073/1168342 or stackoverflow.com/q/3160699/1168342
– Fuhrmanator
Nov 19 at 15:31

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up vote
1
down vote

favorite

I have a do: in Pharo that takes a long time to process. I'd like to show the progress of it to the user. How is that done in Pharo?

edited Nov 19 at 15:32

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

Dear down voter who left no comment: how is this question worse than stackoverflow.com/questions/3951903 or stackoverflow.com/q/238073/1168342 or stackoverflow.com/q/3160699/1168342
– Fuhrmanator
Nov 19 at 15:31

add a comment |

up vote
1
down vote

favorite

I have a do: in Pharo that takes a long time to process. I'd like to show the progress of it to the user. How is that done in Pharo?

edited Nov 19 at 15:32

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

I have a do: in Pharo that takes a long time to process. I'd like to show the progress of it to the user. How is that done in Pharo?

pharo

edited Nov 19 at 15:32

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

edited Nov 19 at 15:32

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

edited Nov 19 at 15:32

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

asked Nov 19 at 13:23

Fuhrmanator

4,96833166

Dear down voter who left no comment: how is this question worse than stackoverflow.com/questions/3951903 or stackoverflow.com/q/238073/1168342 or stackoverflow.com/q/3160699/1168342
– Fuhrmanator
Nov 19 at 15:31

add a comment |

Dear down voter who left no comment: how is this question worse than stackoverflow.com/questions/3951903 or stackoverflow.com/q/238073/1168342 or stackoverflow.com/q/3160699/1168342
– Fuhrmanator
Nov 19 at 15:31

Dear down voter who left no comment: how is this question worse than stackoverflow.com/questions/3951903 or stackoverflow.com/q/238073/1168342 or stackoverflow.com/q/3160699/1168342
– Fuhrmanator
Nov 19 at 15:31

add a comment |

1 Answer
1

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oldest

votes

up vote
5
down vote

accepted

Here are two ways:

Collection borrows from UIManager and supports a displayingProgress: every: milliseconds variant of do::
```
(1 to: 60)

   do: [ :e | (Delay forSeconds: 0.5) wait "simulate a delay" ]

   displayingProgress: [ :e | 'waiting ' , e asString ] every: 1000
```
You can play with the every: on this example to see that if you set it to less than 1000ms, it will update more often (setting it to 100 will show you every value of the interval).

Also, you can simply use displayingProgress: 'Waiting...' to only show the same string the whole time, without a block.

Using the Job class. Here's a similar solution as above:

myColl := 1 to: 20.

[ :job | 

myColl

   do: [ :e | 

      job

        progress: e / myColl size;

        title: 'waiting ' , e asString.

      (Delay forSeconds: 0.5) wait ] ] asJob run

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
5
down vote

accepted

Here are two ways:

Collection borrows from UIManager and supports a displayingProgress: every: milliseconds variant of do::
```
(1 to: 60)

   do: [ :e | (Delay forSeconds: 0.5) wait "simulate a delay" ]

   displayingProgress: [ :e | 'waiting ' , e asString ] every: 1000
```
You can play with the every: on this example to see that if you set it to less than 1000ms, it will update more often (setting it to 100 will show you every value of the interval).

Also, you can simply use displayingProgress: 'Waiting...' to only show the same string the whole time, without a block.

Using the Job class. Here's a similar solution as above:

myColl := 1 to: 20.

[ :job | 

myColl

   do: [ :e | 

      job

        progress: e / myColl size;

        title: 'waiting ' , e asString.

      (Delay forSeconds: 0.5) wait ] ] asJob run

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

add a comment |

up vote
5
down vote

accepted

Here are two ways:

Collection borrows from UIManager and supports a displayingProgress: every: milliseconds variant of do::
```
(1 to: 60)

   do: [ :e | (Delay forSeconds: 0.5) wait "simulate a delay" ]

   displayingProgress: [ :e | 'waiting ' , e asString ] every: 1000
```
You can play with the every: on this example to see that if you set it to less than 1000ms, it will update more often (setting it to 100 will show you every value of the interval).

Also, you can simply use displayingProgress: 'Waiting...' to only show the same string the whole time, without a block.

Using the Job class. Here's a similar solution as above:

myColl := 1 to: 20.

[ :job | 

myColl

   do: [ :e | 

      job

        progress: e / myColl size;

        title: 'waiting ' , e asString.

      (Delay forSeconds: 0.5) wait ] ] asJob run

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

add a comment |

up vote
5
down vote

accepted

Here are two ways:

Collection borrows from UIManager and supports a displayingProgress: every: milliseconds variant of do::
```
(1 to: 60)

   do: [ :e | (Delay forSeconds: 0.5) wait "simulate a delay" ]

   displayingProgress: [ :e | 'waiting ' , e asString ] every: 1000
```
You can play with the every: on this example to see that if you set it to less than 1000ms, it will update more often (setting it to 100 will show you every value of the interval).

Also, you can simply use displayingProgress: 'Waiting...' to only show the same string the whole time, without a block.

Using the Job class. Here's a similar solution as above:

myColl := 1 to: 20.

[ :job | 

myColl

   do: [ :e | 

      job

        progress: e / myColl size;

        title: 'waiting ' , e asString.

      (Delay forSeconds: 0.5) wait ] ] asJob run

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

Here are two ways:

Collection borrows from UIManager and supports a displayingProgress: every: milliseconds variant of do::
```
(1 to: 60)

   do: [ :e | (Delay forSeconds: 0.5) wait "simulate a delay" ]

   displayingProgress: [ :e | 'waiting ' , e asString ] every: 1000
```
You can play with the every: on this example to see that if you set it to less than 1000ms, it will update more often (setting it to 100 will show you every value of the interval).

Also, you can simply use displayingProgress: 'Waiting...' to only show the same string the whole time, without a block.

Using the Job class. Here's a similar solution as above:

myColl := 1 to: 20.

[ :job | 

myColl

   do: [ :e | 

      job

        progress: e / myColl size;

        title: 'waiting ' , e asString.

      (Delay forSeconds: 0.5) wait ] ] asJob run

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

answered Nov 19 at 13:23

Fuhrmanator

4,96833166

add a comment |

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