How to transform the data and calculate the TFIDF value?











up vote
0
down vote

favorite












My data format is:
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2],...}
Each element in datas is a sentence ,and each number is a word.I want to get the TFIDF value for each number. How to do it with sklearn or other ways?



My code:



from sklearn.feature_extraction.text import TfidfTransformer  
from sklearn.feature_extraction.text import CountVectorizer
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2]}
vectorizer=CountVectorizer()

transformer = TfidfTransformer()
tfidf = transformer.fit_transform(vectorizer.fit_transform(datas))
print(tfidf)


My code doesn't work.Error:



Traceback (most recent call last):   File
"C:/Users/zhuowei/Desktop/OpenNE-master/OpenNE-
master/src/openne/buildTree.py", line 103, in <module>
X = vectorizer.fit_transform(datas) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 869, in fit_transform
self.fixed_vocabulary_) File "C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 792, in _count_vocab
for feature in analyze(doc): File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 266, in <lambda>
tokenize(preprocess(self.decode(doc))), stop_words) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 232, in <lambda>
return lambda x: strip_accents(x.lower())
AttributeError: 'int' object has no attribute 'lower'









share|improve this question
























  • What did you search for in order to solve this, and what did you find? What did you try, and why didn't it work?
    – tripleee
    Nov 19 at 8:33










  • I have put my code above
    – Z Mario
    Nov 19 at 8:43










  • Thanks for the code. Please include the full traceback still, though.
    – tripleee
    Nov 19 at 8:44










  • ok I have add the full traceback, I think my way is wrong ,but I don't know how to fix it
    – Z Mario
    Nov 19 at 8:52










  • Unfortunately, that doesn't look like a full traceback. Also str(nodes[0]) in the traceback doesn't seem to correspond to anything in your question. You should probably review the guidance for how to create a Minimal, Complete, and Verifiable example.
    – tripleee
    Nov 19 at 8:53

















up vote
0
down vote

favorite












My data format is:
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2],...}
Each element in datas is a sentence ,and each number is a word.I want to get the TFIDF value for each number. How to do it with sklearn or other ways?



My code:



from sklearn.feature_extraction.text import TfidfTransformer  
from sklearn.feature_extraction.text import CountVectorizer
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2]}
vectorizer=CountVectorizer()

transformer = TfidfTransformer()
tfidf = transformer.fit_transform(vectorizer.fit_transform(datas))
print(tfidf)


My code doesn't work.Error:



Traceback (most recent call last):   File
"C:/Users/zhuowei/Desktop/OpenNE-master/OpenNE-
master/src/openne/buildTree.py", line 103, in <module>
X = vectorizer.fit_transform(datas) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 869, in fit_transform
self.fixed_vocabulary_) File "C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 792, in _count_vocab
for feature in analyze(doc): File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 266, in <lambda>
tokenize(preprocess(self.decode(doc))), stop_words) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 232, in <lambda>
return lambda x: strip_accents(x.lower())
AttributeError: 'int' object has no attribute 'lower'









share|improve this question
























  • What did you search for in order to solve this, and what did you find? What did you try, and why didn't it work?
    – tripleee
    Nov 19 at 8:33










  • I have put my code above
    – Z Mario
    Nov 19 at 8:43










  • Thanks for the code. Please include the full traceback still, though.
    – tripleee
    Nov 19 at 8:44










  • ok I have add the full traceback, I think my way is wrong ,but I don't know how to fix it
    – Z Mario
    Nov 19 at 8:52










  • Unfortunately, that doesn't look like a full traceback. Also str(nodes[0]) in the traceback doesn't seem to correspond to anything in your question. You should probably review the guidance for how to create a Minimal, Complete, and Verifiable example.
    – tripleee
    Nov 19 at 8:53















up vote
0
down vote

favorite









up vote
0
down vote

favorite











My data format is:
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2],...}
Each element in datas is a sentence ,and each number is a word.I want to get the TFIDF value for each number. How to do it with sklearn or other ways?



My code:



from sklearn.feature_extraction.text import TfidfTransformer  
from sklearn.feature_extraction.text import CountVectorizer
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2]}
vectorizer=CountVectorizer()

transformer = TfidfTransformer()
tfidf = transformer.fit_transform(vectorizer.fit_transform(datas))
print(tfidf)


My code doesn't work.Error:



Traceback (most recent call last):   File
"C:/Users/zhuowei/Desktop/OpenNE-master/OpenNE-
master/src/openne/buildTree.py", line 103, in <module>
X = vectorizer.fit_transform(datas) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 869, in fit_transform
self.fixed_vocabulary_) File "C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 792, in _count_vocab
for feature in analyze(doc): File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 266, in <lambda>
tokenize(preprocess(self.decode(doc))), stop_words) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 232, in <lambda>
return lambda x: strip_accents(x.lower())
AttributeError: 'int' object has no attribute 'lower'









share|improve this question















My data format is:
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2],...}
Each element in datas is a sentence ,and each number is a word.I want to get the TFIDF value for each number. How to do it with sklearn or other ways?



My code:



from sklearn.feature_extraction.text import TfidfTransformer  
from sklearn.feature_extraction.text import CountVectorizer
datas = {[1,2,4,6,7],[2,3],[5,6,8,3,5],[2],[93,23,4,5,11,3,5,2]}
vectorizer=CountVectorizer()

transformer = TfidfTransformer()
tfidf = transformer.fit_transform(vectorizer.fit_transform(datas))
print(tfidf)


My code doesn't work.Error:



Traceback (most recent call last):   File
"C:/Users/zhuowei/Desktop/OpenNE-master/OpenNE-
master/src/openne/buildTree.py", line 103, in <module>
X = vectorizer.fit_transform(datas) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 869, in fit_transform
self.fixed_vocabulary_) File "C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 792, in _count_vocab
for feature in analyze(doc): File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 266, in <lambda>
tokenize(preprocess(self.decode(doc))), stop_words) File
"C:UserszhuoweiAnaconda3libsite-
packagessklearnfeature_extractiontext.py", line 232, in <lambda>
return lambda x: strip_accents(x.lower())
AttributeError: 'int' object has no attribute 'lower'






python-3.x scikit-learn nlp tf-idf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 at 9:01

























asked Nov 19 at 8:20









Z Mario

246




246












  • What did you search for in order to solve this, and what did you find? What did you try, and why didn't it work?
    – tripleee
    Nov 19 at 8:33










  • I have put my code above
    – Z Mario
    Nov 19 at 8:43










  • Thanks for the code. Please include the full traceback still, though.
    – tripleee
    Nov 19 at 8:44










  • ok I have add the full traceback, I think my way is wrong ,but I don't know how to fix it
    – Z Mario
    Nov 19 at 8:52










  • Unfortunately, that doesn't look like a full traceback. Also str(nodes[0]) in the traceback doesn't seem to correspond to anything in your question. You should probably review the guidance for how to create a Minimal, Complete, and Verifiable example.
    – tripleee
    Nov 19 at 8:53




















  • What did you search for in order to solve this, and what did you find? What did you try, and why didn't it work?
    – tripleee
    Nov 19 at 8:33










  • I have put my code above
    – Z Mario
    Nov 19 at 8:43










  • Thanks for the code. Please include the full traceback still, though.
    – tripleee
    Nov 19 at 8:44










  • ok I have add the full traceback, I think my way is wrong ,but I don't know how to fix it
    – Z Mario
    Nov 19 at 8:52










  • Unfortunately, that doesn't look like a full traceback. Also str(nodes[0]) in the traceback doesn't seem to correspond to anything in your question. You should probably review the guidance for how to create a Minimal, Complete, and Verifiable example.
    – tripleee
    Nov 19 at 8:53


















What did you search for in order to solve this, and what did you find? What did you try, and why didn't it work?
– tripleee
Nov 19 at 8:33




What did you search for in order to solve this, and what did you find? What did you try, and why didn't it work?
– tripleee
Nov 19 at 8:33












I have put my code above
– Z Mario
Nov 19 at 8:43




I have put my code above
– Z Mario
Nov 19 at 8:43












Thanks for the code. Please include the full traceback still, though.
– tripleee
Nov 19 at 8:44




Thanks for the code. Please include the full traceback still, though.
– tripleee
Nov 19 at 8:44












ok I have add the full traceback, I think my way is wrong ,but I don't know how to fix it
– Z Mario
Nov 19 at 8:52




ok I have add the full traceback, I think my way is wrong ,but I don't know how to fix it
– Z Mario
Nov 19 at 8:52












Unfortunately, that doesn't look like a full traceback. Also str(nodes[0]) in the traceback doesn't seem to correspond to anything in your question. You should probably review the guidance for how to create a Minimal, Complete, and Verifiable example.
– tripleee
Nov 19 at 8:53






Unfortunately, that doesn't look like a full traceback. Also str(nodes[0]) in the traceback doesn't seem to correspond to anything in your question. You should probably review the guidance for how to create a Minimal, Complete, and Verifiable example.
– tripleee
Nov 19 at 8:53














2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










You are using CountVectorizer which requires an iterable of strings. Something like:



datas = ['First sentence', 
'Second sentence', ...
...
'Yet another sentence']


But your data is a list of lists, which is why the error occurs. You need to make the inner lists as strings for the CountVectorizer to work. You can do this:



datas = [' '.join(map(str, x)) for x in datas]


This will result in datas like this:



['1 2 4 6 7', '2 3', '5 6 8 3 5', '2', '93 23 4 5 11 3 5 2']


Now this form is consumable by CountVectorizer. But even then you will not get proper results, because of the default token_pattern in CountVectorizer:




token_pattern : ’(?u)bww+b’



string Regular expression denoting what constitutes a
“token”, only used if analyzer == 'word'. The default regexp select
tokens of 2 or more alphanumeric characters (punctuation is completely
ignored and always treated as a token separator)




In order for it to consider your numbers as words, you will need to change it so that it can accept single letters as words by doing this:



vectorizer = CountVectorizer(token_pattern=r"(?u)bw+b")


Then it should work. But now your numbers are changed into strings






share|improve this answer























  • It worked ,thank you very much
    – Z Mario
    Nov 19 at 12:31


















up vote
-1
down vote













Using our term frequency matrix, the idf weight for can be calculated like below.



# idf
( idf <- log( ncol(tf) / ( 1 + rowSums(tf != 0) ) ) )


Now that we have our matrix with the term frequency and the idf weight, we’re ready to calculate the full tf-idf weight. To do this matrix multiplication, we will also have to transform the idf vector into a diagonal matrix. Both calculations are shown below.



# diagonal matrix
( idf <- diag(idf) )

tf_idf <- crossprod(tf, idf)
colnames(tf_idf) <- rownames(tf)
tf_idf


For each vector v→, you divide it by its norm (length, magnitude). Calculation as below



# Note that normalization is computed "row-wise"
tf_idf / sqrt( rowSums( tf_idf^2 ) )





share|improve this answer























  • This doesn't look like Python at all.
    – tripleee
    Nov 19 at 8:32










  • but how to build frequency matrix ?
    – Z Mario
    Nov 19 at 8:47










  • Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
    – Amal Dominic
    Nov 19 at 9:15













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










You are using CountVectorizer which requires an iterable of strings. Something like:



datas = ['First sentence', 
'Second sentence', ...
...
'Yet another sentence']


But your data is a list of lists, which is why the error occurs. You need to make the inner lists as strings for the CountVectorizer to work. You can do this:



datas = [' '.join(map(str, x)) for x in datas]


This will result in datas like this:



['1 2 4 6 7', '2 3', '5 6 8 3 5', '2', '93 23 4 5 11 3 5 2']


Now this form is consumable by CountVectorizer. But even then you will not get proper results, because of the default token_pattern in CountVectorizer:




token_pattern : ’(?u)bww+b’



string Regular expression denoting what constitutes a
“token”, only used if analyzer == 'word'. The default regexp select
tokens of 2 or more alphanumeric characters (punctuation is completely
ignored and always treated as a token separator)




In order for it to consider your numbers as words, you will need to change it so that it can accept single letters as words by doing this:



vectorizer = CountVectorizer(token_pattern=r"(?u)bw+b")


Then it should work. But now your numbers are changed into strings






share|improve this answer























  • It worked ,thank you very much
    – Z Mario
    Nov 19 at 12:31















up vote
3
down vote



accepted










You are using CountVectorizer which requires an iterable of strings. Something like:



datas = ['First sentence', 
'Second sentence', ...
...
'Yet another sentence']


But your data is a list of lists, which is why the error occurs. You need to make the inner lists as strings for the CountVectorizer to work. You can do this:



datas = [' '.join(map(str, x)) for x in datas]


This will result in datas like this:



['1 2 4 6 7', '2 3', '5 6 8 3 5', '2', '93 23 4 5 11 3 5 2']


Now this form is consumable by CountVectorizer. But even then you will not get proper results, because of the default token_pattern in CountVectorizer:




token_pattern : ’(?u)bww+b’



string Regular expression denoting what constitutes a
“token”, only used if analyzer == 'word'. The default regexp select
tokens of 2 or more alphanumeric characters (punctuation is completely
ignored and always treated as a token separator)




In order for it to consider your numbers as words, you will need to change it so that it can accept single letters as words by doing this:



vectorizer = CountVectorizer(token_pattern=r"(?u)bw+b")


Then it should work. But now your numbers are changed into strings






share|improve this answer























  • It worked ,thank you very much
    – Z Mario
    Nov 19 at 12:31













up vote
3
down vote



accepted







up vote
3
down vote



accepted






You are using CountVectorizer which requires an iterable of strings. Something like:



datas = ['First sentence', 
'Second sentence', ...
...
'Yet another sentence']


But your data is a list of lists, which is why the error occurs. You need to make the inner lists as strings for the CountVectorizer to work. You can do this:



datas = [' '.join(map(str, x)) for x in datas]


This will result in datas like this:



['1 2 4 6 7', '2 3', '5 6 8 3 5', '2', '93 23 4 5 11 3 5 2']


Now this form is consumable by CountVectorizer. But even then you will not get proper results, because of the default token_pattern in CountVectorizer:




token_pattern : ’(?u)bww+b’



string Regular expression denoting what constitutes a
“token”, only used if analyzer == 'word'. The default regexp select
tokens of 2 or more alphanumeric characters (punctuation is completely
ignored and always treated as a token separator)




In order for it to consider your numbers as words, you will need to change it so that it can accept single letters as words by doing this:



vectorizer = CountVectorizer(token_pattern=r"(?u)bw+b")


Then it should work. But now your numbers are changed into strings






share|improve this answer














You are using CountVectorizer which requires an iterable of strings. Something like:



datas = ['First sentence', 
'Second sentence', ...
...
'Yet another sentence']


But your data is a list of lists, which is why the error occurs. You need to make the inner lists as strings for the CountVectorizer to work. You can do this:



datas = [' '.join(map(str, x)) for x in datas]


This will result in datas like this:



['1 2 4 6 7', '2 3', '5 6 8 3 5', '2', '93 23 4 5 11 3 5 2']


Now this form is consumable by CountVectorizer. But even then you will not get proper results, because of the default token_pattern in CountVectorizer:




token_pattern : ’(?u)bww+b’



string Regular expression denoting what constitutes a
“token”, only used if analyzer == 'word'. The default regexp select
tokens of 2 or more alphanumeric characters (punctuation is completely
ignored and always treated as a token separator)




In order for it to consider your numbers as words, you will need to change it so that it can accept single letters as words by doing this:



vectorizer = CountVectorizer(token_pattern=r"(?u)bw+b")


Then it should work. But now your numbers are changed into strings







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 at 9:13

























answered Nov 19 at 9:04









Vivek Kumar

14.2k41849




14.2k41849












  • It worked ,thank you very much
    – Z Mario
    Nov 19 at 12:31


















  • It worked ,thank you very much
    – Z Mario
    Nov 19 at 12:31
















It worked ,thank you very much
– Z Mario
Nov 19 at 12:31




It worked ,thank you very much
– Z Mario
Nov 19 at 12:31












up vote
-1
down vote













Using our term frequency matrix, the idf weight for can be calculated like below.



# idf
( idf <- log( ncol(tf) / ( 1 + rowSums(tf != 0) ) ) )


Now that we have our matrix with the term frequency and the idf weight, we’re ready to calculate the full tf-idf weight. To do this matrix multiplication, we will also have to transform the idf vector into a diagonal matrix. Both calculations are shown below.



# diagonal matrix
( idf <- diag(idf) )

tf_idf <- crossprod(tf, idf)
colnames(tf_idf) <- rownames(tf)
tf_idf


For each vector v→, you divide it by its norm (length, magnitude). Calculation as below



# Note that normalization is computed "row-wise"
tf_idf / sqrt( rowSums( tf_idf^2 ) )





share|improve this answer























  • This doesn't look like Python at all.
    – tripleee
    Nov 19 at 8:32










  • but how to build frequency matrix ?
    – Z Mario
    Nov 19 at 8:47










  • Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
    – Amal Dominic
    Nov 19 at 9:15

















up vote
-1
down vote













Using our term frequency matrix, the idf weight for can be calculated like below.



# idf
( idf <- log( ncol(tf) / ( 1 + rowSums(tf != 0) ) ) )


Now that we have our matrix with the term frequency and the idf weight, we’re ready to calculate the full tf-idf weight. To do this matrix multiplication, we will also have to transform the idf vector into a diagonal matrix. Both calculations are shown below.



# diagonal matrix
( idf <- diag(idf) )

tf_idf <- crossprod(tf, idf)
colnames(tf_idf) <- rownames(tf)
tf_idf


For each vector v→, you divide it by its norm (length, magnitude). Calculation as below



# Note that normalization is computed "row-wise"
tf_idf / sqrt( rowSums( tf_idf^2 ) )





share|improve this answer























  • This doesn't look like Python at all.
    – tripleee
    Nov 19 at 8:32










  • but how to build frequency matrix ?
    – Z Mario
    Nov 19 at 8:47










  • Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
    – Amal Dominic
    Nov 19 at 9:15















up vote
-1
down vote










up vote
-1
down vote









Using our term frequency matrix, the idf weight for can be calculated like below.



# idf
( idf <- log( ncol(tf) / ( 1 + rowSums(tf != 0) ) ) )


Now that we have our matrix with the term frequency and the idf weight, we’re ready to calculate the full tf-idf weight. To do this matrix multiplication, we will also have to transform the idf vector into a diagonal matrix. Both calculations are shown below.



# diagonal matrix
( idf <- diag(idf) )

tf_idf <- crossprod(tf, idf)
colnames(tf_idf) <- rownames(tf)
tf_idf


For each vector v→, you divide it by its norm (length, magnitude). Calculation as below



# Note that normalization is computed "row-wise"
tf_idf / sqrt( rowSums( tf_idf^2 ) )





share|improve this answer














Using our term frequency matrix, the idf weight for can be calculated like below.



# idf
( idf <- log( ncol(tf) / ( 1 + rowSums(tf != 0) ) ) )


Now that we have our matrix with the term frequency and the idf weight, we’re ready to calculate the full tf-idf weight. To do this matrix multiplication, we will also have to transform the idf vector into a diagonal matrix. Both calculations are shown below.



# diagonal matrix
( idf <- diag(idf) )

tf_idf <- crossprod(tf, idf)
colnames(tf_idf) <- rownames(tf)
tf_idf


For each vector v→, you divide it by its norm (length, magnitude). Calculation as below



# Note that normalization is computed "row-wise"
tf_idf / sqrt( rowSums( tf_idf^2 ) )






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 at 8:31









tripleee

87.1k12122177




87.1k12122177










answered Nov 19 at 8:25









Amal Dominic

12




12












  • This doesn't look like Python at all.
    – tripleee
    Nov 19 at 8:32










  • but how to build frequency matrix ?
    – Z Mario
    Nov 19 at 8:47










  • Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
    – Amal Dominic
    Nov 19 at 9:15




















  • This doesn't look like Python at all.
    – tripleee
    Nov 19 at 8:32










  • but how to build frequency matrix ?
    – Z Mario
    Nov 19 at 8:47










  • Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
    – Amal Dominic
    Nov 19 at 9:15


















This doesn't look like Python at all.
– tripleee
Nov 19 at 8:32




This doesn't look like Python at all.
– tripleee
Nov 19 at 8:32












but how to build frequency matrix ?
– Z Mario
Nov 19 at 8:47




but how to build frequency matrix ?
– Z Mario
Nov 19 at 8:47












Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
– Amal Dominic
Nov 19 at 9:15






Case of "R" stackoverflow.com/questions/43357603/… Case of Python stackoverflow.com/questions/41300583/…
– Amal Dominic
Nov 19 at 9:15




















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