What problems might you encounter if you use a block size much greater than AES?











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What problems might you encounter if you use a block size much greater than AES (1000 bits, say)?










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  • Are there any such Cryptographic algorithm? If you have a secure one 1) Small messages will be very big. 2) key size will be big. 3) big,big big
    – kelalaka
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What problems might you encounter if you use a block size much greater than AES (1000 bits, say)?










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  • Are there any such Cryptographic algorithm? If you have a secure one 1) Small messages will be very big. 2) key size will be big. 3) big,big big
    – kelalaka
    4 hours ago













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What problems might you encounter if you use a block size much greater than AES (1000 bits, say)?










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What problems might you encounter if you use a block size much greater than AES (1000 bits, say)?







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  • Are there any such Cryptographic algorithm? If you have a secure one 1) Small messages will be very big. 2) key size will be big. 3) big,big big
    – kelalaka
    4 hours ago


















  • Are there any such Cryptographic algorithm? If you have a secure one 1) Small messages will be very big. 2) key size will be big. 3) big,big big
    – kelalaka
    4 hours ago
















Are there any such Cryptographic algorithm? If you have a secure one 1) Small messages will be very big. 2) key size will be big. 3) big,big big
– kelalaka
4 hours ago




Are there any such Cryptographic algorithm? If you have a secure one 1) Small messages will be very big. 2) key size will be big. 3) big,big big
– kelalaka
4 hours ago










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It may be very tricky to have a good distribution / diffusion of the input bits for each round. That would mean that you would either require a very intricate design for each round, or a lot of rounds to make up for it.





Furthermore it will also mean that you need to perform an operation of at least 1000 bits to perform any kind of calculation. This is not a desirable property in most circumstances. For some modes of operation such as CBC, it will mean that the minimum message size would be 1000 bits - and the IV would take up another 1000 bits. For counter (CTR) mode your message will not grow as only part of the output can be used. However, that still means doing 1000 bit calculations for possibly much smaller messages.



Most modes of operation function quite well for block sizes of 128 bits, although 256 bits would be beneficial for modes such as CTR (because the IV is split between a nonce and the counter).





Although a large block size is desirable for use in the design of hash functions, the avalanche effect does require a good diffusion of bits. Threefish - the block cipher used for Skein, one of the SHA-3 finalists - however does support a block size of 1024 bits, so ~1000 bits is certainly not unheard of (quite often the internal hash state is at least double the intermediate / output size). Skein 512 however requires 80 (!) rounds of Threefish1024 so it certainly wasn't the fastest algorithm out there.





A relatively fast large block cipher may also be beneficial for some format preserving encryption, by the way. In principle a single block encrypt of a unique value is secure, so having a large block size may be helpful avoid repetition of blocks. You could build a cipher with a larger block size from a block cipher with a small block size, but those kind of constructs are generally not all that efficient.






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    1 Answer
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    1 Answer
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    It may be very tricky to have a good distribution / diffusion of the input bits for each round. That would mean that you would either require a very intricate design for each round, or a lot of rounds to make up for it.





    Furthermore it will also mean that you need to perform an operation of at least 1000 bits to perform any kind of calculation. This is not a desirable property in most circumstances. For some modes of operation such as CBC, it will mean that the minimum message size would be 1000 bits - and the IV would take up another 1000 bits. For counter (CTR) mode your message will not grow as only part of the output can be used. However, that still means doing 1000 bit calculations for possibly much smaller messages.



    Most modes of operation function quite well for block sizes of 128 bits, although 256 bits would be beneficial for modes such as CTR (because the IV is split between a nonce and the counter).





    Although a large block size is desirable for use in the design of hash functions, the avalanche effect does require a good diffusion of bits. Threefish - the block cipher used for Skein, one of the SHA-3 finalists - however does support a block size of 1024 bits, so ~1000 bits is certainly not unheard of (quite often the internal hash state is at least double the intermediate / output size). Skein 512 however requires 80 (!) rounds of Threefish1024 so it certainly wasn't the fastest algorithm out there.





    A relatively fast large block cipher may also be beneficial for some format preserving encryption, by the way. In principle a single block encrypt of a unique value is secure, so having a large block size may be helpful avoid repetition of blocks. You could build a cipher with a larger block size from a block cipher with a small block size, but those kind of constructs are generally not all that efficient.






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      up vote
      2
      down vote













      It may be very tricky to have a good distribution / diffusion of the input bits for each round. That would mean that you would either require a very intricate design for each round, or a lot of rounds to make up for it.





      Furthermore it will also mean that you need to perform an operation of at least 1000 bits to perform any kind of calculation. This is not a desirable property in most circumstances. For some modes of operation such as CBC, it will mean that the minimum message size would be 1000 bits - and the IV would take up another 1000 bits. For counter (CTR) mode your message will not grow as only part of the output can be used. However, that still means doing 1000 bit calculations for possibly much smaller messages.



      Most modes of operation function quite well for block sizes of 128 bits, although 256 bits would be beneficial for modes such as CTR (because the IV is split between a nonce and the counter).





      Although a large block size is desirable for use in the design of hash functions, the avalanche effect does require a good diffusion of bits. Threefish - the block cipher used for Skein, one of the SHA-3 finalists - however does support a block size of 1024 bits, so ~1000 bits is certainly not unheard of (quite often the internal hash state is at least double the intermediate / output size). Skein 512 however requires 80 (!) rounds of Threefish1024 so it certainly wasn't the fastest algorithm out there.





      A relatively fast large block cipher may also be beneficial for some format preserving encryption, by the way. In principle a single block encrypt of a unique value is secure, so having a large block size may be helpful avoid repetition of blocks. You could build a cipher with a larger block size from a block cipher with a small block size, but those kind of constructs are generally not all that efficient.






      share|improve this answer

























        up vote
        2
        down vote










        up vote
        2
        down vote









        It may be very tricky to have a good distribution / diffusion of the input bits for each round. That would mean that you would either require a very intricate design for each round, or a lot of rounds to make up for it.





        Furthermore it will also mean that you need to perform an operation of at least 1000 bits to perform any kind of calculation. This is not a desirable property in most circumstances. For some modes of operation such as CBC, it will mean that the minimum message size would be 1000 bits - and the IV would take up another 1000 bits. For counter (CTR) mode your message will not grow as only part of the output can be used. However, that still means doing 1000 bit calculations for possibly much smaller messages.



        Most modes of operation function quite well for block sizes of 128 bits, although 256 bits would be beneficial for modes such as CTR (because the IV is split between a nonce and the counter).





        Although a large block size is desirable for use in the design of hash functions, the avalanche effect does require a good diffusion of bits. Threefish - the block cipher used for Skein, one of the SHA-3 finalists - however does support a block size of 1024 bits, so ~1000 bits is certainly not unheard of (quite often the internal hash state is at least double the intermediate / output size). Skein 512 however requires 80 (!) rounds of Threefish1024 so it certainly wasn't the fastest algorithm out there.





        A relatively fast large block cipher may also be beneficial for some format preserving encryption, by the way. In principle a single block encrypt of a unique value is secure, so having a large block size may be helpful avoid repetition of blocks. You could build a cipher with a larger block size from a block cipher with a small block size, but those kind of constructs are generally not all that efficient.






        share|improve this answer














        It may be very tricky to have a good distribution / diffusion of the input bits for each round. That would mean that you would either require a very intricate design for each round, or a lot of rounds to make up for it.





        Furthermore it will also mean that you need to perform an operation of at least 1000 bits to perform any kind of calculation. This is not a desirable property in most circumstances. For some modes of operation such as CBC, it will mean that the minimum message size would be 1000 bits - and the IV would take up another 1000 bits. For counter (CTR) mode your message will not grow as only part of the output can be used. However, that still means doing 1000 bit calculations for possibly much smaller messages.



        Most modes of operation function quite well for block sizes of 128 bits, although 256 bits would be beneficial for modes such as CTR (because the IV is split between a nonce and the counter).





        Although a large block size is desirable for use in the design of hash functions, the avalanche effect does require a good diffusion of bits. Threefish - the block cipher used for Skein, one of the SHA-3 finalists - however does support a block size of 1024 bits, so ~1000 bits is certainly not unheard of (quite often the internal hash state is at least double the intermediate / output size). Skein 512 however requires 80 (!) rounds of Threefish1024 so it certainly wasn't the fastest algorithm out there.





        A relatively fast large block cipher may also be beneficial for some format preserving encryption, by the way. In principle a single block encrypt of a unique value is secure, so having a large block size may be helpful avoid repetition of blocks. You could build a cipher with a larger block size from a block cipher with a small block size, but those kind of constructs are generally not all that efficient.







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        edited 4 hours ago

























        answered 4 hours ago









        Maarten Bodewes

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