Auto-Arima creates a straight line help
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I'm trying to create a forecast using autoarima with some data, but i always get a straight-line, can someone please help me? :)
This is what i've got so far
install.packages("forecast")
install.packages("scales")
library(forecast)
datos <-read.csv("C:/Users/sarit/Documents/SÉPTIMO CUATRI/iieg/dator.csv",header=T)
monto=datos$monto.XVI
montots<-ts(monto)
montots<-ts(monto,frequency = 12,start = c(2007,1), end = c(2018,8))
montots
plot(montots)
auto.arima(montots)
fit=arima(montots,order=c(0,1,0))
a=forecast(fit,h=5)
plot(forecast(fit,h=5))
So basically, with the autoarima function i get (0,1,0), and when i plot the forecast i get a straight line like this:
my data looks like this
thank you
r time-series forecasting arima prediction
add a comment |
up vote
2
down vote
favorite
I'm trying to create a forecast using autoarima with some data, but i always get a straight-line, can someone please help me? :)
This is what i've got so far
install.packages("forecast")
install.packages("scales")
library(forecast)
datos <-read.csv("C:/Users/sarit/Documents/SÉPTIMO CUATRI/iieg/dator.csv",header=T)
monto=datos$monto.XVI
montots<-ts(monto)
montots<-ts(monto,frequency = 12,start = c(2007,1), end = c(2018,8))
montots
plot(montots)
auto.arima(montots)
fit=arima(montots,order=c(0,1,0))
a=forecast(fit,h=5)
plot(forecast(fit,h=5))
So basically, with the autoarima function i get (0,1,0), and when i plot the forecast i get a straight line like this:
my data looks like this
thank you
r time-series forecasting arima prediction
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I'm trying to create a forecast using autoarima with some data, but i always get a straight-line, can someone please help me? :)
This is what i've got so far
install.packages("forecast")
install.packages("scales")
library(forecast)
datos <-read.csv("C:/Users/sarit/Documents/SÉPTIMO CUATRI/iieg/dator.csv",header=T)
monto=datos$monto.XVI
montots<-ts(monto)
montots<-ts(monto,frequency = 12,start = c(2007,1), end = c(2018,8))
montots
plot(montots)
auto.arima(montots)
fit=arima(montots,order=c(0,1,0))
a=forecast(fit,h=5)
plot(forecast(fit,h=5))
So basically, with the autoarima function i get (0,1,0), and when i plot the forecast i get a straight line like this:
my data looks like this
thank you
r time-series forecasting arima prediction
I'm trying to create a forecast using autoarima with some data, but i always get a straight-line, can someone please help me? :)
This is what i've got so far
install.packages("forecast")
install.packages("scales")
library(forecast)
datos <-read.csv("C:/Users/sarit/Documents/SÉPTIMO CUATRI/iieg/dator.csv",header=T)
monto=datos$monto.XVI
montots<-ts(monto)
montots<-ts(monto,frequency = 12,start = c(2007,1), end = c(2018,8))
montots
plot(montots)
auto.arima(montots)
fit=arima(montots,order=c(0,1,0))
a=forecast(fit,h=5)
plot(forecast(fit,h=5))
So basically, with the autoarima function i get (0,1,0), and when i plot the forecast i get a straight line like this:
my data looks like this
thank you
r time-series forecasting arima prediction
r time-series forecasting arima prediction
asked Nov 19 at 6:37
sarah lopez
132
132
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
6
down vote
accepted
Note first of all that your plot does not come from a call to auto.arima()
, but from one to arima()
. There is a difference.
By supplying order=c(0,1,0)
to arima()
, you tell it to fit a model of the following type:
$$ y_t-y_{t-1} = epsilon_t, $$
or
$$ y_t=y_{t-1} + epsilon_t. $$
That is, you believe that the increments over the last observation follow a normal distribution, $epsilon_tsim N(0,sigma^2)$.
For your point forecast, forecast()
will use the expected value for $epsilon_t$. Which is zero. So your next forecast is simply the last observation:
$$ hat{y}_t=y_{t-1}. $$
And this is iterated. You end up with a flat line.
Try actually fitting using auto.arima()
. However, your time series does not exhibit any obvious structure, like trend or seasonality. (Autoregressive or moving average behavior are harder to spot by eye.) In such a situation, a flat line may well be the best forecast: Is it unusual for the MEAN to outperform ARIMA?
You may be interested in the excellent free online book Forecasting: Principles and Practice (2nd ed.) by Athanasopoulos & Hyndman.
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
accepted
Note first of all that your plot does not come from a call to auto.arima()
, but from one to arima()
. There is a difference.
By supplying order=c(0,1,0)
to arima()
, you tell it to fit a model of the following type:
$$ y_t-y_{t-1} = epsilon_t, $$
or
$$ y_t=y_{t-1} + epsilon_t. $$
That is, you believe that the increments over the last observation follow a normal distribution, $epsilon_tsim N(0,sigma^2)$.
For your point forecast, forecast()
will use the expected value for $epsilon_t$. Which is zero. So your next forecast is simply the last observation:
$$ hat{y}_t=y_{t-1}. $$
And this is iterated. You end up with a flat line.
Try actually fitting using auto.arima()
. However, your time series does not exhibit any obvious structure, like trend or seasonality. (Autoregressive or moving average behavior are harder to spot by eye.) In such a situation, a flat line may well be the best forecast: Is it unusual for the MEAN to outperform ARIMA?
You may be interested in the excellent free online book Forecasting: Principles and Practice (2nd ed.) by Athanasopoulos & Hyndman.
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
add a comment |
up vote
6
down vote
accepted
Note first of all that your plot does not come from a call to auto.arima()
, but from one to arima()
. There is a difference.
By supplying order=c(0,1,0)
to arima()
, you tell it to fit a model of the following type:
$$ y_t-y_{t-1} = epsilon_t, $$
or
$$ y_t=y_{t-1} + epsilon_t. $$
That is, you believe that the increments over the last observation follow a normal distribution, $epsilon_tsim N(0,sigma^2)$.
For your point forecast, forecast()
will use the expected value for $epsilon_t$. Which is zero. So your next forecast is simply the last observation:
$$ hat{y}_t=y_{t-1}. $$
And this is iterated. You end up with a flat line.
Try actually fitting using auto.arima()
. However, your time series does not exhibit any obvious structure, like trend or seasonality. (Autoregressive or moving average behavior are harder to spot by eye.) In such a situation, a flat line may well be the best forecast: Is it unusual for the MEAN to outperform ARIMA?
You may be interested in the excellent free online book Forecasting: Principles and Practice (2nd ed.) by Athanasopoulos & Hyndman.
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
add a comment |
up vote
6
down vote
accepted
up vote
6
down vote
accepted
Note first of all that your plot does not come from a call to auto.arima()
, but from one to arima()
. There is a difference.
By supplying order=c(0,1,0)
to arima()
, you tell it to fit a model of the following type:
$$ y_t-y_{t-1} = epsilon_t, $$
or
$$ y_t=y_{t-1} + epsilon_t. $$
That is, you believe that the increments over the last observation follow a normal distribution, $epsilon_tsim N(0,sigma^2)$.
For your point forecast, forecast()
will use the expected value for $epsilon_t$. Which is zero. So your next forecast is simply the last observation:
$$ hat{y}_t=y_{t-1}. $$
And this is iterated. You end up with a flat line.
Try actually fitting using auto.arima()
. However, your time series does not exhibit any obvious structure, like trend or seasonality. (Autoregressive or moving average behavior are harder to spot by eye.) In such a situation, a flat line may well be the best forecast: Is it unusual for the MEAN to outperform ARIMA?
You may be interested in the excellent free online book Forecasting: Principles and Practice (2nd ed.) by Athanasopoulos & Hyndman.
Note first of all that your plot does not come from a call to auto.arima()
, but from one to arima()
. There is a difference.
By supplying order=c(0,1,0)
to arima()
, you tell it to fit a model of the following type:
$$ y_t-y_{t-1} = epsilon_t, $$
or
$$ y_t=y_{t-1} + epsilon_t. $$
That is, you believe that the increments over the last observation follow a normal distribution, $epsilon_tsim N(0,sigma^2)$.
For your point forecast, forecast()
will use the expected value for $epsilon_t$. Which is zero. So your next forecast is simply the last observation:
$$ hat{y}_t=y_{t-1}. $$
And this is iterated. You end up with a flat line.
Try actually fitting using auto.arima()
. However, your time series does not exhibit any obvious structure, like trend or seasonality. (Autoregressive or moving average behavior are harder to spot by eye.) In such a situation, a flat line may well be the best forecast: Is it unusual for the MEAN to outperform ARIMA?
You may be interested in the excellent free online book Forecasting: Principles and Practice (2nd ed.) by Athanasopoulos & Hyndman.
answered Nov 19 at 7:08
Stephan Kolassa
43.3k690159
43.3k690159
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
add a comment |
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
Thank you!! I was wondering, would you use another type of function for this kind of data? Because I tried using the auto.arima fitting but still doesn't work
– sarah lopez
Nov 26 at 1:17
add a comment |
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