Getting List of Words Input for Word Search Generator
In this program, this user will have the opportunity to generate their own word search. In the beginning of the program, the user will be shown a menu of instructions in which they can choose between these options:
1. Create a word search
2. Print the word search
3. View solutions to the word search
4. Exit the program
When choosing to create a word search, the user is asked to enter words of their choice, line by line. These words will be stored in a 1-D array.
The user will have to enter a minimum of 20 words, maximum at 260. At every batch of 20 words, the user will be asked if they want to add more words. If the user chooses to add more words, the program will prompt him/her to enter more words until they have reached the max number of words.
If they choose to stop adding more words, the program will jump right into converting the 1-D array to an Array List, and then create the word search, which is where I am having a little problem at.
if (choice == 1) {
System.out.println("Enter words of your choice line-by-line. You can enter a maximum of 260 words (i.e., 10 words per letter)");
System.out.println("");
String wordList = new String[260];
// This for loop will loop around with it`s body the user decides they have added enough words and wish to proceed
for (int i = 0; i < wordList.length; i++) {
wordList[i] = input.nextLine();
if (wordList[i] == wordList[19] || wordList[i] == wordList[39] || wordList[i] == wordList[59] || wordList[i] == wordList[79] || wordList[i] == wordList[99] || wordList[i] == wordList[119]|| wordList[i] == wordList[139]) {
System.out.print("Do you want to keep adding words? Enter Y/N: ");
String answer = input.next().toUpperCase();
if (answer == "Y") {
wordList[i] = input.nextLine();
} if (answer == "N") {
break;
}//end of inner if
}//end of outer if
}//end of for loop
List<String> words = Arrays.asList(wordList);
createWordSearch(words);When the user types in "N," the program is supposed to end the for loop and jump right into the part after }//end of for loop. Ive added 'break;' in order to stop the loop, but instead Im pretty sure it is stopping the entire program from proceeding. When I remove the 'break;' the program keeps prompting me to add more words (basically until there are 260 words added in total).
java javascript beginner array
asked 26 mins ago
Yashvi Shah
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
In this program, this user will have the opportunity to generate their own word search. In the beginning of the program, the user will be shown a menu of instructions in which they can choose between these options:
1. Create a word search
2. Print the word search
3. View solutions to the word search
4. Exit the program
When choosing to create a word search, the user is asked to enter words of their choice, line by line. These words will be stored in a 1-D array.
The user will have to enter a minimum of 20 words, maximum at 260. At every batch of 20 words, the user will be asked if they want to add more words. If the user chooses to add more words, the program will prompt him/her to enter more words until they have reached the max number of words.
If they choose to stop adding more words, the program will jump right into converting the 1-D array to an Array List, and then create the word search, which is where I am having a little problem at.
if (choice == 1) {
System.out.println("Enter words of your choice line-by-line. You can enter a maximum of 260 words (i.e., 10 words per letter)");
System.out.println("");
String wordList = new String[260];
// This for loop will loop around with it`s body the user decides they have added enough words and wish to proceed
for (int i = 0; i < wordList.length; i++) {
wordList[i] = input.nextLine();
if (wordList[i] == wordList[19] || wordList[i] == wordList[39] || wordList[i] == wordList[59] || wordList[i] == wordList[79] || wordList[i] == wordList[99] || wordList[i] == wordList[119]|| wordList[i] == wordList[139]) {
System.out.print("Do you want to keep adding words? Enter Y/N: ");
String answer = input.next().toUpperCase();
if (answer == "Y") {
wordList[i] = input.nextLine();
} if (answer == "N") {
break;
}//end of inner if
}//end of outer if
}//end of for loop
List<String> words = Arrays.asList(wordList);
createWordSearch(words);When the user types in "N," the program is supposed to end the for loop and jump right into the part after }//end of for loop. Ive added 'break;' in order to stop the loop, but instead Im pretty sure it is stopping the entire program from proceeding. When I remove the 'break;' the program keeps prompting me to add more words (basically until there are 260 words added in total).
java javascript beginner array
asked 26 mins ago
Yashvi Shah
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
In this program, this user will have the opportunity to generate their own word search. In the beginning of the program, the user will be shown a menu of instructions in which they can choose between these options:
1. Create a word search
2. Print the word search
3. View solutions to the word search
4. Exit the program
When choosing to create a word search, the user is asked to enter words of their choice, line by line. These words will be stored in a 1-D array.
The user will have to enter a minimum of 20 words, maximum at 260. At every batch of 20 words, the user will be asked if they want to add more words. If the user chooses to add more words, the program will prompt him/her to enter more words until they have reached the max number of words.
If they choose to stop adding more words, the program will jump right into converting the 1-D array to an Array List, and then create the word search, which is where I am having a little problem at.
if (choice == 1) {
System.out.println("Enter words of your choice line-by-line. You can enter a maximum of 260 words (i.e., 10 words per letter)");
System.out.println("");
String wordList = new String[260];
// This for loop will loop around with it`s body the user decides they have added enough words and wish to proceed
for (int i = 0; i < wordList.length; i++) {
wordList[i] = input.nextLine();
if (wordList[i] == wordList[19] || wordList[i] == wordList[39] || wordList[i] == wordList[59] || wordList[i] == wordList[79] || wordList[i] == wordList[99] || wordList[i] == wordList[119]|| wordList[i] == wordList[139]) {
System.out.print("Do you want to keep adding words? Enter Y/N: ");
String answer = input.next().toUpperCase();
if (answer == "Y") {
wordList[i] = input.nextLine();
} if (answer == "N") {
break;
}//end of inner if
}//end of outer if
}//end of for loop
List<String> words = Arrays.asList(wordList);
createWordSearch(words);When the user types in "N," the program is supposed to end the for loop and jump right into the part after }//end of for loop. Ive added 'break;' in order to stop the loop, but instead Im pretty sure it is stopping the entire program from proceeding. When I remove the 'break;' the program keeps prompting me to add more words (basically until there are 260 words added in total).
java javascript beginner array
asked 26 mins ago
Yashvi Shah
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
In this program, this user will have the opportunity to generate their own word search. In the beginning of the program, the user will be shown a menu of instructions in which they can choose between these options:
1. Create a word search
2. Print the word search
3. View solutions to the word search
4. Exit the program
When choosing to create a word search, the user is asked to enter words of their choice, line by line. These words will be stored in a 1-D array.
The user will have to enter a minimum of 20 words, maximum at 260. At every batch of 20 words, the user will be asked if they want to add more words. If the user chooses to add more words, the program will prompt him/her to enter more words until they have reached the max number of words.
If they choose to stop adding more words, the program will jump right into converting the 1-D array to an Array List, and then create the word search, which is where I am having a little problem at.
if (choice == 1) {
System.out.println("Enter words of your choice line-by-line. You can enter a maximum of 260 words (i.e., 10 words per letter)");
System.out.println("");
String wordList = new String[260];
// This for loop will loop around with it`s body the user decides they have added enough words and wish to proceed
for (int i = 0; i < wordList.length; i++) {
wordList[i] = input.nextLine();
if (wordList[i] == wordList[19] || wordList[i] == wordList[39] || wordList[i] == wordList[59] || wordList[i] == wordList[79] || wordList[i] == wordList[99] || wordList[i] == wordList[119]|| wordList[i] == wordList[139]) {
System.out.print("Do you want to keep adding words? Enter Y/N: ");
String answer = input.next().toUpperCase();
if (answer == "Y") {
wordList[i] = input.nextLine();
} if (answer == "N") {
break;
}//end of inner if
}//end of outer if
}//end of for loop
List<String> words = Arrays.asList(wordList);
createWordSearch(words);When the user types in "N," the program is supposed to end the for loop and jump right into the part after }//end of for loop. Ive added 'break;' in order to stop the loop, but instead Im pretty sure it is stopping the entire program from proceeding. When I remove the 'break;' the program keeps prompting me to add more words (basically until there are 260 words added in total).
if (choice == 1) {
System.out.println("Enter words of your choice line-by-line. You can enter a maximum of 260 words (i.e., 10 words per letter)");
System.out.println("");
String wordList = new String[260];
// This for loop will loop around with it`s body the user decides they have added enough words and wish to proceed
for (int i = 0; i < wordList.length; i++) {
wordList[i] = input.nextLine();
if (wordList[i] == wordList[19] || wordList[i] == wordList[39] || wordList[i] == wordList[59] || wordList[i] == wordList[79] || wordList[i] == wordList[99] || wordList[i] == wordList[119]|| wordList[i] == wordList[139]) {
System.out.print("Do you want to keep adding words? Enter Y/N: ");
String answer = input.next().toUpperCase();
if (answer == "Y") {
wordList[i] = input.nextLine();
} if (answer == "N") {
break;
}//end of inner if
}//end of outer if
}//end of for loop
List<String> words = Arrays.asList(wordList);
createWordSearch(words);if (choice == 1) {
System.out.println("Enter words of your choice line-by-line. You can enter a maximum of 260 words (i.e., 10 words per letter)");
System.out.println("");
String wordList = new String[260];
// This for loop will loop around with it`s body the user decides they have added enough words and wish to proceed
for (int i = 0; i < wordList.length; i++) {
wordList[i] = input.nextLine();
if (wordList[i] == wordList[19] || wordList[i] == wordList[39] || wordList[i] == wordList[59] || wordList[i] == wordList[79] || wordList[i] == wordList[99] || wordList[i] == wordList[119]|| wordList[i] == wordList[139]) {
System.out.print("Do you want to keep adding words? Enter Y/N: ");
String answer = input.next().toUpperCase();
if (answer == "Y") {
wordList[i] = input.nextLine();
} if (answer == "N") {
break;
}//end of inner if
}//end of outer if
}//end of for loop
List<String> words = Arrays.asList(wordList);
createWordSearch(words);java javascript beginner array
java javascript beginner array
asked 26 mins ago
Yashvi Shah
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 26 mins ago
Yashvi Shah
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 26 mins ago
Yashvi Shah
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 26 mins ago
Yashvi Shah
11
asked 26 mins ago
Yashvi Shah
11
11
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yashvi Shah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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