Postgresql: Extract text starting from number
I have a table os which contains below data
id name
-- ----
1 windows server 2012 R2
2 windows 2016 SQL
3 Oracle linux 7.5
I need to extract 2012 R2 from windows server 2012 R2 and 2016 SQL from windows 2016 SQL and 7.5 from Oracle linux 7.5
I tried below query but it returns only the number like 2012 and 2016 and 7
SELECT name, substring(name FROM '[0-9]+') FROM os;
For eg How can I extract
2012 R2fromwindows server 2012 R2using
postgresql query?
sql postgresql
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
add a comment |
I have a table os which contains below data
id name
-- ----
1 windows server 2012 R2
2 windows 2016 SQL
3 Oracle linux 7.5
I need to extract 2012 R2 from windows server 2012 R2 and 2016 SQL from windows 2016 SQL and 7.5 from Oracle linux 7.5
I tried below query but it returns only the number like 2012 and 2016 and 7
SELECT name, substring(name FROM '[0-9]+') FROM os;
For eg How can I extract
2012 R2fromwindows server 2012 R2using
postgresql query?
sql postgresql
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
2
What if it has strings like7.5.1or2012 Release 2etc?
– Kaushik Nayak
Nov 22 '18 at 8:01
I need to extract 7.5.1 and 2012 Release 2 as well
– Hemadri Dasari
Nov 22 '18 at 8:16
add a comment |
I have a table os which contains below data
id name
-- ----
1 windows server 2012 R2
2 windows 2016 SQL
3 Oracle linux 7.5
I need to extract 2012 R2 from windows server 2012 R2 and 2016 SQL from windows 2016 SQL and 7.5 from Oracle linux 7.5
I tried below query but it returns only the number like 2012 and 2016 and 7
SELECT name, substring(name FROM '[0-9]+') FROM os;
For eg How can I extract
2012 R2fromwindows server 2012 R2using
postgresql query?
sql postgresql
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
I have a table os which contains below data
id name
-- ----
1 windows server 2012 R2
2 windows 2016 SQL
3 Oracle linux 7.5
I need to extract 2012 R2 from windows server 2012 R2 and 2016 SQL from windows 2016 SQL and 7.5 from Oracle linux 7.5
I tried below query but it returns only the number like 2012 and 2016 and 7
SELECT name, substring(name FROM '[0-9]+') FROM os;
For eg How can I extract
2012 R2fromwindows server 2012 R2using
postgresql query?
sql postgresql
sql postgresql
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
asked Nov 22 '18 at 7:57
Hemadri DasariHemadri Dasari
8,37911440
8,37911440
2
What if it has strings like7.5.1or2012 Release 2etc?
– Kaushik Nayak
Nov 22 '18 at 8:01
I need to extract 7.5.1 and 2012 Release 2 as well
– Hemadri Dasari
Nov 22 '18 at 8:16
add a comment |
2
What if it has strings like7.5.1or2012 Release 2etc?
– Kaushik Nayak
Nov 22 '18 at 8:01
I need to extract 7.5.1 and 2012 Release 2 as well
– Hemadri Dasari
Nov 22 '18 at 8:16
2
2
What if it has strings like
7.5.1 or 2012 Release 2 etc?– Kaushik Nayak
Nov 22 '18 at 8:01
What if it has strings like
7.5.1 or 2012 Release 2 etc?– Kaushik Nayak
Nov 22 '18 at 8:01
I need to extract 7.5.1 and 2012 Release 2 as well
– Hemadri Dasari
Nov 22 '18 at 8:16
I need to extract 7.5.1 and 2012 Release 2 as well
– Hemadri Dasari
Nov 22 '18 at 8:16
add a comment |
1 Answer
1
active
oldest
votes
Please try SELECT name, substring(name FROM '[0-9]+.*') FROM os;
answered Nov 22 '18 at 8:01
IvienIvien
2594
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53426237%2fpostgresql-extract-text-starting-from-number%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Please try SELECT name, substring(name FROM '[0-9]+.*') FROM os;
answered Nov 22 '18 at 8:01
IvienIvien
2594
add a comment |
Please try SELECT name, substring(name FROM '[0-9]+.*') FROM os;
answered Nov 22 '18 at 8:01
IvienIvien
2594
add a comment |
Please try SELECT name, substring(name FROM '[0-9]+.*') FROM os;
answered Nov 22 '18 at 8:01
IvienIvien
2594
Please try SELECT name, substring(name FROM '[0-9]+.*') FROM os;
answered Nov 22 '18 at 8:01
IvienIvien
2594
answered Nov 22 '18 at 8:01
IvienIvien
2594
answered Nov 22 '18 at 8:01
IvienIvien
2594
answered Nov 22 '18 at 8:01
IvienIvien
2594
2594
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53426237%2fpostgresql-extract-text-starting-from-number%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
What if it has strings like
7.5.1or2012 Release 2etc?– Kaushik Nayak
Nov 22 '18 at 8:01
I need to extract 7.5.1 and 2012 Release 2 as well
– Hemadri Dasari
Nov 22 '18 at 8:16