Python code for Krikwood-Buff Integrals
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I am writing a code for the Krikwood-Buff Integrals which has the formula as: https://i.stack.imgur.com/lMtie.png
import os
import numpy as np
import matplotlib
from matplotlib import pyplot as plt
A = np.loadtxt ('abc.dat')
B = open('1.dat','w')
r = A[:,0] #r is the 1st column (ie., x-axis values)
g = A[:,1] #g is the 2nd column (ie., y-axis column)
integrand = (g-1)*(r**2)
for i in range(len(r)):
B.write (str(r[i])+'t'+(str(integrand[i]))+'n')
integral = np.trapz(integrand[:-1],r[:-1])*4*np.pi
print 'The integral in the equation2 is ',str(integral)
But when i run this code, i get an increase in the 1st peak(which is wrong)[],
when compared to the expected result image []
Any suggestions on how to improve this code..??
Thank you.
python
New contributor
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add a comment |
$begingroup$
I am writing a code for the Krikwood-Buff Integrals which has the formula as: https://i.stack.imgur.com/lMtie.png
import os
import numpy as np
import matplotlib
from matplotlib import pyplot as plt
A = np.loadtxt ('abc.dat')
B = open('1.dat','w')
r = A[:,0] #r is the 1st column (ie., x-axis values)
g = A[:,1] #g is the 2nd column (ie., y-axis column)
integrand = (g-1)*(r**2)
for i in range(len(r)):
B.write (str(r[i])+'t'+(str(integrand[i]))+'n')
integral = np.trapz(integrand[:-1],r[:-1])*4*np.pi
print 'The integral in the equation2 is ',str(integral)
But when i run this code, i get an increase in the 1st peak(which is wrong)[],
when compared to the expected result image []
Any suggestions on how to improve this code..??
Thank you.
python
New contributor
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$begingroup$
Welcome to Code Review. Your code must work correctly before we can review it. See the help center.
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– 200_success
6 mins ago
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Yes, my code is working correctly.
$endgroup$
– D.H.N
5 mins ago
$begingroup$
You just said that the results were wrong!
$endgroup$
– 200_success
4 mins ago
$begingroup$
yes, I meant w.r.t the 1st peak.(i should get a small peak, but there is a higher value of the peak.) So how do i optimize it..?? I have written the code according to the equation.
$endgroup$
– D.H.N
2 mins ago
add a comment |
$begingroup$
I am writing a code for the Krikwood-Buff Integrals which has the formula as: https://i.stack.imgur.com/lMtie.png
import os
import numpy as np
import matplotlib
from matplotlib import pyplot as plt
A = np.loadtxt ('abc.dat')
B = open('1.dat','w')
r = A[:,0] #r is the 1st column (ie., x-axis values)
g = A[:,1] #g is the 2nd column (ie., y-axis column)
integrand = (g-1)*(r**2)
for i in range(len(r)):
B.write (str(r[i])+'t'+(str(integrand[i]))+'n')
integral = np.trapz(integrand[:-1],r[:-1])*4*np.pi
print 'The integral in the equation2 is ',str(integral)
But when i run this code, i get an increase in the 1st peak(which is wrong)[],
when compared to the expected result image []
Any suggestions on how to improve this code..??
Thank you.
python
New contributor
$endgroup$
I am writing a code for the Krikwood-Buff Integrals which has the formula as: https://i.stack.imgur.com/lMtie.png
import os
import numpy as np
import matplotlib
from matplotlib import pyplot as plt
A = np.loadtxt ('abc.dat')
B = open('1.dat','w')
r = A[:,0] #r is the 1st column (ie., x-axis values)
g = A[:,1] #g is the 2nd column (ie., y-axis column)
integrand = (g-1)*(r**2)
for i in range(len(r)):
B.write (str(r[i])+'t'+(str(integrand[i]))+'n')
integral = np.trapz(integrand[:-1],r[:-1])*4*np.pi
print 'The integral in the equation2 is ',str(integral)
But when i run this code, i get an increase in the 1st peak(which is wrong)[],
when compared to the expected result image []
Any suggestions on how to improve this code..??
Thank you.
python
python
New contributor
New contributor
edited 6 mins ago
D.H.N
New contributor
asked 10 mins ago
D.H.ND.H.N
11
11
New contributor
New contributor
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Welcome to Code Review. Your code must work correctly before we can review it. See the help center.
$endgroup$
– 200_success
6 mins ago
$begingroup$
Yes, my code is working correctly.
$endgroup$
– D.H.N
5 mins ago
$begingroup$
You just said that the results were wrong!
$endgroup$
– 200_success
4 mins ago
$begingroup$
yes, I meant w.r.t the 1st peak.(i should get a small peak, but there is a higher value of the peak.) So how do i optimize it..?? I have written the code according to the equation.
$endgroup$
– D.H.N
2 mins ago
add a comment |
$begingroup$
Welcome to Code Review. Your code must work correctly before we can review it. See the help center.
$endgroup$
– 200_success
6 mins ago
$begingroup$
Yes, my code is working correctly.
$endgroup$
– D.H.N
5 mins ago
$begingroup$
You just said that the results were wrong!
$endgroup$
– 200_success
4 mins ago
$begingroup$
yes, I meant w.r.t the 1st peak.(i should get a small peak, but there is a higher value of the peak.) So how do i optimize it..?? I have written the code according to the equation.
$endgroup$
– D.H.N
2 mins ago
$begingroup$
Welcome to Code Review. Your code must work correctly before we can review it. See the help center.
$endgroup$
– 200_success
6 mins ago
$begingroup$
Welcome to Code Review. Your code must work correctly before we can review it. See the help center.
$endgroup$
– 200_success
6 mins ago
$begingroup$
Yes, my code is working correctly.
$endgroup$
– D.H.N
5 mins ago
$begingroup$
Yes, my code is working correctly.
$endgroup$
– D.H.N
5 mins ago
$begingroup$
You just said that the results were wrong!
$endgroup$
– 200_success
4 mins ago
$begingroup$
You just said that the results were wrong!
$endgroup$
– 200_success
4 mins ago
$begingroup$
yes, I meant w.r.t the 1st peak.(i should get a small peak, but there is a higher value of the peak.) So how do i optimize it..?? I have written the code according to the equation.
$endgroup$
– D.H.N
2 mins ago
$begingroup$
yes, I meant w.r.t the 1st peak.(i should get a small peak, but there is a higher value of the peak.) So how do i optimize it..?? I have written the code according to the equation.
$endgroup$
– D.H.N
2 mins ago
add a comment |
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$begingroup$
Welcome to Code Review. Your code must work correctly before we can review it. See the help center.
$endgroup$
– 200_success
6 mins ago
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Yes, my code is working correctly.
$endgroup$
– D.H.N
5 mins ago
$begingroup$
You just said that the results were wrong!
$endgroup$
– 200_success
4 mins ago
$begingroup$
yes, I meant w.r.t the 1st peak.(i should get a small peak, but there is a higher value of the peak.) So how do i optimize it..?? I have written the code according to the equation.
$endgroup$
– D.H.N
2 mins ago