Simplifying the use of std::function stored in an std::vector within a class
I have written this basic class to store std::function<T>
within std::vector<T>
and I have two free function templates foo()
and bar()
that both return void
and take a std::vector<T>
as their parameter. Currently they do exactly the same for simplicity sakes; but let's say for future reference they will be doing different calculations or tasks. So far this is what I have come up with:
#include <vector>
#include <functional
#include <iostream>
#include <exception>
template<typename T>
class MyClass {
private:
std::vector<std::function<void(std::vector<T>)>> myFuncs_;
public:
MyClass() = default;
void addFunc( std::function<void(std::vector<T>)> func ) {
myFuncs_.push_back(func);
}
std::function<void(std::vector<T>)> caller(unsigned idx) {
return myFuncs_.at(idx);
}
};
template<typename T>
void foo(std::vector<T> data) {
std::cout << "foo() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
template<typename T>
void bar(std::vector<T> data) {
std::cout << "bar() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
int main() {
try {
MyClass<int> myClass;
std::vector<int> a{ 1,3,5,7,9 };
std::vector<int> b{ 2,4,6,8,10 };
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>, a);
std::function<void(std::vector<int>)> funcB = std::bind(bar<int>, b);
myClass.addFunc( funcA );
myClass.addFunc( funcB );
myClass.caller(0)(a);
myClass.caller(1)(b);
} catch( std::runtime_error& e ) {
std::cerr << e.what() << std::endl;
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
And this sure enough outputs:
foo() called:
1 3 5 7 9
bar() called:
2 4 6 8 10
Here's what I would like to know: is there or are there any way(s) to simplify this code; some of the syntax looks redundant, for example: In the main function after I had instantiated an instance of my class template and created an std::vector
with values, I then create an instance of std::function<T>
using std::bind
with the function I want to then add to my class's vector. Then after binding them and adding them to my class's container, this is where I call the class's function to index the function I want to call using std::functions
's operator()
. However the function is expecting a std::vector<T>
so it appears that I am passing this vector<T>
multiple times as you can see from this part from my code above.
// std::vector<T> being passed to std::bind
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>,a);
myClass.addFunc( funcA );
myClass.caller(0)(a); // Again std::vector<T> being passed but to `std::function`'s operator because the stored function requires this parameter.
Can this be simplified or is this just in the semantics of how std::function
and std::bind
work? If this can be simplified, would it be done within the class itself to make it easier on the user or would it be from the user side?
c++ template c++17
add a comment |
I have written this basic class to store std::function<T>
within std::vector<T>
and I have two free function templates foo()
and bar()
that both return void
and take a std::vector<T>
as their parameter. Currently they do exactly the same for simplicity sakes; but let's say for future reference they will be doing different calculations or tasks. So far this is what I have come up with:
#include <vector>
#include <functional
#include <iostream>
#include <exception>
template<typename T>
class MyClass {
private:
std::vector<std::function<void(std::vector<T>)>> myFuncs_;
public:
MyClass() = default;
void addFunc( std::function<void(std::vector<T>)> func ) {
myFuncs_.push_back(func);
}
std::function<void(std::vector<T>)> caller(unsigned idx) {
return myFuncs_.at(idx);
}
};
template<typename T>
void foo(std::vector<T> data) {
std::cout << "foo() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
template<typename T>
void bar(std::vector<T> data) {
std::cout << "bar() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
int main() {
try {
MyClass<int> myClass;
std::vector<int> a{ 1,3,5,7,9 };
std::vector<int> b{ 2,4,6,8,10 };
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>, a);
std::function<void(std::vector<int>)> funcB = std::bind(bar<int>, b);
myClass.addFunc( funcA );
myClass.addFunc( funcB );
myClass.caller(0)(a);
myClass.caller(1)(b);
} catch( std::runtime_error& e ) {
std::cerr << e.what() << std::endl;
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
And this sure enough outputs:
foo() called:
1 3 5 7 9
bar() called:
2 4 6 8 10
Here's what I would like to know: is there or are there any way(s) to simplify this code; some of the syntax looks redundant, for example: In the main function after I had instantiated an instance of my class template and created an std::vector
with values, I then create an instance of std::function<T>
using std::bind
with the function I want to then add to my class's vector. Then after binding them and adding them to my class's container, this is where I call the class's function to index the function I want to call using std::functions
's operator()
. However the function is expecting a std::vector<T>
so it appears that I am passing this vector<T>
multiple times as you can see from this part from my code above.
// std::vector<T> being passed to std::bind
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>,a);
myClass.addFunc( funcA );
myClass.caller(0)(a); // Again std::vector<T> being passed but to `std::function`'s operator because the stored function requires this parameter.
Can this be simplified or is this just in the semantics of how std::function
and std::bind
work? If this can be simplified, would it be done within the class itself to make it easier on the user or would it be from the user side?
c++ template c++17
add a comment |
I have written this basic class to store std::function<T>
within std::vector<T>
and I have two free function templates foo()
and bar()
that both return void
and take a std::vector<T>
as their parameter. Currently they do exactly the same for simplicity sakes; but let's say for future reference they will be doing different calculations or tasks. So far this is what I have come up with:
#include <vector>
#include <functional
#include <iostream>
#include <exception>
template<typename T>
class MyClass {
private:
std::vector<std::function<void(std::vector<T>)>> myFuncs_;
public:
MyClass() = default;
void addFunc( std::function<void(std::vector<T>)> func ) {
myFuncs_.push_back(func);
}
std::function<void(std::vector<T>)> caller(unsigned idx) {
return myFuncs_.at(idx);
}
};
template<typename T>
void foo(std::vector<T> data) {
std::cout << "foo() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
template<typename T>
void bar(std::vector<T> data) {
std::cout << "bar() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
int main() {
try {
MyClass<int> myClass;
std::vector<int> a{ 1,3,5,7,9 };
std::vector<int> b{ 2,4,6,8,10 };
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>, a);
std::function<void(std::vector<int>)> funcB = std::bind(bar<int>, b);
myClass.addFunc( funcA );
myClass.addFunc( funcB );
myClass.caller(0)(a);
myClass.caller(1)(b);
} catch( std::runtime_error& e ) {
std::cerr << e.what() << std::endl;
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
And this sure enough outputs:
foo() called:
1 3 5 7 9
bar() called:
2 4 6 8 10
Here's what I would like to know: is there or are there any way(s) to simplify this code; some of the syntax looks redundant, for example: In the main function after I had instantiated an instance of my class template and created an std::vector
with values, I then create an instance of std::function<T>
using std::bind
with the function I want to then add to my class's vector. Then after binding them and adding them to my class's container, this is where I call the class's function to index the function I want to call using std::functions
's operator()
. However the function is expecting a std::vector<T>
so it appears that I am passing this vector<T>
multiple times as you can see from this part from my code above.
// std::vector<T> being passed to std::bind
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>,a);
myClass.addFunc( funcA );
myClass.caller(0)(a); // Again std::vector<T> being passed but to `std::function`'s operator because the stored function requires this parameter.
Can this be simplified or is this just in the semantics of how std::function
and std::bind
work? If this can be simplified, would it be done within the class itself to make it easier on the user or would it be from the user side?
c++ template c++17
I have written this basic class to store std::function<T>
within std::vector<T>
and I have two free function templates foo()
and bar()
that both return void
and take a std::vector<T>
as their parameter. Currently they do exactly the same for simplicity sakes; but let's say for future reference they will be doing different calculations or tasks. So far this is what I have come up with:
#include <vector>
#include <functional
#include <iostream>
#include <exception>
template<typename T>
class MyClass {
private:
std::vector<std::function<void(std::vector<T>)>> myFuncs_;
public:
MyClass() = default;
void addFunc( std::function<void(std::vector<T>)> func ) {
myFuncs_.push_back(func);
}
std::function<void(std::vector<T>)> caller(unsigned idx) {
return myFuncs_.at(idx);
}
};
template<typename T>
void foo(std::vector<T> data) {
std::cout << "foo() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
template<typename T>
void bar(std::vector<T> data) {
std::cout << "bar() called:n";
for (auto& d : data)
std::cout << d << " ";
std::cout << 'n';
}
int main() {
try {
MyClass<int> myClass;
std::vector<int> a{ 1,3,5,7,9 };
std::vector<int> b{ 2,4,6,8,10 };
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>, a);
std::function<void(std::vector<int>)> funcB = std::bind(bar<int>, b);
myClass.addFunc( funcA );
myClass.addFunc( funcB );
myClass.caller(0)(a);
myClass.caller(1)(b);
} catch( std::runtime_error& e ) {
std::cerr << e.what() << std::endl;
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
And this sure enough outputs:
foo() called:
1 3 5 7 9
bar() called:
2 4 6 8 10
Here's what I would like to know: is there or are there any way(s) to simplify this code; some of the syntax looks redundant, for example: In the main function after I had instantiated an instance of my class template and created an std::vector
with values, I then create an instance of std::function<T>
using std::bind
with the function I want to then add to my class's vector. Then after binding them and adding them to my class's container, this is where I call the class's function to index the function I want to call using std::functions
's operator()
. However the function is expecting a std::vector<T>
so it appears that I am passing this vector<T>
multiple times as you can see from this part from my code above.
// std::vector<T> being passed to std::bind
std::function<void(std::vector<int>)> funcA = std::bind(foo<int>,a);
myClass.addFunc( funcA );
myClass.caller(0)(a); // Again std::vector<T> being passed but to `std::function`'s operator because the stored function requires this parameter.
Can this be simplified or is this just in the semantics of how std::function
and std::bind
work? If this can be simplified, would it be done within the class itself to make it easier on the user or would it be from the user side?
c++ template c++17
c++ template c++17
asked 4 mins ago
Francis Cugler
25116
25116
add a comment |
add a comment |
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