How to split and keep float numbers together Ruby and Python

I am programming a math expression checker. I have this string:

oper = "((234+3.32)+(cos4-sin65))"

I want to split this string by separating all "()"s and operators minus numbers or trigonometric ratios to get this result:

oper = ['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

How would the split be?

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

add a comment |

I am programming a math expression checker. I have this string:

oper = "((234+3.32)+(cos4-sin65))"

I want to split this string by separating all "()"s and operators minus numbers or trigonometric ratios to get this result:

oper = ['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

How would the split be?

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

add a comment |

I am programming a math expression checker. I have this string:

oper = "((234+3.32)+(cos4-sin65))"

I want to split this string by separating all "()"s and operators minus numbers or trigonometric ratios to get this result:

oper = ['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

How would the split be?

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

I am programming a math expression checker. I have this string:

oper = "((234+3.32)+(cos4-sin65))"

I want to split this string by separating all "()"s and operators minus numbers or trigonometric ratios to get this result:

oper = ['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

How would the split be?

python ruby string split

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

asked Nov 22 '18 at 21:22

Alejandro Rodriguez

133

add a comment |

3 Answers
3

active

oldest

votes

Ruby:

oper = "((234+3.32)+(cos4-sin65))"

re = Regexp.union("(" ,")", "+", "-", /[^()-+]+/)

p oper.scan(re) # => ["(", "(", "234", "+", "3.32", ")", "+", "(", "cos4", "-", "sin65", ")", ")"]

edited Nov 22 '18 at 22:13

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

add a comment |

Here's my example solution.

oper = "((234+3.32)+(cos4-sin65))"

separators = ['(', ')', '+', '-', 'cos', 'sin']



def sep_at_beg(x):

    for separator in separators:

        if len(x) >= len(separator) and x.startswith(separator):

            if separator in ['cos', 'sin']:

                if len(x) > len(separator)+1 and x[len(separator)+1].isdigit():

                    return x[:len(separator)+2]

                return x[:len(separator)+1]

            return separator

    return False



def separate(x):

    return_x = 

    idx = 0

    so_far = ''

    while idx < len(x):

        separator = sep_at_beg(x[idx:])

        if separator:

            if so_far:

                return_x.append(so_far)

            return_x.append(separator)



            so_far = ''

            idx += len(separator)

        else:

            so_far += x[idx]

            idx += 1

    if so_far:

        return_x.append(so_far)

    return return_x



oper = separate(oper)

print(oper)

Outputs:

['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

edited Nov 22 '18 at 22:12

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

add a comment |

There is an easier way, use it:

oper = "((234+3.32)+(cos4-sin65))"

separators=["(",")","+","-"]



def my_split(o, l, j="@"):

    for e in l:

        o = o.replace(e, j+e+j)

    return [e for e in o.split(j) if e]



print(my_split(oper, separators))

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

Ruby:

oper = "((234+3.32)+(cos4-sin65))"

re = Regexp.union("(" ,")", "+", "-", /[^()-+]+/)

p oper.scan(re) # => ["(", "(", "234", "+", "3.32", ")", "+", "(", "cos4", "-", "sin65", ")", ")"]

edited Nov 22 '18 at 22:13

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

add a comment |

Ruby:

oper = "((234+3.32)+(cos4-sin65))"

re = Regexp.union("(" ,")", "+", "-", /[^()-+]+/)

p oper.scan(re) # => ["(", "(", "234", "+", "3.32", ")", "+", "(", "cos4", "-", "sin65", ")", ")"]

edited Nov 22 '18 at 22:13

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

add a comment |

Ruby:

oper = "((234+3.32)+(cos4-sin65))"

re = Regexp.union("(" ,")", "+", "-", /[^()-+]+/)

p oper.scan(re) # => ["(", "(", "234", "+", "3.32", ")", "+", "(", "cos4", "-", "sin65", ")", ")"]

edited Nov 22 '18 at 22:13

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

Ruby:

oper = "((234+3.32)+(cos4-sin65))"

re = Regexp.union("(" ,")", "+", "-", /[^()-+]+/)

p oper.scan(re) # => ["(", "(", "234", "+", "3.32", ")", "+", "(", "cos4", "-", "sin65", ")", ")"]

edited Nov 22 '18 at 22:13

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

edited Nov 22 '18 at 22:13

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

answered Nov 22 '18 at 22:07

steenslag

62.3k11100140

add a comment |

Here's my example solution.

oper = "((234+3.32)+(cos4-sin65))"

separators = ['(', ')', '+', '-', 'cos', 'sin']



def sep_at_beg(x):

    for separator in separators:

        if len(x) >= len(separator) and x.startswith(separator):

            if separator in ['cos', 'sin']:

                if len(x) > len(separator)+1 and x[len(separator)+1].isdigit():

                    return x[:len(separator)+2]

                return x[:len(separator)+1]

            return separator

    return False



def separate(x):

    return_x = 

    idx = 0

    so_far = ''

    while idx < len(x):

        separator = sep_at_beg(x[idx:])

        if separator:

            if so_far:

                return_x.append(so_far)

            return_x.append(separator)



            so_far = ''

            idx += len(separator)

        else:

            so_far += x[idx]

            idx += 1

    if so_far:

        return_x.append(so_far)

    return return_x



oper = separate(oper)

print(oper)

Outputs:

['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

edited Nov 22 '18 at 22:12

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

add a comment |

Here's my example solution.

oper = "((234+3.32)+(cos4-sin65))"

separators = ['(', ')', '+', '-', 'cos', 'sin']



def sep_at_beg(x):

    for separator in separators:

        if len(x) >= len(separator) and x.startswith(separator):

            if separator in ['cos', 'sin']:

                if len(x) > len(separator)+1 and x[len(separator)+1].isdigit():

                    return x[:len(separator)+2]

                return x[:len(separator)+1]

            return separator

    return False



def separate(x):

    return_x = 

    idx = 0

    so_far = ''

    while idx < len(x):

        separator = sep_at_beg(x[idx:])

        if separator:

            if so_far:

                return_x.append(so_far)

            return_x.append(separator)



            so_far = ''

            idx += len(separator)

        else:

            so_far += x[idx]

            idx += 1

    if so_far:

        return_x.append(so_far)

    return return_x



oper = separate(oper)

print(oper)

Outputs:

['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

edited Nov 22 '18 at 22:12

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

add a comment |

Here's my example solution.

oper = "((234+3.32)+(cos4-sin65))"

separators = ['(', ')', '+', '-', 'cos', 'sin']



def sep_at_beg(x):

    for separator in separators:

        if len(x) >= len(separator) and x.startswith(separator):

            if separator in ['cos', 'sin']:

                if len(x) > len(separator)+1 and x[len(separator)+1].isdigit():

                    return x[:len(separator)+2]

                return x[:len(separator)+1]

            return separator

    return False



def separate(x):

    return_x = 

    idx = 0

    so_far = ''

    while idx < len(x):

        separator = sep_at_beg(x[idx:])

        if separator:

            if so_far:

                return_x.append(so_far)

            return_x.append(separator)



            so_far = ''

            idx += len(separator)

        else:

            so_far += x[idx]

            idx += 1

    if so_far:

        return_x.append(so_far)

    return return_x



oper = separate(oper)

print(oper)

Outputs:

['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

edited Nov 22 '18 at 22:12

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

Here's my example solution.

oper = "((234+3.32)+(cos4-sin65))"

separators = ['(', ')', '+', '-', 'cos', 'sin']



def sep_at_beg(x):

    for separator in separators:

        if len(x) >= len(separator) and x.startswith(separator):

            if separator in ['cos', 'sin']:

                if len(x) > len(separator)+1 and x[len(separator)+1].isdigit():

                    return x[:len(separator)+2]

                return x[:len(separator)+1]

            return separator

    return False



def separate(x):

    return_x = 

    idx = 0

    so_far = ''

    while idx < len(x):

        separator = sep_at_beg(x[idx:])

        if separator:

            if so_far:

                return_x.append(so_far)

            return_x.append(separator)



            so_far = ''

            idx += len(separator)

        else:

            so_far += x[idx]

            idx += 1

    if so_far:

        return_x.append(so_far)

    return return_x



oper = separate(oper)

print(oper)

Outputs:

['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

edited Nov 22 '18 at 22:12

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

edited Nov 22 '18 at 22:12

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

answered Nov 22 '18 at 21:36

Filip Młynarski

1,7711413

add a comment |

There is an easier way, use it:

oper = "((234+3.32)+(cos4-sin65))"

separators=["(",")","+","-"]



def my_split(o, l, j="@"):

    for e in l:

        o = o.replace(e, j+e+j)

    return [e for e in o.split(j) if e]



print(my_split(oper, separators))

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

add a comment |

There is an easier way, use it:

oper = "((234+3.32)+(cos4-sin65))"

separators=["(",")","+","-"]



def my_split(o, l, j="@"):

    for e in l:

        o = o.replace(e, j+e+j)

    return [e for e in o.split(j) if e]



print(my_split(oper, separators))

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

add a comment |

There is an easier way, use it:

oper = "((234+3.32)+(cos4-sin65))"

separators=["(",")","+","-"]



def my_split(o, l, j="@"):

    for e in l:

        o = o.replace(e, j+e+j)

    return [e for e in o.split(j) if e]



print(my_split(oper, separators))

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

There is an easier way, use it:

oper = "((234+3.32)+(cos4-sin65))"

separators=["(",")","+","-"]



def my_split(o, l, j="@"):

    for e in l:

        o = o.replace(e, j+e+j)

    return [e for e in o.split(j) if e]



print(my_split(oper, separators))

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

answered Nov 22 '18 at 23:50

Miklos Horvath

192112

add a comment |

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