Significant figures while finding errors












3












$begingroup$


The question which arose my confusion:




Two resistors with resistance $R_1 = 100pm 3 Omega$, and $R_2 = 200pm 4 Omega$ are connected in (a) series, (b) in parallel. Find the equivalent resistance of both combinations.




In the end, my answer came out to be (a) $300pm 7 Omega$ and (b) $66.7pm 2 Omega$. But according to my book, my response for (b) is incorrect.



It said that the equivalent resistance should have an error of $pm 1.8$ not my rounded off answer $pm 2$. And it (book) explicitly states that the error in (b) should be "expressed as $pm 1.8$ to keep in conformity with the rules of significant figures." I don't understand how this makes any sense (especially how it conforms to the rules of significant figures). Help anyone?










share|cite|improve this question









$endgroup$

















    3












    $begingroup$


    The question which arose my confusion:




    Two resistors with resistance $R_1 = 100pm 3 Omega$, and $R_2 = 200pm 4 Omega$ are connected in (a) series, (b) in parallel. Find the equivalent resistance of both combinations.




    In the end, my answer came out to be (a) $300pm 7 Omega$ and (b) $66.7pm 2 Omega$. But according to my book, my response for (b) is incorrect.



    It said that the equivalent resistance should have an error of $pm 1.8$ not my rounded off answer $pm 2$. And it (book) explicitly states that the error in (b) should be "expressed as $pm 1.8$ to keep in conformity with the rules of significant figures." I don't understand how this makes any sense (especially how it conforms to the rules of significant figures). Help anyone?










    share|cite|improve this question









    $endgroup$















      3












      3








      3





      $begingroup$


      The question which arose my confusion:




      Two resistors with resistance $R_1 = 100pm 3 Omega$, and $R_2 = 200pm 4 Omega$ are connected in (a) series, (b) in parallel. Find the equivalent resistance of both combinations.




      In the end, my answer came out to be (a) $300pm 7 Omega$ and (b) $66.7pm 2 Omega$. But according to my book, my response for (b) is incorrect.



      It said that the equivalent resistance should have an error of $pm 1.8$ not my rounded off answer $pm 2$. And it (book) explicitly states that the error in (b) should be "expressed as $pm 1.8$ to keep in conformity with the rules of significant figures." I don't understand how this makes any sense (especially how it conforms to the rules of significant figures). Help anyone?










      share|cite|improve this question









      $endgroup$




      The question which arose my confusion:




      Two resistors with resistance $R_1 = 100pm 3 Omega$, and $R_2 = 200pm 4 Omega$ are connected in (a) series, (b) in parallel. Find the equivalent resistance of both combinations.




      In the end, my answer came out to be (a) $300pm 7 Omega$ and (b) $66.7pm 2 Omega$. But according to my book, my response for (b) is incorrect.



      It said that the equivalent resistance should have an error of $pm 1.8$ not my rounded off answer $pm 2$. And it (book) explicitly states that the error in (b) should be "expressed as $pm 1.8$ to keep in conformity with the rules of significant figures." I don't understand how this makes any sense (especially how it conforms to the rules of significant figures). Help anyone?







      error-analysis






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked 2 hours ago









      Apekshik PanigrahiApekshik Panigrahi

      1647




      1647






















          2 Answers
          2






          active

          oldest

          votes


















          3












          $begingroup$

          The easy part is that $66.7 pm 2$ is wrong. It is wrong because unless we know the tenths digit of the error, expressing the main value to the tenth's digit doesn't make sense: we'd be force to drop the result in that digit as soon as we add or subtract. So we should write $67 pm 2$ or write both the main figure and the uncertainty to the tenths column (that is, $66.7 pm 1.8$).



          The harder part (and indeed the part with a little wiggle room) is recognizing that both of the inputs are accurate to better than three percent, so they should be treated as having about three digits of precision. However, if you are old enough to recall the slide-rule convention for leading 1s (which requires that $1.00 times 10^2$ is a figure with only two digits of precision), you might feel that that fractional errors of a few percent should imply two digits not three.



          Part of the problem is that there is no completely internally consistent way to deal with uncertainty using the crude tool that is significant figures. Working scientists don't follow a checklist on significant figures they just always remember to not write figures that have no meaning. And in that frame of mind I would prefer $66.7 pm 1.8$.






          share|cite|improve this answer









          $endgroup$





















            3












            $begingroup$

            I'm not sure about keeping significant figures, but when you report a number with uncertainty you need to make sure the both values have the same number of decimal places. This is probably what they mean, since if you are going to use $66.7$, then you should report the uncertainty to the same number of decimal places, which goes to $1.8$



            From what I have been taught, reporting measurements with uncertainties gets rid of the need for significant figures. Significant figures are more of a "fast and loose" way to report uncertainty in a measurement. For example, if I measure the length of something using a ruler that has ticks every centimeter to be $5.4 rm {cm}$, what I really mean is that I am certain that the length falls between the $5 rm{cm}$ and $6 rm{cm}$ ticks, and I estimate it to be $0.4 rm{cm}$ from the $5 rm{cm}$ tick. The final significant digit tells me which number I am not certain about. This is why if we were to then add multiple length measurements, we need to keep track of significant figures, since this is how we are choosing to keep track of our uncertainty.






            share|cite|improve this answer









            $endgroup$













              Your Answer





              StackExchange.ifUsing("editor", function () {
              return StackExchange.using("mathjaxEditing", function () {
              StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
              StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
              });
              });
              }, "mathjax-editing");

              StackExchange.ready(function() {
              var channelOptions = {
              tags: "".split(" "),
              id: "151"
              };
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function() {
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled) {
              StackExchange.using("snippets", function() {
              createEditor();
              });
              }
              else {
              createEditor();
              }
              });

              function createEditor() {
              StackExchange.prepareEditor({
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: false,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: null,
              bindNavPrevention: true,
              postfix: "",
              imageUploader: {
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              },
              noCode: true, onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              });


              }
              });














              draft saved

              draft discarded


















              StackExchange.ready(
              function () {
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f459323%2fsignificant-figures-while-finding-errors%23new-answer', 'question_page');
              }
              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              3












              $begingroup$

              The easy part is that $66.7 pm 2$ is wrong. It is wrong because unless we know the tenths digit of the error, expressing the main value to the tenth's digit doesn't make sense: we'd be force to drop the result in that digit as soon as we add or subtract. So we should write $67 pm 2$ or write both the main figure and the uncertainty to the tenths column (that is, $66.7 pm 1.8$).



              The harder part (and indeed the part with a little wiggle room) is recognizing that both of the inputs are accurate to better than three percent, so they should be treated as having about three digits of precision. However, if you are old enough to recall the slide-rule convention for leading 1s (which requires that $1.00 times 10^2$ is a figure with only two digits of precision), you might feel that that fractional errors of a few percent should imply two digits not three.



              Part of the problem is that there is no completely internally consistent way to deal with uncertainty using the crude tool that is significant figures. Working scientists don't follow a checklist on significant figures they just always remember to not write figures that have no meaning. And in that frame of mind I would prefer $66.7 pm 1.8$.






              share|cite|improve this answer









              $endgroup$


















                3












                $begingroup$

                The easy part is that $66.7 pm 2$ is wrong. It is wrong because unless we know the tenths digit of the error, expressing the main value to the tenth's digit doesn't make sense: we'd be force to drop the result in that digit as soon as we add or subtract. So we should write $67 pm 2$ or write both the main figure and the uncertainty to the tenths column (that is, $66.7 pm 1.8$).



                The harder part (and indeed the part with a little wiggle room) is recognizing that both of the inputs are accurate to better than three percent, so they should be treated as having about three digits of precision. However, if you are old enough to recall the slide-rule convention for leading 1s (which requires that $1.00 times 10^2$ is a figure with only two digits of precision), you might feel that that fractional errors of a few percent should imply two digits not three.



                Part of the problem is that there is no completely internally consistent way to deal with uncertainty using the crude tool that is significant figures. Working scientists don't follow a checklist on significant figures they just always remember to not write figures that have no meaning. And in that frame of mind I would prefer $66.7 pm 1.8$.






                share|cite|improve this answer









                $endgroup$
















                  3












                  3








                  3





                  $begingroup$

                  The easy part is that $66.7 pm 2$ is wrong. It is wrong because unless we know the tenths digit of the error, expressing the main value to the tenth's digit doesn't make sense: we'd be force to drop the result in that digit as soon as we add or subtract. So we should write $67 pm 2$ or write both the main figure and the uncertainty to the tenths column (that is, $66.7 pm 1.8$).



                  The harder part (and indeed the part with a little wiggle room) is recognizing that both of the inputs are accurate to better than three percent, so they should be treated as having about three digits of precision. However, if you are old enough to recall the slide-rule convention for leading 1s (which requires that $1.00 times 10^2$ is a figure with only two digits of precision), you might feel that that fractional errors of a few percent should imply two digits not three.



                  Part of the problem is that there is no completely internally consistent way to deal with uncertainty using the crude tool that is significant figures. Working scientists don't follow a checklist on significant figures they just always remember to not write figures that have no meaning. And in that frame of mind I would prefer $66.7 pm 1.8$.






                  share|cite|improve this answer









                  $endgroup$



                  The easy part is that $66.7 pm 2$ is wrong. It is wrong because unless we know the tenths digit of the error, expressing the main value to the tenth's digit doesn't make sense: we'd be force to drop the result in that digit as soon as we add or subtract. So we should write $67 pm 2$ or write both the main figure and the uncertainty to the tenths column (that is, $66.7 pm 1.8$).



                  The harder part (and indeed the part with a little wiggle room) is recognizing that both of the inputs are accurate to better than three percent, so they should be treated as having about three digits of precision. However, if you are old enough to recall the slide-rule convention for leading 1s (which requires that $1.00 times 10^2$ is a figure with only two digits of precision), you might feel that that fractional errors of a few percent should imply two digits not three.



                  Part of the problem is that there is no completely internally consistent way to deal with uncertainty using the crude tool that is significant figures. Working scientists don't follow a checklist on significant figures they just always remember to not write figures that have no meaning. And in that frame of mind I would prefer $66.7 pm 1.8$.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 2 hours ago









                  dmckeedmckee

                  74.2k6134267




                  74.2k6134267























                      3












                      $begingroup$

                      I'm not sure about keeping significant figures, but when you report a number with uncertainty you need to make sure the both values have the same number of decimal places. This is probably what they mean, since if you are going to use $66.7$, then you should report the uncertainty to the same number of decimal places, which goes to $1.8$



                      From what I have been taught, reporting measurements with uncertainties gets rid of the need for significant figures. Significant figures are more of a "fast and loose" way to report uncertainty in a measurement. For example, if I measure the length of something using a ruler that has ticks every centimeter to be $5.4 rm {cm}$, what I really mean is that I am certain that the length falls between the $5 rm{cm}$ and $6 rm{cm}$ ticks, and I estimate it to be $0.4 rm{cm}$ from the $5 rm{cm}$ tick. The final significant digit tells me which number I am not certain about. This is why if we were to then add multiple length measurements, we need to keep track of significant figures, since this is how we are choosing to keep track of our uncertainty.






                      share|cite|improve this answer









                      $endgroup$


















                        3












                        $begingroup$

                        I'm not sure about keeping significant figures, but when you report a number with uncertainty you need to make sure the both values have the same number of decimal places. This is probably what they mean, since if you are going to use $66.7$, then you should report the uncertainty to the same number of decimal places, which goes to $1.8$



                        From what I have been taught, reporting measurements with uncertainties gets rid of the need for significant figures. Significant figures are more of a "fast and loose" way to report uncertainty in a measurement. For example, if I measure the length of something using a ruler that has ticks every centimeter to be $5.4 rm {cm}$, what I really mean is that I am certain that the length falls between the $5 rm{cm}$ and $6 rm{cm}$ ticks, and I estimate it to be $0.4 rm{cm}$ from the $5 rm{cm}$ tick. The final significant digit tells me which number I am not certain about. This is why if we were to then add multiple length measurements, we need to keep track of significant figures, since this is how we are choosing to keep track of our uncertainty.






                        share|cite|improve this answer









                        $endgroup$
















                          3












                          3








                          3





                          $begingroup$

                          I'm not sure about keeping significant figures, but when you report a number with uncertainty you need to make sure the both values have the same number of decimal places. This is probably what they mean, since if you are going to use $66.7$, then you should report the uncertainty to the same number of decimal places, which goes to $1.8$



                          From what I have been taught, reporting measurements with uncertainties gets rid of the need for significant figures. Significant figures are more of a "fast and loose" way to report uncertainty in a measurement. For example, if I measure the length of something using a ruler that has ticks every centimeter to be $5.4 rm {cm}$, what I really mean is that I am certain that the length falls between the $5 rm{cm}$ and $6 rm{cm}$ ticks, and I estimate it to be $0.4 rm{cm}$ from the $5 rm{cm}$ tick. The final significant digit tells me which number I am not certain about. This is why if we were to then add multiple length measurements, we need to keep track of significant figures, since this is how we are choosing to keep track of our uncertainty.






                          share|cite|improve this answer









                          $endgroup$



                          I'm not sure about keeping significant figures, but when you report a number with uncertainty you need to make sure the both values have the same number of decimal places. This is probably what they mean, since if you are going to use $66.7$, then you should report the uncertainty to the same number of decimal places, which goes to $1.8$



                          From what I have been taught, reporting measurements with uncertainties gets rid of the need for significant figures. Significant figures are more of a "fast and loose" way to report uncertainty in a measurement. For example, if I measure the length of something using a ruler that has ticks every centimeter to be $5.4 rm {cm}$, what I really mean is that I am certain that the length falls between the $5 rm{cm}$ and $6 rm{cm}$ ticks, and I estimate it to be $0.4 rm{cm}$ from the $5 rm{cm}$ tick. The final significant digit tells me which number I am not certain about. This is why if we were to then add multiple length measurements, we need to keep track of significant figures, since this is how we are choosing to keep track of our uncertainty.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered 2 hours ago









                          Aaron StevensAaron Stevens

                          10.3k31742




                          10.3k31742






























                              draft saved

                              draft discarded




















































                              Thanks for contributing an answer to Physics Stack Exchange!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid



                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.


                              Use MathJax to format equations. MathJax reference.


                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function () {
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f459323%2fsignificant-figures-while-finding-errors%23new-answer', 'question_page');
                              }
                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              Popular posts from this blog

                              Costa Masnaga

                              Fotorealismo

                              Sidney Franklin