Perl Passing Function as an Argument - Undefined Sub Reference
I'm reading the book "Higher Order Perl" by Mark Jason Dominus and I'm stuck on one of the first examples. It revolves around solving the Tower of Hanoi problem recursively, which my program does fine. The problem is, the book develops the example by refactoring the code, where rather than simply printing what the solution is doing, the solution function takes another parameter. This is a function that in my case simply does the same thing.
The problem is, I have defined my auxiliary function and I've attempted to pass it by reference, and then call it from the main function, but I am getting the following error.
Can't use an undefined value as a subroutine reference at main.pl line 86.
This version does not take a function as an argument and correctly solves the problem.
#!/usr/bin/perl
use utf8;
use v5.26;
use strict;
use warnings;
sub SolveTowerOfHanoiProblem0 {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
say "Move disk #$n from $start to $end.";
} else {
SolveTowerOfHanoiProblem0($n - 1, $start, $extra, $end);
say "Move disk #$n from $start to $end.";
SolveTowerOfHanoiProblem0($n - 1, $extra, $end, $start);
}
}
SolveTowerOfHanoiProblem0(3, 'A', 'C', 'B');
Output:
Move disk #1 from A to C.
Move disk #2 from A to B.
Move disk #1 from C to B.
Move disk #3 from A to C.
Move disk #1 from B to A.
Move disk #2 from B to C.
Move disk #1 from A to C.
I want to refactor the code to have the line that outputs what is happening in each step to be independent of the solution code, so for the time being I wrote another function that simply does the same thing, but is passed as an argument by the caller:
sub SolveTowerOfHanoiProblem {
my ($n, $start, $end, $extra, $moveDisk) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
SolveTowerOfHanoiProblem($n - 1, $extra, $end, $start);
}
}
sub PrintInstruction {
my ($disk, $start, $end) = @_;
say "Move disk #$disk from $start to $end.";
}
SolveTowerOfHanoiProblem(8, 'A', 'C', 'B', &PrintInstruction);
I am getting the following runtime error: Can't use an undefined value as a subroutine reference at main.pl line 86
. This is where I call the passed-in function for the first time.
Line 86:
if ($n == 1) {
$moveDisk->($n, $start, $end); # <---- Here, Line 86
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
I don't understand why the sub reference would be undefined. I've defined the function I'm referencing, and from what I've found so far (PerlMonks - Call subroutine by reference ?) I seem to be calling the function correctly.
I've looked at this question as well, but my PrintInstruction
function isn't defined in a module, it's defined locally, so if I understand correctly I don't need the $
symbol in the reference.
What am I missing?
perl
add a comment |
I'm reading the book "Higher Order Perl" by Mark Jason Dominus and I'm stuck on one of the first examples. It revolves around solving the Tower of Hanoi problem recursively, which my program does fine. The problem is, the book develops the example by refactoring the code, where rather than simply printing what the solution is doing, the solution function takes another parameter. This is a function that in my case simply does the same thing.
The problem is, I have defined my auxiliary function and I've attempted to pass it by reference, and then call it from the main function, but I am getting the following error.
Can't use an undefined value as a subroutine reference at main.pl line 86.
This version does not take a function as an argument and correctly solves the problem.
#!/usr/bin/perl
use utf8;
use v5.26;
use strict;
use warnings;
sub SolveTowerOfHanoiProblem0 {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
say "Move disk #$n from $start to $end.";
} else {
SolveTowerOfHanoiProblem0($n - 1, $start, $extra, $end);
say "Move disk #$n from $start to $end.";
SolveTowerOfHanoiProblem0($n - 1, $extra, $end, $start);
}
}
SolveTowerOfHanoiProblem0(3, 'A', 'C', 'B');
Output:
Move disk #1 from A to C.
Move disk #2 from A to B.
Move disk #1 from C to B.
Move disk #3 from A to C.
Move disk #1 from B to A.
Move disk #2 from B to C.
Move disk #1 from A to C.
I want to refactor the code to have the line that outputs what is happening in each step to be independent of the solution code, so for the time being I wrote another function that simply does the same thing, but is passed as an argument by the caller:
sub SolveTowerOfHanoiProblem {
my ($n, $start, $end, $extra, $moveDisk) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
SolveTowerOfHanoiProblem($n - 1, $extra, $end, $start);
}
}
sub PrintInstruction {
my ($disk, $start, $end) = @_;
say "Move disk #$disk from $start to $end.";
}
SolveTowerOfHanoiProblem(8, 'A', 'C', 'B', &PrintInstruction);
I am getting the following runtime error: Can't use an undefined value as a subroutine reference at main.pl line 86
. This is where I call the passed-in function for the first time.
Line 86:
if ($n == 1) {
$moveDisk->($n, $start, $end); # <---- Here, Line 86
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
I don't understand why the sub reference would be undefined. I've defined the function I'm referencing, and from what I've found so far (PerlMonks - Call subroutine by reference ?) I seem to be calling the function correctly.
I've looked at this question as well, but my PrintInstruction
function isn't defined in a module, it's defined locally, so if I understand correctly I don't need the $
symbol in the reference.
What am I missing?
perl
add a comment |
I'm reading the book "Higher Order Perl" by Mark Jason Dominus and I'm stuck on one of the first examples. It revolves around solving the Tower of Hanoi problem recursively, which my program does fine. The problem is, the book develops the example by refactoring the code, where rather than simply printing what the solution is doing, the solution function takes another parameter. This is a function that in my case simply does the same thing.
The problem is, I have defined my auxiliary function and I've attempted to pass it by reference, and then call it from the main function, but I am getting the following error.
Can't use an undefined value as a subroutine reference at main.pl line 86.
This version does not take a function as an argument and correctly solves the problem.
#!/usr/bin/perl
use utf8;
use v5.26;
use strict;
use warnings;
sub SolveTowerOfHanoiProblem0 {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
say "Move disk #$n from $start to $end.";
} else {
SolveTowerOfHanoiProblem0($n - 1, $start, $extra, $end);
say "Move disk #$n from $start to $end.";
SolveTowerOfHanoiProblem0($n - 1, $extra, $end, $start);
}
}
SolveTowerOfHanoiProblem0(3, 'A', 'C', 'B');
Output:
Move disk #1 from A to C.
Move disk #2 from A to B.
Move disk #1 from C to B.
Move disk #3 from A to C.
Move disk #1 from B to A.
Move disk #2 from B to C.
Move disk #1 from A to C.
I want to refactor the code to have the line that outputs what is happening in each step to be independent of the solution code, so for the time being I wrote another function that simply does the same thing, but is passed as an argument by the caller:
sub SolveTowerOfHanoiProblem {
my ($n, $start, $end, $extra, $moveDisk) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
SolveTowerOfHanoiProblem($n - 1, $extra, $end, $start);
}
}
sub PrintInstruction {
my ($disk, $start, $end) = @_;
say "Move disk #$disk from $start to $end.";
}
SolveTowerOfHanoiProblem(8, 'A', 'C', 'B', &PrintInstruction);
I am getting the following runtime error: Can't use an undefined value as a subroutine reference at main.pl line 86
. This is where I call the passed-in function for the first time.
Line 86:
if ($n == 1) {
$moveDisk->($n, $start, $end); # <---- Here, Line 86
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
I don't understand why the sub reference would be undefined. I've defined the function I'm referencing, and from what I've found so far (PerlMonks - Call subroutine by reference ?) I seem to be calling the function correctly.
I've looked at this question as well, but my PrintInstruction
function isn't defined in a module, it's defined locally, so if I understand correctly I don't need the $
symbol in the reference.
What am I missing?
perl
I'm reading the book "Higher Order Perl" by Mark Jason Dominus and I'm stuck on one of the first examples. It revolves around solving the Tower of Hanoi problem recursively, which my program does fine. The problem is, the book develops the example by refactoring the code, where rather than simply printing what the solution is doing, the solution function takes another parameter. This is a function that in my case simply does the same thing.
The problem is, I have defined my auxiliary function and I've attempted to pass it by reference, and then call it from the main function, but I am getting the following error.
Can't use an undefined value as a subroutine reference at main.pl line 86.
This version does not take a function as an argument and correctly solves the problem.
#!/usr/bin/perl
use utf8;
use v5.26;
use strict;
use warnings;
sub SolveTowerOfHanoiProblem0 {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
say "Move disk #$n from $start to $end.";
} else {
SolveTowerOfHanoiProblem0($n - 1, $start, $extra, $end);
say "Move disk #$n from $start to $end.";
SolveTowerOfHanoiProblem0($n - 1, $extra, $end, $start);
}
}
SolveTowerOfHanoiProblem0(3, 'A', 'C', 'B');
Output:
Move disk #1 from A to C.
Move disk #2 from A to B.
Move disk #1 from C to B.
Move disk #3 from A to C.
Move disk #1 from B to A.
Move disk #2 from B to C.
Move disk #1 from A to C.
I want to refactor the code to have the line that outputs what is happening in each step to be independent of the solution code, so for the time being I wrote another function that simply does the same thing, but is passed as an argument by the caller:
sub SolveTowerOfHanoiProblem {
my ($n, $start, $end, $extra, $moveDisk) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
SolveTowerOfHanoiProblem($n - 1, $extra, $end, $start);
}
}
sub PrintInstruction {
my ($disk, $start, $end) = @_;
say "Move disk #$disk from $start to $end.";
}
SolveTowerOfHanoiProblem(8, 'A', 'C', 'B', &PrintInstruction);
I am getting the following runtime error: Can't use an undefined value as a subroutine reference at main.pl line 86
. This is where I call the passed-in function for the first time.
Line 86:
if ($n == 1) {
$moveDisk->($n, $start, $end); # <---- Here, Line 86
} else {
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
I don't understand why the sub reference would be undefined. I've defined the function I'm referencing, and from what I've found so far (PerlMonks - Call subroutine by reference ?) I seem to be calling the function correctly.
I've looked at this question as well, but my PrintInstruction
function isn't defined in a module, it's defined locally, so if I understand correctly I don't need the $
symbol in the reference.
What am I missing?
perl
perl
asked Nov 22 '18 at 20:00
Jose Fernando Lopez FernandezJose Fernando Lopez Fernandez
555416
555416
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The SolveTowerOfHanoiProblem function expects a code ref as last (fifth) argument, but you are not passing it when you invoke it in your « else » block :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
Should be written as :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end, $moveDisk);
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
add a comment |
You are passing the code ref to the original call to SolveTowerOfHanoiProblem
, but not to the recursive calls.
You could simply pass the code ref.
SolveTowerOfHanoiProblem($n - 1, ..., $moveDisk);
Or could remove the need to pass the same value over and over again.
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
local *helper = sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
helper($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
helper($n - 1, $extra, $end, $start);
}
};
helper(@_);
}
Same, but using a feature introduced in Perl 5.16:
use feature qw( current_sub );
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
__SUB__->($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
__SUB__->($n - 1, $extra, $end, $start);
}
}->(@_);
}
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
1
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
add a comment |
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2 Answers
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2 Answers
2
active
oldest
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active
oldest
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oldest
votes
The SolveTowerOfHanoiProblem function expects a code ref as last (fifth) argument, but you are not passing it when you invoke it in your « else » block :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
Should be written as :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end, $moveDisk);
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
add a comment |
The SolveTowerOfHanoiProblem function expects a code ref as last (fifth) argument, but you are not passing it when you invoke it in your « else » block :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
Should be written as :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end, $moveDisk);
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
add a comment |
The SolveTowerOfHanoiProblem function expects a code ref as last (fifth) argument, but you are not passing it when you invoke it in your « else » block :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
Should be written as :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end, $moveDisk);
The SolveTowerOfHanoiProblem function expects a code ref as last (fifth) argument, but you are not passing it when you invoke it in your « else » block :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end);
Should be written as :
SolveTowerOfHanoiProblem($n - 1, $start, $extra, $end, $moveDisk);
answered Nov 22 '18 at 20:24
GMBGMB
10.9k2824
10.9k2824
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
add a comment |
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
Wow, I cannot believe I missed that. Thanks a lot, I appreciate it
– Jose Fernando Lopez Fernandez
Nov 22 '18 at 20:39
add a comment |
You are passing the code ref to the original call to SolveTowerOfHanoiProblem
, but not to the recursive calls.
You could simply pass the code ref.
SolveTowerOfHanoiProblem($n - 1, ..., $moveDisk);
Or could remove the need to pass the same value over and over again.
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
local *helper = sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
helper($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
helper($n - 1, $extra, $end, $start);
}
};
helper(@_);
}
Same, but using a feature introduced in Perl 5.16:
use feature qw( current_sub );
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
__SUB__->($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
__SUB__->($n - 1, $extra, $end, $start);
}
}->(@_);
}
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
1
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
add a comment |
You are passing the code ref to the original call to SolveTowerOfHanoiProblem
, but not to the recursive calls.
You could simply pass the code ref.
SolveTowerOfHanoiProblem($n - 1, ..., $moveDisk);
Or could remove the need to pass the same value over and over again.
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
local *helper = sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
helper($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
helper($n - 1, $extra, $end, $start);
}
};
helper(@_);
}
Same, but using a feature introduced in Perl 5.16:
use feature qw( current_sub );
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
__SUB__->($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
__SUB__->($n - 1, $extra, $end, $start);
}
}->(@_);
}
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
1
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
add a comment |
You are passing the code ref to the original call to SolveTowerOfHanoiProblem
, but not to the recursive calls.
You could simply pass the code ref.
SolveTowerOfHanoiProblem($n - 1, ..., $moveDisk);
Or could remove the need to pass the same value over and over again.
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
local *helper = sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
helper($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
helper($n - 1, $extra, $end, $start);
}
};
helper(@_);
}
Same, but using a feature introduced in Perl 5.16:
use feature qw( current_sub );
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
__SUB__->($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
__SUB__->($n - 1, $extra, $end, $start);
}
}->(@_);
}
You are passing the code ref to the original call to SolveTowerOfHanoiProblem
, but not to the recursive calls.
You could simply pass the code ref.
SolveTowerOfHanoiProblem($n - 1, ..., $moveDisk);
Or could remove the need to pass the same value over and over again.
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
local *helper = sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
helper($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
helper($n - 1, $extra, $end, $start);
}
};
helper(@_);
}
Same, but using a feature introduced in Perl 5.16:
use feature qw( current_sub );
sub SolveTowerOfHanoiProblem {
my $moveDisk = pop;
sub {
my ($n, $start, $end, $extra) = @_;
if ($n == 1) {
$moveDisk->($n, $start, $end);
} else {
__SUB__->($n - 1, $start, $extra, $end);
$moveDisk->($n, $start, $end);
__SUB__->($n - 1, $extra, $end, $start);
}
}->(@_);
}
edited Nov 24 '18 at 6:02
answered Nov 23 '18 at 5:32
ikegamiikegami
263k11177397
263k11177397
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
1
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
add a comment |
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
1
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
Wow, I hadn't come across nested subroutines like this, thanks for the heads up
– Jose Fernando Lopez Fernandez
Nov 24 '18 at 4:27
1
1
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
Just don't nest named subs
– ikegami
Nov 24 '18 at 4:29
add a comment |
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