Variable from if statement - jQuery
0
Why does console.log() shows A and not B? How do I get it to show B from the variable set in the if statement when the #input changes value?
var myNumber = 1;
var myLetter = 'A';
$('button').click(function(){
if( myNumber == 1 ){
myLetter = 'B';
}
});
$('#input').change(function(){
console.log( myLetter );
});
jquery variables if-statement
asked Nov 24 '18 at 1:41
JohanJohan
2715
add a comment |
0
Why does console.log() shows A and not B? How do I get it to show B from the variable set in the if statement when the #input changes value?
var myNumber = 1;
var myLetter = 'A';
$('button').click(function(){
if( myNumber == 1 ){
myLetter = 'B';
}
});
$('#input').change(function(){
console.log( myLetter );
});
jquery variables if-statement
asked Nov 24 '18 at 1:41
JohanJohan
2715
1
it showBmaybe in somewhere it set toA
– ewwink
Nov 24 '18 at 1:48
To show myLetter = 'B' you just need to click a button in the dom. Did you clicked any button? Or find if any where myNumber or myLetter was changed in you code.
– Muhammad Ashikuzzaman
Nov 24 '18 at 4:08
Your code looks good and the output is also as expected(It shows B when #input changes value). I don't find any issues. Have a look at this working fiddle: jsfiddle.net/z3qvjdtx/2
– Vishnu Baliga
Nov 24 '18 at 6:43
add a comment |
0
0
0
Why does console.log() shows A and not B? How do I get it to show B from the variable set in the if statement when the #input changes value?
var myNumber = 1;
var myLetter = 'A';
$('button').click(function(){
if( myNumber == 1 ){
myLetter = 'B';
}
});
$('#input').change(function(){
console.log( myLetter );
});
jquery variables if-statement
asked Nov 24 '18 at 1:41
JohanJohan
2715
Why does console.log() shows A and not B? How do I get it to show B from the variable set in the if statement when the #input changes value?
var myNumber = 1;
var myLetter = 'A';
$('button').click(function(){
if( myNumber == 1 ){
myLetter = 'B';
}
});
$('#input').change(function(){
console.log( myLetter );
});
jquery variables if-statement
jquery variables if-statement
asked Nov 24 '18 at 1:41
JohanJohan
2715
asked Nov 24 '18 at 1:41
JohanJohan
2715
edited Nov 24 '18 at 1:55
Johan
asked Nov 24 '18 at 1:41
JohanJohan
2715
asked Nov 24 '18 at 1:41
JohanJohan
2715
asked Nov 24 '18 at 1:41
JohanJohan
2715
2715
1
it showBmaybe in somewhere it set toA
– ewwink
Nov 24 '18 at 1:48
To show myLetter = 'B' you just need to click a button in the dom. Did you clicked any button? Or find if any where myNumber or myLetter was changed in you code.
– Muhammad Ashikuzzaman
Nov 24 '18 at 4:08
Your code looks good and the output is also as expected(It shows B when #input changes value). I don't find any issues. Have a look at this working fiddle: jsfiddle.net/z3qvjdtx/2
– Vishnu Baliga
Nov 24 '18 at 6:43
add a comment |
1
it showBmaybe in somewhere it set toA
– ewwink
Nov 24 '18 at 1:48
To show myLetter = 'B' you just need to click a button in the dom. Did you clicked any button? Or find if any where myNumber or myLetter was changed in you code.
– Muhammad Ashikuzzaman
Nov 24 '18 at 4:08
Your code looks good and the output is also as expected(It shows B when #input changes value). I don't find any issues. Have a look at this working fiddle: jsfiddle.net/z3qvjdtx/2
– Vishnu Baliga
Nov 24 '18 at 6:43
1
1
it show
B maybe in somewhere it set to A– ewwink
Nov 24 '18 at 1:48
it show
B maybe in somewhere it set to A– ewwink
Nov 24 '18 at 1:48
To show myLetter = 'B' you just need to click a button in the dom. Did you clicked any button? Or find if any where myNumber or myLetter was changed in you code.
– Muhammad Ashikuzzaman
Nov 24 '18 at 4:08
To show myLetter = 'B' you just need to click a button in the dom. Did you clicked any button? Or find if any where myNumber or myLetter was changed in you code.
– Muhammad Ashikuzzaman
Nov 24 '18 at 4:08
Your code looks good and the output is also as expected(It shows B when #input changes value). I don't find any issues. Have a look at this working fiddle: jsfiddle.net/z3qvjdtx/2
– Vishnu Baliga
Nov 24 '18 at 6:43
Your code looks good and the output is also as expected(It shows B when #input changes value). I don't find any issues. Have a look at this working fiddle: jsfiddle.net/z3qvjdtx/2
– Vishnu Baliga
Nov 24 '18 at 6:43
add a comment |
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1
it show
Bmaybe in somewhere it set toA– ewwink
Nov 24 '18 at 1:48
To show myLetter = 'B' you just need to click a button in the dom. Did you clicked any button? Or find if any where myNumber or myLetter was changed in you code.
– Muhammad Ashikuzzaman
Nov 24 '18 at 4:08
Your code looks good and the output is also as expected(It shows B when #input changes value). I don't find any issues. Have a look at this working fiddle: jsfiddle.net/z3qvjdtx/2
– Vishnu Baliga
Nov 24 '18 at 6:43