double to float without rounding python
say a = 580991.3636
When I b = np.float32(a)
b 580991.4
I'm after b 580991.3636
I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).
python-3.x floating-point
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
add a comment |
say a = 580991.3636
When I b = np.float32(a)
b 580991.4
I'm after b 580991.3636
I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).
python-3.x floating-point
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
2
The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4
– Patricia Shanahan
Nov 25 '18 at 16:47
add a comment |
say a = 580991.3636
When I b = np.float32(a)
b 580991.4
I'm after b 580991.3636
I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).
python-3.x floating-point
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
say a = 580991.3636
When I b = np.float32(a)
b 580991.4
I'm after b 580991.3636
I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).
python-3.x floating-point
python-3.x floating-point
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
edited Nov 25 '18 at 19:04
Gary Nobles
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
asked Nov 25 '18 at 16:39
Gary NoblesGary Nobles
358316
358316
2
The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4
– Patricia Shanahan
Nov 25 '18 at 16:47
add a comment |
2
The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4
– Patricia Shanahan
Nov 25 '18 at 16:47
2
2
The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4
– Patricia Shanahan
Nov 25 '18 at 16:47
The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4
– Patricia Shanahan
Nov 25 '18 at 16:47
add a comment |
1 Answer
1
active
oldest
votes
Float32 can only offer between 6 and 9 digits of precision.
Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.
If you need it to be more precise it has to be a double or use the python's library decimal.
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53469624%2fdouble-to-float-without-rounding-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Float32 can only offer between 6 and 9 digits of precision.
Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.
If you need it to be more precise it has to be a double or use the python's library decimal.
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
add a comment |
Float32 can only offer between 6 and 9 digits of precision.
Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.
If you need it to be more precise it has to be a double or use the python's library decimal.
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
add a comment |
Float32 can only offer between 6 and 9 digits of precision.
Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.
If you need it to be more precise it has to be a double or use the python's library decimal.
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
Float32 can only offer between 6 and 9 digits of precision.
Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.
If you need it to be more precise it has to be a double or use the python's library decimal.
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
edited Nov 25 '18 at 16:50
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
answered Nov 25 '18 at 16:43
user9849588user9849588
48428
48428
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53469624%2fdouble-to-float-without-rounding-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4
– Patricia Shanahan
Nov 25 '18 at 16:47