Generating values for columns between a range
1
I have the following dataset
A B begin_yr end_yr
asset brown 2007 2010
asset blue 2008 2008
basics caramel 2015 2015
cows dork 2004 2006
I want A and B to have rows for each year represented.
I expanded for each year:
gen x = end_yr - begin_yr
expand x +1
This gives me the following:
A B begin_yr end_yr x
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset blue 2008 2008 0
basics caramel 2015 2015 0
cows dork 2004 2006 2
Ultimately, I want the following dataset:
A B begin_yr end_yr x year
asset brown 2007 2010 3 2007
asset brown 2007 2010 3 2008
asset brown 2007 2010 3 2009
asset brown 2007 2010 3 2010
asset blue 2008 2008 0 2008
basics caramel 2015 2015 0 2015
cows dork 2004 2006 2 2004
cows dork 2004 2006 2 2005
cows dork 2004 2006 2 2006
This is what I have so far:
gen year = begin_yr if begin_yr!=end_yr
How do I populate the rest of the variable year?
stata stata-macros
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
asked Nov 20 at 18:54
Jyothsna Harithsa
445
add a comment |
1
I have the following dataset
A B begin_yr end_yr
asset brown 2007 2010
asset blue 2008 2008
basics caramel 2015 2015
cows dork 2004 2006
I want A and B to have rows for each year represented.
I expanded for each year:
gen x = end_yr - begin_yr
expand x +1
This gives me the following:
A B begin_yr end_yr x
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset blue 2008 2008 0
basics caramel 2015 2015 0
cows dork 2004 2006 2
Ultimately, I want the following dataset:
A B begin_yr end_yr x year
asset brown 2007 2010 3 2007
asset brown 2007 2010 3 2008
asset brown 2007 2010 3 2009
asset brown 2007 2010 3 2010
asset blue 2008 2008 0 2008
basics caramel 2015 2015 0 2015
cows dork 2004 2006 2 2004
cows dork 2004 2006 2 2005
cows dork 2004 2006 2 2006
This is what I have so far:
gen year = begin_yr if begin_yr!=end_yr
How do I populate the rest of the variable year?
stata stata-macros
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
asked Nov 20 at 18:54
Jyothsna Harithsa
445
add a comment |
1
1
1
I have the following dataset
A B begin_yr end_yr
asset brown 2007 2010
asset blue 2008 2008
basics caramel 2015 2015
cows dork 2004 2006
I want A and B to have rows for each year represented.
I expanded for each year:
gen x = end_yr - begin_yr
expand x +1
This gives me the following:
A B begin_yr end_yr x
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset blue 2008 2008 0
basics caramel 2015 2015 0
cows dork 2004 2006 2
Ultimately, I want the following dataset:
A B begin_yr end_yr x year
asset brown 2007 2010 3 2007
asset brown 2007 2010 3 2008
asset brown 2007 2010 3 2009
asset brown 2007 2010 3 2010
asset blue 2008 2008 0 2008
basics caramel 2015 2015 0 2015
cows dork 2004 2006 2 2004
cows dork 2004 2006 2 2005
cows dork 2004 2006 2 2006
This is what I have so far:
gen year = begin_yr if begin_yr!=end_yr
How do I populate the rest of the variable year?
stata stata-macros
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
asked Nov 20 at 18:54
Jyothsna Harithsa
445
I have the following dataset
A B begin_yr end_yr
asset brown 2007 2010
asset blue 2008 2008
basics caramel 2015 2015
cows dork 2004 2006
I want A and B to have rows for each year represented.
I expanded for each year:
gen x = end_yr - begin_yr
expand x +1
This gives me the following:
A B begin_yr end_yr x
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset brown 2007 2010 3
asset blue 2008 2008 0
basics caramel 2015 2015 0
cows dork 2004 2006 2
Ultimately, I want the following dataset:
A B begin_yr end_yr x year
asset brown 2007 2010 3 2007
asset brown 2007 2010 3 2008
asset brown 2007 2010 3 2009
asset brown 2007 2010 3 2010
asset blue 2008 2008 0 2008
basics caramel 2015 2015 0 2015
cows dork 2004 2006 2 2004
cows dork 2004 2006 2 2005
cows dork 2004 2006 2 2006
This is what I have so far:
gen year = begin_yr if begin_yr!=end_yr
How do I populate the rest of the variable year?
stata stata-macros
stata stata-macros
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
asked Nov 20 at 18:54
Jyothsna Harithsa
445
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
asked Nov 20 at 18:54
Jyothsna Harithsa
445
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
edited Nov 20 at 19:40
Pearly Spencer
9,909173358
9,909173358
asked Nov 20 at 18:54
Jyothsna Harithsa
445
asked Nov 20 at 18:54
Jyothsna Harithsa
445
asked Nov 20 at 18:54
Jyothsna Harithsa
445
445
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
3
Here's a twist building on @Pearly Spencer's code:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
gen toexpand = end - begin + 1
expand toexpand
bysort A : gen year = begin + _n - 1
list, sepby(A)
+--------------------------------------------------------+
| A B begin_yr end_yr toexpand year |
|--------------------------------------------------------|
1. | asset brown 2007 2010 4 2007 |
2. | asset brown 2007 2010 4 2008 |
3. | asset brown 2007 2010 4 2009 |
4. | asset brown 2007 2010 4 2010 |
|--------------------------------------------------------|
5. | basics caramel 2015 2015 1 2015 |
|--------------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------------+
Nothing against tsset or tsfill but neither is needed for this.
answered Nov 20 at 19:21
Nick Cox
25k42038
add a comment |
2
The following works for me:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
generate id = _n
expand 2
clonevar year = begin_yr
bysort id: replace year = end_yr[2] if _n == _N
drop if _n == 3
tsset id year
tsfill
foreach var in A B begin_yr end_yr {
bysort id: replace `var' = `var'[1]
}
list
+--------------------------------------------------+
| A B begin_yr end_yr id year |
|--------------------------------------------------|
1. | asset brown 2007 2010 1 2007 |
2. | asset brown 2007 2010 1 2008 |
3. | asset brown 2007 2010 1 2009 |
4. | asset brown 2007 2010 1 2010 |
5. | basics caramel 2015 2015 2 2015 |
|--------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------+
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
Here's a twist building on @Pearly Spencer's code:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
gen toexpand = end - begin + 1
expand toexpand
bysort A : gen year = begin + _n - 1
list, sepby(A)
+--------------------------------------------------------+
| A B begin_yr end_yr toexpand year |
|--------------------------------------------------------|
1. | asset brown 2007 2010 4 2007 |
2. | asset brown 2007 2010 4 2008 |
3. | asset brown 2007 2010 4 2009 |
4. | asset brown 2007 2010 4 2010 |
|--------------------------------------------------------|
5. | basics caramel 2015 2015 1 2015 |
|--------------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------------+
Nothing against tsset or tsfill but neither is needed for this.
answered Nov 20 at 19:21
Nick Cox
25k42038
add a comment |
3
Here's a twist building on @Pearly Spencer's code:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
gen toexpand = end - begin + 1
expand toexpand
bysort A : gen year = begin + _n - 1
list, sepby(A)
+--------------------------------------------------------+
| A B begin_yr end_yr toexpand year |
|--------------------------------------------------------|
1. | asset brown 2007 2010 4 2007 |
2. | asset brown 2007 2010 4 2008 |
3. | asset brown 2007 2010 4 2009 |
4. | asset brown 2007 2010 4 2010 |
|--------------------------------------------------------|
5. | basics caramel 2015 2015 1 2015 |
|--------------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------------+
Nothing against tsset or tsfill but neither is needed for this.
answered Nov 20 at 19:21
Nick Cox
25k42038
add a comment |
3
3
3
Here's a twist building on @Pearly Spencer's code:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
gen toexpand = end - begin + 1
expand toexpand
bysort A : gen year = begin + _n - 1
list, sepby(A)
+--------------------------------------------------------+
| A B begin_yr end_yr toexpand year |
|--------------------------------------------------------|
1. | asset brown 2007 2010 4 2007 |
2. | asset brown 2007 2010 4 2008 |
3. | asset brown 2007 2010 4 2009 |
4. | asset brown 2007 2010 4 2010 |
|--------------------------------------------------------|
5. | basics caramel 2015 2015 1 2015 |
|--------------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------------+
Nothing against tsset or tsfill but neither is needed for this.
answered Nov 20 at 19:21
Nick Cox
25k42038
Here's a twist building on @Pearly Spencer's code:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
gen toexpand = end - begin + 1
expand toexpand
bysort A : gen year = begin + _n - 1
list, sepby(A)
+--------------------------------------------------------+
| A B begin_yr end_yr toexpand year |
|--------------------------------------------------------|
1. | asset brown 2007 2010 4 2007 |
2. | asset brown 2007 2010 4 2008 |
3. | asset brown 2007 2010 4 2009 |
4. | asset brown 2007 2010 4 2010 |
|--------------------------------------------------------|
5. | basics caramel 2015 2015 1 2015 |
|--------------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------------+
Nothing against tsset or tsfill but neither is needed for this.
answered Nov 20 at 19:21
Nick Cox
25k42038
answered Nov 20 at 19:21
Nick Cox
25k42038
answered Nov 20 at 19:21
Nick Cox
25k42038
answered Nov 20 at 19:21
Nick Cox
25k42038
25k42038
add a comment |
add a comment |
2
The following works for me:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
generate id = _n
expand 2
clonevar year = begin_yr
bysort id: replace year = end_yr[2] if _n == _N
drop if _n == 3
tsset id year
tsfill
foreach var in A B begin_yr end_yr {
bysort id: replace `var' = `var'[1]
}
list
+--------------------------------------------------+
| A B begin_yr end_yr id year |
|--------------------------------------------------|
1. | asset brown 2007 2010 1 2007 |
2. | asset brown 2007 2010 1 2008 |
3. | asset brown 2007 2010 1 2009 |
4. | asset brown 2007 2010 1 2010 |
5. | basics caramel 2015 2015 2 2015 |
|--------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------+
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
add a comment |
2
The following works for me:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
generate id = _n
expand 2
clonevar year = begin_yr
bysort id: replace year = end_yr[2] if _n == _N
drop if _n == 3
tsset id year
tsfill
foreach var in A B begin_yr end_yr {
bysort id: replace `var' = `var'[1]
}
list
+--------------------------------------------------+
| A B begin_yr end_yr id year |
|--------------------------------------------------|
1. | asset brown 2007 2010 1 2007 |
2. | asset brown 2007 2010 1 2008 |
3. | asset brown 2007 2010 1 2009 |
4. | asset brown 2007 2010 1 2010 |
5. | basics caramel 2015 2015 2 2015 |
|--------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------+
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
add a comment |
2
2
2
The following works for me:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
generate id = _n
expand 2
clonevar year = begin_yr
bysort id: replace year = end_yr[2] if _n == _N
drop if _n == 3
tsset id year
tsfill
foreach var in A B begin_yr end_yr {
bysort id: replace `var' = `var'[1]
}
list
+--------------------------------------------------+
| A B begin_yr end_yr id year |
|--------------------------------------------------|
1. | asset brown 2007 2010 1 2007 |
2. | asset brown 2007 2010 1 2008 |
3. | asset brown 2007 2010 1 2009 |
4. | asset brown 2007 2010 1 2010 |
5. | basics caramel 2015 2015 2 2015 |
|--------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------+
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
The following works for me:
clear
input strL A strL B begin_yr end_yr
asset brown 2007 2010
basics caramel 2015 2015
cows dork 2004 2006
end
generate id = _n
expand 2
clonevar year = begin_yr
bysort id: replace year = end_yr[2] if _n == _N
drop if _n == 3
tsset id year
tsfill
foreach var in A B begin_yr end_yr {
bysort id: replace `var' = `var'[1]
}
list
+--------------------------------------------------+
| A B begin_yr end_yr id year |
|--------------------------------------------------|
1. | asset brown 2007 2010 1 2007 |
2. | asset brown 2007 2010 1 2008 |
3. | asset brown 2007 2010 1 2009 |
4. | asset brown 2007 2010 1 2010 |
5. | basics caramel 2015 2015 2 2015 |
|--------------------------------------------------|
6. | cows dork 2004 2006 3 2004 |
7. | cows dork 2004 2006 3 2005 |
8. | cows dork 2004 2006 3 2006 |
+--------------------------------------------------+
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
edited Nov 20 at 19:16
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
answered Nov 20 at 19:10
Pearly Spencer
9,909173358
9,909173358
add a comment |
add a comment |
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