subtract 1 hour from date in unix shell script
32
I have the following in a shell script. How can I subtract one hour while retaining the formatting?
DATE=`date "+%m/%d/%Y -%H:%M:%S"`
shell datetime unix
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
add a comment |
32
I have the following in a shell script. How can I subtract one hour while retaining the formatting?
DATE=`date "+%m/%d/%Y -%H:%M:%S"`
shell datetime unix
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
add a comment |
32
32
32
3
I have the following in a shell script. How can I subtract one hour while retaining the formatting?
DATE=`date "+%m/%d/%Y -%H:%M:%S"`
shell datetime unix
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
I have the following in a shell script. How can I subtract one hour while retaining the formatting?
DATE=`date "+%m/%d/%Y -%H:%M:%S"`
shell datetime unix
shell datetime unix
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
edited May 9 '11 at 20:57
Karl Bielefeldt
32.9k44880
32.9k44880
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
asked May 9 '11 at 8:26
shamir chaikinshamir chaikin
161139
161139
add a comment |
add a comment |
7 Answers
7
active
oldest
votes
48
The following command works on recent versions of GNU date:
date -d '1 hour ago' "+%m/%d/%Y -%H:%M:%S"
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
1
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
add a comment |
8
date -v-60M "+%m/%d/%Y -%H:%M:%S"
DATE=`date -v-60M "+%m/%d/%Y -%H:%M:%S"`
If you have bash version 4.4+ you can use bash's internal date printing and arithmetics:
printf "current date: %(%m/%d/%Y -%H:%M:%S)Tn"
printf "date - 60min: %(%m/%d/%Y -%H:%M:%S)Tn" $(( $(printf "%(%s)T") - 60 * 60 ))
The $(printf "%(%s)T") prints the epoch seconds, the $(( epoch - 60*60 )) is bash-aritmetics - subtracting 1hour in seconds. Prints:
current date: 04/20/2017 -18:14:31
date - 60min: 04/20/2017 -17:14:31
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
This doesn't work indateshipped on Ubuntu.
– Flimm
Jun 15 '16 at 16:10
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
add a comment |
4
if you need substract with timestamp :
timestamp=$(date +%s -d '1 hour ago');
answered Dec 4 '15 at 15:15
leGabianleGabian
412
add a comment |
2
Convert to timestamp (a long integer), subtract the right number of milliseconds, reformat to the format you need.
Hard to give more details since you don't specify a programming language...
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
ahh.. i am using shell script, my formula go like this -DATE=date "+%m/%d/%Y -%H:%M:%S"and from DATE i want to subtract 1 hour
– shamir chaikin
May 9 '11 at 8:32
1
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
add a comment |
1
This work on my Ubuntu 16.04 date:
date --date="@$(($(date +%s) - 3600))" "+%m/%d/%Y -%H:%M:%S"
And the date version is date (GNU coreutils) 8.25
answered Mar 21 '17 at 12:14
ray_gray_g
265
add a comment |
1
If you need change timezone before subtraction with new format too:
$(TZ=US/Eastern date -d '1 hour ago' '+%Y-%m-%d %H:%M')
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
add a comment |
0
Here another way to subtract 1 hour.
yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'`
echo $yesterdayDate
Output:
2018-11-23 23:09
I hope that It can help someone.
Best Regards!
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
add a comment |
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7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
48
The following command works on recent versions of GNU date:
date -d '1 hour ago' "+%m/%d/%Y -%H:%M:%S"
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
1
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
add a comment |
48
The following command works on recent versions of GNU date:
date -d '1 hour ago' "+%m/%d/%Y -%H:%M:%S"
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
1
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
add a comment |
48
48
48
The following command works on recent versions of GNU date:
date -d '1 hour ago' "+%m/%d/%Y -%H:%M:%S"
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
The following command works on recent versions of GNU date:
date -d '1 hour ago' "+%m/%d/%Y -%H:%M:%S"
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
answered May 9 '11 at 8:35
dogbanedogbane
192k65320374
192k65320374
1
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
add a comment |
1
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
1
1
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
i recieve -date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff]
– shamir chaikin
May 9 '11 at 8:40
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
@shamir this means your version of date does not support this option.
– dogbane
May 9 '11 at 8:41
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
i figure it out - i post it because may be you know some other way to do it on solaris machine?
– shamir chaikin
May 9 '11 at 9:16
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
@shamir, it may be easiest to just install GNU date. You can use a different prefix or path so it doesn't conflict with the "official" one. When I used to do a lot of work on Solaris, I installed a number of GNU utilities in my /home/karl/bin because they have these handy extra options.
– Karl Bielefeldt
May 9 '11 at 23:48
add a comment |
8
date -v-60M "+%m/%d/%Y -%H:%M:%S"
DATE=`date -v-60M "+%m/%d/%Y -%H:%M:%S"`
If you have bash version 4.4+ you can use bash's internal date printing and arithmetics:
printf "current date: %(%m/%d/%Y -%H:%M:%S)Tn"
printf "date - 60min: %(%m/%d/%Y -%H:%M:%S)Tn" $(( $(printf "%(%s)T") - 60 * 60 ))
The $(printf "%(%s)T") prints the epoch seconds, the $(( epoch - 60*60 )) is bash-aritmetics - subtracting 1hour in seconds. Prints:
current date: 04/20/2017 -18:14:31
date - 60min: 04/20/2017 -17:14:31
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
This doesn't work indateshipped on Ubuntu.
– Flimm
Jun 15 '16 at 16:10
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
add a comment |
8
date -v-60M "+%m/%d/%Y -%H:%M:%S"
DATE=`date -v-60M "+%m/%d/%Y -%H:%M:%S"`
If you have bash version 4.4+ you can use bash's internal date printing and arithmetics:
printf "current date: %(%m/%d/%Y -%H:%M:%S)Tn"
printf "date - 60min: %(%m/%d/%Y -%H:%M:%S)Tn" $(( $(printf "%(%s)T") - 60 * 60 ))
The $(printf "%(%s)T") prints the epoch seconds, the $(( epoch - 60*60 )) is bash-aritmetics - subtracting 1hour in seconds. Prints:
current date: 04/20/2017 -18:14:31
date - 60min: 04/20/2017 -17:14:31
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
This doesn't work indateshipped on Ubuntu.
– Flimm
Jun 15 '16 at 16:10
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
add a comment |
8
8
8
date -v-60M "+%m/%d/%Y -%H:%M:%S"
DATE=`date -v-60M "+%m/%d/%Y -%H:%M:%S"`
If you have bash version 4.4+ you can use bash's internal date printing and arithmetics:
printf "current date: %(%m/%d/%Y -%H:%M:%S)Tn"
printf "date - 60min: %(%m/%d/%Y -%H:%M:%S)Tn" $(( $(printf "%(%s)T") - 60 * 60 ))
The $(printf "%(%s)T") prints the epoch seconds, the $(( epoch - 60*60 )) is bash-aritmetics - subtracting 1hour in seconds. Prints:
current date: 04/20/2017 -18:14:31
date - 60min: 04/20/2017 -17:14:31
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
date -v-60M "+%m/%d/%Y -%H:%M:%S"
DATE=`date -v-60M "+%m/%d/%Y -%H:%M:%S"`
If you have bash version 4.4+ you can use bash's internal date printing and arithmetics:
printf "current date: %(%m/%d/%Y -%H:%M:%S)Tn"
printf "date - 60min: %(%m/%d/%Y -%H:%M:%S)Tn" $(( $(printf "%(%s)T") - 60 * 60 ))
The $(printf "%(%s)T") prints the epoch seconds, the $(( epoch - 60*60 )) is bash-aritmetics - subtracting 1hour in seconds. Prints:
current date: 04/20/2017 -18:14:31
date - 60min: 04/20/2017 -17:14:31
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
edited Apr 20 '17 at 16:18
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
answered May 9 '11 at 21:11
jm666jm666
43.6k1175144
43.6k1175144
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
This doesn't work indateshipped on Ubuntu.
– Flimm
Jun 15 '16 at 16:10
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
add a comment |
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
This doesn't work indateshipped on Ubuntu.
– Flimm
Jun 15 '16 at 16:10
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
yes my OS not support it, thanks any way
– shamir chaikin
May 11 '11 at 5:30
This doesn't work in
date shipped on Ubuntu.– Flimm
Jun 15 '16 at 16:10
This doesn't work in
date shipped on Ubuntu.– Flimm
Jun 15 '16 at 16:10
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
@Flimm This works on OS X and I expect BSD as well
– Jason S
Oct 14 '16 at 1:04
add a comment |
4
if you need substract with timestamp :
timestamp=$(date +%s -d '1 hour ago');
answered Dec 4 '15 at 15:15
leGabianleGabian
412
add a comment |
4
if you need substract with timestamp :
timestamp=$(date +%s -d '1 hour ago');
answered Dec 4 '15 at 15:15
leGabianleGabian
412
add a comment |
4
4
4
if you need substract with timestamp :
timestamp=$(date +%s -d '1 hour ago');
answered Dec 4 '15 at 15:15
leGabianleGabian
412
if you need substract with timestamp :
timestamp=$(date +%s -d '1 hour ago');
answered Dec 4 '15 at 15:15
leGabianleGabian
412
answered Dec 4 '15 at 15:15
leGabianleGabian
412
answered Dec 4 '15 at 15:15
leGabianleGabian
412
answered Dec 4 '15 at 15:15
leGabianleGabian
412
412
add a comment |
add a comment |
2
Convert to timestamp (a long integer), subtract the right number of milliseconds, reformat to the format you need.
Hard to give more details since you don't specify a programming language...
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
ahh.. i am using shell script, my formula go like this -DATE=date "+%m/%d/%Y -%H:%M:%S"and from DATE i want to subtract 1 hour
– shamir chaikin
May 9 '11 at 8:32
1
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
add a comment |
2
Convert to timestamp (a long integer), subtract the right number of milliseconds, reformat to the format you need.
Hard to give more details since you don't specify a programming language...
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
ahh.. i am using shell script, my formula go like this -DATE=date "+%m/%d/%Y -%H:%M:%S"and from DATE i want to subtract 1 hour
– shamir chaikin
May 9 '11 at 8:32
1
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
add a comment |
2
2
2
Convert to timestamp (a long integer), subtract the right number of milliseconds, reformat to the format you need.
Hard to give more details since you don't specify a programming language...
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
Convert to timestamp (a long integer), subtract the right number of milliseconds, reformat to the format you need.
Hard to give more details since you don't specify a programming language...
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
answered May 9 '11 at 8:29
PhiLhoPhiLho
35.1k379122
35.1k379122
ahh.. i am using shell script, my formula go like this -DATE=date "+%m/%d/%Y -%H:%M:%S"and from DATE i want to subtract 1 hour
– shamir chaikin
May 9 '11 at 8:32
1
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
add a comment |
ahh.. i am using shell script, my formula go like this -DATE=date "+%m/%d/%Y -%H:%M:%S"and from DATE i want to subtract 1 hour
– shamir chaikin
May 9 '11 at 8:32
1
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
ahh.. i am using shell script, my formula go like this -DATE=
date "+%m/%d/%Y -%H:%M:%S" and from DATE i want to subtract 1 hour– shamir chaikin
May 9 '11 at 8:32
ahh.. i am using shell script, my formula go like this -DATE=
date "+%m/%d/%Y -%H:%M:%S" and from DATE i want to subtract 1 hour– shamir chaikin
May 9 '11 at 8:32
1
1
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
Are you required to stay in shell? An inline awk or perl script could easily subtract an hour and output in your required format.
– CoreyStup
May 9 '11 at 20:38
add a comment |
1
This work on my Ubuntu 16.04 date:
date --date="@$(($(date +%s) - 3600))" "+%m/%d/%Y -%H:%M:%S"
And the date version is date (GNU coreutils) 8.25
answered Mar 21 '17 at 12:14
ray_gray_g
265
add a comment |
1
This work on my Ubuntu 16.04 date:
date --date="@$(($(date +%s) - 3600))" "+%m/%d/%Y -%H:%M:%S"
And the date version is date (GNU coreutils) 8.25
answered Mar 21 '17 at 12:14
ray_gray_g
265
add a comment |
1
1
1
This work on my Ubuntu 16.04 date:
date --date="@$(($(date +%s) - 3600))" "+%m/%d/%Y -%H:%M:%S"
And the date version is date (GNU coreutils) 8.25
answered Mar 21 '17 at 12:14
ray_gray_g
265
This work on my Ubuntu 16.04 date:
date --date="@$(($(date +%s) - 3600))" "+%m/%d/%Y -%H:%M:%S"
And the date version is date (GNU coreutils) 8.25
answered Mar 21 '17 at 12:14
ray_gray_g
265
answered Mar 21 '17 at 12:14
ray_gray_g
265
answered Mar 21 '17 at 12:14
ray_gray_g
265
answered Mar 21 '17 at 12:14
ray_gray_g
265
265
add a comment |
add a comment |
1
If you need change timezone before subtraction with new format too:
$(TZ=US/Eastern date -d '1 hour ago' '+%Y-%m-%d %H:%M')
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
add a comment |
1
If you need change timezone before subtraction with new format too:
$(TZ=US/Eastern date -d '1 hour ago' '+%Y-%m-%d %H:%M')
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
add a comment |
1
1
1
If you need change timezone before subtraction with new format too:
$(TZ=US/Eastern date -d '1 hour ago' '+%Y-%m-%d %H:%M')
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
If you need change timezone before subtraction with new format too:
$(TZ=US/Eastern date -d '1 hour ago' '+%Y-%m-%d %H:%M')
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
answered May 24 '18 at 10:37
Kenan DumanKenan Duman
544
544
add a comment |
add a comment |
0
Here another way to subtract 1 hour.
yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'`
echo $yesterdayDate
Output:
2018-11-23 23:09
I hope that It can help someone.
Best Regards!
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
add a comment |
0
Here another way to subtract 1 hour.
yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'`
echo $yesterdayDate
Output:
2018-11-23 23:09
I hope that It can help someone.
Best Regards!
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
add a comment |
0
0
0
Here another way to subtract 1 hour.
yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'`
echo $yesterdayDate
Output:
2018-11-23 23:09
I hope that It can help someone.
Best Regards!
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
Here another way to subtract 1 hour.
yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'`
echo $yesterdayDate
Output:
2018-11-23 23:09
I hope that It can help someone.
Best Regards!
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
answered Nov 24 '18 at 21:29
Javier MuñozJavier Muñoz
3311518
3311518
add a comment |
add a comment |
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