importing multiline JSON file in python












0















I am trying to import a JSON file in python that has many objects like the following:



{"ID": 1989,  "Attrib1": "74574d4c6",    "Attrib2": null,    "Attrib3": "41324" }
{"ID": 1990, "Attrib1": "1652857c6", "Attrib2": asd123, "Attrib3": "424" }


The file has line break for each object therefore, the json.load(file) is failing on the first line break.



I tried to iterate through them with:



with open(myFileLocation,'r') as myfile:
for line in myfile:
Data = json.loads(row)
return Data


but I couldn't add each line to a dictionary object as it doesn't have append (or any other method that am aware of).



How can I return all the objects in the JSON file as a dictionary?










share|improve this question

























  • You can create an empty dictionary with my_dict = {} and add new key-value pairs to it with my_dict[new_key] = new_value. First though, you'll need to decide which field of your JSON object you want as the key.

    – dmitriys
    Nov 25 '18 at 6:40


















0















I am trying to import a JSON file in python that has many objects like the following:



{"ID": 1989,  "Attrib1": "74574d4c6",    "Attrib2": null,    "Attrib3": "41324" }
{"ID": 1990, "Attrib1": "1652857c6", "Attrib2": asd123, "Attrib3": "424" }


The file has line break for each object therefore, the json.load(file) is failing on the first line break.



I tried to iterate through them with:



with open(myFileLocation,'r') as myfile:
for line in myfile:
Data = json.loads(row)
return Data


but I couldn't add each line to a dictionary object as it doesn't have append (or any other method that am aware of).



How can I return all the objects in the JSON file as a dictionary?










share|improve this question

























  • You can create an empty dictionary with my_dict = {} and add new key-value pairs to it with my_dict[new_key] = new_value. First though, you'll need to decide which field of your JSON object you want as the key.

    – dmitriys
    Nov 25 '18 at 6:40
















0












0








0








I am trying to import a JSON file in python that has many objects like the following:



{"ID": 1989,  "Attrib1": "74574d4c6",    "Attrib2": null,    "Attrib3": "41324" }
{"ID": 1990, "Attrib1": "1652857c6", "Attrib2": asd123, "Attrib3": "424" }


The file has line break for each object therefore, the json.load(file) is failing on the first line break.



I tried to iterate through them with:



with open(myFileLocation,'r') as myfile:
for line in myfile:
Data = json.loads(row)
return Data


but I couldn't add each line to a dictionary object as it doesn't have append (or any other method that am aware of).



How can I return all the objects in the JSON file as a dictionary?










share|improve this question
















I am trying to import a JSON file in python that has many objects like the following:



{"ID": 1989,  "Attrib1": "74574d4c6",    "Attrib2": null,    "Attrib3": "41324" }
{"ID": 1990, "Attrib1": "1652857c6", "Attrib2": asd123, "Attrib3": "424" }


The file has line break for each object therefore, the json.load(file) is failing on the first line break.



I tried to iterate through them with:



with open(myFileLocation,'r') as myfile:
for line in myfile:
Data = json.loads(row)
return Data


but I couldn't add each line to a dictionary object as it doesn't have append (or any other method that am aware of).



How can I return all the objects in the JSON file as a dictionary?







python json import






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 25 '18 at 6:40









MaJoR

534115




534115










asked Nov 25 '18 at 6:29









MahmoudMahmoud

83




83













  • You can create an empty dictionary with my_dict = {} and add new key-value pairs to it with my_dict[new_key] = new_value. First though, you'll need to decide which field of your JSON object you want as the key.

    – dmitriys
    Nov 25 '18 at 6:40





















  • You can create an empty dictionary with my_dict = {} and add new key-value pairs to it with my_dict[new_key] = new_value. First though, you'll need to decide which field of your JSON object you want as the key.

    – dmitriys
    Nov 25 '18 at 6:40



















You can create an empty dictionary with my_dict = {} and add new key-value pairs to it with my_dict[new_key] = new_value. First though, you'll need to decide which field of your JSON object you want as the key.

– dmitriys
Nov 25 '18 at 6:40







You can create an empty dictionary with my_dict = {} and add new key-value pairs to it with my_dict[new_key] = new_value. First though, you'll need to decide which field of your JSON object you want as the key.

– dmitriys
Nov 25 '18 at 6:40














1 Answer
1






active

oldest

votes


















0














json.loads (and json.load) does not decode multiple json objects.



>>>json.loads('{}')
{}
>>>json.loads('{}{}')
JSONDecodeError Traceback (most
recent call last)
<ipython-input-7-0285b42a3a05> in <module>()
----> 1 json.loads('{}{}')

~AppDataLocalContinuumanaconda3libjson__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
352 parse_int is None and parse_float is None and
353 parse_constant is None and object_pairs_hook
is None and not kw):
--> 354 return _default_decoder.decode(s)
355 if cls is None:
356 cls = JSONDecoder

~AppDataLocalContinuumanaconda3libjsondecoder.py in decode(self, s, _w)
340 end = _w(s, end).end()
341 if end != len(s):
--> 342 raise JSONDecodeError("Extra data", s, end)
343 return obj
344

JSONDecodeError: Extra data: line 1 column 3 (char 2)


To dump multiple dictionaries, you could wrap them in a list by dumping the list.



>>> dict1 = {}
>>> dict2 = {}
>>> json.dumps([dict1, dict2])
'[{}, {}]'
>>> json.loads(json.dumps([dict1, dict2]))
[{}, {}]


Also Use append as follows



list = 
for line in open('data.json'), 'r'):
list.append(json.loads(line)





share|improve this answer


























  • I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

    – Mahmoud
    Nov 25 '18 at 16:35











  • d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

    – ersh
    Jan 22 at 7:13













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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














json.loads (and json.load) does not decode multiple json objects.



>>>json.loads('{}')
{}
>>>json.loads('{}{}')
JSONDecodeError Traceback (most
recent call last)
<ipython-input-7-0285b42a3a05> in <module>()
----> 1 json.loads('{}{}')

~AppDataLocalContinuumanaconda3libjson__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
352 parse_int is None and parse_float is None and
353 parse_constant is None and object_pairs_hook
is None and not kw):
--> 354 return _default_decoder.decode(s)
355 if cls is None:
356 cls = JSONDecoder

~AppDataLocalContinuumanaconda3libjsondecoder.py in decode(self, s, _w)
340 end = _w(s, end).end()
341 if end != len(s):
--> 342 raise JSONDecodeError("Extra data", s, end)
343 return obj
344

JSONDecodeError: Extra data: line 1 column 3 (char 2)


To dump multiple dictionaries, you could wrap them in a list by dumping the list.



>>> dict1 = {}
>>> dict2 = {}
>>> json.dumps([dict1, dict2])
'[{}, {}]'
>>> json.loads(json.dumps([dict1, dict2]))
[{}, {}]


Also Use append as follows



list = 
for line in open('data.json'), 'r'):
list.append(json.loads(line)





share|improve this answer


























  • I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

    – Mahmoud
    Nov 25 '18 at 16:35











  • d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

    – ersh
    Jan 22 at 7:13


















0














json.loads (and json.load) does not decode multiple json objects.



>>>json.loads('{}')
{}
>>>json.loads('{}{}')
JSONDecodeError Traceback (most
recent call last)
<ipython-input-7-0285b42a3a05> in <module>()
----> 1 json.loads('{}{}')

~AppDataLocalContinuumanaconda3libjson__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
352 parse_int is None and parse_float is None and
353 parse_constant is None and object_pairs_hook
is None and not kw):
--> 354 return _default_decoder.decode(s)
355 if cls is None:
356 cls = JSONDecoder

~AppDataLocalContinuumanaconda3libjsondecoder.py in decode(self, s, _w)
340 end = _w(s, end).end()
341 if end != len(s):
--> 342 raise JSONDecodeError("Extra data", s, end)
343 return obj
344

JSONDecodeError: Extra data: line 1 column 3 (char 2)


To dump multiple dictionaries, you could wrap them in a list by dumping the list.



>>> dict1 = {}
>>> dict2 = {}
>>> json.dumps([dict1, dict2])
'[{}, {}]'
>>> json.loads(json.dumps([dict1, dict2]))
[{}, {}]


Also Use append as follows



list = 
for line in open('data.json'), 'r'):
list.append(json.loads(line)





share|improve this answer


























  • I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

    – Mahmoud
    Nov 25 '18 at 16:35











  • d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

    – ersh
    Jan 22 at 7:13
















0












0








0







json.loads (and json.load) does not decode multiple json objects.



>>>json.loads('{}')
{}
>>>json.loads('{}{}')
JSONDecodeError Traceback (most
recent call last)
<ipython-input-7-0285b42a3a05> in <module>()
----> 1 json.loads('{}{}')

~AppDataLocalContinuumanaconda3libjson__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
352 parse_int is None and parse_float is None and
353 parse_constant is None and object_pairs_hook
is None and not kw):
--> 354 return _default_decoder.decode(s)
355 if cls is None:
356 cls = JSONDecoder

~AppDataLocalContinuumanaconda3libjsondecoder.py in decode(self, s, _w)
340 end = _w(s, end).end()
341 if end != len(s):
--> 342 raise JSONDecodeError("Extra data", s, end)
343 return obj
344

JSONDecodeError: Extra data: line 1 column 3 (char 2)


To dump multiple dictionaries, you could wrap them in a list by dumping the list.



>>> dict1 = {}
>>> dict2 = {}
>>> json.dumps([dict1, dict2])
'[{}, {}]'
>>> json.loads(json.dumps([dict1, dict2]))
[{}, {}]


Also Use append as follows



list = 
for line in open('data.json'), 'r'):
list.append(json.loads(line)





share|improve this answer















json.loads (and json.load) does not decode multiple json objects.



>>>json.loads('{}')
{}
>>>json.loads('{}{}')
JSONDecodeError Traceback (most
recent call last)
<ipython-input-7-0285b42a3a05> in <module>()
----> 1 json.loads('{}{}')

~AppDataLocalContinuumanaconda3libjson__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
352 parse_int is None and parse_float is None and
353 parse_constant is None and object_pairs_hook
is None and not kw):
--> 354 return _default_decoder.decode(s)
355 if cls is None:
356 cls = JSONDecoder

~AppDataLocalContinuumanaconda3libjsondecoder.py in decode(self, s, _w)
340 end = _w(s, end).end()
341 if end != len(s):
--> 342 raise JSONDecodeError("Extra data", s, end)
343 return obj
344

JSONDecodeError: Extra data: line 1 column 3 (char 2)


To dump multiple dictionaries, you could wrap them in a list by dumping the list.



>>> dict1 = {}
>>> dict2 = {}
>>> json.dumps([dict1, dict2])
'[{}, {}]'
>>> json.loads(json.dumps([dict1, dict2]))
[{}, {}]


Also Use append as follows



list = 
for line in open('data.json'), 'r'):
list.append(json.loads(line)






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 25 '18 at 6:48

























answered Nov 25 '18 at 6:43









ershersh

243




243













  • I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

    – Mahmoud
    Nov 25 '18 at 16:35











  • d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

    – ersh
    Jan 22 at 7:13





















  • I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

    – Mahmoud
    Nov 25 '18 at 16:35











  • d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

    – ersh
    Jan 22 at 7:13



















I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

– Mahmoud
Nov 25 '18 at 16:35





I am able to add the file content as a list but, I need to analyze the JSON data and I can't do that on a list as far as I know it should be a dictionary.

– Mahmoud
Nov 25 '18 at 16:35













d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

– ersh
Jan 22 at 7:13







d = dict(itertools.zip_longest(l[::2], l[1::2], fillvalue='')) This can convert the list to a dictionary.

– ersh
Jan 22 at 7:13






















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