sort two completly different type of array with one common properties
Hi I have two array with different properties and only properties has common sort_order
and I want to merge this two array and want to sort this two array by sort_order
.
Here is the code:
var array1:[AnyObject] = [{
"name":"obj1Array1"
"sort_order": 4
"type":"G"
},{
"name":"obj2Array1"
"sort_order": 1
"type":"G"
},{
"name":"obj31Array1"
"sort_order": 5
"type":"G"
}]
var array2:[AnyObject] = [{
"Group":"M"
"sort_order": 3
"type":"G"
},{
"Group":"C"
"sort_order": 2
"type":"G"
},{
"Group":"D"
"sort_order": 6
"type":"G"
}]
arrays swift
add a comment |
Hi I have two array with different properties and only properties has common sort_order
and I want to merge this two array and want to sort this two array by sort_order
.
Here is the code:
var array1:[AnyObject] = [{
"name":"obj1Array1"
"sort_order": 4
"type":"G"
},{
"name":"obj2Array1"
"sort_order": 1
"type":"G"
},{
"name":"obj31Array1"
"sort_order": 5
"type":"G"
}]
var array2:[AnyObject] = [{
"Group":"M"
"sort_order": 3
"type":"G"
},{
"Group":"C"
"sort_order": 2
"type":"G"
},{
"Group":"D"
"sort_order": 6
"type":"G"
}]
arrays swift
if you merge them both, how will you know which is an object of array1 and which is that of array2 when you use it? or is it like this:name
from array1 is the same asgroup
from array2?
– Rakesha Shastri
Nov 26 '18 at 10:21
because I already created model classes for this objects
– Nirav Hathi
Nov 26 '18 at 10:24
For objects to be in the same array, they all have to be of the same type. So, if they are of the same type, sayAny
, how would you know which object is of which type when you want to access them from the said array.
– Rakesha Shastri
Nov 26 '18 at 10:25
you should be able to achieve that using protocol
– kathayatnk
Nov 26 '18 at 10:34
add a comment |
Hi I have two array with different properties and only properties has common sort_order
and I want to merge this two array and want to sort this two array by sort_order
.
Here is the code:
var array1:[AnyObject] = [{
"name":"obj1Array1"
"sort_order": 4
"type":"G"
},{
"name":"obj2Array1"
"sort_order": 1
"type":"G"
},{
"name":"obj31Array1"
"sort_order": 5
"type":"G"
}]
var array2:[AnyObject] = [{
"Group":"M"
"sort_order": 3
"type":"G"
},{
"Group":"C"
"sort_order": 2
"type":"G"
},{
"Group":"D"
"sort_order": 6
"type":"G"
}]
arrays swift
Hi I have two array with different properties and only properties has common sort_order
and I want to merge this two array and want to sort this two array by sort_order
.
Here is the code:
var array1:[AnyObject] = [{
"name":"obj1Array1"
"sort_order": 4
"type":"G"
},{
"name":"obj2Array1"
"sort_order": 1
"type":"G"
},{
"name":"obj31Array1"
"sort_order": 5
"type":"G"
}]
var array2:[AnyObject] = [{
"Group":"M"
"sort_order": 3
"type":"G"
},{
"Group":"C"
"sort_order": 2
"type":"G"
},{
"Group":"D"
"sort_order": 6
"type":"G"
}]
arrays swift
arrays swift
edited Nov 26 '18 at 11:23
kit
1,10631017
1,10631017
asked Nov 26 '18 at 10:18
Nirav HathiNirav Hathi
4351518
4351518
if you merge them both, how will you know which is an object of array1 and which is that of array2 when you use it? or is it like this:name
from array1 is the same asgroup
from array2?
– Rakesha Shastri
Nov 26 '18 at 10:21
because I already created model classes for this objects
– Nirav Hathi
Nov 26 '18 at 10:24
For objects to be in the same array, they all have to be of the same type. So, if they are of the same type, sayAny
, how would you know which object is of which type when you want to access them from the said array.
– Rakesha Shastri
Nov 26 '18 at 10:25
you should be able to achieve that using protocol
– kathayatnk
Nov 26 '18 at 10:34
add a comment |
if you merge them both, how will you know which is an object of array1 and which is that of array2 when you use it? or is it like this:name
from array1 is the same asgroup
from array2?
– Rakesha Shastri
Nov 26 '18 at 10:21
because I already created model classes for this objects
– Nirav Hathi
Nov 26 '18 at 10:24
For objects to be in the same array, they all have to be of the same type. So, if they are of the same type, sayAny
, how would you know which object is of which type when you want to access them from the said array.
– Rakesha Shastri
Nov 26 '18 at 10:25
you should be able to achieve that using protocol
– kathayatnk
Nov 26 '18 at 10:34
if you merge them both, how will you know which is an object of array1 and which is that of array2 when you use it? or is it like this:
name
from array1 is the same as group
from array2?– Rakesha Shastri
Nov 26 '18 at 10:21
if you merge them both, how will you know which is an object of array1 and which is that of array2 when you use it? or is it like this:
name
from array1 is the same as group
from array2?– Rakesha Shastri
Nov 26 '18 at 10:21
because I already created model classes for this objects
– Nirav Hathi
Nov 26 '18 at 10:24
because I already created model classes for this objects
– Nirav Hathi
Nov 26 '18 at 10:24
For objects to be in the same array, they all have to be of the same type. So, if they are of the same type, say
Any
, how would you know which object is of which type when you want to access them from the said array.– Rakesha Shastri
Nov 26 '18 at 10:25
For objects to be in the same array, they all have to be of the same type. So, if they are of the same type, say
Any
, how would you know which object is of which type when you want to access them from the said array.– Rakesha Shastri
Nov 26 '18 at 10:25
you should be able to achieve that using protocol
– kathayatnk
Nov 26 '18 at 10:34
you should be able to achieve that using protocol
– kathayatnk
Nov 26 '18 at 10:34
add a comment |
4 Answers
4
active
oldest
votes
Ah, I guess, in good old Objective-C days, we could have used a sort predicate.
Well, those days are behind us and protocols are ministers in new Swift government.
Lets see what protocols can do in this case.
You could define a protocol that has sort_order as a property.
This protocol needs to be conformed by both your object types (A and B in below code. Also, made them Codable for yet more protocol magic).
Then you can create a merged array of type Ordered, and use sort function on that array.
protocol Ordered {
var sort_order:Int{get}
}
struct A:Codable, Ordered {
let name:String
let sort_order:Int
let type:String
}
struct B:Codable, Ordered {
let Group:String
let sort_order:Int
let type:String
}
var array1:[A] =
var array2:[B] =
var mergedArray:[Ordered] = array1
for item in array2 {
mergedArray.append(item)
}
mergedArray.sort { (A, B) -> Bool in
return A.sort_order < B.sort_order
}
add a comment |
Use this
var array1 : [[String : Any]] = [[ "name" : "obj1Array1", "sort_order" : 4, "type":"G" ],
[ "name":"obj2Array1","sort_order": 1,"type":"G"],
["name":"obj31Array1","sort_order": 5,"type":"G"]]
var array2 : [[String : Any]] = [[ "Group":"M", "sort_order": 3,"type":"G"],
["Group":"C", "sort_order": 2,"type":"G"],
["Group":"D","sort_order": 6,"type":"G"]]
let newArr = [array1, array2].flatMap({$0}).sorted(by: { ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) })
add a comment |
Here how you can do it using swift 4-
var array1: [[String: Any]] = [
["name": "obj1Array1", "sort_order": 4, "type": "G"],
["name": "obj2Array1", "sort_order": 1, "type": "G"],
["name": "obj3Array1", "sort_order": 5, "type": "G"]
]
var array2: [[String: Any]] = [
["Group": "M", "sort_order": 3, "type": "G"],
["Group": "C", "sort_order": 2, "type": "G"],
["Group": "D", "sort_order": 6, "type": "G"]
]
let mergedArray = array1 + array2
let sortedAndMerged = mergedArray.sorted{ ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) }
print(sortedAndMerged)
// prints [["type": "G", "name": "obj2Array1", "sort_order": 1], ["Group": "C", "sort_order": 2, "type": "G"], ["Group": "M", "sort_order": 3, "type": "G"], ["type": "G", "name": "obj1Array1", "sort_order": 4], ["type": "G", "name": "obj3Array1", "sort_order": 5], ["Group": "D", "sort_order": 6, "type": "G"]]
add a comment |
You can try like this
let array1: [[String:Any]] = [ [
"name":"obj1Array1",
"sort_order": 4,
"type":"G"
],
[
"name":"obj2Array1",
"sort_order":1,
"type":"G"
],
[
"name":"obj31Array1",
"sort_order":5,
"type":"G"
]]
let array2: [[String:Any]] = [ [
"Group":"M",
"sort_order": 3,
"type":"G"
],
[
"Group":"C",
"sort_order": 2,
"type":"G"
],
[
"Group":"D",
"sort_order": 6,
"type":"G"
]
]
var new = array1 + array2
new = new.sorted{
($0["sort_order"] as! Int) < ($1["sort_order"] as! Int)
}
print(new)
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Ah, I guess, in good old Objective-C days, we could have used a sort predicate.
Well, those days are behind us and protocols are ministers in new Swift government.
Lets see what protocols can do in this case.
You could define a protocol that has sort_order as a property.
This protocol needs to be conformed by both your object types (A and B in below code. Also, made them Codable for yet more protocol magic).
Then you can create a merged array of type Ordered, and use sort function on that array.
protocol Ordered {
var sort_order:Int{get}
}
struct A:Codable, Ordered {
let name:String
let sort_order:Int
let type:String
}
struct B:Codable, Ordered {
let Group:String
let sort_order:Int
let type:String
}
var array1:[A] =
var array2:[B] =
var mergedArray:[Ordered] = array1
for item in array2 {
mergedArray.append(item)
}
mergedArray.sort { (A, B) -> Bool in
return A.sort_order < B.sort_order
}
add a comment |
Ah, I guess, in good old Objective-C days, we could have used a sort predicate.
Well, those days are behind us and protocols are ministers in new Swift government.
Lets see what protocols can do in this case.
You could define a protocol that has sort_order as a property.
This protocol needs to be conformed by both your object types (A and B in below code. Also, made them Codable for yet more protocol magic).
Then you can create a merged array of type Ordered, and use sort function on that array.
protocol Ordered {
var sort_order:Int{get}
}
struct A:Codable, Ordered {
let name:String
let sort_order:Int
let type:String
}
struct B:Codable, Ordered {
let Group:String
let sort_order:Int
let type:String
}
var array1:[A] =
var array2:[B] =
var mergedArray:[Ordered] = array1
for item in array2 {
mergedArray.append(item)
}
mergedArray.sort { (A, B) -> Bool in
return A.sort_order < B.sort_order
}
add a comment |
Ah, I guess, in good old Objective-C days, we could have used a sort predicate.
Well, those days are behind us and protocols are ministers in new Swift government.
Lets see what protocols can do in this case.
You could define a protocol that has sort_order as a property.
This protocol needs to be conformed by both your object types (A and B in below code. Also, made them Codable for yet more protocol magic).
Then you can create a merged array of type Ordered, and use sort function on that array.
protocol Ordered {
var sort_order:Int{get}
}
struct A:Codable, Ordered {
let name:String
let sort_order:Int
let type:String
}
struct B:Codable, Ordered {
let Group:String
let sort_order:Int
let type:String
}
var array1:[A] =
var array2:[B] =
var mergedArray:[Ordered] = array1
for item in array2 {
mergedArray.append(item)
}
mergedArray.sort { (A, B) -> Bool in
return A.sort_order < B.sort_order
}
Ah, I guess, in good old Objective-C days, we could have used a sort predicate.
Well, those days are behind us and protocols are ministers in new Swift government.
Lets see what protocols can do in this case.
You could define a protocol that has sort_order as a property.
This protocol needs to be conformed by both your object types (A and B in below code. Also, made them Codable for yet more protocol magic).
Then you can create a merged array of type Ordered, and use sort function on that array.
protocol Ordered {
var sort_order:Int{get}
}
struct A:Codable, Ordered {
let name:String
let sort_order:Int
let type:String
}
struct B:Codable, Ordered {
let Group:String
let sort_order:Int
let type:String
}
var array1:[A] =
var array2:[B] =
var mergedArray:[Ordered] = array1
for item in array2 {
mergedArray.append(item)
}
mergedArray.sort { (A, B) -> Bool in
return A.sort_order < B.sort_order
}
edited Nov 26 '18 at 10:44
answered Nov 26 '18 at 10:35
Puneet SharmaPuneet Sharma
7,86011928
7,86011928
add a comment |
add a comment |
Use this
var array1 : [[String : Any]] = [[ "name" : "obj1Array1", "sort_order" : 4, "type":"G" ],
[ "name":"obj2Array1","sort_order": 1,"type":"G"],
["name":"obj31Array1","sort_order": 5,"type":"G"]]
var array2 : [[String : Any]] = [[ "Group":"M", "sort_order": 3,"type":"G"],
["Group":"C", "sort_order": 2,"type":"G"],
["Group":"D","sort_order": 6,"type":"G"]]
let newArr = [array1, array2].flatMap({$0}).sorted(by: { ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) })
add a comment |
Use this
var array1 : [[String : Any]] = [[ "name" : "obj1Array1", "sort_order" : 4, "type":"G" ],
[ "name":"obj2Array1","sort_order": 1,"type":"G"],
["name":"obj31Array1","sort_order": 5,"type":"G"]]
var array2 : [[String : Any]] = [[ "Group":"M", "sort_order": 3,"type":"G"],
["Group":"C", "sort_order": 2,"type":"G"],
["Group":"D","sort_order": 6,"type":"G"]]
let newArr = [array1, array2].flatMap({$0}).sorted(by: { ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) })
add a comment |
Use this
var array1 : [[String : Any]] = [[ "name" : "obj1Array1", "sort_order" : 4, "type":"G" ],
[ "name":"obj2Array1","sort_order": 1,"type":"G"],
["name":"obj31Array1","sort_order": 5,"type":"G"]]
var array2 : [[String : Any]] = [[ "Group":"M", "sort_order": 3,"type":"G"],
["Group":"C", "sort_order": 2,"type":"G"],
["Group":"D","sort_order": 6,"type":"G"]]
let newArr = [array1, array2].flatMap({$0}).sorted(by: { ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) })
Use this
var array1 : [[String : Any]] = [[ "name" : "obj1Array1", "sort_order" : 4, "type":"G" ],
[ "name":"obj2Array1","sort_order": 1,"type":"G"],
["name":"obj31Array1","sort_order": 5,"type":"G"]]
var array2 : [[String : Any]] = [[ "Group":"M", "sort_order": 3,"type":"G"],
["Group":"C", "sort_order": 2,"type":"G"],
["Group":"D","sort_order": 6,"type":"G"]]
let newArr = [array1, array2].flatMap({$0}).sorted(by: { ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) })
answered Nov 26 '18 at 10:34
dahiya_boydahiya_boy
5,54511031
5,54511031
add a comment |
add a comment |
Here how you can do it using swift 4-
var array1: [[String: Any]] = [
["name": "obj1Array1", "sort_order": 4, "type": "G"],
["name": "obj2Array1", "sort_order": 1, "type": "G"],
["name": "obj3Array1", "sort_order": 5, "type": "G"]
]
var array2: [[String: Any]] = [
["Group": "M", "sort_order": 3, "type": "G"],
["Group": "C", "sort_order": 2, "type": "G"],
["Group": "D", "sort_order": 6, "type": "G"]
]
let mergedArray = array1 + array2
let sortedAndMerged = mergedArray.sorted{ ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) }
print(sortedAndMerged)
// prints [["type": "G", "name": "obj2Array1", "sort_order": 1], ["Group": "C", "sort_order": 2, "type": "G"], ["Group": "M", "sort_order": 3, "type": "G"], ["type": "G", "name": "obj1Array1", "sort_order": 4], ["type": "G", "name": "obj3Array1", "sort_order": 5], ["Group": "D", "sort_order": 6, "type": "G"]]
add a comment |
Here how you can do it using swift 4-
var array1: [[String: Any]] = [
["name": "obj1Array1", "sort_order": 4, "type": "G"],
["name": "obj2Array1", "sort_order": 1, "type": "G"],
["name": "obj3Array1", "sort_order": 5, "type": "G"]
]
var array2: [[String: Any]] = [
["Group": "M", "sort_order": 3, "type": "G"],
["Group": "C", "sort_order": 2, "type": "G"],
["Group": "D", "sort_order": 6, "type": "G"]
]
let mergedArray = array1 + array2
let sortedAndMerged = mergedArray.sorted{ ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) }
print(sortedAndMerged)
// prints [["type": "G", "name": "obj2Array1", "sort_order": 1], ["Group": "C", "sort_order": 2, "type": "G"], ["Group": "M", "sort_order": 3, "type": "G"], ["type": "G", "name": "obj1Array1", "sort_order": 4], ["type": "G", "name": "obj3Array1", "sort_order": 5], ["Group": "D", "sort_order": 6, "type": "G"]]
add a comment |
Here how you can do it using swift 4-
var array1: [[String: Any]] = [
["name": "obj1Array1", "sort_order": 4, "type": "G"],
["name": "obj2Array1", "sort_order": 1, "type": "G"],
["name": "obj3Array1", "sort_order": 5, "type": "G"]
]
var array2: [[String: Any]] = [
["Group": "M", "sort_order": 3, "type": "G"],
["Group": "C", "sort_order": 2, "type": "G"],
["Group": "D", "sort_order": 6, "type": "G"]
]
let mergedArray = array1 + array2
let sortedAndMerged = mergedArray.sorted{ ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) }
print(sortedAndMerged)
// prints [["type": "G", "name": "obj2Array1", "sort_order": 1], ["Group": "C", "sort_order": 2, "type": "G"], ["Group": "M", "sort_order": 3, "type": "G"], ["type": "G", "name": "obj1Array1", "sort_order": 4], ["type": "G", "name": "obj3Array1", "sort_order": 5], ["Group": "D", "sort_order": 6, "type": "G"]]
Here how you can do it using swift 4-
var array1: [[String: Any]] = [
["name": "obj1Array1", "sort_order": 4, "type": "G"],
["name": "obj2Array1", "sort_order": 1, "type": "G"],
["name": "obj3Array1", "sort_order": 5, "type": "G"]
]
var array2: [[String: Any]] = [
["Group": "M", "sort_order": 3, "type": "G"],
["Group": "C", "sort_order": 2, "type": "G"],
["Group": "D", "sort_order": 6, "type": "G"]
]
let mergedArray = array1 + array2
let sortedAndMerged = mergedArray.sorted{ ($0["sort_order"] as! Int) < ($1["sort_order"] as! Int) }
print(sortedAndMerged)
// prints [["type": "G", "name": "obj2Array1", "sort_order": 1], ["Group": "C", "sort_order": 2, "type": "G"], ["Group": "M", "sort_order": 3, "type": "G"], ["type": "G", "name": "obj1Array1", "sort_order": 4], ["type": "G", "name": "obj3Array1", "sort_order": 5], ["Group": "D", "sort_order": 6, "type": "G"]]
answered Nov 26 '18 at 10:36
NivNiv
317211
317211
add a comment |
add a comment |
You can try like this
let array1: [[String:Any]] = [ [
"name":"obj1Array1",
"sort_order": 4,
"type":"G"
],
[
"name":"obj2Array1",
"sort_order":1,
"type":"G"
],
[
"name":"obj31Array1",
"sort_order":5,
"type":"G"
]]
let array2: [[String:Any]] = [ [
"Group":"M",
"sort_order": 3,
"type":"G"
],
[
"Group":"C",
"sort_order": 2,
"type":"G"
],
[
"Group":"D",
"sort_order": 6,
"type":"G"
]
]
var new = array1 + array2
new = new.sorted{
($0["sort_order"] as! Int) < ($1["sort_order"] as! Int)
}
print(new)
add a comment |
You can try like this
let array1: [[String:Any]] = [ [
"name":"obj1Array1",
"sort_order": 4,
"type":"G"
],
[
"name":"obj2Array1",
"sort_order":1,
"type":"G"
],
[
"name":"obj31Array1",
"sort_order":5,
"type":"G"
]]
let array2: [[String:Any]] = [ [
"Group":"M",
"sort_order": 3,
"type":"G"
],
[
"Group":"C",
"sort_order": 2,
"type":"G"
],
[
"Group":"D",
"sort_order": 6,
"type":"G"
]
]
var new = array1 + array2
new = new.sorted{
($0["sort_order"] as! Int) < ($1["sort_order"] as! Int)
}
print(new)
add a comment |
You can try like this
let array1: [[String:Any]] = [ [
"name":"obj1Array1",
"sort_order": 4,
"type":"G"
],
[
"name":"obj2Array1",
"sort_order":1,
"type":"G"
],
[
"name":"obj31Array1",
"sort_order":5,
"type":"G"
]]
let array2: [[String:Any]] = [ [
"Group":"M",
"sort_order": 3,
"type":"G"
],
[
"Group":"C",
"sort_order": 2,
"type":"G"
],
[
"Group":"D",
"sort_order": 6,
"type":"G"
]
]
var new = array1 + array2
new = new.sorted{
($0["sort_order"] as! Int) < ($1["sort_order"] as! Int)
}
print(new)
You can try like this
let array1: [[String:Any]] = [ [
"name":"obj1Array1",
"sort_order": 4,
"type":"G"
],
[
"name":"obj2Array1",
"sort_order":1,
"type":"G"
],
[
"name":"obj31Array1",
"sort_order":5,
"type":"G"
]]
let array2: [[String:Any]] = [ [
"Group":"M",
"sort_order": 3,
"type":"G"
],
[
"Group":"C",
"sort_order": 2,
"type":"G"
],
[
"Group":"D",
"sort_order": 6,
"type":"G"
]
]
var new = array1 + array2
new = new.sorted{
($0["sort_order"] as! Int) < ($1["sort_order"] as! Int)
}
print(new)
answered Nov 26 '18 at 10:38
Mahesh MMahesh M
357
357
add a comment |
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if you merge them both, how will you know which is an object of array1 and which is that of array2 when you use it? or is it like this:
name
from array1 is the same asgroup
from array2?– Rakesha Shastri
Nov 26 '18 at 10:21
because I already created model classes for this objects
– Nirav Hathi
Nov 26 '18 at 10:24
For objects to be in the same array, they all have to be of the same type. So, if they are of the same type, say
Any
, how would you know which object is of which type when you want to access them from the said array.– Rakesha Shastri
Nov 26 '18 at 10:25
you should be able to achieve that using protocol
– kathayatnk
Nov 26 '18 at 10:34