Extracting grouped objects into a flattened list












0












$begingroup$


I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.



So check the below:





  1. my original object

  2. my result object desired

  3. my slow solution (works, but is slow)




1. my original object:



  const data = [
{
"id": 1,
"name": "Application",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition": {
"step": "none"
},
"isDefault": false
}
]
}
]
},
{
"id": 3,
"name": "Processing",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
},
{
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
}
]
}
]
}
];


2. object desired:



 [
{
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
},
{
"id": 1078,
"code": "processing-auto-process",
"value": "0"
},
{
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
}
]


My slow solution:



const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ({ id: config.id, code: config.code, value: config.value })))).reduce((l,n) => l.concat(n), ).reduce((l2,n2) => l2.concat(n2),));









share|improve this question











$endgroup$








  • 2




    $begingroup$
    Is the ES6 spread operator available to you? result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value}))))))
    $endgroup$
    – Oh My Goodness
    5 hours ago












  • $begingroup$
    yes it is available.
    $endgroup$
    – Roger Oliveira
    5 hours ago










  • $begingroup$
    AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
    $endgroup$
    – Roger Oliveira
    5 hours ago
















0












$begingroup$


I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.



So check the below:





  1. my original object

  2. my result object desired

  3. my slow solution (works, but is slow)




1. my original object:



  const data = [
{
"id": 1,
"name": "Application",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition": {
"step": "none"
},
"isDefault": false
}
]
}
]
},
{
"id": 3,
"name": "Processing",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
},
{
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
}
]
}
]
}
];


2. object desired:



 [
{
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
},
{
"id": 1078,
"code": "processing-auto-process",
"value": "0"
},
{
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
}
]


My slow solution:



const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ({ id: config.id, code: config.code, value: config.value })))).reduce((l,n) => l.concat(n), ).reduce((l2,n2) => l2.concat(n2),));









share|improve this question











$endgroup$








  • 2




    $begingroup$
    Is the ES6 spread operator available to you? result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value}))))))
    $endgroup$
    – Oh My Goodness
    5 hours ago












  • $begingroup$
    yes it is available.
    $endgroup$
    – Roger Oliveira
    5 hours ago










  • $begingroup$
    AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
    $endgroup$
    – Roger Oliveira
    5 hours ago














0












0








0


1



$begingroup$


I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.



So check the below:





  1. my original object

  2. my result object desired

  3. my slow solution (works, but is slow)




1. my original object:



  const data = [
{
"id": 1,
"name": "Application",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition": {
"step": "none"
},
"isDefault": false
}
]
}
]
},
{
"id": 3,
"name": "Processing",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
},
{
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
}
]
}
]
}
];


2. object desired:



 [
{
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
},
{
"id": 1078,
"code": "processing-auto-process",
"value": "0"
},
{
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
}
]


My slow solution:



const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ({ id: config.id, code: config.code, value: config.value })))).reduce((l,n) => l.concat(n), ).reduce((l2,n2) => l2.concat(n2),));









share|improve this question











$endgroup$




I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.



So check the below:





  1. my original object

  2. my result object desired

  3. my slow solution (works, but is slow)




1. my original object:



  const data = [
{
"id": 1,
"name": "Application",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition": {
"step": "none"
},
"isDefault": false
}
]
}
]
},
{
"id": 3,
"name": "Processing",
"groups": [
{
"groupName": "",
"configurations": [
{
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
},
{
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
}
]
}
]
}
];


2. object desired:



 [
{
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
},
{
"id": 1078,
"code": "processing-auto-process",
"value": "0"
},
{
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
}
]


My slow solution:



const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ({ id: config.id, code: config.code, value: config.value })))).reduce((l,n) => l.concat(n), ).reduce((l2,n2) => l2.concat(n2),));






javascript ecmascript-6






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share|improve this question








edited 8 mins ago









200_success

130k17155419




130k17155419










asked 6 hours ago









Roger OliveiraRoger Oliveira

150111




150111








  • 2




    $begingroup$
    Is the ES6 spread operator available to you? result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value}))))))
    $endgroup$
    – Oh My Goodness
    5 hours ago












  • $begingroup$
    yes it is available.
    $endgroup$
    – Roger Oliveira
    5 hours ago










  • $begingroup$
    AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
    $endgroup$
    – Roger Oliveira
    5 hours ago














  • 2




    $begingroup$
    Is the ES6 spread operator available to you? result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value}))))))
    $endgroup$
    – Oh My Goodness
    5 hours ago












  • $begingroup$
    yes it is available.
    $endgroup$
    – Roger Oliveira
    5 hours ago










  • $begingroup$
    AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
    $endgroup$
    – Roger Oliveira
    5 hours ago








2




2




$begingroup$
Is the ES6 spread operator available to you? result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value}))))))
$endgroup$
– Oh My Goodness
5 hours ago






$begingroup$
Is the ES6 spread operator available to you? result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value}))))))
$endgroup$
– Oh My Goodness
5 hours ago














$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago




$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago












$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago




$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago










1 Answer
1






active

oldest

votes


















2












$begingroup$

As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:



result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value})))))) 





share|improve this answer









$endgroup$













  • $begingroup$
    also, the use of the command .flat() would help somehow in this solution? thanks.
    $endgroup$
    – Roger Oliveira
    2 hours ago












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:



result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value})))))) 





share|improve this answer









$endgroup$













  • $begingroup$
    also, the use of the command .flat() would help somehow in this solution? thanks.
    $endgroup$
    – Roger Oliveira
    2 hours ago
















2












$begingroup$

As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:



result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value})))))) 





share|improve this answer









$endgroup$













  • $begingroup$
    also, the use of the command .flat() would help somehow in this solution? thanks.
    $endgroup$
    – Roger Oliveira
    2 hours ago














2












2








2





$begingroup$

As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:



result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value})))))) 





share|improve this answer









$endgroup$



As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:



result = .concat(....concat(...data.map( d => d.groups.map( g => g.configurations.map( c => ({id:c.id, code:c.code, value:c.value})))))) 






share|improve this answer












share|improve this answer



share|improve this answer










answered 5 hours ago









Oh My GoodnessOh My Goodness

1,874314




1,874314












  • $begingroup$
    also, the use of the command .flat() would help somehow in this solution? thanks.
    $endgroup$
    – Roger Oliveira
    2 hours ago


















  • $begingroup$
    also, the use of the command .flat() would help somehow in this solution? thanks.
    $endgroup$
    – Roger Oliveira
    2 hours ago
















$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago




$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago


















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