error specified index is not a column of x (as_tbl_time)
I am trying to use as_tbl_time but I am receiving the error in the title.
library(tidyverse)
library(lubridate)
dates <- c("01/01/18 1:01:10 PM" ,"01/01/18 1:10:10 PM")
vals <- c(100, 200)
df <- data.frame(dates, vals)
df$dates <- dmy_hms(df$dates)
df <- as_tbl_time(df, index = df$dates)
r tibble
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
add a comment |
I am trying to use as_tbl_time but I am receiving the error in the title.
library(tidyverse)
library(lubridate)
dates <- c("01/01/18 1:01:10 PM" ,"01/01/18 1:10:10 PM")
vals <- c(100, 200)
df <- data.frame(dates, vals)
df$dates <- dmy_hms(df$dates)
df <- as_tbl_time(df, index = df$dates)
r tibble
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
add a comment |
I am trying to use as_tbl_time but I am receiving the error in the title.
library(tidyverse)
library(lubridate)
dates <- c("01/01/18 1:01:10 PM" ,"01/01/18 1:10:10 PM")
vals <- c(100, 200)
df <- data.frame(dates, vals)
df$dates <- dmy_hms(df$dates)
df <- as_tbl_time(df, index = df$dates)
r tibble
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
I am trying to use as_tbl_time but I am receiving the error in the title.
library(tidyverse)
library(lubridate)
dates <- c("01/01/18 1:01:10 PM" ,"01/01/18 1:10:10 PM")
vals <- c(100, 200)
df <- data.frame(dates, vals)
df$dates <- dmy_hms(df$dates)
df <- as_tbl_time(df, index = df$dates)
r tibble
r tibble
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
asked Nov 26 '18 at 10:21
GeorgeGeorge
2,831851114
2,831851114
add a comment |
add a comment |
1 Answer
1
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oldest
votes
From the documentation:
index The bare column name of the column to be used as the index.
So you just need the column name: tibbletime::as_tbl_time(df, index = dates)
Not df$.
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
From the documentation:
index The bare column name of the column to be used as the index.
So you just need the column name: tibbletime::as_tbl_time(df, index = dates)
Not df$.
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
add a comment |
From the documentation:
index The bare column name of the column to be used as the index.
So you just need the column name: tibbletime::as_tbl_time(df, index = dates)
Not df$.
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
add a comment |
From the documentation:
index The bare column name of the column to be used as the index.
So you just need the column name: tibbletime::as_tbl_time(df, index = dates)
Not df$.
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
From the documentation:
index The bare column name of the column to be used as the index.
So you just need the column name: tibbletime::as_tbl_time(df, index = dates)
Not df$.
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
answered Nov 26 '18 at 10:30
RLaveRLave
5,21911226
5,21911226
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
add a comment |
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
Thanks!I missed that!
– George
Nov 26 '18 at 10:33
add a comment |
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