grep: constructing a regex pattern to exclude several groups
I have a folder with three files:
$ ls
aaa.txt abc.txt def.txt
If I want to grep the output excluding the abc.txt file I can do:
$ ls | grep -v 'abc'
aaa.txt
def.txt
If I want to exclude two files I can do:
$ ls | grep -v 'abc' | grep -v 'def'
aaa.txt
But how can I do this using one regex and one grep invocation?
This does not work:
$ ls | grep -v '[(abc)(def)]'
neither does this:
$ ls | grep -v "abc|def"
grep
asked Nov 20 at 7:29
kurtgn
1,74521938
add a comment |
I have a folder with three files:
$ ls
aaa.txt abc.txt def.txt
If I want to grep the output excluding the abc.txt file I can do:
$ ls | grep -v 'abc'
aaa.txt
def.txt
If I want to exclude two files I can do:
$ ls | grep -v 'abc' | grep -v 'def'
aaa.txt
But how can I do this using one regex and one grep invocation?
This does not work:
$ ls | grep -v '[(abc)(def)]'
neither does this:
$ ls | grep -v "abc|def"
grep
asked Nov 20 at 7:29
kurtgn
1,74521938
add a comment |
I have a folder with three files:
$ ls
aaa.txt abc.txt def.txt
If I want to grep the output excluding the abc.txt file I can do:
$ ls | grep -v 'abc'
aaa.txt
def.txt
If I want to exclude two files I can do:
$ ls | grep -v 'abc' | grep -v 'def'
aaa.txt
But how can I do this using one regex and one grep invocation?
This does not work:
$ ls | grep -v '[(abc)(def)]'
neither does this:
$ ls | grep -v "abc|def"
grep
asked Nov 20 at 7:29
kurtgn
1,74521938
I have a folder with three files:
$ ls
aaa.txt abc.txt def.txt
If I want to grep the output excluding the abc.txt file I can do:
$ ls | grep -v 'abc'
aaa.txt
def.txt
If I want to exclude two files I can do:
$ ls | grep -v 'abc' | grep -v 'def'
aaa.txt
But how can I do this using one regex and one grep invocation?
This does not work:
$ ls | grep -v '[(abc)(def)]'
neither does this:
$ ls | grep -v "abc|def"
grep
grep
asked Nov 20 at 7:29
kurtgn
1,74521938
asked Nov 20 at 7:29
kurtgn
1,74521938
asked Nov 20 at 7:29
kurtgn
1,74521938
asked Nov 20 at 7:29
kurtgn
1,74521938
asked Nov 20 at 7:29
kurtgn
1,74521938
1,74521938
add a comment |
add a comment |
1 Answer
1
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oldest
votes
Use the ERE(Extended Regular Expression) pattern for the alternation match | which is not enabled by default in BRE (which grep uses by default)
grep -vE "abc|def"
or use the extended grep, i.e. egrep which enables the ERE by default
egrep -v "abc|def"
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use the ERE(Extended Regular Expression) pattern for the alternation match | which is not enabled by default in BRE (which grep uses by default)
grep -vE "abc|def"
or use the extended grep, i.e. egrep which enables the ERE by default
egrep -v "abc|def"
add a comment |
Use the ERE(Extended Regular Expression) pattern for the alternation match | which is not enabled by default in BRE (which grep uses by default)
grep -vE "abc|def"
or use the extended grep, i.e. egrep which enables the ERE by default
egrep -v "abc|def"
add a comment |
Use the ERE(Extended Regular Expression) pattern for the alternation match | which is not enabled by default in BRE (which grep uses by default)
grep -vE "abc|def"
or use the extended grep, i.e. egrep which enables the ERE by default
egrep -v "abc|def"
Use the ERE(Extended Regular Expression) pattern for the alternation match | which is not enabled by default in BRE (which grep uses by default)
grep -vE "abc|def"
or use the extended grep, i.e. egrep which enables the ERE by default
egrep -v "abc|def"
answered Nov 20 at 7:31
community wiki
Inian
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