python sequence order with optional values











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Looking for some help generating some code to create all the possible sequences based on permanent and optional values. Example...



The sequences are saved in a MySQL Db and the each value can be optional



So there is a sequence for example that returns the following order



1,2,3,4



1 & 2 are required
3 & 4 are optional



So the outcome would return the following sequence possibilities:
[1,2], [1,2,3,4], [1,2,3], [1,2,4]



Then I could compare a sequence to those to ensure the sequence received matches the order it should.



Any help is appreciated.










share|improve this question


























    up vote
    0
    down vote

    favorite












    Looking for some help generating some code to create all the possible sequences based on permanent and optional values. Example...



    The sequences are saved in a MySQL Db and the each value can be optional



    So there is a sequence for example that returns the following order



    1,2,3,4



    1 & 2 are required
    3 & 4 are optional



    So the outcome would return the following sequence possibilities:
    [1,2], [1,2,3,4], [1,2,3], [1,2,4]



    Then I could compare a sequence to those to ensure the sequence received matches the order it should.



    Any help is appreciated.










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Looking for some help generating some code to create all the possible sequences based on permanent and optional values. Example...



      The sequences are saved in a MySQL Db and the each value can be optional



      So there is a sequence for example that returns the following order



      1,2,3,4



      1 & 2 are required
      3 & 4 are optional



      So the outcome would return the following sequence possibilities:
      [1,2], [1,2,3,4], [1,2,3], [1,2,4]



      Then I could compare a sequence to those to ensure the sequence received matches the order it should.



      Any help is appreciated.










      share|improve this question













      Looking for some help generating some code to create all the possible sequences based on permanent and optional values. Example...



      The sequences are saved in a MySQL Db and the each value can be optional



      So there is a sequence for example that returns the following order



      1,2,3,4



      1 & 2 are required
      3 & 4 are optional



      So the outcome would return the following sequence possibilities:
      [1,2], [1,2,3,4], [1,2,3], [1,2,4]



      Then I could compare a sequence to those to ensure the sequence received matches the order it should.



      Any help is appreciated.







      python order sequence






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      asked Nov 19 at 19:18









      tsc1217

      32




      32
























          1 Answer
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          You are actually only interested in the superset of the "optional" sequence. You can get your output by finding this superset and append each of its members to the "required" list.



          from itertools import combinations

          required = [1, 2]
          optional = [3, 4]

          superset_optional = [combinations(optional, i) for i in range(len(optional) + 1)]
          for combinations in superset_optional:
          for comb in combinations :
          print(required + list(comb))

          # [1, 2]
          # [1, 2, 3]
          # [1, 2, 4]
          # [1, 2, 3, 4]





          share|improve this answer























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            You are actually only interested in the superset of the "optional" sequence. You can get your output by finding this superset and append each of its members to the "required" list.



            from itertools import combinations

            required = [1, 2]
            optional = [3, 4]

            superset_optional = [combinations(optional, i) for i in range(len(optional) + 1)]
            for combinations in superset_optional:
            for comb in combinations :
            print(required + list(comb))

            # [1, 2]
            # [1, 2, 3]
            # [1, 2, 4]
            # [1, 2, 3, 4]





            share|improve this answer



























              up vote
              0
              down vote



              accepted










              You are actually only interested in the superset of the "optional" sequence. You can get your output by finding this superset and append each of its members to the "required" list.



              from itertools import combinations

              required = [1, 2]
              optional = [3, 4]

              superset_optional = [combinations(optional, i) for i in range(len(optional) + 1)]
              for combinations in superset_optional:
              for comb in combinations :
              print(required + list(comb))

              # [1, 2]
              # [1, 2, 3]
              # [1, 2, 4]
              # [1, 2, 3, 4]





              share|improve this answer

























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                You are actually only interested in the superset of the "optional" sequence. You can get your output by finding this superset and append each of its members to the "required" list.



                from itertools import combinations

                required = [1, 2]
                optional = [3, 4]

                superset_optional = [combinations(optional, i) for i in range(len(optional) + 1)]
                for combinations in superset_optional:
                for comb in combinations :
                print(required + list(comb))

                # [1, 2]
                # [1, 2, 3]
                # [1, 2, 4]
                # [1, 2, 3, 4]





                share|improve this answer














                You are actually only interested in the superset of the "optional" sequence. You can get your output by finding this superset and append each of its members to the "required" list.



                from itertools import combinations

                required = [1, 2]
                optional = [3, 4]

                superset_optional = [combinations(optional, i) for i in range(len(optional) + 1)]
                for combinations in superset_optional:
                for comb in combinations :
                print(required + list(comb))

                # [1, 2]
                # [1, 2, 3]
                # [1, 2, 4]
                # [1, 2, 3, 4]






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 19 at 19:38

























                answered Nov 19 at 19:29









                DeepSpace

                35.5k44067




                35.5k44067






























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