(Beginner question) How do I get a specific data from an OpenWeatherMap API
I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.
But after searching for a few hours I still have no clue how I'm supposed to do it.
I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.
I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:
<a href="#" style="float:right;">Outside Temp: 6℃</a>
(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)
But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:
{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}
So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:
function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};
openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);
openweathermapapi.send();
}
After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.
Thank you
PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ
javascript html openweathermap
add a comment |
I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.
But after searching for a few hours I still have no clue how I'm supposed to do it.
I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.
I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:
<a href="#" style="float:right;">Outside Temp: 6℃</a>
(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)
But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:
{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}
So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:
function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};
openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);
openweathermapapi.send();
}
After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.
Thank you
PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ
javascript html openweathermap
Just add &units=imperial to the end of your API request URL.
– Caleb H.
Nov 20 '18 at 22:56
1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
Nov 21 '18 at 1:58
pls let me know if it worked
– Yash Soni
Dec 2 '18 at 19:38
I really appreciated the answer but sadly I didn't completely understand it and couldn't get it to work at the time. But my partner (our assignment was in groups) later got time and somehow got it working. So once again, thank you!
– Roy Zhou
Dec 5 '18 at 19:01
add a comment |
I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.
But after searching for a few hours I still have no clue how I'm supposed to do it.
I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.
I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:
<a href="#" style="float:right;">Outside Temp: 6℃</a>
(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)
But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:
{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}
So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:
function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};
openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);
openweathermapapi.send();
}
After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.
Thank you
PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ
javascript html openweathermap
I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.
But after searching for a few hours I still have no clue how I'm supposed to do it.
I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.
I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:
<a href="#" style="float:right;">Outside Temp: 6℃</a>
(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)
But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:
{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}
So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:
function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};
openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);
openweathermapapi.send();
}
After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.
Thank you
PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ
javascript html openweathermap
javascript html openweathermap
asked Nov 20 '18 at 22:53
Roy Zhou
61
61
Just add &units=imperial to the end of your API request URL.
– Caleb H.
Nov 20 '18 at 22:56
1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
Nov 21 '18 at 1:58
pls let me know if it worked
– Yash Soni
Dec 2 '18 at 19:38
I really appreciated the answer but sadly I didn't completely understand it and couldn't get it to work at the time. But my partner (our assignment was in groups) later got time and somehow got it working. So once again, thank you!
– Roy Zhou
Dec 5 '18 at 19:01
add a comment |
Just add &units=imperial to the end of your API request URL.
– Caleb H.
Nov 20 '18 at 22:56
1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
Nov 21 '18 at 1:58
pls let me know if it worked
– Yash Soni
Dec 2 '18 at 19:38
I really appreciated the answer but sadly I didn't completely understand it and couldn't get it to work at the time. But my partner (our assignment was in groups) later got time and somehow got it working. So once again, thank you!
– Roy Zhou
Dec 5 '18 at 19:01
Just add &units=imperial to the end of your API request URL.
– Caleb H.
Nov 20 '18 at 22:56
Just add &units=imperial to the end of your API request URL.
– Caleb H.
Nov 20 '18 at 22:56
1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
Nov 21 '18 at 1:58
1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
Nov 21 '18 at 1:58
pls let me know if it worked
– Yash Soni
Dec 2 '18 at 19:38
pls let me know if it worked
– Yash Soni
Dec 2 '18 at 19:38
I really appreciated the answer but sadly I didn't completely understand it and couldn't get it to work at the time. But my partner (our assignment was in groups) later got time and somehow got it working. So once again, thank you!
– Roy Zhou
Dec 5 '18 at 19:01
I really appreciated the answer but sadly I didn't completely understand it and couldn't get it to work at the time. But my partner (our assignment was in groups) later got time and somehow got it working. So once again, thank you!
– Roy Zhou
Dec 5 '18 at 19:01
add a comment |
1 Answer
1
active
oldest
votes
here's an example of getting current location's weather details
first get your current system's location using this
var getIP = 'http://ip-api.com/json/';
then, it returns you your location's details in json
THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag
var weatherjson = "";
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
})
})
Explanation of above code:-
the sample json returned
{
"coord": {
"lon": -122.08,
"lat": 37.39
},
"weather": [
{
"id": 721,
"main": "Haze",
"description": "haze",
"icon": "50n"
},
{
"id": 711,
"main": "Smoke",
"description": "smoke",
"icon": "50n"
}
],
"base": "stations",
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
"visibility": 11265,
"wind": {
"speed": 1.13,
"deg": 128.002
},
"clouds": {
"all": 90
},
"dt": 1542782400,
"sys": {
"type": 1,
"id": 471,
"message": 0.003,
"country": "US",
"sunrise": 1542812064,
"sunset": 1542848035
},
"id": 420006353,
"name": "Mountain View",
"cod": 200
}
The main column contains the degree of your own location named (TEMP)
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
Now we need to show the TEMPERATURE on display level
<a href="#" id="mytemp" style="float:right;">Outside Temp: 6℃</a>
given an identity to your temperature containing anchor tag named ID which is "mytemp"
now find the ID and update the temperature
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53402805%2fbeginner-question-how-do-i-get-a-specific-data-from-an-openweathermap-api%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
here's an example of getting current location's weather details
first get your current system's location using this
var getIP = 'http://ip-api.com/json/';
then, it returns you your location's details in json
THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag
var weatherjson = "";
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
})
})
Explanation of above code:-
the sample json returned
{
"coord": {
"lon": -122.08,
"lat": 37.39
},
"weather": [
{
"id": 721,
"main": "Haze",
"description": "haze",
"icon": "50n"
},
{
"id": 711,
"main": "Smoke",
"description": "smoke",
"icon": "50n"
}
],
"base": "stations",
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
"visibility": 11265,
"wind": {
"speed": 1.13,
"deg": 128.002
},
"clouds": {
"all": 90
},
"dt": 1542782400,
"sys": {
"type": 1,
"id": 471,
"message": 0.003,
"country": "US",
"sunrise": 1542812064,
"sunset": 1542848035
},
"id": 420006353,
"name": "Mountain View",
"cod": 200
}
The main column contains the degree of your own location named (TEMP)
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
Now we need to show the TEMPERATURE on display level
<a href="#" id="mytemp" style="float:right;">Outside Temp: 6℃</a>
given an identity to your temperature containing anchor tag named ID which is "mytemp"
now find the ID and update the temperature
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
add a comment |
here's an example of getting current location's weather details
first get your current system's location using this
var getIP = 'http://ip-api.com/json/';
then, it returns you your location's details in json
THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag
var weatherjson = "";
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
})
})
Explanation of above code:-
the sample json returned
{
"coord": {
"lon": -122.08,
"lat": 37.39
},
"weather": [
{
"id": 721,
"main": "Haze",
"description": "haze",
"icon": "50n"
},
{
"id": 711,
"main": "Smoke",
"description": "smoke",
"icon": "50n"
}
],
"base": "stations",
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
"visibility": 11265,
"wind": {
"speed": 1.13,
"deg": 128.002
},
"clouds": {
"all": 90
},
"dt": 1542782400,
"sys": {
"type": 1,
"id": 471,
"message": 0.003,
"country": "US",
"sunrise": 1542812064,
"sunset": 1542848035
},
"id": 420006353,
"name": "Mountain View",
"cod": 200
}
The main column contains the degree of your own location named (TEMP)
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
Now we need to show the TEMPERATURE on display level
<a href="#" id="mytemp" style="float:right;">Outside Temp: 6℃</a>
given an identity to your temperature containing anchor tag named ID which is "mytemp"
now find the ID and update the temperature
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
add a comment |
here's an example of getting current location's weather details
first get your current system's location using this
var getIP = 'http://ip-api.com/json/';
then, it returns you your location's details in json
THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag
var weatherjson = "";
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
})
})
Explanation of above code:-
the sample json returned
{
"coord": {
"lon": -122.08,
"lat": 37.39
},
"weather": [
{
"id": 721,
"main": "Haze",
"description": "haze",
"icon": "50n"
},
{
"id": 711,
"main": "Smoke",
"description": "smoke",
"icon": "50n"
}
],
"base": "stations",
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
"visibility": 11265,
"wind": {
"speed": 1.13,
"deg": 128.002
},
"clouds": {
"all": 90
},
"dt": 1542782400,
"sys": {
"type": 1,
"id": 471,
"message": 0.003,
"country": "US",
"sunrise": 1542812064,
"sunset": 1542848035
},
"id": 420006353,
"name": "Mountain View",
"cod": 200
}
The main column contains the degree of your own location named (TEMP)
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
Now we need to show the TEMPERATURE on display level
<a href="#" id="mytemp" style="float:right;">Outside Temp: 6℃</a>
given an identity to your temperature containing anchor tag named ID which is "mytemp"
now find the ID and update the temperature
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
here's an example of getting current location's weather details
first get your current system's location using this
var getIP = 'http://ip-api.com/json/';
then, it returns you your location's details in json
THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag
var weatherjson = "";
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
})
})
Explanation of above code:-
the sample json returned
{
"coord": {
"lon": -122.08,
"lat": 37.39
},
"weather": [
{
"id": 721,
"main": "Haze",
"description": "haze",
"icon": "50n"
},
{
"id": 711,
"main": "Smoke",
"description": "smoke",
"icon": "50n"
}
],
"base": "stations",
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
"visibility": 11265,
"wind": {
"speed": 1.13,
"deg": 128.002
},
"clouds": {
"all": 90
},
"dt": 1542782400,
"sys": {
"type": 1,
"id": 471,
"message": 0.003,
"country": "US",
"sunrise": 1542812064,
"sunset": 1542848035
},
"id": 420006353,
"name": "Mountain View",
"cod": 200
}
The main column contains the degree of your own location named (TEMP)
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
Now we need to show the TEMPERATURE on display level
<a href="#" id="mytemp" style="float:right;">Outside Temp: 6℃</a>
given an identity to your temperature containing anchor tag named ID which is "mytemp"
now find the ID and update the temperature
//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
answered Nov 21 '18 at 7:05
Yash Soni
47510
47510
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53402805%2fbeginner-question-how-do-i-get-a-specific-data-from-an-openweathermap-api%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Just add &units=imperial to the end of your API request URL.
– Caleb H.
Nov 20 '18 at 22:56
1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
Nov 21 '18 at 1:58
pls let me know if it worked
– Yash Soni
Dec 2 '18 at 19:38
I really appreciated the answer but sadly I didn't completely understand it and couldn't get it to work at the time. But my partner (our assignment was in groups) later got time and somehow got it working. So once again, thank you!
– Roy Zhou
Dec 5 '18 at 19:01