count files with regex in java
I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:
public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}
public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}
java regex
edited Nov 25 '18 at 4:53
uli
519313
asked Nov 25 '18 at 3:41
HanHan
84
add a comment |
I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:
public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}
public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}
java regex
edited Nov 25 '18 at 4:53
uli
519313
asked Nov 25 '18 at 3:41
HanHan
84
Typo: liatFiles
– Pavitra
Nov 25 '18 at 3:55
add a comment |
I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:
public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}
public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}
java regex
edited Nov 25 '18 at 4:53
uli
519313
asked Nov 25 '18 at 3:41
HanHan
84
I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:
public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}
public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}
java regex
java regex
edited Nov 25 '18 at 4:53
uli
519313
asked Nov 25 '18 at 3:41
HanHan
84
edited Nov 25 '18 at 4:53
uli
519313
asked Nov 25 '18 at 3:41
HanHan
84
edited Nov 25 '18 at 4:53
uli
519313
edited Nov 25 '18 at 4:53
uli
519313
edited Nov 25 '18 at 4:53
uli
519313
519313
asked Nov 25 '18 at 3:41
HanHan
84
asked Nov 25 '18 at 3:41
HanHan
84
asked Nov 25 '18 at 3:41
HanHan
84
84
Typo: liatFiles
– Pavitra
Nov 25 '18 at 3:55
add a comment |
Typo: liatFiles
– Pavitra
Nov 25 '18 at 3:55
Typo: liatFiles
– Pavitra
Nov 25 '18 at 3:55
Typo: liatFiles
– Pavitra
Nov 25 '18 at 3:55
add a comment |
2 Answers
2
active
oldest
votes
You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.
Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.
Thoughts:
input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.
answered Nov 25 '18 at 5:18
uliuli
519313
add a comment |
I think your regex should be
((d+))+.
You also need to escape special character to use this regex in Java code as followed:
(\(\d+\))+\.
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
The issue is withrealname.
– uli
Nov 25 '18 at 4:56
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.
Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.
Thoughts:
input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.
answered Nov 25 '18 at 5:18
uliuli
519313
add a comment |
You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.
Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.
Thoughts:
input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.
answered Nov 25 '18 at 5:18
uliuli
519313
add a comment |
You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.
Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.
Thoughts:
input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.
answered Nov 25 '18 at 5:18
uliuli
519313
You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.
Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.
Thoughts:
input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.
answered Nov 25 '18 at 5:18
uliuli
519313
answered Nov 25 '18 at 5:18
uliuli
519313
answered Nov 25 '18 at 5:18
uliuli
519313
answered Nov 25 '18 at 5:18
uliuli
519313
519313
add a comment |
add a comment |
I think your regex should be
((d+))+.
You also need to escape special character to use this regex in Java code as followed:
(\(\d+\))+\.
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
The issue is withrealname.
– uli
Nov 25 '18 at 4:56
add a comment |
I think your regex should be
((d+))+.
You also need to escape special character to use this regex in Java code as followed:
(\(\d+\))+\.
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
The issue is withrealname.
– uli
Nov 25 '18 at 4:56
add a comment |
I think your regex should be
((d+))+.
You also need to escape special character to use this regex in Java code as followed:
(\(\d+\))+\.
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
I think your regex should be
((d+))+.
You also need to escape special character to use this regex in Java code as followed:
(\(\d+\))+\.
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
answered Nov 25 '18 at 4:10
thanh ngothanh ngo
54939
54939
The issue is withrealname.
– uli
Nov 25 '18 at 4:56
add a comment |
The issue is withrealname.
– uli
Nov 25 '18 at 4:56
The issue is with
realname.– uli
Nov 25 '18 at 4:56
The issue is with
realname.– uli
Nov 25 '18 at 4:56
add a comment |
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Typo: liatFiles
– Pavitra
Nov 25 '18 at 3:55