Getting error on input []: findDistance() takes 0 positional arguments but 1 was given
The first part of my code is calculating the distance between two locations on Earth. The second part of my code is returning a list containing all of the cities stored in the database that are in the United States. The database is saved in a file named "city_data.db" containing a table named "cities" with columns ("country_code", "city_name", "region", "population", "latitude", "longitude"). Note that the country code for the United States is "us".
The third part of my code is returning a list containing all of the cities stored in the database that are in the United States sorted by their great circle distance from the city of Buffalo. Use (42.8864, -78.8784) for the latitude/longitude of Buffalo
I am getting error on input : findDistance() takes 0 positional arguments but 1 was given. What am I doing wrong?
import sqlite3
import math
conn = sqlite3.connect("city_data.db")
c = conn.cursor()
conn.commit()
#Part 1
def great_circle_distance(lat1, lon1, lat2, lon2):
radius = 6371
dlat = math.radians(lat2-lat1)
dlon = math.radians(lon2-lon1)
a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1))
* math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)
c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
d = radius * c
return d
#Part 2
def get_us_cities():
get_city = c.execute("SELECT * FROM cities WHERE country_code = 'us'").fetchall()
return [x for x in get_city]
#Part 3
def findDistance():
citieslist = get_us_cities()
lat1 = 42.8864
lon1 = -78.8784
lat2 = citieslist[4]
lon2= citieslist[5]
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
def closest_cities():
array = get_us_cities()
array.sort(key = findDistance)
return array
python sql database algorithm sorting
add a comment |
The first part of my code is calculating the distance between two locations on Earth. The second part of my code is returning a list containing all of the cities stored in the database that are in the United States. The database is saved in a file named "city_data.db" containing a table named "cities" with columns ("country_code", "city_name", "region", "population", "latitude", "longitude"). Note that the country code for the United States is "us".
The third part of my code is returning a list containing all of the cities stored in the database that are in the United States sorted by their great circle distance from the city of Buffalo. Use (42.8864, -78.8784) for the latitude/longitude of Buffalo
I am getting error on input : findDistance() takes 0 positional arguments but 1 was given. What am I doing wrong?
import sqlite3
import math
conn = sqlite3.connect("city_data.db")
c = conn.cursor()
conn.commit()
#Part 1
def great_circle_distance(lat1, lon1, lat2, lon2):
radius = 6371
dlat = math.radians(lat2-lat1)
dlon = math.radians(lon2-lon1)
a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1))
* math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)
c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
d = radius * c
return d
#Part 2
def get_us_cities():
get_city = c.execute("SELECT * FROM cities WHERE country_code = 'us'").fetchall()
return [x for x in get_city]
#Part 3
def findDistance():
citieslist = get_us_cities()
lat1 = 42.8864
lon1 = -78.8784
lat2 = citieslist[4]
lon2= citieslist[5]
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
def closest_cities():
array = get_us_cities()
array.sort(key = findDistance)
return array
python sql database algorithm sorting
add a comment |
The first part of my code is calculating the distance between two locations on Earth. The second part of my code is returning a list containing all of the cities stored in the database that are in the United States. The database is saved in a file named "city_data.db" containing a table named "cities" with columns ("country_code", "city_name", "region", "population", "latitude", "longitude"). Note that the country code for the United States is "us".
The third part of my code is returning a list containing all of the cities stored in the database that are in the United States sorted by their great circle distance from the city of Buffalo. Use (42.8864, -78.8784) for the latitude/longitude of Buffalo
I am getting error on input : findDistance() takes 0 positional arguments but 1 was given. What am I doing wrong?
import sqlite3
import math
conn = sqlite3.connect("city_data.db")
c = conn.cursor()
conn.commit()
#Part 1
def great_circle_distance(lat1, lon1, lat2, lon2):
radius = 6371
dlat = math.radians(lat2-lat1)
dlon = math.radians(lon2-lon1)
a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1))
* math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)
c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
d = radius * c
return d
#Part 2
def get_us_cities():
get_city = c.execute("SELECT * FROM cities WHERE country_code = 'us'").fetchall()
return [x for x in get_city]
#Part 3
def findDistance():
citieslist = get_us_cities()
lat1 = 42.8864
lon1 = -78.8784
lat2 = citieslist[4]
lon2= citieslist[5]
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
def closest_cities():
array = get_us_cities()
array.sort(key = findDistance)
return array
python sql database algorithm sorting
The first part of my code is calculating the distance between two locations on Earth. The second part of my code is returning a list containing all of the cities stored in the database that are in the United States. The database is saved in a file named "city_data.db" containing a table named "cities" with columns ("country_code", "city_name", "region", "population", "latitude", "longitude"). Note that the country code for the United States is "us".
The third part of my code is returning a list containing all of the cities stored in the database that are in the United States sorted by their great circle distance from the city of Buffalo. Use (42.8864, -78.8784) for the latitude/longitude of Buffalo
I am getting error on input : findDistance() takes 0 positional arguments but 1 was given. What am I doing wrong?
import sqlite3
import math
conn = sqlite3.connect("city_data.db")
c = conn.cursor()
conn.commit()
#Part 1
def great_circle_distance(lat1, lon1, lat2, lon2):
radius = 6371
dlat = math.radians(lat2-lat1)
dlon = math.radians(lon2-lon1)
a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1))
* math.cos(math.radians(lat2)) * math.sin(dlon/2) * math.sin(dlon/2)
c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
d = radius * c
return d
#Part 2
def get_us_cities():
get_city = c.execute("SELECT * FROM cities WHERE country_code = 'us'").fetchall()
return [x for x in get_city]
#Part 3
def findDistance():
citieslist = get_us_cities()
lat1 = 42.8864
lon1 = -78.8784
lat2 = citieslist[4]
lon2= citieslist[5]
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
def closest_cities():
array = get_us_cities()
array.sort(key = findDistance)
return array
python sql database algorithm sorting
python sql database algorithm sorting
edited Nov 25 '18 at 4:27
asked Nov 25 '18 at 4:14
user10649535
add a comment |
add a comment |
1 Answer
1
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oldest
votes
You're doing
array.sort(key = findDistance)
That means that the sorting algorithm is using findDistance()
to find a "key" for each value it's sorting. Basically, it takes a list, does findDistance()
for every item in that list, and then sorts the list according to the return values. As such, array.sort()
expects that whatever it's given as a key
will be able to take one value and spit out another value that can be used for sorting.
I don't know how you're structuring your database, or what format your array is going to be in, but let's assume for this example that each item in the array is a list, with indexes corresponding to the columns you listed (for example, "latitude" would be index 4
, "longitude would be index 5
, etc). Then, you'd want to rewrite findDistance()
to take one of those as a parameter:
def findDistance(city):
lat1 = 42.8864
lon1 = -78.8784
lat2 = city[4] # notice how we're using the variable that was passed in,
lon2 = city[5] # instead of accessing get_us_cities()
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
1
Don't forget,get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you callarray.sort()
, you're doing it on an array that you already initialized to that list of cities. Thesort()
function will automatically apply the key to each element of that list, by passing that element intofindDistance()
. So,get_us_cities()
is already involved by the timefindDistance()
is called - you don't have to bring it in again.
– Green Cloak Guy
Nov 25 '18 at 5:01
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
You're doing
array.sort(key = findDistance)
That means that the sorting algorithm is using findDistance()
to find a "key" for each value it's sorting. Basically, it takes a list, does findDistance()
for every item in that list, and then sorts the list according to the return values. As such, array.sort()
expects that whatever it's given as a key
will be able to take one value and spit out another value that can be used for sorting.
I don't know how you're structuring your database, or what format your array is going to be in, but let's assume for this example that each item in the array is a list, with indexes corresponding to the columns you listed (for example, "latitude" would be index 4
, "longitude would be index 5
, etc). Then, you'd want to rewrite findDistance()
to take one of those as a parameter:
def findDistance(city):
lat1 = 42.8864
lon1 = -78.8784
lat2 = city[4] # notice how we're using the variable that was passed in,
lon2 = city[5] # instead of accessing get_us_cities()
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
1
Don't forget,get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you callarray.sort()
, you're doing it on an array that you already initialized to that list of cities. Thesort()
function will automatically apply the key to each element of that list, by passing that element intofindDistance()
. So,get_us_cities()
is already involved by the timefindDistance()
is called - you don't have to bring it in again.
– Green Cloak Guy
Nov 25 '18 at 5:01
add a comment |
You're doing
array.sort(key = findDistance)
That means that the sorting algorithm is using findDistance()
to find a "key" for each value it's sorting. Basically, it takes a list, does findDistance()
for every item in that list, and then sorts the list according to the return values. As such, array.sort()
expects that whatever it's given as a key
will be able to take one value and spit out another value that can be used for sorting.
I don't know how you're structuring your database, or what format your array is going to be in, but let's assume for this example that each item in the array is a list, with indexes corresponding to the columns you listed (for example, "latitude" would be index 4
, "longitude would be index 5
, etc). Then, you'd want to rewrite findDistance()
to take one of those as a parameter:
def findDistance(city):
lat1 = 42.8864
lon1 = -78.8784
lat2 = city[4] # notice how we're using the variable that was passed in,
lon2 = city[5] # instead of accessing get_us_cities()
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
1
Don't forget,get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you callarray.sort()
, you're doing it on an array that you already initialized to that list of cities. Thesort()
function will automatically apply the key to each element of that list, by passing that element intofindDistance()
. So,get_us_cities()
is already involved by the timefindDistance()
is called - you don't have to bring it in again.
– Green Cloak Guy
Nov 25 '18 at 5:01
add a comment |
You're doing
array.sort(key = findDistance)
That means that the sorting algorithm is using findDistance()
to find a "key" for each value it's sorting. Basically, it takes a list, does findDistance()
for every item in that list, and then sorts the list according to the return values. As such, array.sort()
expects that whatever it's given as a key
will be able to take one value and spit out another value that can be used for sorting.
I don't know how you're structuring your database, or what format your array is going to be in, but let's assume for this example that each item in the array is a list, with indexes corresponding to the columns you listed (for example, "latitude" would be index 4
, "longitude would be index 5
, etc). Then, you'd want to rewrite findDistance()
to take one of those as a parameter:
def findDistance(city):
lat1 = 42.8864
lon1 = -78.8784
lat2 = city[4] # notice how we're using the variable that was passed in,
lon2 = city[5] # instead of accessing get_us_cities()
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
You're doing
array.sort(key = findDistance)
That means that the sorting algorithm is using findDistance()
to find a "key" for each value it's sorting. Basically, it takes a list, does findDistance()
for every item in that list, and then sorts the list according to the return values. As such, array.sort()
expects that whatever it's given as a key
will be able to take one value and spit out another value that can be used for sorting.
I don't know how you're structuring your database, or what format your array is going to be in, but let's assume for this example that each item in the array is a list, with indexes corresponding to the columns you listed (for example, "latitude" would be index 4
, "longitude would be index 5
, etc). Then, you'd want to rewrite findDistance()
to take one of those as a parameter:
def findDistance(city):
lat1 = 42.8864
lon1 = -78.8784
lat2 = city[4] # notice how we're using the variable that was passed in,
lon2 = city[5] # instead of accessing get_us_cities()
distance = great_circle_distance(lat1, lon1, lat2, lon2)
return distance
answered Nov 25 '18 at 4:40
Green Cloak GuyGreen Cloak Guy
2,9441720
2,9441720
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
1
Don't forget,get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you callarray.sort()
, you're doing it on an array that you already initialized to that list of cities. Thesort()
function will automatically apply the key to each element of that list, by passing that element intofindDistance()
. So,get_us_cities()
is already involved by the timefindDistance()
is called - you don't have to bring it in again.
– Green Cloak Guy
Nov 25 '18 at 5:01
add a comment |
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
1
Don't forget,get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you callarray.sort()
, you're doing it on an array that you already initialized to that list of cities. Thesort()
function will automatically apply the key to each element of that list, by passing that element intofindDistance()
. So,get_us_cities()
is already involved by the timefindDistance()
is called - you don't have to bring it in again.
– Green Cloak Guy
Nov 25 '18 at 5:01
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
Can you explain a little bit more of why I want to pass city as a parameter to finddistance() instead of trying to access latitude and longitude from get_us_cities(). Because somehow, your code gives me the correct output.
– user10649535
Nov 25 '18 at 4:55
1
1
Don't forget,
get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you call array.sort()
, you're doing it on an array that you already initialized to that list of cities. The sort()
function will automatically apply the key to each element of that list, by passing that element into findDistance()
. So, get_us_cities()
is already involved by the time findDistance()
is called - you don't have to bring it in again.– Green Cloak Guy
Nov 25 '18 at 5:01
Don't forget,
get_us_cities()
gives you the entire list of cities (or a list of lists, in this case) - when you call array.sort()
, you're doing it on an array that you already initialized to that list of cities. The sort()
function will automatically apply the key to each element of that list, by passing that element into findDistance()
. So, get_us_cities()
is already involved by the time findDistance()
is called - you don't have to bring it in again.– Green Cloak Guy
Nov 25 '18 at 5:01
add a comment |
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