Java Script - Regular Expression matching a word in a string

-1

I am trying to find a match in a string with JavaScript. I want to work with the RegEx function.

My example (what I have tried):

var str = "hello.you"; 

var patt1 = '\b' + str + '\b';

var result = str.match(patt1);

But this does not give me the result which I except. I just want to print "you".

Thanks all in advance.

asked Nov 20 '18 at 19:34

Lia

608

1

Why do you expect you when you use /bhello.youb/ regex against hello.you string? What are you trying to achieve?
– Wiktor Stribiżew
Nov 20 '18 at 19:36

Thx for your answer. I just wanted to show what I have tried so far. I want to print the word "you" in the string "hello.you" with Regex @WiktorStribiżew
– Lia
Nov 20 '18 at 19:42

@Lia You don't need regex for that. Just return the word "you" and you're done. Unless there are different variations of that string? In that case you really should elaborate on what you expect if the string is not "hello.you". Do you want to get everything after the dot? What if there is more than one dot? Be specific.
– Ivar
Nov 20 '18 at 19:49

1

Then use result = str.match(/.(w+)/)[1]. Or str.match(/.([^.]+)/)[1]. Or just str.split('.')[1]
– Wiktor Stribiżew
Nov 20 '18 at 19:49

1

Note it won't work in case of Привет.Петя (=Russian for Hello.Peter) because w does not match non-ASCII letters and digits.
– Wiktor Stribiżew
Nov 20 '18 at 19:55

|
show 2 more comments

-1

I am trying to find a match in a string with JavaScript. I want to work with the RegEx function.

My example (what I have tried):

var str = "hello.you"; 

var patt1 = '\b' + str + '\b';

var result = str.match(patt1);

But this does not give me the result which I except. I just want to print "you".

Thanks all in advance.

asked Nov 20 '18 at 19:34

Lia

608

1

Why do you expect you when you use /bhello.youb/ regex against hello.you string? What are you trying to achieve?
– Wiktor Stribiżew
Nov 20 '18 at 19:36

Thx for your answer. I just wanted to show what I have tried so far. I want to print the word "you" in the string "hello.you" with Regex @WiktorStribiżew
– Lia
Nov 20 '18 at 19:42

@Lia You don't need regex for that. Just return the word "you" and you're done. Unless there are different variations of that string? In that case you really should elaborate on what you expect if the string is not "hello.you". Do you want to get everything after the dot? What if there is more than one dot? Be specific.
– Ivar
Nov 20 '18 at 19:49

1

Then use result = str.match(/.(w+)/)[1]. Or str.match(/.([^.]+)/)[1]. Or just str.split('.')[1]
– Wiktor Stribiżew
Nov 20 '18 at 19:49

1

Note it won't work in case of Привет.Петя (=Russian for Hello.Peter) because w does not match non-ASCII letters and digits.
– Wiktor Stribiżew
Nov 20 '18 at 19:55

|
show 2 more comments

-1

I am trying to find a match in a string with JavaScript. I want to work with the RegEx function.

My example (what I have tried):

var str = "hello.you"; 

var patt1 = '\b' + str + '\b';

var result = str.match(patt1);

But this does not give me the result which I except. I just want to print "you".

Thanks all in advance.

asked Nov 20 '18 at 19:34

Lia

608

I am trying to find a match in a string with JavaScript. I want to work with the RegEx function.

My example (what I have tried):

var str = "hello.you"; 

var patt1 = '\b' + str + '\b';

var result = str.match(patt1);

But this does not give me the result which I except. I just want to print "you".

Thanks all in advance.

javascript regex

asked Nov 20 '18 at 19:34

Lia

608

asked Nov 20 '18 at 19:34

Lia

608

asked Nov 20 '18 at 19:34

Lia

608

asked Nov 20 '18 at 19:34

Lia

608

asked Nov 20 '18 at 19:34

Lia

608

1

Why do you expect you when you use /bhello.youb/ regex against hello.you string? What are you trying to achieve?
– Wiktor Stribiżew
Nov 20 '18 at 19:36

Thx for your answer. I just wanted to show what I have tried so far. I want to print the word "you" in the string "hello.you" with Regex @WiktorStribiżew
– Lia
Nov 20 '18 at 19:42

@Lia You don't need regex for that. Just return the word "you" and you're done. Unless there are different variations of that string? In that case you really should elaborate on what you expect if the string is not "hello.you". Do you want to get everything after the dot? What if there is more than one dot? Be specific.
– Ivar
Nov 20 '18 at 19:49

1

Then use result = str.match(/.(w+)/)[1]. Or str.match(/.([^.]+)/)[1]. Or just str.split('.')[1]
– Wiktor Stribiżew
Nov 20 '18 at 19:49

1

Note it won't work in case of Привет.Петя (=Russian for Hello.Peter) because w does not match non-ASCII letters and digits.
– Wiktor Stribiżew
Nov 20 '18 at 19:55

|
show 2 more comments

1

Why do you expect you when you use /bhello.youb/ regex against hello.you string? What are you trying to achieve?
– Wiktor Stribiżew
Nov 20 '18 at 19:36

Thx for your answer. I just wanted to show what I have tried so far. I want to print the word "you" in the string "hello.you" with Regex @WiktorStribiżew
– Lia
Nov 20 '18 at 19:42

@Lia You don't need regex for that. Just return the word "you" and you're done. Unless there are different variations of that string? In that case you really should elaborate on what you expect if the string is not "hello.you". Do you want to get everything after the dot? What if there is more than one dot? Be specific.
– Ivar
Nov 20 '18 at 19:49

1

Then use result = str.match(/.(w+)/)[1]. Or str.match(/.([^.]+)/)[1]. Or just str.split('.')[1]
– Wiktor Stribiżew
Nov 20 '18 at 19:49

1

Note it won't work in case of Привет.Петя (=Russian for Hello.Peter) because w does not match non-ASCII letters and digits.
– Wiktor Stribiżew
Nov 20 '18 at 19:55

Why do you expect you when you use /bhello.youb/ regex against hello.you string? What are you trying to achieve?
– Wiktor Stribiżew
Nov 20 '18 at 19:36

Thx for your answer. I just wanted to show what I have tried so far. I want to print the word "you" in the string "hello.you" with Regex @WiktorStribiżew
– Lia
Nov 20 '18 at 19:42

@Lia You don't need regex for that. Just return the word "you" and you're done. Unless there are different variations of that string? In that case you really should elaborate on what you expect if the string is not "hello.you". Do you want to get everything after the dot? What if there is more than one dot? Be specific.
– Ivar
Nov 20 '18 at 19:49

Then use result = str.match(/.(w+)/)[1]. Or str.match(/.([^.]+)/)[1]. Or just str.split('.')[1]
– Wiktor Stribiżew
Nov 20 '18 at 19:49

Note it won't work in case of Привет.Петя (=Russian for Hello.Peter) because w does not match non-ASCII letters and digits.
– Wiktor Stribiżew
Nov 20 '18 at 19:55

|
show 2 more comments

1 Answer
1

active

oldest

votes

So you jumped right into a pretty advanced regex topic. You sort of want to do a lookahead (the word AFTER a given boundary character). The following will get you there:

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

... And what that does, is uses (?<=.) to indicate "something that comes after a period", followed by w+ to indicate a word.

I'd recommend using a regex tester, and build from that. I use https://www.regextester.com/

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

Running the code snippet returns SyntaxError: invalid regexp group when using Firefox.
– ams
Nov 20 '18 at 20:02

Wondering if FireFox is supporting lookaheads/lookbehinds yet.
– Snowmonkey
Nov 23 '18 at 20:20

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

So you jumped right into a pretty advanced regex topic. You sort of want to do a lookahead (the word AFTER a given boundary character). The following will get you there:

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

... And what that does, is uses (?<=.) to indicate "something that comes after a period", followed by w+ to indicate a word.

I'd recommend using a regex tester, and build from that. I use https://www.regextester.com/

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

Running the code snippet returns SyntaxError: invalid regexp group when using Firefox.
– ams
Nov 20 '18 at 20:02

Wondering if FireFox is supporting lookaheads/lookbehinds yet.
– Snowmonkey
Nov 23 '18 at 20:20

add a comment |

So you jumped right into a pretty advanced regex topic. You sort of want to do a lookahead (the word AFTER a given boundary character). The following will get you there:

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

... And what that does, is uses (?<=.) to indicate "something that comes after a period", followed by w+ to indicate a word.

I'd recommend using a regex tester, and build from that. I use https://www.regextester.com/

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

Running the code snippet returns SyntaxError: invalid regexp group when using Firefox.
– ams
Nov 20 '18 at 20:02

Wondering if FireFox is supporting lookaheads/lookbehinds yet.
– Snowmonkey
Nov 23 '18 at 20:20

add a comment |

So you jumped right into a pretty advanced regex topic. You sort of want to do a lookahead (the word AFTER a given boundary character). The following will get you there:

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

... And what that does, is uses (?<=.) to indicate "something that comes after a period", followed by w+ to indicate a word.

I'd recommend using a regex tester, and build from that. I use https://www.regextester.com/

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

So you jumped right into a pretty advanced regex topic. You sort of want to do a lookahead (the word AFTER a given boundary character). The following will get you there:

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

... And what that does, is uses (?<=.) to indicate "something that comes after a period", followed by w+ to indicate a word.

I'd recommend using a regex tester, and build from that. I use https://www.regextester.com/

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

let str = "hello.you",

    myRegex = /(?<=.)w+/;

    

let theWord = str.match(myRegex);

console.log(theWord[0]);

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

answered Nov 20 '18 at 19:46

Snowmonkey

2,8571912

Running the code snippet returns SyntaxError: invalid regexp group when using Firefox.
– ams
Nov 20 '18 at 20:02

Wondering if FireFox is supporting lookaheads/lookbehinds yet.
– Snowmonkey
Nov 23 '18 at 20:20

add a comment |

Running the code snippet returns SyntaxError: invalid regexp group when using Firefox.
– ams
Nov 20 '18 at 20:02

Wondering if FireFox is supporting lookaheads/lookbehinds yet.
– Snowmonkey
Nov 23 '18 at 20:20

Running the code snippet returns SyntaxError: invalid regexp group when using Firefox.
– ams
Nov 20 '18 at 20:02

Wondering if FireFox is supporting lookaheads/lookbehinds yet.
– Snowmonkey
Nov 23 '18 at 20:20

add a comment |

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