Filter out array to have only unique values

up vote
11
down vote

favorite

I need to filter out my array to contain only unique values.
this is my array data

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

expected result should be

["X_row7", "X_row4", "X_row6", "X_row10", "X_row11", "X_row8"]

How should i continue my code to get proper result.

newArray = ;

for(n in data){

  if(!newArray.indexOf(n)){

     newArray.push(n);

  }

}

console.log(newArray);

If you need any additional information's please let me know and i will provide. thank you

asked Jul 5 '16 at 15:08

Valor_

97822157

Possible duplicate of Unique values in an array
– Schleis
Jul 5 '16 at 15:10

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].filter(function(v,i,arr){ return i==arr.indexOf(v); })
– Pranav C Balan
Jul 5 '16 at 15:11

Possible duplicate of How to get unique values in an array
– Adeel Imran
Dec 25 '17 at 19:34

add a comment |

up vote
11
down vote

favorite

I need to filter out my array to contain only unique values.
this is my array data

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

expected result should be

["X_row7", "X_row4", "X_row6", "X_row10", "X_row11", "X_row8"]

How should i continue my code to get proper result.

newArray = ;

for(n in data){

  if(!newArray.indexOf(n)){

     newArray.push(n);

  }

}

console.log(newArray);

If you need any additional information's please let me know and i will provide. thank you

asked Jul 5 '16 at 15:08

Valor_

97822157

Possible duplicate of Unique values in an array
– Schleis
Jul 5 '16 at 15:10

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].filter(function(v,i,arr){ return i==arr.indexOf(v); })
– Pranav C Balan
Jul 5 '16 at 15:11

Possible duplicate of How to get unique values in an array
– Adeel Imran
Dec 25 '17 at 19:34

add a comment |

up vote
11
down vote

favorite

I need to filter out my array to contain only unique values.
this is my array data

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

expected result should be

["X_row7", "X_row4", "X_row6", "X_row10", "X_row11", "X_row8"]

How should i continue my code to get proper result.

newArray = ;

for(n in data){

  if(!newArray.indexOf(n)){

     newArray.push(n);

  }

}

console.log(newArray);

If you need any additional information's please let me know and i will provide. thank you

asked Jul 5 '16 at 15:08

Valor_

97822157

I need to filter out my array to contain only unique values.
this is my array data

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

expected result should be

["X_row7", "X_row4", "X_row6", "X_row10", "X_row11", "X_row8"]

How should i continue my code to get proper result.

newArray = ;

for(n in data){

  if(!newArray.indexOf(n)){

     newArray.push(n);

  }

}

console.log(newArray);

If you need any additional information's please let me know and i will provide. thank you

javascript arrays

asked Jul 5 '16 at 15:08

Valor_

97822157

asked Jul 5 '16 at 15:08

Valor_

97822157

asked Jul 5 '16 at 15:08

Valor_

97822157

asked Jul 5 '16 at 15:08

Valor_

97822157

asked Jul 5 '16 at 15:08

Valor_

97822157

Possible duplicate of Unique values in an array
– Schleis
Jul 5 '16 at 15:10

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].filter(function(v,i,arr){ return i==arr.indexOf(v); })
– Pranav C Balan
Jul 5 '16 at 15:11

Possible duplicate of How to get unique values in an array
– Adeel Imran
Dec 25 '17 at 19:34

add a comment |

Possible duplicate of Unique values in an array
– Schleis
Jul 5 '16 at 15:10

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].filter(function(v,i,arr){ return i==arr.indexOf(v); })
– Pranav C Balan
Jul 5 '16 at 15:11

Possible duplicate of How to get unique values in an array
– Adeel Imran
Dec 25 '17 at 19:34

Possible duplicate of Unique values in an array
– Schleis
Jul 5 '16 at 15:10

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].filter(function(v,i,arr){ return i==arr.indexOf(v); })

– Pranav C Balan
Jul 5 '16 at 15:11

["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].filter(function(v,i,arr){ return i==arr.indexOf(v); })

– Pranav C Balan
Jul 5 '16 at 15:11

Possible duplicate of How to get unique values in an array
– Adeel Imran
Dec 25 '17 at 19:34

add a comment |

10 Answers
10

active

oldest

votes

up vote
35
down vote

accepted

You can use Array.filter function to filter out elements of an array based on the return value of a callback function. The callback function runs for every element of the original array.

The logic for the callback function here is that if the indexOf value for current item is same as the index, it means the element has been encountered first time, so it can be considered unique. If not, it means the element has been encountered already, so should be discarded now.

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

UPDATE (16 Nov 2017)

If you can rely on ES6 features, then you can use Set object and Spread operator to create a unique array from a given array, as already specified in @Travis Heeter's answer below:

var uniqueArray = [...new Set(array)]

edited Nov 21 '17 at 12:16

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

2

this is brilliant
– oMiKeY
Nov 15 '17 at 20:10

add a comment |

up vote
13
down vote

As of June 15, 2015 you may use Set() to create a unique array:

var uniqueArray = [...new Set(array)]

For your Example:

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

var newArray = [...new Set(data)]

console.log(newArray)



>> ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

edited Apr 27 '17 at 20:00

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

add a comment |

up vote
5
down vote

You could use a hash table for look up and filter all not included values.

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

edited Nov 11 '17 at 15:45

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

add a comment |

up vote
3
down vote

You can use Map and Spread Operator:

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

add a comment |

up vote
3
down vote

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

1

Please provide context to the code
– Clíodhna
Sep 7 '17 at 9:48

add a comment |

up vote
2
down vote

You can use reduce to loop the array and get the not duplicate values. Also uses an aux object to get the count of added values.

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

add a comment |

up vote
2
down vote

Filtering an array to contain unique values can be achieved using the JavaScript Set and Array.from method, as shown below:

Array.from(new Set(arrayOfNonUniqueValues));

Set

The Set object lets you store unique values of any type, whether
primitive values or object references.

Return value A new Set object.

Array.from()

The Array.from() method creates a new Array instance from an
array-like or iterable object.

Return value A new Array instance.

Example Code:

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

answered Feb 10 at 23:57

JSON C11

3,38443537

add a comment |

up vote
1
down vote

A slight variation on the indexOf method, if you need to filter multiple arrays:

function unique(item, index, array) {

    return array.indexOf(item) == index;

}

Use as such:

arr.filter(unique);

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

add a comment |

up vote
1
down vote

I've always used:

unique = (arr) => arr.filter((item, i, s) => s.lastIndexOf(item) == i);

But recently I had to get unique values for:

["1", 1, "2", 2, "3", 3]

And my old standby didn't cut it, so I came up with this:

uunique = (arr) => Object.keys(Object.assign({}, ...arr.map(a=>({[a]:true}))));

answered Jan 24 at 6:44

TennisVisuals

16916

add a comment |

up vote
1
down vote

Array.prototype.unique = function () {

  return [...new Set(this)]

}

then we can write:

const arr = [1, 5, 2, 2, 2, 3, 4, 3, 2, 1, 5]

const uniqueArr = arr.unique()

answered Nov 19 at 7:20

Zuhair Taha

6921922

add a comment |

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10 Answers
10

active

oldest

votes

10 Answers
10

active

oldest

votes

up vote
35
down vote

accepted

You can use Array.filter function to filter out elements of an array based on the return value of a callback function. The callback function runs for every element of the original array.

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

UPDATE (16 Nov 2017)

If you can rely on ES6 features, then you can use Set object and Spread operator to create a unique array from a given array, as already specified in @Travis Heeter's answer below:

var uniqueArray = [...new Set(array)]

edited Nov 21 '17 at 12:16

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

2

this is brilliant
– oMiKeY
Nov 15 '17 at 20:10

add a comment |

up vote
35
down vote

accepted

You can use Array.filter function to filter out elements of an array based on the return value of a callback function. The callback function runs for every element of the original array.

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

UPDATE (16 Nov 2017)

If you can rely on ES6 features, then you can use Set object and Spread operator to create a unique array from a given array, as already specified in @Travis Heeter's answer below:

var uniqueArray = [...new Set(array)]

edited Nov 21 '17 at 12:16

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

2

this is brilliant
– oMiKeY
Nov 15 '17 at 20:10

add a comment |

up vote
35
down vote

accepted

You can use Array.filter function to filter out elements of an array based on the return value of a callback function. The callback function runs for every element of the original array.

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

UPDATE (16 Nov 2017)

If you can rely on ES6 features, then you can use Set object and Spread operator to create a unique array from a given array, as already specified in @Travis Heeter's answer below:

var uniqueArray = [...new Set(array)]

edited Nov 21 '17 at 12:16

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

You can use Array.filter function to filter out elements of an array based on the return value of a callback function. The callback function runs for every element of the original array.

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

UPDATE (16 Nov 2017)

If you can rely on ES6 features, then you can use Set object and Spread operator to create a unique array from a given array, as already specified in @Travis Heeter's answer below:

var uniqueArray = [...new Set(array)]

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

var arr = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var filteredArray = arr.filter(function(item, pos){

  return arr.indexOf(item)== pos; 

});



console.log( filteredArray );

edited Nov 21 '17 at 12:16

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

edited Nov 21 '17 at 12:16

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

answered Jul 5 '16 at 15:11

Mohit Bhardwaj

5,95611439

2

this is brilliant
– oMiKeY
Nov 15 '17 at 20:10

add a comment |

2

this is brilliant
– oMiKeY
Nov 15 '17 at 20:10

this is brilliant
– oMiKeY
Nov 15 '17 at 20:10

add a comment |

up vote
13
down vote

As of June 15, 2015 you may use Set() to create a unique array:

var uniqueArray = [...new Set(array)]

For your Example:

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

var newArray = [...new Set(data)]

console.log(newArray)



>> ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

edited Apr 27 '17 at 20:00

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

add a comment |

up vote
13
down vote

As of June 15, 2015 you may use Set() to create a unique array:

var uniqueArray = [...new Set(array)]

For your Example:

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

var newArray = [...new Set(data)]

console.log(newArray)



>> ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

edited Apr 27 '17 at 20:00

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

add a comment |

up vote
13
down vote

As of June 15, 2015 you may use Set() to create a unique array:

var uniqueArray = [...new Set(array)]

For your Example:

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

var newArray = [...new Set(data)]

console.log(newArray)



>> ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

edited Apr 27 '17 at 20:00

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

As of June 15, 2015 you may use Set() to create a unique array:

var uniqueArray = [...new Set(array)]

For your Example:

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

var newArray = [...new Set(data)]

console.log(newArray)



>> ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]

edited Apr 27 '17 at 20:00

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

edited Apr 27 '17 at 20:00

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

answered Apr 27 '17 at 18:55

Travis Heeter

4,40424068

add a comment |

up vote
5
down vote

You could use a hash table for look up and filter all not included values.

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

edited Nov 11 '17 at 15:45

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

add a comment |

up vote
5
down vote

You could use a hash table for look up and filter all not included values.

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

edited Nov 11 '17 at 15:45

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

add a comment |

up vote
5
down vote

You could use a hash table for look up and filter all not included values.

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

edited Nov 11 '17 at 15:45

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

You could use a hash table for look up and filter all not included values.

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

var data = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"],

    unique = data.filter(function (a) {

        return !this[a] && (this[a] = true);

    }, Object.create(null));



console.log(unique);

edited Nov 11 '17 at 15:45

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

edited Nov 11 '17 at 15:45

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

answered Jul 5 '16 at 15:11

Nina Scholz

170k1383147

add a comment |

up vote
3
down vote

You can use Map and Spread Operator:

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

add a comment |

up vote
3
down vote

You can use Map and Spread Operator:

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

add a comment |

up vote
3
down vote

You can use Map and Spread Operator:

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

You can use Map and Spread Operator:

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

var rawData = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"];



var unique = new Map();

rawData.forEach(d => unique.set(d, d));

var uniqueItems = [...unique.keys()];



console.log(uniqueItems);

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

answered Jul 5 '16 at 17:23

Morteza Tourani

2,71942638

add a comment |

up vote
3
down vote

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

1

Please provide context to the code
– Clíodhna
Sep 7 '17 at 9:48

add a comment |

up vote
3
down vote

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

1

Please provide context to the code
– Clíodhna
Sep 7 '17 at 9:48

add a comment |

up vote
3
down vote

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

arr = ["I", "do", "love", "JavaScript", "and", "I", "also", "do", "love", "Java"];



uniqueArr = [... new Set(arr)];



// or



reallyUniqueArr = arr.filter((item, pos, ar) => ar.indexOf(item) === pos)



console.log(`${uniqueArr}n${reallyUniqueArr}`)

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

answered Sep 7 '17 at 9:42

Jesse Dirisu

312

1

Please provide context to the code
– Clíodhna
Sep 7 '17 at 9:48

add a comment |

1

Please provide context to the code
– Clíodhna
Sep 7 '17 at 9:48

Please provide context to the code
– Clíodhna
Sep 7 '17 at 9:48

add a comment |

up vote
2
down vote

You can use reduce to loop the array and get the not duplicate values. Also uses an aux object to get the count of added values.

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

add a comment |

up vote
2
down vote

You can use reduce to loop the array and get the not duplicate values. Also uses an aux object to get the count of added values.

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

add a comment |

up vote
2
down vote

You can use reduce to loop the array and get the not duplicate values. Also uses an aux object to get the count of added values.

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

You can use reduce to loop the array and get the not duplicate values. Also uses an aux object to get the count of added values.

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

var aux = {};



var newArray = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"].reduce((tot, curr)=>{

  if(!aux[curr]){

    aux[curr] = 1;

    tot.push(curr);

  }

  return tot;

}, );



console.log(newArray);

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

answered Jul 5 '16 at 15:16

Jose Hermosilla Rodrigo

2,04411027

add a comment |

up vote
2
down vote

Filtering an array to contain unique values can be achieved using the JavaScript Set and Array.from method, as shown below:

Array.from(new Set(arrayOfNonUniqueValues));

Set

The Set object lets you store unique values of any type, whether
primitive values or object references.

Return value A new Set object.

Array.from()

The Array.from() method creates a new Array instance from an
array-like or iterable object.

Return value A new Array instance.

Example Code:

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

answered Feb 10 at 23:57

JSON C11

3,38443537

add a comment |

up vote
2
down vote

Filtering an array to contain unique values can be achieved using the JavaScript Set and Array.from method, as shown below:

Array.from(new Set(arrayOfNonUniqueValues));

Set

The Set object lets you store unique values of any type, whether
primitive values or object references.

Return value A new Set object.

Array.from()

The Array.from() method creates a new Array instance from an
array-like or iterable object.

Return value A new Array instance.

Example Code:

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

answered Feb 10 at 23:57

JSON C11

3,38443537

add a comment |

up vote
2
down vote

Filtering an array to contain unique values can be achieved using the JavaScript Set and Array.from method, as shown below:

Array.from(new Set(arrayOfNonUniqueValues));

Set

The Set object lets you store unique values of any type, whether
primitive values or object references.

Return value A new Set object.

Array.from()

The Array.from() method creates a new Array instance from an
array-like or iterable object.

Return value A new Array instance.

Example Code:

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

answered Feb 10 at 23:57

JSON C11

3,38443537

Filtering an array to contain unique values can be achieved using the JavaScript Set and Array.from method, as shown below:

Array.from(new Set(arrayOfNonUniqueValues));

Set

The Set object lets you store unique values of any type, whether
primitive values or object references.

Return value A new Set object.

Array.from()

The Array.from() method creates a new Array instance from an
array-like or iterable object.

Return value A new Array instance.

Example Code:

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

const array = ["X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11", "X_row7", "X_row4", "X_row6", "X_row10", "X_row8", "X_row9", "X_row11"]



const uniqueArray = Array.from(new Set(array));



console.log("uniqueArray: ", uniqueArray);

answered Feb 10 at 23:57

JSON C11

3,38443537

answered Feb 10 at 23:57

JSON C11

3,38443537

answered Feb 10 at 23:57

JSON C11

3,38443537

answered Feb 10 at 23:57

JSON C11

3,38443537

add a comment |

up vote
1
down vote

A slight variation on the indexOf method, if you need to filter multiple arrays:

function unique(item, index, array) {

    return array.indexOf(item) == index;

}

Use as such:

arr.filter(unique);

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

add a comment |

up vote
1
down vote

A slight variation on the indexOf method, if you need to filter multiple arrays:

function unique(item, index, array) {

    return array.indexOf(item) == index;

}

Use as such:

arr.filter(unique);

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

add a comment |

up vote
1
down vote

A slight variation on the indexOf method, if you need to filter multiple arrays:

function unique(item, index, array) {

    return array.indexOf(item) == index;

}

Use as such:

arr.filter(unique);

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

A slight variation on the indexOf method, if you need to filter multiple arrays:

function unique(item, index, array) {

    return array.indexOf(item) == index;

}

Use as such:

arr.filter(unique);

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

answered Nov 15 '17 at 20:32

oMiKeY

2,91351839

add a comment |

up vote
1
down vote

I've always used:

unique = (arr) => arr.filter((item, i, s) => s.lastIndexOf(item) == i);

But recently I had to get unique values for:

["1", 1, "2", 2, "3", 3]

And my old standby didn't cut it, so I came up with this:

uunique = (arr) => Object.keys(Object.assign({}, ...arr.map(a=>({[a]:true}))));

answered Jan 24 at 6:44

TennisVisuals

16916

add a comment |

up vote
1
down vote

I've always used:

unique = (arr) => arr.filter((item, i, s) => s.lastIndexOf(item) == i);

But recently I had to get unique values for:

["1", 1, "2", 2, "3", 3]

And my old standby didn't cut it, so I came up with this:

uunique = (arr) => Object.keys(Object.assign({}, ...arr.map(a=>({[a]:true}))));

answered Jan 24 at 6:44

TennisVisuals

16916

add a comment |

up vote
1
down vote

I've always used:

unique = (arr) => arr.filter((item, i, s) => s.lastIndexOf(item) == i);

But recently I had to get unique values for:

["1", 1, "2", 2, "3", 3]

And my old standby didn't cut it, so I came up with this:

uunique = (arr) => Object.keys(Object.assign({}, ...arr.map(a=>({[a]:true}))));

answered Jan 24 at 6:44

TennisVisuals

16916

I've always used:

unique = (arr) => arr.filter((item, i, s) => s.lastIndexOf(item) == i);

But recently I had to get unique values for:

["1", 1, "2", 2, "3", 3]

And my old standby didn't cut it, so I came up with this:

uunique = (arr) => Object.keys(Object.assign({}, ...arr.map(a=>({[a]:true}))));

answered Jan 24 at 6:44

TennisVisuals

16916

answered Jan 24 at 6:44

TennisVisuals

16916

answered Jan 24 at 6:44

TennisVisuals

16916

answered Jan 24 at 6:44

TennisVisuals

16916

add a comment |

up vote
1
down vote

Array.prototype.unique = function () {

  return [...new Set(this)]

}

then we can write:

const arr = [1, 5, 2, 2, 2, 3, 4, 3, 2, 1, 5]

const uniqueArr = arr.unique()

answered Nov 19 at 7:20

Zuhair Taha

6921922

add a comment |

up vote
1
down vote

Array.prototype.unique = function () {

  return [...new Set(this)]

}

then we can write:

const arr = [1, 5, 2, 2, 2, 3, 4, 3, 2, 1, 5]

const uniqueArr = arr.unique()

answered Nov 19 at 7:20

Zuhair Taha

6921922

add a comment |

up vote
1
down vote

Array.prototype.unique = function () {

  return [...new Set(this)]

}

then we can write:

const arr = [1, 5, 2, 2, 2, 3, 4, 3, 2, 1, 5]

const uniqueArr = arr.unique()

answered Nov 19 at 7:20

Zuhair Taha

6921922

Array.prototype.unique = function () {

  return [...new Set(this)]

}

then we can write:

const arr = [1, 5, 2, 2, 2, 3, 4, 3, 2, 1, 5]

const uniqueArr = arr.unique()

answered Nov 19 at 7:20

Zuhair Taha

6921922

answered Nov 19 at 7:20

Zuhair Taha

6921922

answered Nov 19 at 7:20

Zuhair Taha

6921922

answered Nov 19 at 7:20

Zuhair Taha

6921922

add a comment |

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