How to fix Error ManyToMany in @RestController?
0
I'm an entity Story:
@Entity
@Table(name = "story", schema = "")
@Data
public class Story implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "sID", unique = true, nullable = false)
private Long sID;
@Column(name = "vnName", nullable = false)
private String vnName;
@ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinTable(name = "_scategory",
joinColumns = {@JoinColumn(name = "sID", nullable = false)},
inverseJoinColumns = {@JoinColumn(name = "cID", nullable = false)})
private List<Category> categoryList;
}
And Entity Category:
@Entity
@Table(name = "category", schema = "", uniqueConstraints = {@UniqueConstraint(columnNames = {"cMetatitle"}),
@UniqueConstraint(columnNames = {"cName"})})
@Data
public class Category implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "cID", unique = true, nullable = false)
private Integer cID;
@Column(name = "cName", unique = true, nullable = false, length = 150)
private String cName;
@ManyToMany(mappedBy = "categoryList")
private List<Story> storyList;
}
But when I grab the Story in RestController, I get the following error message:
WARN http-nio-8080-exec-9
o.s.w.s.m.s.DefaultHandlerExceptionResolver:234 - Failure while trying
to resolve exception
[org.springframework.http.converter.HttpMessageNotWritableException]
java.lang.IllegalStateException: Cannot call sendError() after the
response has been committed
Can anybody show me how to fix it? Thank you!
spring-boot spring-data-jpa
edited Nov 21 '18 at 8:36
want2learn
1,12811123
asked Nov 20 '18 at 19:17
Phuong
437
add a comment |
0
I'm an entity Story:
@Entity
@Table(name = "story", schema = "")
@Data
public class Story implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "sID", unique = true, nullable = false)
private Long sID;
@Column(name = "vnName", nullable = false)
private String vnName;
@ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinTable(name = "_scategory",
joinColumns = {@JoinColumn(name = "sID", nullable = false)},
inverseJoinColumns = {@JoinColumn(name = "cID", nullable = false)})
private List<Category> categoryList;
}
And Entity Category:
@Entity
@Table(name = "category", schema = "", uniqueConstraints = {@UniqueConstraint(columnNames = {"cMetatitle"}),
@UniqueConstraint(columnNames = {"cName"})})
@Data
public class Category implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "cID", unique = true, nullable = false)
private Integer cID;
@Column(name = "cName", unique = true, nullable = false, length = 150)
private String cName;
@ManyToMany(mappedBy = "categoryList")
private List<Story> storyList;
}
But when I grab the Story in RestController, I get the following error message:
WARN http-nio-8080-exec-9
o.s.w.s.m.s.DefaultHandlerExceptionResolver:234 - Failure while trying
to resolve exception
[org.springframework.http.converter.HttpMessageNotWritableException]
java.lang.IllegalStateException: Cannot call sendError() after the
response has been committed
Can anybody show me how to fix it? Thank you!
spring-boot spring-data-jpa
edited Nov 21 '18 at 8:36
want2learn
1,12811123
asked Nov 20 '18 at 19:17
Phuong
437
I don't see relevant code - warn comes from controller.
– Antoniossss
Nov 20 '18 at 19:19
I do not see any field cMetatitle that you put in constrain unique in any class ! is that normal ?
– TinyOS
Nov 21 '18 at 1:51
Else you can add to your application.properties : debug=true and you scheck your created tables how they look like
– TinyOS
Nov 21 '18 at 1:57
I have dropping a fields when writing to allow more code in the post
– Phuong
Nov 21 '18 at 2:51
add a comment |
0
0
0
I'm an entity Story:
@Entity
@Table(name = "story", schema = "")
@Data
public class Story implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "sID", unique = true, nullable = false)
private Long sID;
@Column(name = "vnName", nullable = false)
private String vnName;
@ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinTable(name = "_scategory",
joinColumns = {@JoinColumn(name = "sID", nullable = false)},
inverseJoinColumns = {@JoinColumn(name = "cID", nullable = false)})
private List<Category> categoryList;
}
And Entity Category:
@Entity
@Table(name = "category", schema = "", uniqueConstraints = {@UniqueConstraint(columnNames = {"cMetatitle"}),
@UniqueConstraint(columnNames = {"cName"})})
@Data
public class Category implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "cID", unique = true, nullable = false)
private Integer cID;
@Column(name = "cName", unique = true, nullable = false, length = 150)
private String cName;
@ManyToMany(mappedBy = "categoryList")
private List<Story> storyList;
}
But when I grab the Story in RestController, I get the following error message:
WARN http-nio-8080-exec-9
o.s.w.s.m.s.DefaultHandlerExceptionResolver:234 - Failure while trying
to resolve exception
[org.springframework.http.converter.HttpMessageNotWritableException]
java.lang.IllegalStateException: Cannot call sendError() after the
response has been committed
Can anybody show me how to fix it? Thank you!
spring-boot spring-data-jpa
edited Nov 21 '18 at 8:36
want2learn
1,12811123
asked Nov 20 '18 at 19:17
Phuong
437
I'm an entity Story:
@Entity
@Table(name = "story", schema = "")
@Data
public class Story implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "sID", unique = true, nullable = false)
private Long sID;
@Column(name = "vnName", nullable = false)
private String vnName;
@ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinTable(name = "_scategory",
joinColumns = {@JoinColumn(name = "sID", nullable = false)},
inverseJoinColumns = {@JoinColumn(name = "cID", nullable = false)})
private List<Category> categoryList;
}
And Entity Category:
@Entity
@Table(name = "category", schema = "", uniqueConstraints = {@UniqueConstraint(columnNames = {"cMetatitle"}),
@UniqueConstraint(columnNames = {"cName"})})
@Data
public class Category implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "cID", unique = true, nullable = false)
private Integer cID;
@Column(name = "cName", unique = true, nullable = false, length = 150)
private String cName;
@ManyToMany(mappedBy = "categoryList")
private List<Story> storyList;
}
But when I grab the Story in RestController, I get the following error message:
WARN http-nio-8080-exec-9
o.s.w.s.m.s.DefaultHandlerExceptionResolver:234 - Failure while trying
to resolve exception
[org.springframework.http.converter.HttpMessageNotWritableException]
java.lang.IllegalStateException: Cannot call sendError() after the
response has been committed
Can anybody show me how to fix it? Thank you!
spring-boot spring-data-jpa
spring-boot spring-data-jpa
edited Nov 21 '18 at 8:36
want2learn
1,12811123
asked Nov 20 '18 at 19:17
Phuong
437
edited Nov 21 '18 at 8:36
want2learn
1,12811123
asked Nov 20 '18 at 19:17
Phuong
437
edited Nov 21 '18 at 8:36
want2learn
1,12811123
edited Nov 21 '18 at 8:36
want2learn
1,12811123
edited Nov 21 '18 at 8:36
want2learn
1,12811123
1,12811123
asked Nov 20 '18 at 19:17
Phuong
437
asked Nov 20 '18 at 19:17
Phuong
437
asked Nov 20 '18 at 19:17
Phuong
437
437
I don't see relevant code - warn comes from controller.
– Antoniossss
Nov 20 '18 at 19:19
I do not see any field cMetatitle that you put in constrain unique in any class ! is that normal ?
– TinyOS
Nov 21 '18 at 1:51
Else you can add to your application.properties : debug=true and you scheck your created tables how they look like
– TinyOS
Nov 21 '18 at 1:57
I have dropping a fields when writing to allow more code in the post
– Phuong
Nov 21 '18 at 2:51
add a comment |
I don't see relevant code - warn comes from controller.
– Antoniossss
Nov 20 '18 at 19:19
I do not see any field cMetatitle that you put in constrain unique in any class ! is that normal ?
– TinyOS
Nov 21 '18 at 1:51
Else you can add to your application.properties : debug=true and you scheck your created tables how they look like
– TinyOS
Nov 21 '18 at 1:57
I have dropping a fields when writing to allow more code in the post
– Phuong
Nov 21 '18 at 2:51
I don't see relevant code - warn comes from controller.
– Antoniossss
Nov 20 '18 at 19:19
I don't see relevant code - warn comes from controller.
– Antoniossss
Nov 20 '18 at 19:19
I do not see any field cMetatitle that you put in constrain unique in any class ! is that normal ?
– TinyOS
Nov 21 '18 at 1:51
I do not see any field cMetatitle that you put in constrain unique in any class ! is that normal ?
– TinyOS
Nov 21 '18 at 1:51
Else you can add to your application.properties : debug=true and you scheck your created tables how they look like
– TinyOS
Nov 21 '18 at 1:57
Else you can add to your application.properties : debug=true and you scheck your created tables how they look like
– TinyOS
Nov 21 '18 at 1:57
I have dropping a fields when writing to allow more code in the post
– Phuong
Nov 21 '18 at 2:51
I have dropping a fields when writing to allow more code in the post
– Phuong
Nov 21 '18 at 2:51
add a comment |
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I don't see relevant code - warn comes from controller.
– Antoniossss
Nov 20 '18 at 19:19
I do not see any field cMetatitle that you put in constrain unique in any class ! is that normal ?
– TinyOS
Nov 21 '18 at 1:51
Else you can add to your application.properties : debug=true and you scheck your created tables how they look like
– TinyOS
Nov 21 '18 at 1:57
I have dropping a fields when writing to allow more code in the post
– Phuong
Nov 21 '18 at 2:51