Show a DIV if the URL contains a certain list strings
I'm looking for a way to show/hide a certain DIV based on a list of URL's I have that need to display it. The problem Im running into is that these URL's may contain various parameters that I need to ignore and thats where Im running into trouble.
if(window.location.href == "http://www.google.com/example-one" || window.location.href=="http://www.google.com/example-two"){}
I need a more clean way to do this and just check if multiple strings exist somewhere in the URL.
javascript jquery
asked Nov 20 '18 at 19:33
John Moore
167
add a comment |
I'm looking for a way to show/hide a certain DIV based on a list of URL's I have that need to display it. The problem Im running into is that these URL's may contain various parameters that I need to ignore and thats where Im running into trouble.
if(window.location.href == "http://www.google.com/example-one" || window.location.href=="http://www.google.com/example-two"){}
I need a more clean way to do this and just check if multiple strings exist somewhere in the URL.
javascript jquery
asked Nov 20 '18 at 19:33
John Moore
167
You could use a loop here to check an array of URL's.
– justDan
Nov 20 '18 at 19:36
Your question is not very clear. Are "example-one" and "example-two" what you want to ignore? And always match to www.google.com?
– user1011627
Nov 20 '18 at 19:40
The example is just my old code that checked for very specific URLS. Im looking for something that checks for any string I specify, doesnt ignore anything.
– John Moore
Nov 20 '18 at 21:04
add a comment |
I'm looking for a way to show/hide a certain DIV based on a list of URL's I have that need to display it. The problem Im running into is that these URL's may contain various parameters that I need to ignore and thats where Im running into trouble.
if(window.location.href == "http://www.google.com/example-one" || window.location.href=="http://www.google.com/example-two"){}
I need a more clean way to do this and just check if multiple strings exist somewhere in the URL.
javascript jquery
asked Nov 20 '18 at 19:33
John Moore
167
I'm looking for a way to show/hide a certain DIV based on a list of URL's I have that need to display it. The problem Im running into is that these URL's may contain various parameters that I need to ignore and thats where Im running into trouble.
if(window.location.href == "http://www.google.com/example-one" || window.location.href=="http://www.google.com/example-two"){}
I need a more clean way to do this and just check if multiple strings exist somewhere in the URL.
javascript jquery
javascript jquery
asked Nov 20 '18 at 19:33
John Moore
167
asked Nov 20 '18 at 19:33
John Moore
167
asked Nov 20 '18 at 19:33
John Moore
167
asked Nov 20 '18 at 19:33
John Moore
167
asked Nov 20 '18 at 19:33
John Moore
167
167
You could use a loop here to check an array of URL's.
– justDan
Nov 20 '18 at 19:36
Your question is not very clear. Are "example-one" and "example-two" what you want to ignore? And always match to www.google.com?
– user1011627
Nov 20 '18 at 19:40
The example is just my old code that checked for very specific URLS. Im looking for something that checks for any string I specify, doesnt ignore anything.
– John Moore
Nov 20 '18 at 21:04
add a comment |
You could use a loop here to check an array of URL's.
– justDan
Nov 20 '18 at 19:36
Your question is not very clear. Are "example-one" and "example-two" what you want to ignore? And always match to www.google.com?
– user1011627
Nov 20 '18 at 19:40
The example is just my old code that checked for very specific URLS. Im looking for something that checks for any string I specify, doesnt ignore anything.
– John Moore
Nov 20 '18 at 21:04
You could use a loop here to check an array of URL's.
– justDan
Nov 20 '18 at 19:36
You could use a loop here to check an array of URL's.
– justDan
Nov 20 '18 at 19:36
Your question is not very clear. Are "example-one" and "example-two" what you want to ignore? And always match to www.google.com?
– user1011627
Nov 20 '18 at 19:40
Your question is not very clear. Are "example-one" and "example-two" what you want to ignore? And always match to www.google.com?
– user1011627
Nov 20 '18 at 19:40
The example is just my old code that checked for very specific URLS. Im looking for something that checks for any string I specify, doesnt ignore anything.
– John Moore
Nov 20 '18 at 21:04
The example is just my old code that checked for very specific URLS. Im looking for something that checks for any string I specify, doesnt ignore anything.
– John Moore
Nov 20 '18 at 21:04
add a comment |
1 Answer
1
active
oldest
votes
What about passing your url into a function and then doing a partial search to see if it includes the part of the url you care about withoug the params.
function CheckURL(url) {
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
return value;
}
Or something similar but doing the work in a function that you can call and update as needed.
EDIT:
Based on question as example to hide a div.
function CheckURL(url) {
var x = document.getElementById("example");
x.style.display = "none";
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
if (value) {
x.style.display = "block";
}
}
This hides it initially and then shows it if it meets the criteria.
answered Nov 20 '18 at 19:43
c8irish
1256
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
What about passing your url into a function and then doing a partial search to see if it includes the part of the url you care about withoug the params.
function CheckURL(url) {
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
return value;
}
Or something similar but doing the work in a function that you can call and update as needed.
EDIT:
Based on question as example to hide a div.
function CheckURL(url) {
var x = document.getElementById("example");
x.style.display = "none";
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
if (value) {
x.style.display = "block";
}
}
This hides it initially and then shows it if it meets the criteria.
answered Nov 20 '18 at 19:43
c8irish
1256
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
add a comment |
What about passing your url into a function and then doing a partial search to see if it includes the part of the url you care about withoug the params.
function CheckURL(url) {
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
return value;
}
Or something similar but doing the work in a function that you can call and update as needed.
EDIT:
Based on question as example to hide a div.
function CheckURL(url) {
var x = document.getElementById("example");
x.style.display = "none";
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
if (value) {
x.style.display = "block";
}
}
This hides it initially and then shows it if it meets the criteria.
answered Nov 20 '18 at 19:43
c8irish
1256
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
add a comment |
What about passing your url into a function and then doing a partial search to see if it includes the part of the url you care about withoug the params.
function CheckURL(url) {
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
return value;
}
Or something similar but doing the work in a function that you can call and update as needed.
EDIT:
Based on question as example to hide a div.
function CheckURL(url) {
var x = document.getElementById("example");
x.style.display = "none";
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
if (value) {
x.style.display = "block";
}
}
This hides it initially and then shows it if it meets the criteria.
answered Nov 20 '18 at 19:43
c8irish
1256
What about passing your url into a function and then doing a partial search to see if it includes the part of the url you care about withoug the params.
function CheckURL(url) {
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
return value;
}
Or something similar but doing the work in a function that you can call and update as needed.
EDIT:
Based on question as example to hide a div.
function CheckURL(url) {
var x = document.getElementById("example");
x.style.display = "none";
var value = false;
value = url.includes('google.com');
// value = check 2
// value = check 3
if (value) {
x.style.display = "block";
}
}
This hides it initially and then shows it if it meets the criteria.
answered Nov 20 '18 at 19:43
c8irish
1256
edited Nov 21 '18 at 21:18
answered Nov 20 '18 at 19:43
c8irish
1256
answered Nov 20 '18 at 19:43
c8irish
1256
answered Nov 20 '18 at 19:43
c8irish
1256
1256
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
add a comment |
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
Can you show an example of using this to show a div with an ID of #example?
– John Moore
Nov 20 '18 at 20:05
add a comment |
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You could use a loop here to check an array of URL's.
– justDan
Nov 20 '18 at 19:36
Your question is not very clear. Are "example-one" and "example-two" what you want to ignore? And always match to www.google.com?
– user1011627
Nov 20 '18 at 19:40
The example is just my old code that checked for very specific URLS. Im looking for something that checks for any string I specify, doesnt ignore anything.
– John Moore
Nov 20 '18 at 21:04