How to get the expected value of #function or #line?
I have a function that contains #function and #line that returns a string:
func exportMessage(content: String) -> String {
if let fileURL = URL(string: #file) {
return "(fileURL.lastPathComponent): (#function) - Line: (#line)n(content)"
}
return "(#function) - Line: (#line)n(content)"
}
When trying to use exportMessage above function in another function:
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
The output is:
MyPlayground.playground: exportMessage(content:) - Line: 5
instance is nil
It contains "exportMessage" but not "doSomething" as the name of the function (#function). It is the same for the line number, it is line number in exportMessage() but not in doSomething().
My expectation is to get the function name and the line number for doSomething(), as:
MyPlayground.playground: doSomething() - Line: 12
instance is nil
Since I am aiming to use exportMessage in many functions, I'd assume that it should refers to the caller function. Is it achievable? How?
swift
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
add a comment |
I have a function that contains #function and #line that returns a string:
func exportMessage(content: String) -> String {
if let fileURL = URL(string: #file) {
return "(fileURL.lastPathComponent): (#function) - Line: (#line)n(content)"
}
return "(#function) - Line: (#line)n(content)"
}
When trying to use exportMessage above function in another function:
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
The output is:
MyPlayground.playground: exportMessage(content:) - Line: 5
instance is nil
It contains "exportMessage" but not "doSomething" as the name of the function (#function). It is the same for the line number, it is line number in exportMessage() but not in doSomething().
My expectation is to get the function name and the line number for doSomething(), as:
MyPlayground.playground: doSomething() - Line: 12
instance is nil
Since I am aiming to use exportMessage in many functions, I'd assume that it should refers to the caller function. Is it achievable? How?
swift
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
add a comment |
I have a function that contains #function and #line that returns a string:
func exportMessage(content: String) -> String {
if let fileURL = URL(string: #file) {
return "(fileURL.lastPathComponent): (#function) - Line: (#line)n(content)"
}
return "(#function) - Line: (#line)n(content)"
}
When trying to use exportMessage above function in another function:
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
The output is:
MyPlayground.playground: exportMessage(content:) - Line: 5
instance is nil
It contains "exportMessage" but not "doSomething" as the name of the function (#function). It is the same for the line number, it is line number in exportMessage() but not in doSomething().
My expectation is to get the function name and the line number for doSomething(), as:
MyPlayground.playground: doSomething() - Line: 12
instance is nil
Since I am aiming to use exportMessage in many functions, I'd assume that it should refers to the caller function. Is it achievable? How?
swift
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
I have a function that contains #function and #line that returns a string:
func exportMessage(content: String) -> String {
if let fileURL = URL(string: #file) {
return "(fileURL.lastPathComponent): (#function) - Line: (#line)n(content)"
}
return "(#function) - Line: (#line)n(content)"
}
When trying to use exportMessage above function in another function:
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
The output is:
MyPlayground.playground: exportMessage(content:) - Line: 5
instance is nil
It contains "exportMessage" but not "doSomething" as the name of the function (#function). It is the same for the line number, it is line number in exportMessage() but not in doSomething().
My expectation is to get the function name and the line number for doSomething(), as:
MyPlayground.playground: doSomething() - Line: 12
instance is nil
Since I am aiming to use exportMessage in many functions, I'd assume that it should refers to the caller function. Is it achievable? How?
swift
swift
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
edited Nov 21 '18 at 17:17
Ahmad F
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
asked Nov 21 '18 at 17:07
Ahmad FAhmad F
16.3k104181
16.3k104181
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
What you're proposing wouldn't really make sense, because it wouldn't be clear "which caller should it print"? Why doSomething? Why not the caller of doSomething? Or the caller of the caller? Ultimately, if this is how #function and friends behaved, it would only ever print start from libdyld.dylid.
To achieve the behaviour you want, you have to manually pull in the #function and #line values from the parent context:
func exportMessage(
content: String,
callingFunction: String = #function,
callingLine: Int = #line
) -> String {
if let fileURL = URL(string: callingFunction) {
return "(fileURL.lastPathComponent): (callingFunction) - Line: (callingLine)n(content)"
}
return "(callingFunction) - Line: (callingLine)n(content)"
}
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
add a comment |
Use #function and #line as default values in the method. Default values are evaluated at the point of call.
func exportMessage(content: String, file: String = #file, function: String = #function, line: Int = #line) -> String {
if let fileURL = URL(string: file) {
return "(fileURL.lastPathComponent): (function) - Line: (line)n(content)"
}
return "(function) - Line: (line)n(content)"
}
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
What you're proposing wouldn't really make sense, because it wouldn't be clear "which caller should it print"? Why doSomething? Why not the caller of doSomething? Or the caller of the caller? Ultimately, if this is how #function and friends behaved, it would only ever print start from libdyld.dylid.
To achieve the behaviour you want, you have to manually pull in the #function and #line values from the parent context:
func exportMessage(
content: String,
callingFunction: String = #function,
callingLine: Int = #line
) -> String {
if let fileURL = URL(string: callingFunction) {
return "(fileURL.lastPathComponent): (callingFunction) - Line: (callingLine)n(content)"
}
return "(callingFunction) - Line: (callingLine)n(content)"
}
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
add a comment |
What you're proposing wouldn't really make sense, because it wouldn't be clear "which caller should it print"? Why doSomething? Why not the caller of doSomething? Or the caller of the caller? Ultimately, if this is how #function and friends behaved, it would only ever print start from libdyld.dylid.
To achieve the behaviour you want, you have to manually pull in the #function and #line values from the parent context:
func exportMessage(
content: String,
callingFunction: String = #function,
callingLine: Int = #line
) -> String {
if let fileURL = URL(string: callingFunction) {
return "(fileURL.lastPathComponent): (callingFunction) - Line: (callingLine)n(content)"
}
return "(callingFunction) - Line: (callingLine)n(content)"
}
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
add a comment |
What you're proposing wouldn't really make sense, because it wouldn't be clear "which caller should it print"? Why doSomething? Why not the caller of doSomething? Or the caller of the caller? Ultimately, if this is how #function and friends behaved, it would only ever print start from libdyld.dylid.
To achieve the behaviour you want, you have to manually pull in the #function and #line values from the parent context:
func exportMessage(
content: String,
callingFunction: String = #function,
callingLine: Int = #line
) -> String {
if let fileURL = URL(string: callingFunction) {
return "(fileURL.lastPathComponent): (callingFunction) - Line: (callingLine)n(content)"
}
return "(callingFunction) - Line: (callingLine)n(content)"
}
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
What you're proposing wouldn't really make sense, because it wouldn't be clear "which caller should it print"? Why doSomething? Why not the caller of doSomething? Or the caller of the caller? Ultimately, if this is how #function and friends behaved, it would only ever print start from libdyld.dylid.
To achieve the behaviour you want, you have to manually pull in the #function and #line values from the parent context:
func exportMessage(
content: String,
callingFunction: String = #function,
callingLine: Int = #line
) -> String {
if let fileURL = URL(string: callingFunction) {
return "(fileURL.lastPathComponent): (callingFunction) - Line: (callingLine)n(content)"
}
return "(callingFunction) - Line: (callingLine)n(content)"
}
func doSomething() {
let result = exportMessage(content: "instance is nil")
print(result)
}
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
answered Nov 21 '18 at 17:25
AlexanderAlexander
31.2k54878
31.2k54878
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
add a comment |
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
That's what I got when I checked such a method declaration: developer.apple.com/documentation/swift/1541112-assert. Thanks!
– Ahmad F
Nov 22 '18 at 8:06
add a comment |
Use #function and #line as default values in the method. Default values are evaluated at the point of call.
func exportMessage(content: String, file: String = #file, function: String = #function, line: Int = #line) -> String {
if let fileURL = URL(string: file) {
return "(fileURL.lastPathComponent): (function) - Line: (line)n(content)"
}
return "(function) - Line: (line)n(content)"
}
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
add a comment |
Use #function and #line as default values in the method. Default values are evaluated at the point of call.
func exportMessage(content: String, file: String = #file, function: String = #function, line: Int = #line) -> String {
if let fileURL = URL(string: file) {
return "(fileURL.lastPathComponent): (function) - Line: (line)n(content)"
}
return "(function) - Line: (line)n(content)"
}
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
add a comment |
Use #function and #line as default values in the method. Default values are evaluated at the point of call.
func exportMessage(content: String, file: String = #file, function: String = #function, line: Int = #line) -> String {
if let fileURL = URL(string: file) {
return "(fileURL.lastPathComponent): (function) - Line: (line)n(content)"
}
return "(function) - Line: (line)n(content)"
}
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
Use #function and #line as default values in the method. Default values are evaluated at the point of call.
func exportMessage(content: String, file: String = #file, function: String = #function, line: Int = #line) -> String {
if let fileURL = URL(string: file) {
return "(fileURL.lastPathComponent): (function) - Line: (line)n(content)"
}
return "(function) - Line: (line)n(content)"
}
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
answered Nov 21 '18 at 17:25
Rob NapierRob Napier
200k28294421
200k28294421
add a comment |
add a comment |
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