How to print a specific line in a csv file that is not named csv in python?












0














I'm supposed to write a function that does this specifically.



def get_customer_record(file_handle, n):
"""
-------------------------------------------------------
Find the n-th record in a comma-delimited sequential file.
Records are numbered starting with 0.
Use: result = get_customer_record(file_handle, n)
-------------------------------------------------------
Parameters:
file_handle - file to search (file - open for reading)
n - the number of the record to return (int > 0)
Returns:
result - a list of the fields of the n-th record if it exists,
an empty list otherwise (list)
-------------------------------------------------------
"""


And here is the file.



customers.txt



12345,Tom,Black,300.00,1998-01-30
23456,Alice,Smith,1200.50,1998-02-20
14567,Jane,White,900.00,1998-07-01
43564,Weilin,Zhao,450.25,1998-01-03
45432,Bina,Mehta,278.95,1998-03-21


The Code



list =  
file_handle = open('customers.txt', 'r+', encoding="utf-8")
line = file_handle.readline(n)
list.append(line.strip(','))
file_handle.close()
return list









share|improve this question




















  • 1




    So what have you tried so far? In what way is it not working?
    – Kingsley
    Nov 21 '18 at 2:21










  • Welcome to Stack Overflow! Please take the tour, look around, and read through the Help Center, in particular How do I ask a good question? If you run into a specific problem, research it thoroughly, search thoroughly here, and if you're still stuck post your code and a description of the problem. Also, remember to include Minimum, Complete, Verifiable Example. People will be glad to help
    – Andreas
    Nov 21 '18 at 2:22










  • Welcome to SO, we are a community of volunteers that help answer questions/issues in code. Unfortunately I see no code here, we don't write programs. Please try to answer this yourself and come back if you run into any issues. Don't be afraid to search your question/issue before asking
    – Jaba
    Nov 21 '18 at 2:22












  • Maybe it would help to read about python's CSV Module - docs.python.org/3/library/csv.html or perhaps Python's input and output syntax - docs.python.org/3/tutorial/inputoutput.html
    – Kingsley
    Nov 21 '18 at 2:24










  • @Kingsley list = file_handle = open('customers.txt', 'r+', encoding="utf-8") line = file_handle.readline(n) list.append(line.strip(',')) file_handle.close() return list I have tried doing this, here was what I have in my testing file. from functions import get_customer_record file_handle = open('customers.txt', 'r+', encoding="utf-8") n = int(input()) result = get_customer_record(file_handle, n) print(list)
    – David Enjugu
    Nov 21 '18 at 2:27


















0














I'm supposed to write a function that does this specifically.



def get_customer_record(file_handle, n):
"""
-------------------------------------------------------
Find the n-th record in a comma-delimited sequential file.
Records are numbered starting with 0.
Use: result = get_customer_record(file_handle, n)
-------------------------------------------------------
Parameters:
file_handle - file to search (file - open for reading)
n - the number of the record to return (int > 0)
Returns:
result - a list of the fields of the n-th record if it exists,
an empty list otherwise (list)
-------------------------------------------------------
"""


And here is the file.



customers.txt



12345,Tom,Black,300.00,1998-01-30
23456,Alice,Smith,1200.50,1998-02-20
14567,Jane,White,900.00,1998-07-01
43564,Weilin,Zhao,450.25,1998-01-03
45432,Bina,Mehta,278.95,1998-03-21


The Code



list =  
file_handle = open('customers.txt', 'r+', encoding="utf-8")
line = file_handle.readline(n)
list.append(line.strip(','))
file_handle.close()
return list









share|improve this question




















  • 1




    So what have you tried so far? In what way is it not working?
    – Kingsley
    Nov 21 '18 at 2:21










  • Welcome to Stack Overflow! Please take the tour, look around, and read through the Help Center, in particular How do I ask a good question? If you run into a specific problem, research it thoroughly, search thoroughly here, and if you're still stuck post your code and a description of the problem. Also, remember to include Minimum, Complete, Verifiable Example. People will be glad to help
    – Andreas
    Nov 21 '18 at 2:22










  • Welcome to SO, we are a community of volunteers that help answer questions/issues in code. Unfortunately I see no code here, we don't write programs. Please try to answer this yourself and come back if you run into any issues. Don't be afraid to search your question/issue before asking
    – Jaba
    Nov 21 '18 at 2:22












  • Maybe it would help to read about python's CSV Module - docs.python.org/3/library/csv.html or perhaps Python's input and output syntax - docs.python.org/3/tutorial/inputoutput.html
    – Kingsley
    Nov 21 '18 at 2:24










  • @Kingsley list = file_handle = open('customers.txt', 'r+', encoding="utf-8") line = file_handle.readline(n) list.append(line.strip(',')) file_handle.close() return list I have tried doing this, here was what I have in my testing file. from functions import get_customer_record file_handle = open('customers.txt', 'r+', encoding="utf-8") n = int(input()) result = get_customer_record(file_handle, n) print(list)
    – David Enjugu
    Nov 21 '18 at 2:27
















0












0








0







I'm supposed to write a function that does this specifically.



def get_customer_record(file_handle, n):
"""
-------------------------------------------------------
Find the n-th record in a comma-delimited sequential file.
Records are numbered starting with 0.
Use: result = get_customer_record(file_handle, n)
-------------------------------------------------------
Parameters:
file_handle - file to search (file - open for reading)
n - the number of the record to return (int > 0)
Returns:
result - a list of the fields of the n-th record if it exists,
an empty list otherwise (list)
-------------------------------------------------------
"""


And here is the file.



customers.txt



12345,Tom,Black,300.00,1998-01-30
23456,Alice,Smith,1200.50,1998-02-20
14567,Jane,White,900.00,1998-07-01
43564,Weilin,Zhao,450.25,1998-01-03
45432,Bina,Mehta,278.95,1998-03-21


The Code



list =  
file_handle = open('customers.txt', 'r+', encoding="utf-8")
line = file_handle.readline(n)
list.append(line.strip(','))
file_handle.close()
return list









share|improve this question















I'm supposed to write a function that does this specifically.



def get_customer_record(file_handle, n):
"""
-------------------------------------------------------
Find the n-th record in a comma-delimited sequential file.
Records are numbered starting with 0.
Use: result = get_customer_record(file_handle, n)
-------------------------------------------------------
Parameters:
file_handle - file to search (file - open for reading)
n - the number of the record to return (int > 0)
Returns:
result - a list of the fields of the n-th record if it exists,
an empty list otherwise (list)
-------------------------------------------------------
"""


And here is the file.



customers.txt



12345,Tom,Black,300.00,1998-01-30
23456,Alice,Smith,1200.50,1998-02-20
14567,Jane,White,900.00,1998-07-01
43564,Weilin,Zhao,450.25,1998-01-03
45432,Bina,Mehta,278.95,1998-03-21


The Code



list =  
file_handle = open('customers.txt', 'r+', encoding="utf-8")
line = file_handle.readline(n)
list.append(line.strip(','))
file_handle.close()
return list






python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 2:34









Kingsley

2,25411023




2,25411023










asked Nov 21 '18 at 2:17









David Enjugu

11




11








  • 1




    So what have you tried so far? In what way is it not working?
    – Kingsley
    Nov 21 '18 at 2:21










  • Welcome to Stack Overflow! Please take the tour, look around, and read through the Help Center, in particular How do I ask a good question? If you run into a specific problem, research it thoroughly, search thoroughly here, and if you're still stuck post your code and a description of the problem. Also, remember to include Minimum, Complete, Verifiable Example. People will be glad to help
    – Andreas
    Nov 21 '18 at 2:22










  • Welcome to SO, we are a community of volunteers that help answer questions/issues in code. Unfortunately I see no code here, we don't write programs. Please try to answer this yourself and come back if you run into any issues. Don't be afraid to search your question/issue before asking
    – Jaba
    Nov 21 '18 at 2:22












  • Maybe it would help to read about python's CSV Module - docs.python.org/3/library/csv.html or perhaps Python's input and output syntax - docs.python.org/3/tutorial/inputoutput.html
    – Kingsley
    Nov 21 '18 at 2:24










  • @Kingsley list = file_handle = open('customers.txt', 'r+', encoding="utf-8") line = file_handle.readline(n) list.append(line.strip(',')) file_handle.close() return list I have tried doing this, here was what I have in my testing file. from functions import get_customer_record file_handle = open('customers.txt', 'r+', encoding="utf-8") n = int(input()) result = get_customer_record(file_handle, n) print(list)
    – David Enjugu
    Nov 21 '18 at 2:27
















  • 1




    So what have you tried so far? In what way is it not working?
    – Kingsley
    Nov 21 '18 at 2:21










  • Welcome to Stack Overflow! Please take the tour, look around, and read through the Help Center, in particular How do I ask a good question? If you run into a specific problem, research it thoroughly, search thoroughly here, and if you're still stuck post your code and a description of the problem. Also, remember to include Minimum, Complete, Verifiable Example. People will be glad to help
    – Andreas
    Nov 21 '18 at 2:22










  • Welcome to SO, we are a community of volunteers that help answer questions/issues in code. Unfortunately I see no code here, we don't write programs. Please try to answer this yourself and come back if you run into any issues. Don't be afraid to search your question/issue before asking
    – Jaba
    Nov 21 '18 at 2:22












  • Maybe it would help to read about python's CSV Module - docs.python.org/3/library/csv.html or perhaps Python's input and output syntax - docs.python.org/3/tutorial/inputoutput.html
    – Kingsley
    Nov 21 '18 at 2:24










  • @Kingsley list = file_handle = open('customers.txt', 'r+', encoding="utf-8") line = file_handle.readline(n) list.append(line.strip(',')) file_handle.close() return list I have tried doing this, here was what I have in my testing file. from functions import get_customer_record file_handle = open('customers.txt', 'r+', encoding="utf-8") n = int(input()) result = get_customer_record(file_handle, n) print(list)
    – David Enjugu
    Nov 21 '18 at 2:27










1




1




So what have you tried so far? In what way is it not working?
– Kingsley
Nov 21 '18 at 2:21




So what have you tried so far? In what way is it not working?
– Kingsley
Nov 21 '18 at 2:21












Welcome to Stack Overflow! Please take the tour, look around, and read through the Help Center, in particular How do I ask a good question? If you run into a specific problem, research it thoroughly, search thoroughly here, and if you're still stuck post your code and a description of the problem. Also, remember to include Minimum, Complete, Verifiable Example. People will be glad to help
– Andreas
Nov 21 '18 at 2:22




Welcome to Stack Overflow! Please take the tour, look around, and read through the Help Center, in particular How do I ask a good question? If you run into a specific problem, research it thoroughly, search thoroughly here, and if you're still stuck post your code and a description of the problem. Also, remember to include Minimum, Complete, Verifiable Example. People will be glad to help
– Andreas
Nov 21 '18 at 2:22












Welcome to SO, we are a community of volunteers that help answer questions/issues in code. Unfortunately I see no code here, we don't write programs. Please try to answer this yourself and come back if you run into any issues. Don't be afraid to search your question/issue before asking
– Jaba
Nov 21 '18 at 2:22






Welcome to SO, we are a community of volunteers that help answer questions/issues in code. Unfortunately I see no code here, we don't write programs. Please try to answer this yourself and come back if you run into any issues. Don't be afraid to search your question/issue before asking
– Jaba
Nov 21 '18 at 2:22














Maybe it would help to read about python's CSV Module - docs.python.org/3/library/csv.html or perhaps Python's input and output syntax - docs.python.org/3/tutorial/inputoutput.html
– Kingsley
Nov 21 '18 at 2:24




Maybe it would help to read about python's CSV Module - docs.python.org/3/library/csv.html or perhaps Python's input and output syntax - docs.python.org/3/tutorial/inputoutput.html
– Kingsley
Nov 21 '18 at 2:24












@Kingsley list = file_handle = open('customers.txt', 'r+', encoding="utf-8") line = file_handle.readline(n) list.append(line.strip(',')) file_handle.close() return list I have tried doing this, here was what I have in my testing file. from functions import get_customer_record file_handle = open('customers.txt', 'r+', encoding="utf-8") n = int(input()) result = get_customer_record(file_handle, n) print(list)
– David Enjugu
Nov 21 '18 at 2:27






@Kingsley list = file_handle = open('customers.txt', 'r+', encoding="utf-8") line = file_handle.readline(n) list.append(line.strip(',')) file_handle.close() return list I have tried doing this, here was what I have in my testing file. from functions import get_customer_record file_handle = open('customers.txt', 'r+', encoding="utf-8") n = int(input()) result = get_customer_record(file_handle, n) print(list)
– David Enjugu
Nov 21 '18 at 2:27














2 Answers
2






active

oldest

votes


















1














A simple solution would be iterate through the file using next():



from csv import reader

def get_customer_record(file_handle, n):
with open(file=file_handle) as csvfile:
csv_reader = reader(csvfile)
return next((line for row, line in enumerate(csv_reader) if row == n), )

print(get_customer_record(file_handle='customer.csv', n=3))
# ['43564', 'Weilin', 'Zhao', '450.25', '1998-01-03']

print(get_customer_record(file_handle='customer.csv', n=5))
#





share|improve this answer





























    0














    It's not clear from your syntax whether to return just the row as a string, or the fields split around the ,. I have assumed the single-line.



    The python readline() function does not take an index, it just reads the next line from the file. Below I used readlines() (note the s) which reads all lines from the file. If your file was huge, this would not be so efficient.



    Also a bit of error-handling for out-of-bounds n helps:



    def get_customer_record(file_handle, n):
    lines = file_handle.readlines()
    if (n >= 0 and n < len(lines)):
    return lines[n] # or n-1?
    else:
    return None

    file_handle = open( 'customers.txt', 'r+', encoding="utf-8" )
    fields = get_customer_record( file_handle, 3 )
    print( str( fields ) )


    Of course you may not want to read the whole file, just the next Nth record



    def get_customer_record(file_handle, n):
    if (n >= 0):
    line = file_handle.readline()
    while (n > 0):
    line = file_handle.readline()
    if (line == ''):
    line = None
    break # end of file
    n -= 1
    return line
    else:
    return None


    Obviously this code assumes that n is indexed 0 -> (N-1).






    share|improve this answer























    • Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
      – David Enjugu
      Nov 21 '18 at 3:02










    • @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
      – Kingsley
      Nov 21 '18 at 7:52











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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    A simple solution would be iterate through the file using next():



    from csv import reader

    def get_customer_record(file_handle, n):
    with open(file=file_handle) as csvfile:
    csv_reader = reader(csvfile)
    return next((line for row, line in enumerate(csv_reader) if row == n), )

    print(get_customer_record(file_handle='customer.csv', n=3))
    # ['43564', 'Weilin', 'Zhao', '450.25', '1998-01-03']

    print(get_customer_record(file_handle='customer.csv', n=5))
    #





    share|improve this answer


























      1














      A simple solution would be iterate through the file using next():



      from csv import reader

      def get_customer_record(file_handle, n):
      with open(file=file_handle) as csvfile:
      csv_reader = reader(csvfile)
      return next((line for row, line in enumerate(csv_reader) if row == n), )

      print(get_customer_record(file_handle='customer.csv', n=3))
      # ['43564', 'Weilin', 'Zhao', '450.25', '1998-01-03']

      print(get_customer_record(file_handle='customer.csv', n=5))
      #





      share|improve this answer
























        1












        1








        1






        A simple solution would be iterate through the file using next():



        from csv import reader

        def get_customer_record(file_handle, n):
        with open(file=file_handle) as csvfile:
        csv_reader = reader(csvfile)
        return next((line for row, line in enumerate(csv_reader) if row == n), )

        print(get_customer_record(file_handle='customer.csv', n=3))
        # ['43564', 'Weilin', 'Zhao', '450.25', '1998-01-03']

        print(get_customer_record(file_handle='customer.csv', n=5))
        #





        share|improve this answer












        A simple solution would be iterate through the file using next():



        from csv import reader

        def get_customer_record(file_handle, n):
        with open(file=file_handle) as csvfile:
        csv_reader = reader(csvfile)
        return next((line for row, line in enumerate(csv_reader) if row == n), )

        print(get_customer_record(file_handle='customer.csv', n=3))
        # ['43564', 'Weilin', 'Zhao', '450.25', '1998-01-03']

        print(get_customer_record(file_handle='customer.csv', n=5))
        #






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 3:08









        RoadRunner

        10.7k31340




        10.7k31340

























            0














            It's not clear from your syntax whether to return just the row as a string, or the fields split around the ,. I have assumed the single-line.



            The python readline() function does not take an index, it just reads the next line from the file. Below I used readlines() (note the s) which reads all lines from the file. If your file was huge, this would not be so efficient.



            Also a bit of error-handling for out-of-bounds n helps:



            def get_customer_record(file_handle, n):
            lines = file_handle.readlines()
            if (n >= 0 and n < len(lines)):
            return lines[n] # or n-1?
            else:
            return None

            file_handle = open( 'customers.txt', 'r+', encoding="utf-8" )
            fields = get_customer_record( file_handle, 3 )
            print( str( fields ) )


            Of course you may not want to read the whole file, just the next Nth record



            def get_customer_record(file_handle, n):
            if (n >= 0):
            line = file_handle.readline()
            while (n > 0):
            line = file_handle.readline()
            if (line == ''):
            line = None
            break # end of file
            n -= 1
            return line
            else:
            return None


            Obviously this code assumes that n is indexed 0 -> (N-1).






            share|improve this answer























            • Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
              – David Enjugu
              Nov 21 '18 at 3:02










            • @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
              – Kingsley
              Nov 21 '18 at 7:52
















            0














            It's not clear from your syntax whether to return just the row as a string, or the fields split around the ,. I have assumed the single-line.



            The python readline() function does not take an index, it just reads the next line from the file. Below I used readlines() (note the s) which reads all lines from the file. If your file was huge, this would not be so efficient.



            Also a bit of error-handling for out-of-bounds n helps:



            def get_customer_record(file_handle, n):
            lines = file_handle.readlines()
            if (n >= 0 and n < len(lines)):
            return lines[n] # or n-1?
            else:
            return None

            file_handle = open( 'customers.txt', 'r+', encoding="utf-8" )
            fields = get_customer_record( file_handle, 3 )
            print( str( fields ) )


            Of course you may not want to read the whole file, just the next Nth record



            def get_customer_record(file_handle, n):
            if (n >= 0):
            line = file_handle.readline()
            while (n > 0):
            line = file_handle.readline()
            if (line == ''):
            line = None
            break # end of file
            n -= 1
            return line
            else:
            return None


            Obviously this code assumes that n is indexed 0 -> (N-1).






            share|improve this answer























            • Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
              – David Enjugu
              Nov 21 '18 at 3:02










            • @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
              – Kingsley
              Nov 21 '18 at 7:52














            0












            0








            0






            It's not clear from your syntax whether to return just the row as a string, or the fields split around the ,. I have assumed the single-line.



            The python readline() function does not take an index, it just reads the next line from the file. Below I used readlines() (note the s) which reads all lines from the file. If your file was huge, this would not be so efficient.



            Also a bit of error-handling for out-of-bounds n helps:



            def get_customer_record(file_handle, n):
            lines = file_handle.readlines()
            if (n >= 0 and n < len(lines)):
            return lines[n] # or n-1?
            else:
            return None

            file_handle = open( 'customers.txt', 'r+', encoding="utf-8" )
            fields = get_customer_record( file_handle, 3 )
            print( str( fields ) )


            Of course you may not want to read the whole file, just the next Nth record



            def get_customer_record(file_handle, n):
            if (n >= 0):
            line = file_handle.readline()
            while (n > 0):
            line = file_handle.readline()
            if (line == ''):
            line = None
            break # end of file
            n -= 1
            return line
            else:
            return None


            Obviously this code assumes that n is indexed 0 -> (N-1).






            share|improve this answer














            It's not clear from your syntax whether to return just the row as a string, or the fields split around the ,. I have assumed the single-line.



            The python readline() function does not take an index, it just reads the next line from the file. Below I used readlines() (note the s) which reads all lines from the file. If your file was huge, this would not be so efficient.



            Also a bit of error-handling for out-of-bounds n helps:



            def get_customer_record(file_handle, n):
            lines = file_handle.readlines()
            if (n >= 0 and n < len(lines)):
            return lines[n] # or n-1?
            else:
            return None

            file_handle = open( 'customers.txt', 'r+', encoding="utf-8" )
            fields = get_customer_record( file_handle, 3 )
            print( str( fields ) )


            Of course you may not want to read the whole file, just the next Nth record



            def get_customer_record(file_handle, n):
            if (n >= 0):
            line = file_handle.readline()
            while (n > 0):
            line = file_handle.readline()
            if (line == ''):
            line = None
            break # end of file
            n -= 1
            return line
            else:
            return None


            Obviously this code assumes that n is indexed 0 -> (N-1).







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 21 '18 at 2:48

























            answered Nov 21 '18 at 2:39









            Kingsley

            2,25411023




            2,25411023












            • Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
              – David Enjugu
              Nov 21 '18 at 3:02










            • @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
              – Kingsley
              Nov 21 '18 at 7:52


















            • Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
              – David Enjugu
              Nov 21 '18 at 3:02










            • @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
              – Kingsley
              Nov 21 '18 at 7:52
















            Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
            – David Enjugu
            Nov 21 '18 at 3:02




            Really appreciate the help, my only question is why did you use 3? in the line fields = get..... Thank you
            – David Enjugu
            Nov 21 '18 at 3:02












            @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
            – Kingsley
            Nov 21 '18 at 7:52




            @DavidEnjugu I used 3 just as a test number, no particular reason. But FWIW I tested with 0, 5, 50 and -4 too.
            – Kingsley
            Nov 21 '18 at 7:52


















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