calculate difference between values of a column
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3),
c1=c("w","x","y","z","w","x","y","z","w","x","y","z"),
c2=c("m","m","m","m","f","f","f","f","m","m","m","m"),
c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
> dat
s c1 c2 c3
1 1 w m 1
2 1 x m 2
3 1 y m 3
4 1 z m 4
5 2 w f 5
6 2 x f 6
7 2 y f 7
8 2 z f 8
9 3 w m 9
10 3 x m 10
11 3 y m 11
12 3 z m 12
I'd like to calculate the difference between the c3
values for every combination of c1
(w-x, x-y, etc) and for every s
. The output could look like this
s diff c2 c3
1 w-x m -1
1 w-y m -2
1 w-z m -3
1 x-y m -1
etc
I thought the aggregate
function should work but I don't know how to define the combinations and pass them to the function argument.
r difference
add a comment |
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3),
c1=c("w","x","y","z","w","x","y","z","w","x","y","z"),
c2=c("m","m","m","m","f","f","f","f","m","m","m","m"),
c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
> dat
s c1 c2 c3
1 1 w m 1
2 1 x m 2
3 1 y m 3
4 1 z m 4
5 2 w f 5
6 2 x f 6
7 2 y f 7
8 2 z f 8
9 3 w m 9
10 3 x m 10
11 3 y m 11
12 3 z m 12
I'd like to calculate the difference between the c3
values for every combination of c1
(w-x, x-y, etc) and for every s
. The output could look like this
s diff c2 c3
1 w-x m -1
1 w-y m -2
1 w-z m -3
1 x-y m -1
etc
I thought the aggregate
function should work but I don't know how to define the combinations and pass them to the function argument.
r difference
What is the significance ofs
andc2
? Are you actually interested in diff ofs&c1&c2
with others&c1&c2
s?
– Evan Friedland
Nov 21 '18 at 2:30
add a comment |
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3),
c1=c("w","x","y","z","w","x","y","z","w","x","y","z"),
c2=c("m","m","m","m","f","f","f","f","m","m","m","m"),
c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
> dat
s c1 c2 c3
1 1 w m 1
2 1 x m 2
3 1 y m 3
4 1 z m 4
5 2 w f 5
6 2 x f 6
7 2 y f 7
8 2 z f 8
9 3 w m 9
10 3 x m 10
11 3 y m 11
12 3 z m 12
I'd like to calculate the difference between the c3
values for every combination of c1
(w-x, x-y, etc) and for every s
. The output could look like this
s diff c2 c3
1 w-x m -1
1 w-y m -2
1 w-z m -3
1 x-y m -1
etc
I thought the aggregate
function should work but I don't know how to define the combinations and pass them to the function argument.
r difference
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3),
c1=c("w","x","y","z","w","x","y","z","w","x","y","z"),
c2=c("m","m","m","m","f","f","f","f","m","m","m","m"),
c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
> dat
s c1 c2 c3
1 1 w m 1
2 1 x m 2
3 1 y m 3
4 1 z m 4
5 2 w f 5
6 2 x f 6
7 2 y f 7
8 2 z f 8
9 3 w m 9
10 3 x m 10
11 3 y m 11
12 3 z m 12
I'd like to calculate the difference between the c3
values for every combination of c1
(w-x, x-y, etc) and for every s
. The output could look like this
s diff c2 c3
1 w-x m -1
1 w-y m -2
1 w-z m -3
1 x-y m -1
etc
I thought the aggregate
function should work but I don't know how to define the combinations and pass them to the function argument.
r difference
r difference
edited Nov 21 '18 at 2:31
Ronak Shah
32.9k103753
32.9k103753
asked Nov 21 '18 at 2:11
HappyPy
1,91262135
1,91262135
What is the significance ofs
andc2
? Are you actually interested in diff ofs&c1&c2
with others&c1&c2
s?
– Evan Friedland
Nov 21 '18 at 2:30
add a comment |
What is the significance ofs
andc2
? Are you actually interested in diff ofs&c1&c2
with others&c1&c2
s?
– Evan Friedland
Nov 21 '18 at 2:30
What is the significance of
s
and c2
? Are you actually interested in diff of s&c1&c2
with other s&c1&c2
s?– Evan Friedland
Nov 21 '18 at 2:30
What is the significance of
s
and c2
? Are you actually interested in diff of s&c1&c2
with other s&c1&c2
s?– Evan Friedland
Nov 21 '18 at 2:30
add a comment |
2 Answers
2
active
oldest
votes
If you are willing to use dplyr
something like this should work.
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3), c1=c("w","x","y","z","w","x","y","z","w","x","y","z"), c2=c("m","m","m","m","f","f","f","f","m","m","m","m"), c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
library(dplyr)
dat$c1 <- as.character(dat$c1)
dat2 <- dat %>%
left_join(dat, by = c("s", "c2")) %>%
filter(c1.x > c1.y) %>%
transmute(s, diff = paste(c1.y, c1.x, sep = "-"), c2, c3 = c3.y - c3.x)
dat2
## s diff c2 c3
## 1 1 w-x m -1
## 2 1 w-y m -2
## 3 1 x-y m -1
## 4 1 w-z m -3
## 5 1 x-z m -2
## 6 1 y-z m -1
## 7 2 w-x f -1
## 8 2 w-y f -2
## 9 2 x-y f -1
## 10 2 w-z f -3
## 11 2 x-z f -2
## 12 2 y-z f -1
## 13 3 w-x m -1
## 14 3 w-y m -2
## 15 3 x-y m -1
## 16 3 w-z m -3
## 17 3 x-z m -2
## 18 3 y-z m -1
add a comment |
do.call(rbind, lapply(split(dat, dat$s), function(a){
a$c1 = as.character(a$c1)
d = setNames(data.frame(t(combn(unique(a$c1), 2, FUN = function(x){
list(x[1], x[2], a$c3[a$c1 == x[1]] - a$c3[a$c1 == x[2]])
}))), c("col1", "col2", "val"))
d$s = a$s[1]
d$c2 = a$c2[1]
d
}))
# col1 col2 val s c2
#1.1 w x -1 1 m
#1.2 w y -2 1 m
#1.3 w z -3 1 m
#1.4 x y -1 1 m
#1.5 x z -2 1 m
#1.6 y z -1 1 m
#2.1 w x -1 2 f
#2.2 w y -2 2 f
#2.3 w z -3 2 f
#2.4 x y -1 2 f
#2.5 x z -2 2 f
#2.6 y z -1 2 f
#3.1 w x -1 3 m
#3.2 w y -2 3 m
#3.3 w z -3 3 m
#3.4 x y -1 3 m
#3.5 x z -2 3 m
#3.6 y z -1 3 m
add a comment |
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2 Answers
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2 Answers
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If you are willing to use dplyr
something like this should work.
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3), c1=c("w","x","y","z","w","x","y","z","w","x","y","z"), c2=c("m","m","m","m","f","f","f","f","m","m","m","m"), c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
library(dplyr)
dat$c1 <- as.character(dat$c1)
dat2 <- dat %>%
left_join(dat, by = c("s", "c2")) %>%
filter(c1.x > c1.y) %>%
transmute(s, diff = paste(c1.y, c1.x, sep = "-"), c2, c3 = c3.y - c3.x)
dat2
## s diff c2 c3
## 1 1 w-x m -1
## 2 1 w-y m -2
## 3 1 x-y m -1
## 4 1 w-z m -3
## 5 1 x-z m -2
## 6 1 y-z m -1
## 7 2 w-x f -1
## 8 2 w-y f -2
## 9 2 x-y f -1
## 10 2 w-z f -3
## 11 2 x-z f -2
## 12 2 y-z f -1
## 13 3 w-x m -1
## 14 3 w-y m -2
## 15 3 x-y m -1
## 16 3 w-z m -3
## 17 3 x-z m -2
## 18 3 y-z m -1
add a comment |
If you are willing to use dplyr
something like this should work.
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3), c1=c("w","x","y","z","w","x","y","z","w","x","y","z"), c2=c("m","m","m","m","f","f","f","f","m","m","m","m"), c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
library(dplyr)
dat$c1 <- as.character(dat$c1)
dat2 <- dat %>%
left_join(dat, by = c("s", "c2")) %>%
filter(c1.x > c1.y) %>%
transmute(s, diff = paste(c1.y, c1.x, sep = "-"), c2, c3 = c3.y - c3.x)
dat2
## s diff c2 c3
## 1 1 w-x m -1
## 2 1 w-y m -2
## 3 1 x-y m -1
## 4 1 w-z m -3
## 5 1 x-z m -2
## 6 1 y-z m -1
## 7 2 w-x f -1
## 8 2 w-y f -2
## 9 2 x-y f -1
## 10 2 w-z f -3
## 11 2 x-z f -2
## 12 2 y-z f -1
## 13 3 w-x m -1
## 14 3 w-y m -2
## 15 3 x-y m -1
## 16 3 w-z m -3
## 17 3 x-z m -2
## 18 3 y-z m -1
add a comment |
If you are willing to use dplyr
something like this should work.
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3), c1=c("w","x","y","z","w","x","y","z","w","x","y","z"), c2=c("m","m","m","m","f","f","f","f","m","m","m","m"), c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
library(dplyr)
dat$c1 <- as.character(dat$c1)
dat2 <- dat %>%
left_join(dat, by = c("s", "c2")) %>%
filter(c1.x > c1.y) %>%
transmute(s, diff = paste(c1.y, c1.x, sep = "-"), c2, c3 = c3.y - c3.x)
dat2
## s diff c2 c3
## 1 1 w-x m -1
## 2 1 w-y m -2
## 3 1 x-y m -1
## 4 1 w-z m -3
## 5 1 x-z m -2
## 6 1 y-z m -1
## 7 2 w-x f -1
## 8 2 w-y f -2
## 9 2 x-y f -1
## 10 2 w-z f -3
## 11 2 x-z f -2
## 12 2 y-z f -1
## 13 3 w-x m -1
## 14 3 w-y m -2
## 15 3 x-y m -1
## 16 3 w-z m -3
## 17 3 x-z m -2
## 18 3 y-z m -1
If you are willing to use dplyr
something like this should work.
dat <- data.frame(s=c(1,1,1,1,2,2,2,2,3,3,3,3), c1=c("w","x","y","z","w","x","y","z","w","x","y","z"), c2=c("m","m","m","m","f","f","f","f","m","m","m","m"), c3=c(1,2,3,4,5,6,7,8,9,10,11,12))
library(dplyr)
dat$c1 <- as.character(dat$c1)
dat2 <- dat %>%
left_join(dat, by = c("s", "c2")) %>%
filter(c1.x > c1.y) %>%
transmute(s, diff = paste(c1.y, c1.x, sep = "-"), c2, c3 = c3.y - c3.x)
dat2
## s diff c2 c3
## 1 1 w-x m -1
## 2 1 w-y m -2
## 3 1 x-y m -1
## 4 1 w-z m -3
## 5 1 x-z m -2
## 6 1 y-z m -1
## 7 2 w-x f -1
## 8 2 w-y f -2
## 9 2 x-y f -1
## 10 2 w-z f -3
## 11 2 x-z f -2
## 12 2 y-z f -1
## 13 3 w-x m -1
## 14 3 w-y m -2
## 15 3 x-y m -1
## 16 3 w-z m -3
## 17 3 x-z m -2
## 18 3 y-z m -1
answered Nov 21 '18 at 2:39
jmuhlenkamp
1,403525
1,403525
add a comment |
add a comment |
do.call(rbind, lapply(split(dat, dat$s), function(a){
a$c1 = as.character(a$c1)
d = setNames(data.frame(t(combn(unique(a$c1), 2, FUN = function(x){
list(x[1], x[2], a$c3[a$c1 == x[1]] - a$c3[a$c1 == x[2]])
}))), c("col1", "col2", "val"))
d$s = a$s[1]
d$c2 = a$c2[1]
d
}))
# col1 col2 val s c2
#1.1 w x -1 1 m
#1.2 w y -2 1 m
#1.3 w z -3 1 m
#1.4 x y -1 1 m
#1.5 x z -2 1 m
#1.6 y z -1 1 m
#2.1 w x -1 2 f
#2.2 w y -2 2 f
#2.3 w z -3 2 f
#2.4 x y -1 2 f
#2.5 x z -2 2 f
#2.6 y z -1 2 f
#3.1 w x -1 3 m
#3.2 w y -2 3 m
#3.3 w z -3 3 m
#3.4 x y -1 3 m
#3.5 x z -2 3 m
#3.6 y z -1 3 m
add a comment |
do.call(rbind, lapply(split(dat, dat$s), function(a){
a$c1 = as.character(a$c1)
d = setNames(data.frame(t(combn(unique(a$c1), 2, FUN = function(x){
list(x[1], x[2], a$c3[a$c1 == x[1]] - a$c3[a$c1 == x[2]])
}))), c("col1", "col2", "val"))
d$s = a$s[1]
d$c2 = a$c2[1]
d
}))
# col1 col2 val s c2
#1.1 w x -1 1 m
#1.2 w y -2 1 m
#1.3 w z -3 1 m
#1.4 x y -1 1 m
#1.5 x z -2 1 m
#1.6 y z -1 1 m
#2.1 w x -1 2 f
#2.2 w y -2 2 f
#2.3 w z -3 2 f
#2.4 x y -1 2 f
#2.5 x z -2 2 f
#2.6 y z -1 2 f
#3.1 w x -1 3 m
#3.2 w y -2 3 m
#3.3 w z -3 3 m
#3.4 x y -1 3 m
#3.5 x z -2 3 m
#3.6 y z -1 3 m
add a comment |
do.call(rbind, lapply(split(dat, dat$s), function(a){
a$c1 = as.character(a$c1)
d = setNames(data.frame(t(combn(unique(a$c1), 2, FUN = function(x){
list(x[1], x[2], a$c3[a$c1 == x[1]] - a$c3[a$c1 == x[2]])
}))), c("col1", "col2", "val"))
d$s = a$s[1]
d$c2 = a$c2[1]
d
}))
# col1 col2 val s c2
#1.1 w x -1 1 m
#1.2 w y -2 1 m
#1.3 w z -3 1 m
#1.4 x y -1 1 m
#1.5 x z -2 1 m
#1.6 y z -1 1 m
#2.1 w x -1 2 f
#2.2 w y -2 2 f
#2.3 w z -3 2 f
#2.4 x y -1 2 f
#2.5 x z -2 2 f
#2.6 y z -1 2 f
#3.1 w x -1 3 m
#3.2 w y -2 3 m
#3.3 w z -3 3 m
#3.4 x y -1 3 m
#3.5 x z -2 3 m
#3.6 y z -1 3 m
do.call(rbind, lapply(split(dat, dat$s), function(a){
a$c1 = as.character(a$c1)
d = setNames(data.frame(t(combn(unique(a$c1), 2, FUN = function(x){
list(x[1], x[2], a$c3[a$c1 == x[1]] - a$c3[a$c1 == x[2]])
}))), c("col1", "col2", "val"))
d$s = a$s[1]
d$c2 = a$c2[1]
d
}))
# col1 col2 val s c2
#1.1 w x -1 1 m
#1.2 w y -2 1 m
#1.3 w z -3 1 m
#1.4 x y -1 1 m
#1.5 x z -2 1 m
#1.6 y z -1 1 m
#2.1 w x -1 2 f
#2.2 w y -2 2 f
#2.3 w z -3 2 f
#2.4 x y -1 2 f
#2.5 x z -2 2 f
#2.6 y z -1 2 f
#3.1 w x -1 3 m
#3.2 w y -2 3 m
#3.3 w z -3 3 m
#3.4 x y -1 3 m
#3.5 x z -2 3 m
#3.6 y z -1 3 m
answered Nov 21 '18 at 3:18
d.b
18.5k41846
18.5k41846
add a comment |
add a comment |
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What is the significance of
s
andc2
? Are you actually interested in diff ofs&c1&c2
with others&c1&c2
s?– Evan Friedland
Nov 21 '18 at 2:30