how to parse the following string using regular expression (JS)
I have the following string: "bytes 5242880-5253879/5253880"
I need to take parse the string and extract the numbers using regexp in JS, thanks
javascript regex
edited Nov 20 at 15:34
pushkin
3,939112651
asked Nov 20 at 15:12
Elad Katz
6,01932961
add a comment |
I have the following string: "bytes 5242880-5253879/5253880"
I need to take parse the string and extract the numbers using regexp in JS, thanks
javascript regex
edited Nov 20 at 15:34
pushkin
3,939112651
asked Nov 20 at 15:12
Elad Katz
6,01932961
1
Please show your efforts, SO is not a free code writing service.
– Peter B
Nov 20 at 15:14
add a comment |
I have the following string: "bytes 5242880-5253879/5253880"
I need to take parse the string and extract the numbers using regexp in JS, thanks
javascript regex
edited Nov 20 at 15:34
pushkin
3,939112651
asked Nov 20 at 15:12
Elad Katz
6,01932961
I have the following string: "bytes 5242880-5253879/5253880"
I need to take parse the string and extract the numbers using regexp in JS, thanks
javascript regex
javascript regex
edited Nov 20 at 15:34
pushkin
3,939112651
asked Nov 20 at 15:12
Elad Katz
6,01932961
edited Nov 20 at 15:34
pushkin
3,939112651
asked Nov 20 at 15:12
Elad Katz
6,01932961
edited Nov 20 at 15:34
pushkin
3,939112651
edited Nov 20 at 15:34
pushkin
3,939112651
edited Nov 20 at 15:34
pushkin
3,939112651
3,939112651
asked Nov 20 at 15:12
Elad Katz
6,01932961
asked Nov 20 at 15:12
Elad Katz
6,01932961
asked Nov 20 at 15:12
Elad Katz
6,01932961
6,01932961
1
Please show your efforts, SO is not a free code writing service.
– Peter B
Nov 20 at 15:14
add a comment |
1
Please show your efforts, SO is not a free code writing service.
– Peter B
Nov 20 at 15:14
1
1
Please show your efforts, SO is not a free code writing service.
– Peter B
Nov 20 at 15:14
Please show your efforts, SO is not a free code writing service.
– Peter B
Nov 20 at 15:14
add a comment |
3 Answers
3
active
oldest
votes
Your question is quite vague but the following regex will match each number (separated by the dash and forward slash) in groups 1..3:
const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])answered Nov 20 at 15:18
alexjackson
221
add a comment |
You should be able to just match the numbers with d+.
let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)answered Nov 20 at 15:14
Mark Meyer
35.4k32855
add a comment |
string input = "bytes 5242880-5253879/5253880";
string result = Regex.Replace(input, @"(?:^|)(d{7,8})(?!d)", "");
Console.WriteLine(result); // >> 524288052538795253880
answered Nov 20 at 15:29
Sarah117
236
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your question is quite vague but the following regex will match each number (separated by the dash and forward slash) in groups 1..3:
const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])answered Nov 20 at 15:18
alexjackson
221
add a comment |
Your question is quite vague but the following regex will match each number (separated by the dash and forward slash) in groups 1..3:
const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])answered Nov 20 at 15:18
alexjackson
221
add a comment |
Your question is quite vague but the following regex will match each number (separated by the dash and forward slash) in groups 1..3:
const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])answered Nov 20 at 15:18
alexjackson
221
Your question is quite vague but the following regex will match each number (separated by the dash and forward slash) in groups 1..3:
const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])const str = "bytes 5242880-5253879/5253880"
let n = str.match(/bytes (d.*)-(d.*)/(d.*)/)
console.log("Match 1:", n[1])
console.log("Match 2:", n[2])
console.log("Match 3:", n[3])answered Nov 20 at 15:18
alexjackson
221
answered Nov 20 at 15:18
alexjackson
221
answered Nov 20 at 15:18
alexjackson
221
answered Nov 20 at 15:18
alexjackson
221
221
add a comment |
add a comment |
You should be able to just match the numbers with d+.
let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)answered Nov 20 at 15:14
Mark Meyer
35.4k32855
add a comment |
You should be able to just match the numbers with d+.
let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)answered Nov 20 at 15:14
Mark Meyer
35.4k32855
add a comment |
You should be able to just match the numbers with d+.
let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)answered Nov 20 at 15:14
Mark Meyer
35.4k32855
You should be able to just match the numbers with d+.
let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)let str = "bytes 5242880-5253879/5253880"
let n = str.match(/d+/g)
console.log(n)answered Nov 20 at 15:14
Mark Meyer
35.4k32855
answered Nov 20 at 15:14
Mark Meyer
35.4k32855
answered Nov 20 at 15:14
Mark Meyer
35.4k32855
answered Nov 20 at 15:14
Mark Meyer
35.4k32855
35.4k32855
add a comment |
add a comment |
string input = "bytes 5242880-5253879/5253880";
string result = Regex.Replace(input, @"(?:^|)(d{7,8})(?!d)", "");
Console.WriteLine(result); // >> 524288052538795253880
answered Nov 20 at 15:29
Sarah117
236
add a comment |
string input = "bytes 5242880-5253879/5253880";
string result = Regex.Replace(input, @"(?:^|)(d{7,8})(?!d)", "");
Console.WriteLine(result); // >> 524288052538795253880
answered Nov 20 at 15:29
Sarah117
236
add a comment |
string input = "bytes 5242880-5253879/5253880";
string result = Regex.Replace(input, @"(?:^|)(d{7,8})(?!d)", "");
Console.WriteLine(result); // >> 524288052538795253880
answered Nov 20 at 15:29
Sarah117
236
string input = "bytes 5242880-5253879/5253880";
string result = Regex.Replace(input, @"(?:^|)(d{7,8})(?!d)", "");
Console.WriteLine(result); // >> 524288052538795253880
answered Nov 20 at 15:29
Sarah117
236
answered Nov 20 at 15:29
Sarah117
236
answered Nov 20 at 15:29
Sarah117
236
answered Nov 20 at 15:29
Sarah117
236
236
add a comment |
add a comment |
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1
Please show your efforts, SO is not a free code writing service.
– Peter B
Nov 20 at 15:14