Dynamically import component in React based on config entries
I have multiple apps as part of one React-redux-typescript project. All of these individual apps are part of a core-application. I want to dynamically set up routing.
My current routes look like this:
Routes.tsx
import HomePageApp from "../Components/Home/HomeApp";
import TestApp from "../Components/Test/TestApp";
export default function Routes() {
return (
<Switch>
<RedirectIfAuthenticated
exact={true}
isAuthenticated={true}
path={Path.homePath} --> "/"
component={HomePage} ---> AppName coming from import statement on top
redirectPath={Path.homePath} --> "/"
/>
<RedirectIfAuthenticated
isAuthenticated={true}
path={Path.apps.test} --> "/test"
component={TestApp} --> AppName from import on top
redirectPath={Path.homePath} --> "/"
/>
</Switch>
);
}
And RedirectIfAuthenticated simply redirects to correct applications' landing pages.
RedirectIfAuthenticated.tsx
export default function RedirectIfAuthenticated({
component,
redirectPath,
isAuthenticated,
...rest
}: IRedirectIfAuthenticatedProps) {
const Component = component;
const render = (renderProps: RouteComponentProps<any>) => {
let element = <Component {...renderProps} />;
return element;
};
return <Route {...rest} render={render}/>;
}
I've a config file like this:
Manifest.ts
export let manifest = {
apps: [
{
componentPath: "/Test/App",
path: "/test",
name: "Test"
},
...more objects for other apps
]
};
In my Routes.tsx, I want to make use of my manifest to render the RedirectIfAuthenticated component.
so I can figure out this change:
for brevity showing the dirty approach but the actual code iterates over the manifest using .map and renders RedirectIfAutenticated.
const app = manifest.apps.find(app => app.name === "Test");
<Switch>
<RedirectIfAuthenticated
isAuthenticated={true}
path={app.path} --> "/test"
component={What should I do here? How to pass component reference by path??}
redirectPath={"/"} ==> I typically get this from my manifest..
/>
</Switch>
One option is to do this:
component={require("path from manifest").default}
but our tslint throws a bunch of errors at this. Other than this I can't figure out how to pass the component reference here dynamically. Looking for a better approach.
The Routes.tsx needs to be dynamic so that adding new apps is a matter of configuration so I can't do imports on top because I dont know what's gonna be added in config. Thanks.
reactjs typescript ecmascript-6 import router
add a comment |
I have multiple apps as part of one React-redux-typescript project. All of these individual apps are part of a core-application. I want to dynamically set up routing.
My current routes look like this:
Routes.tsx
import HomePageApp from "../Components/Home/HomeApp";
import TestApp from "../Components/Test/TestApp";
export default function Routes() {
return (
<Switch>
<RedirectIfAuthenticated
exact={true}
isAuthenticated={true}
path={Path.homePath} --> "/"
component={HomePage} ---> AppName coming from import statement on top
redirectPath={Path.homePath} --> "/"
/>
<RedirectIfAuthenticated
isAuthenticated={true}
path={Path.apps.test} --> "/test"
component={TestApp} --> AppName from import on top
redirectPath={Path.homePath} --> "/"
/>
</Switch>
);
}
And RedirectIfAuthenticated simply redirects to correct applications' landing pages.
RedirectIfAuthenticated.tsx
export default function RedirectIfAuthenticated({
component,
redirectPath,
isAuthenticated,
...rest
}: IRedirectIfAuthenticatedProps) {
const Component = component;
const render = (renderProps: RouteComponentProps<any>) => {
let element = <Component {...renderProps} />;
return element;
};
return <Route {...rest} render={render}/>;
}
I've a config file like this:
Manifest.ts
export let manifest = {
apps: [
{
componentPath: "/Test/App",
path: "/test",
name: "Test"
},
...more objects for other apps
]
};
In my Routes.tsx, I want to make use of my manifest to render the RedirectIfAuthenticated component.
so I can figure out this change:
for brevity showing the dirty approach but the actual code iterates over the manifest using .map and renders RedirectIfAutenticated.
const app = manifest.apps.find(app => app.name === "Test");
<Switch>
<RedirectIfAuthenticated
isAuthenticated={true}
path={app.path} --> "/test"
component={What should I do here? How to pass component reference by path??}
redirectPath={"/"} ==> I typically get this from my manifest..
/>
</Switch>
One option is to do this:
component={require("path from manifest").default}
but our tslint throws a bunch of errors at this. Other than this I can't figure out how to pass the component reference here dynamically. Looking for a better approach.
The Routes.tsx needs to be dynamic so that adding new apps is a matter of configuration so I can't do imports on top because I dont know what's gonna be added in config. Thanks.
reactjs typescript ecmascript-6 import router
If your React version isv16.6.x
then you can try to use React.lazy doing something likecomponent={React.lazy(() => import("path from manifest"))}
<- you don't need to extract.default
withlazy
as it's done automatically. Also refer to my Shameless Plug: Loading React Components Dynamically on Demand
– Sung Kim
Nov 20 at 19:12
add a comment |
I have multiple apps as part of one React-redux-typescript project. All of these individual apps are part of a core-application. I want to dynamically set up routing.
My current routes look like this:
Routes.tsx
import HomePageApp from "../Components/Home/HomeApp";
import TestApp from "../Components/Test/TestApp";
export default function Routes() {
return (
<Switch>
<RedirectIfAuthenticated
exact={true}
isAuthenticated={true}
path={Path.homePath} --> "/"
component={HomePage} ---> AppName coming from import statement on top
redirectPath={Path.homePath} --> "/"
/>
<RedirectIfAuthenticated
isAuthenticated={true}
path={Path.apps.test} --> "/test"
component={TestApp} --> AppName from import on top
redirectPath={Path.homePath} --> "/"
/>
</Switch>
);
}
And RedirectIfAuthenticated simply redirects to correct applications' landing pages.
RedirectIfAuthenticated.tsx
export default function RedirectIfAuthenticated({
component,
redirectPath,
isAuthenticated,
...rest
}: IRedirectIfAuthenticatedProps) {
const Component = component;
const render = (renderProps: RouteComponentProps<any>) => {
let element = <Component {...renderProps} />;
return element;
};
return <Route {...rest} render={render}/>;
}
I've a config file like this:
Manifest.ts
export let manifest = {
apps: [
{
componentPath: "/Test/App",
path: "/test",
name: "Test"
},
...more objects for other apps
]
};
In my Routes.tsx, I want to make use of my manifest to render the RedirectIfAuthenticated component.
so I can figure out this change:
for brevity showing the dirty approach but the actual code iterates over the manifest using .map and renders RedirectIfAutenticated.
const app = manifest.apps.find(app => app.name === "Test");
<Switch>
<RedirectIfAuthenticated
isAuthenticated={true}
path={app.path} --> "/test"
component={What should I do here? How to pass component reference by path??}
redirectPath={"/"} ==> I typically get this from my manifest..
/>
</Switch>
One option is to do this:
component={require("path from manifest").default}
but our tslint throws a bunch of errors at this. Other than this I can't figure out how to pass the component reference here dynamically. Looking for a better approach.
The Routes.tsx needs to be dynamic so that adding new apps is a matter of configuration so I can't do imports on top because I dont know what's gonna be added in config. Thanks.
reactjs typescript ecmascript-6 import router
I have multiple apps as part of one React-redux-typescript project. All of these individual apps are part of a core-application. I want to dynamically set up routing.
My current routes look like this:
Routes.tsx
import HomePageApp from "../Components/Home/HomeApp";
import TestApp from "../Components/Test/TestApp";
export default function Routes() {
return (
<Switch>
<RedirectIfAuthenticated
exact={true}
isAuthenticated={true}
path={Path.homePath} --> "/"
component={HomePage} ---> AppName coming from import statement on top
redirectPath={Path.homePath} --> "/"
/>
<RedirectIfAuthenticated
isAuthenticated={true}
path={Path.apps.test} --> "/test"
component={TestApp} --> AppName from import on top
redirectPath={Path.homePath} --> "/"
/>
</Switch>
);
}
And RedirectIfAuthenticated simply redirects to correct applications' landing pages.
RedirectIfAuthenticated.tsx
export default function RedirectIfAuthenticated({
component,
redirectPath,
isAuthenticated,
...rest
}: IRedirectIfAuthenticatedProps) {
const Component = component;
const render = (renderProps: RouteComponentProps<any>) => {
let element = <Component {...renderProps} />;
return element;
};
return <Route {...rest} render={render}/>;
}
I've a config file like this:
Manifest.ts
export let manifest = {
apps: [
{
componentPath: "/Test/App",
path: "/test",
name: "Test"
},
...more objects for other apps
]
};
In my Routes.tsx, I want to make use of my manifest to render the RedirectIfAuthenticated component.
so I can figure out this change:
for brevity showing the dirty approach but the actual code iterates over the manifest using .map and renders RedirectIfAutenticated.
const app = manifest.apps.find(app => app.name === "Test");
<Switch>
<RedirectIfAuthenticated
isAuthenticated={true}
path={app.path} --> "/test"
component={What should I do here? How to pass component reference by path??}
redirectPath={"/"} ==> I typically get this from my manifest..
/>
</Switch>
One option is to do this:
component={require("path from manifest").default}
but our tslint throws a bunch of errors at this. Other than this I can't figure out how to pass the component reference here dynamically. Looking for a better approach.
The Routes.tsx needs to be dynamic so that adding new apps is a matter of configuration so I can't do imports on top because I dont know what's gonna be added in config. Thanks.
reactjs typescript ecmascript-6 import router
reactjs typescript ecmascript-6 import router
edited Nov 20 at 19:00
asked Nov 20 at 18:30
clever_bassi
1,34721033
1,34721033
If your React version isv16.6.x
then you can try to use React.lazy doing something likecomponent={React.lazy(() => import("path from manifest"))}
<- you don't need to extract.default
withlazy
as it's done automatically. Also refer to my Shameless Plug: Loading React Components Dynamically on Demand
– Sung Kim
Nov 20 at 19:12
add a comment |
If your React version isv16.6.x
then you can try to use React.lazy doing something likecomponent={React.lazy(() => import("path from manifest"))}
<- you don't need to extract.default
withlazy
as it's done automatically. Also refer to my Shameless Plug: Loading React Components Dynamically on Demand
– Sung Kim
Nov 20 at 19:12
If your React version is
v16.6.x
then you can try to use React.lazy doing something like component={React.lazy(() => import("path from manifest"))}
<- you don't need to extract .default
with lazy
as it's done automatically. Also refer to my Shameless Plug: Loading React Components Dynamically on Demand– Sung Kim
Nov 20 at 19:12
If your React version is
v16.6.x
then you can try to use React.lazy doing something like component={React.lazy(() => import("path from manifest"))}
<- you don't need to extract .default
with lazy
as it's done automatically. Also refer to my Shameless Plug: Loading React Components Dynamically on Demand– Sung Kim
Nov 20 at 19:12
add a comment |
1 Answer
1
active
oldest
votes
I was able to use dynamic imports to achieve this. I used this article to understand a few concepts.
private loadComponentFromPath(path: string) {
import(`../../ScriptsApp/${path}`).then(component =>
this.setState({
component: component.default
})
);
}
One important distinction here is if I don't give the path from the root of the app, I get an error saying "Unable to find the module". This is why I've given the full path from the root.
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I was able to use dynamic imports to achieve this. I used this article to understand a few concepts.
private loadComponentFromPath(path: string) {
import(`../../ScriptsApp/${path}`).then(component =>
this.setState({
component: component.default
})
);
}
One important distinction here is if I don't give the path from the root of the app, I get an error saying "Unable to find the module". This is why I've given the full path from the root.
add a comment |
I was able to use dynamic imports to achieve this. I used this article to understand a few concepts.
private loadComponentFromPath(path: string) {
import(`../../ScriptsApp/${path}`).then(component =>
this.setState({
component: component.default
})
);
}
One important distinction here is if I don't give the path from the root of the app, I get an error saying "Unable to find the module". This is why I've given the full path from the root.
add a comment |
I was able to use dynamic imports to achieve this. I used this article to understand a few concepts.
private loadComponentFromPath(path: string) {
import(`../../ScriptsApp/${path}`).then(component =>
this.setState({
component: component.default
})
);
}
One important distinction here is if I don't give the path from the root of the app, I get an error saying "Unable to find the module". This is why I've given the full path from the root.
I was able to use dynamic imports to achieve this. I used this article to understand a few concepts.
private loadComponentFromPath(path: string) {
import(`../../ScriptsApp/${path}`).then(component =>
this.setState({
component: component.default
})
);
}
One important distinction here is if I don't give the path from the root of the app, I get an error saying "Unable to find the module". This is why I've given the full path from the root.
answered Nov 30 at 23:04
clever_bassi
1,34721033
1,34721033
add a comment |
add a comment |
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If your React version is
v16.6.x
then you can try to use React.lazy doing something likecomponent={React.lazy(() => import("path from manifest"))}
<- you don't need to extract.default
withlazy
as it's done automatically. Also refer to my Shameless Plug: Loading React Components Dynamically on Demand– Sung Kim
Nov 20 at 19:12